`<complex>` 函数

项目
10/12/2023

abs

计算复数的模数。

template <class Type>
Type abs(const complex<Type>& complexNum);

参数

complexNum
要确定取模的复数。

返回值

复数取模。

备注

复数的取模是测量表示复数矢量的长度。复数 a + bi 的模数是 (a² + b²) 的平方根，写作 |a + bi|。复数 a + bi 的范数是 (a² + b²)。复数的 norm 是其取模的平方。

示例

// complex_abs.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;

   // Complex numbers can be entered in polar form with
   // modulus and argument parameter inputs but are
   // stored in Cartesian form as real & imag coordinates
   complex <double> c1 ( polar ( 5.0 ) );   // Default argument = 0
   complex <double> c2 ( polar ( 5.0 , pi / 6 ) );
   complex <double> c3 ( polar ( 5.0 , 13 * pi / 6 ) );
   cout << "c1 = polar ( 5.0 ) = " << c1 << endl;
   cout << "c2 = polar ( 5.0 , pi / 6 ) = " << c2 << endl;
   cout << "c3 = polar ( 5.0 , 13 * pi / 6 ) = " << c3 << endl;

   // The modulus and argument of a complex number can be recovered
   // using abs & arg member functions
   double absc1 = abs ( c1 );
   double argc1 = arg ( c1 );
   cout << "The modulus of c1 is recovered from c1 using: abs ( c1 ) = "
        << absc1 << endl;
   cout << "Argument of c1 is recovered from c1 using:\n arg ( c1 ) = "
        << argc1 << " radians, which is " << argc1 * 180 / pi
        << " degrees." << endl;

   double absc2 = abs ( c2 );
   double argc2 = arg ( c2 );
   cout << "The modulus of c2 is recovered from c2 using: abs ( c2 ) = "
        << absc2 << endl;
   cout << "Argument of c2 is recovered from c2 using:\n arg ( c2 ) = "
        << argc2 << " radians, which is " << argc2 * 180 / pi
        << " degrees." << endl;

   // Testing if the principal angles of c2 and c3 are the same
   if ( (arg ( c2 ) <= ( arg ( c3 ) + .00000001) ) ||
        (arg ( c2 ) >= ( arg ( c3 ) - .00000001) ) )
      cout << "The complex numbers c2 & c3 have the "
           << "same principal arguments."<< endl;
   else
      cout << "The complex numbers c2 & c3 don't have the "
           << "same principal arguments." << endl;
}

c1 = polar ( 5.0 ) = (5,0)
c2 = polar ( 5.0 , pi / 6 ) = (4.33013,2.5)
c3 = polar ( 5.0 , 13 * pi / 6 ) = (4.33013,2.5)
The modulus of c1 is recovered from c1 using: abs ( c1 ) = 5
Argument of c1 is recovered from c1 using:
arg ( c1 ) = 0 radians, which is 0 degrees.
The modulus of c2 is recovered from c2 using: abs ( c2 ) = 5
Argument of c2 is recovered from c2 using:
arg ( c2 ) = 0.523599 radians, which is 30 degrees.
The complex numbers c2 & c3 have the same principal arguments.

acos

template<class T> complex<T> acos(const complex<T>&);

acosh

template<class T> complex<T> acosh(const complex<T>&);

arg

从复数中提取自变量。

template <class Type>
Type arg(const complex<Type>& complexNum);

参数

complexNum
要确定参数的复数。

返回值

复数的参数。

注解

参数是在复平面的正实轴中所进行的复向量的角度。对于复数 a + bi，参数等于反正切值 (b/a)。该角度从正实轴以逆时针方向测量时为正值，以顺时针方向测量时则为负值。主体值大于 -pi 且小于或等于 +pi。

示例

// complex_arg.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;

   // Complex numbers can be entered in polar form with
   // modulus and argument parameter inputs but are
   // stored in Cartesian form as real & imag coordinates
   complex <double> c1 ( polar ( 5.0 ) );   // Default argument = 0
   complex <double> c2 ( polar ( 5.0 , pi / 6 ) );
   complex <double> c3 ( polar ( 5.0 , 13 * pi / 6 ) );
   cout << "c1 = polar ( 5.0 ) = " << c1 << endl;
   cout << "c2 = polar ( 5.0 , pi / 6 ) = " << c2 << endl;
   cout << "c3 = polar ( 5.0 , 13 * pi / 6 ) = " << c3 << endl;

   // The modulus and argument of a complex number can be rcovered
   // using abs & arg member functions
   double absc1 = abs ( c1 );
   double argc1 = arg ( c1 );
   cout << "The modulus of c1 is recovered from c1 using: abs ( c1 ) = "
        << absc1 << endl;
   cout << "Argument of c1 is recovered from c1 using:\n arg ( c1 ) = "
        << argc1 << " radians, which is " << argc1 * 180 / pi
        << " degrees." << endl;

   double absc2 = abs ( c2 );
   double argc2 = arg ( c2 );
   cout << "The modulus of c2 is recovered from c2 using: abs ( c2 ) = "
        << absc2 << endl;
   cout << "Argument of c2 is recovered from c2 using:\n arg ( c2 ) = "
        << argc2 << " radians, which is " << argc2 * 180 / pi
        << " degrees." << endl;

   // Testing if the principal angles of c2 and c3 are the same
   if ( (arg ( c2 ) <= ( arg ( c3 ) + .00000001) ) ||
        (arg ( c2 ) >= ( arg ( c3 ) - .00000001) ) )
      cout << "The complex numbers c2 & c3 have the "
           << "same principal arguments."<< endl;
   else
      cout << "The complex numbers c2 & c3 don't have the "
           << "same principal arguments." << endl;
}

c1 = polar ( 5.0 ) = (5,0)
c2 = polar ( 5.0 , pi / 6 ) = (4.33013,2.5)
c3 = polar ( 5.0 , 13 * pi / 6 ) = (4.33013,2.5)
The modulus of c1 is recovered from c1 using: abs ( c1 ) = 5
Argument of c1 is recovered from c1 using:
arg ( c1 ) = 0 radians, which is 0 degrees.
The modulus of c2 is recovered from c2 using: abs ( c2 ) = 5
Argument of c2 is recovered from c2 using:
arg ( c2 ) = 0.523599 radians, which is 30 degrees.
The complex numbers c2 & c3 have the same principal arguments.

asin

template<class T> complex<T> asin(const complex<T>&);

asinh

template<class T> complex<T> asinh(const complex<T>&);

atan

template<class T> complex<T> atan(const complex<T>&);

atanh

template<class T> complex<T> atanh(const complex<T>&);

conj

返回复数的复数共轭。

template <class Type>
complex<Type> conj(const complex<Type>& complexNum);

参数

complexNum
要返回的复共轭的复数。

返回值

输入复数的复共轭。

备注

复数 a + bi 的复共轭为 a - bi。复数及其共轭的乘积是数 a2 + b2 的 norm。

示例

// complex_conj.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;

   complex <double> c1 ( 4.0 , 3.0 );
   cout << "The complex number c1 = " << c1 << endl;

   double dr1 = real ( c1 );
   cout << "The real part of c1 is real ( c1 ) = "
        << dr1 << "." << endl;

   double di1 = imag ( c1 );
   cout << "The imaginary part of c1 is imag ( c1 ) = "
        << di1 << "." << endl;

   complex <double> c2 = conj ( c1 );
   cout << "The complex conjugate of c1 is c2 = conj ( c1 )= "
        << c2 << endl;

   double dr2 = real ( c2 );
   cout << "The real part of c2 is real ( c2 ) = "
        << dr2 << "." << endl;

   double di2 = imag ( c2 );
   cout << "The imaginary part of c2 is imag ( c2 ) = "
        << di2 << "." << endl;

   // The real part of the product of a complex number
   // and its conjugate is the norm of the number
   complex <double> c3 = c1 * c2;
   cout << "The norm of (c1 * conj (c1) ) is c1 * c2 = "
        << real( c3 ) << endl;
}

The complex number c1 = (4,3)
The real part of c1 is real ( c1 ) = 4.
The imaginary part of c1 is imag ( c1 ) = 3.
The complex conjugate of c1 is c2 = conj ( c1 )= (4,-3)
The real part of c2 is real ( c2 ) = 4.
The imaginary part of c2 is imag ( c2 ) = -3.
The norm of (c1 * conj (c1) ) is c1 * c2 = 25

cos

返回复数的余弦值。

template <class Type>
complex<Type> cos(const complex<Type>& complexNum);

参数

complexNum
要确定其余弦的复数。

返回值

输入复数的余弦的复数。

备注

定义复余弦的标识：

cos (z) = (1/2)*(exp (iz) + exp (- iz) )

cos (z) = cos (a + bi) = cos (a) cosh ( b) - isin (a) sinh (b)

示例

// complex_cos.cpp
// compile with: /EHsc
#include <vector>
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;
   complex <double> c1 ( 3.0 , 4.0 );
   cout << "Complex number c1 = " << c1 << endl;

   // Values of cosine of a complex number c1
   complex <double> c2 = cos ( c1 );
   cout << "Complex number c2 = cos ( c1 ) = " << c2 << endl;
   double absc2 = abs ( c2 );
   double argc2 = arg ( c2 );
   cout << "The modulus of c2 is: " << absc2 << endl;
   cout << "The argument of c2 is: "<< argc2 << " radians, which is "
        << argc2 * 180 / pi << " degrees." << endl << endl;

   // Cosines of the standard angles in the first
   // two quadrants of the complex plane
   vector <complex <double> > v1;
   vector <complex <double> >::iterator Iter1;
   complex <double> vc1  ( polar (1.0, pi / 6) );
   v1.push_back( cos ( vc1 ) );
   complex <double> vc2  ( polar (1.0, pi / 3) );
   v1.push_back( cos ( vc2 ) );
   complex <double> vc3  ( polar (1.0, pi / 2) );
   v1.push_back( cos ( vc3) );
   complex <double> vc4  ( polar (1.0, 2 * pi / 3) );
   v1.push_back( cos ( vc4 ) );
   complex <double> vc5  ( polar (1.0, 5 * pi / 6) );
   v1.push_back( cos ( vc5 ) );
   complex <double> vc6  ( polar (1.0,  pi ) );
   v1.push_back( cos ( vc6 ) );

   cout << "The complex components cos (vci), where abs (vci) = 1"
        << "\n& arg (vci) = i * pi / 6 of the vector v1 are:\n" ;
   for ( Iter1 = v1.begin( ) ; Iter1 != v1.end( ) ; Iter1++ )
      cout << *Iter1 << endl;
}

Complex number c1 = (3,4)
Complex number c2 = cos ( c1 ) = (-27.0349,-3.85115)
The modulus of c2 is: 27.3079
The argument of c2 is: -3.00009 radians, which is -171.893 degrees.

The complex components cos (vci), where abs (vci) = 1
& arg (vci) = i * pi / 6 of the vector v1 are:
(0.730543,-0.39695)
(1.22777,-0.469075)
(1.54308,1.21529e-013)
(1.22777,0.469075)
(0.730543,0.39695)
(0.540302,-1.74036e-013)

cosh

返回复数的双曲余弦值。

template <class Type>
complex<Type> cosh(const complex<Type>& complexNum);

参数

complexNum
要确定其双曲余弦的复数。

返回值

输入复数的双曲余弦的复数。

注解

定义复双曲余弦的标识：

cos (z) = (1/2)*( exp (z) + exp (- z) )

cos (z) = cosh (a + bi) = cosh (a) cos (b) + isinh (a) sin (b)

示例

// complex_cosh.cpp
// compile with: /EHsc
#include <vector>
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;
   complex <double> c1 ( 3.0 , 4.0 );
   cout << "Complex number c1 = " << c1 << endl;

   // Values of cosine of a complex number c1
   complex <double> c2 = cosh ( c1 );
   cout << "Complex number c2 = cosh ( c1 ) = " << c2 << endl;
   double absc2 = abs ( c2 );
   double argc2 = arg ( c2 );
   cout << "The modulus of c2 is: " << absc2 << endl;
   cout << "The argument of c2 is: "<< argc2 << " radians, which is "
        << argc2 * 180 / pi << " degrees." << endl << endl;

   // Hyperbolic cosines of the standard angles
   // in the first two quadrants of the complex plane
   vector <complex <double> > v1;
   vector <complex <double> >::iterator Iter1;
   complex <double> vc1  ( polar (1.0, pi / 6) );
   v1.push_back( cosh ( vc1 ) );
   complex <double> vc2  ( polar (1.0, pi / 3) );
   v1.push_back( cosh ( vc2 ) );
   complex <double> vc3  ( polar (1.0, pi / 2) );
   v1.push_back( cosh ( vc3) );
   complex <double> vc4  ( polar (1.0, 2 * pi / 3) );
   v1.push_back( cosh ( vc4 ) );
   complex <double> vc5  ( polar (1.0, 5 * pi / 6) );
   v1.push_back( cosh ( vc5 ) );
   complex <double> vc6  ( polar (1.0,  pi ) );
   v1.push_back( cosh ( vc6 ) );

   cout << "The complex components cosh (vci), where abs (vci) = 1"
        << "\n& arg (vci) = i * pi / 6 of the vector v1 are:\n" ;
   for ( Iter1 = v1.begin( ) ; Iter1 != v1.end( ) ; Iter1++ )
      cout << *Iter1 << endl;
}

Complex number c1 = (3,4)
Complex number c2 = cosh ( c1 ) = (-6.58066,-7.58155)
The modulus of c2 is: 10.0392
The argument of c2 is: -2.28564 radians, which is -130.957 degrees.

The complex components cosh (vci), where abs (vci) = 1
& arg (vci) = i * pi / 6 of the vector v1 are:
(1.22777,0.469075)
(0.730543,0.39695)
(0.540302,-8.70178e-014)
(0.730543,-0.39695)
(1.22777,-0.469075)
(1.54308,2.43059e-013)

exp

返回复数的指数函数。

template <class Type>
complex<Type> exp(const complex<Type>& complexNum);

参数

complexNum
要确定其指数的复数。

返回值

输入复数的指数的复数。

示例

// complex_exp.cpp
// compile with: /EHsc
#include <vector>
#include <complex>
#include <iostream>

int main() {
   using namespace std;
   double pi = 3.14159265359;
   complex <double> c1 ( 1 , pi/6 );
   cout << "Complex number c1 = " << c1 << endl;

   // Value of exponential of a complex number c1:
   // note the argument of c2 is determined by the
   // imaginary part of c1 & the modulus by the real part
   complex <double> c2 = exp ( c1 );
   cout << "Complex number c2 = exp ( c1 ) = " << c2 << endl;
   double absc2 = abs ( c2 );
   double argc2 = arg ( c2 );
   cout << "The modulus of c2 is: " << absc2 << endl;
   cout << "The argument of c2 is: "<< argc2 << " radians, which is "
        << argc2 * 180 / pi << " degrees." << endl << endl;

   // Exponentials of the standard angles
   // in the first two quadrants of the complex plane
   vector <complex <double> > v1;
   vector <complex <double> >::iterator Iter1;
   complex <double> vc1  ( 0.0 , -pi );
   v1.push_back( exp ( vc1 ) );
   complex <double> vc2  ( 0.0, -2 * pi / 3 );
   v1.push_back( exp ( vc2 ) );
   complex <double> vc3  ( 0.0, 0.0 );
   v1.push_back( exp ( vc3 ) );
   complex <double> vc4  ( 0.0, pi / 3 );
   v1.push_back( exp ( vc4 ) );
   complex <double> vc5  ( 0.0 , 2 * pi / 3 );
   v1.push_back( exp ( vc5 ) );
   complex <double> vc6  ( 0.0, pi );
   v1.push_back( exp ( vc6 ) );

   cout << "The complex components exp (vci), where abs (vci) = 1"
        << "\n& arg (vci) = i * pi / 3 of the vector v1 are:\n" ;
   for ( Iter1 = v1.begin() ; Iter1 != v1.end() ; Iter1++ )
      cout <<  ( * Iter1 ) << "\n     with argument = "
           << ( 180/pi ) * arg ( *Iter1 )
           << " degrees\n     modulus = "
           << abs ( * Iter1 ) << endl;
}

imag

提取复数的虚分量。

template <class Type>
Type imag(const complex<Type>& complexNum);

参数

complexNum
要提取其实部的复数。

返回值

作为全局函数的复数的虚部。

备注

此模板函数无法用于修改复数的实部。要更改实部，必须为新复数分配分量值。

示例

// complexc_imag.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   complex <double> c1 ( 4.0 , 3.0 );
   cout << "The complex number c1 = " << c1 << endl;

   double dr1 = real ( c1 );
   cout << "The real part of c1 is real ( c1 ) = "
        << dr1 << "." << endl;

   double di1 = imag ( c1 );
   cout << "The imaginary part of c1 is imag ( c1 ) = "
        << di1 << "." << endl;
}

The complex number c1 = (4,3)
The real part of c1 is real ( c1 ) = 4.
The imaginary part of c1 is imag ( c1 ) = 3.

log

返回复数的自然对数。

template <class Type>
complex<Type> log(const complex<Type>& complexNum);

参数

complexNum
要确定其自然对数的复数。

返回值

输入复数的自然对数的复数。

注解

沿负实轴的分支剪切。

示例

// complex_log.cpp
// compile with: /EHsc
#include <vector>
#include <complex>
#include <iostream>

int main() {
   using namespace std;
   double pi = 3.14159265359;
   complex <double> c1 ( 3.0 , 4.0 );
   cout << "Complex number c1 = " << c1 << endl;

   // Values of log of a complex number c1
   complex <double> c2 = log ( c1 );
   cout << "Complex number c2 = log ( c1 ) = " << c2 << endl;
   double absc2 = abs ( c2 );
   double argc2 = arg ( c2 );
   cout << "The modulus of c2 is: " << absc2 << endl;
   cout << "The argument of c2 is: "<< argc2 << " radians, which is "
        << argc2 * 180 / pi << " degrees." << endl << endl;

   // log of the standard angles
   // in the first two quadrants of the complex plane
   vector <complex <double> > v1;
   vector <complex <double> >::iterator Iter1;
   complex <double> vc1  ( polar (1.0, pi / 6) );
   v1.push_back( log ( vc1 ) );
   complex <double> vc2  ( polar (1.0, pi / 3) );
   v1.push_back( log ( vc2 ) );
   complex <double> vc3  ( polar (1.0, pi / 2) );
   v1.push_back( log ( vc3) );
   complex <double> vc4  ( polar (1.0, 2 * pi / 3) );
   v1.push_back( log ( vc4 ) );
   complex <double> vc5  ( polar (1.0, 5 * pi / 6) );
   v1.push_back( log ( vc5 ) );
   complex <double> vc6  ( polar (1.0,  pi ) );
   v1.push_back( log ( vc6 ) );

   cout << "The complex components log (vci), where abs (vci) = 1 "
        << "\n& arg (vci) = i * pi / 6 of the vector v1 are:\n" ;
   for ( Iter1 = v1.begin() ; Iter1 != v1.end() ; Iter1++ )
      cout << *Iter1 << " " << endl;
}

log10

返回复数的以 10 为底的对数。

template <class Type>
complex<Type> log10(const complex<Type>& complexNum);

参数

complexNum
要确定以 10 为底的对数的复数。

返回值

输入复数以 10 为底的对数的复数。

注解

沿负实轴的分支剪切。

示例

// complex_log10.cpp
// compile with: /EHsc
#include <vector>
#include <complex>
#include <iostream>

int main() {
   using namespace std;
   double pi = 3.14159265359;
   complex <double> c1 ( 3.0 , 4.0 );
   cout << "Complex number c1 = " << c1 << endl;

   // Values of log10 of a complex number c1
   complex <double> c2 = log10 ( c1 );
   cout << "Complex number c2 = log10 ( c1 ) = " << c2 << endl;
   double absc2 = abs ( c2 );
   double argc2 = arg ( c2 );
   cout << "The modulus of c2 is: " << absc2 << endl;
   cout << "The argument of c2 is: "<< argc2 << " radians, which is "
        << argc2 * 180 / pi << " degrees." << endl << endl;

   // log10 of the standard angles
   // in the first two quadrants of the complex plane
   vector <complex <double> > v1;
   vector <complex <double> >::iterator Iter1;
   complex <double> vc1  ( polar (1.0, pi / 6) );
   v1.push_back( log10 ( vc1 ) );
   complex <double> vc2  ( polar (1.0, pi / 3) );
   v1.push_back( log10 ( vc2 ) );
   complex <double> vc3  ( polar (1.0, pi / 2) );
   v1.push_back( log10 ( vc3) );
   complex <double> vc4  ( polar (1.0, 2 * pi / 3) );
   v1.push_back( log10 ( vc4 ) );
   complex <double> vc5  ( polar (1.0, 5 * pi / 6) );
   v1.push_back( log10 ( vc5 ) );
   complex <double> vc6  ( polar (1.0,  pi ) );
   v1.push_back( log10 ( vc6 ) );

   cout << "The complex components log10 (vci), where abs (vci) = 1"
        << "\n& arg (vci) = i * pi / 6 of the vector v1 are:\n" ;
   for ( Iter1 = v1.begin( ) ; Iter1 != v1.end( ) ; Iter1++ )
      cout << *Iter1 << endl;
}

norm

提取复数的范数。

template <class Type>
Type norm(const complex<Type>& complexNum);

参数

complexNum
要确定其 norm 的复数。

返回值

复数的 norm。

备注

复数 a + bi 的范数是 (a² + b²)。复数的 norm 是其取模的平方。复数的取模是测量表示复数矢量的长度。复数 a + bi 的模数是 (a² + b²) 的平方根，写作 |a + bi|。

示例

// complex_norm.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;

   // Complex numbers can be entered in polar form with
   // modulus and argument parameter inputs but are
   // stored in Cartesian form as real & imag coordinates
   complex <double> c1 ( polar ( 5.0 ) );   // Default argument = 0
   complex <double> c2 ( polar ( 5.0 , pi / 6 ) );
   complex <double> c3 ( polar ( 5.0 , 13 * pi / 6 ) );
   cout << "c1 = polar ( 5.0 ) = " << c1 << endl;
   cout << "c2 = polar ( 5.0 , pi / 6 ) = " << c2 << endl;
   cout << "c3 = polar ( 5.0 , 13 * pi / 6 ) = " << c3 << endl;

   if ( (arg ( c2 ) <= ( arg ( c3 ) + .00000001) ) ||
        (arg ( c2 ) >= ( arg ( c3 ) - .00000001) ) )
      cout << "The complex numbers c2 & c3 have the "
           << "same principal arguments."<< endl;
   else
      cout << "The complex numbers c2 & c3 don't have the "
           << "same principal arguments." << endl;

   // The modulus and argument of a complex number can be recovered
   double absc2 = abs ( c2 );
   double argc2 = arg ( c2 );
   cout << "The modulus of c2 is recovered from c2 using: abs ( c2 ) = "
        << absc2 << endl;
   cout << "Argument of c2 is recovered from c2 using:\n arg ( c2 ) = "
        << argc2 << " radians, which is " << argc2 * 180 / pi
        << " degrees." << endl;

   // The norm of a complex number is the square of its modulus
   double normc2 = norm ( c2 );
   double sqrtnormc2 = sqrt ( normc2 );
   cout << "The norm of c2 given by: norm ( c2 ) = " << normc2 << endl;
   cout << "The modulus of c2 is the square root of the norm: "
        << "sqrt ( normc2 ) = " << sqrtnormc2 << ".";
}

c1 = polar ( 5.0 ) = (5,0)
c2 = polar ( 5.0 , pi / 6 ) = (4.33013,2.5)
c3 = polar ( 5.0 , 13 * pi / 6 ) = (4.33013,2.5)
The complex numbers c2 & c3 have the same principal arguments.
The modulus of c2 is recovered from c2 using: abs ( c2 ) = 5
Argument of c2 is recovered from c2 using:
arg ( c2 ) = 0.523599 radians, which is 30 degrees.
The norm of c2 given by: norm ( c2 ) = 25
The modulus of c2 is the square root of the norm: sqrt ( normc2 ) = 5.

polar

返回以笛卡尔坐标形式表示的，对应于指定模数和自变量的复数。

template <class Type>
complex<Type> polar(const Type& _Modulus, const Type& _Argument = 0);

参数

_Modulus
所输入的复数取模。

_Argument
所输入的复数的参数。

返回值

极坐标视图中指定的复数的笛卡尔视图。

备注

复数的极坐标视图提供了取模 r 和 p 参数，其中这些参数通过公式 a = r * cos p 和 b = r * sin p 与实部和虚部笛卡尔分量 a 和 b 相关。 =

示例

// complex_polar.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;

   // Complex numbers can be entered in polar form with
   // modulus and argument parameter inputs but are
   // stored in Cartesian form as real & imag coordinates
   complex <double> c1 ( polar ( 5.0 ) );   // Default argument = 0
   complex <double> c2 ( polar ( 5.0 , pi / 6 ) );
   complex <double> c3 ( polar ( 5.0 , 13 * pi / 6 ) );
   cout << "c1 = polar ( 5.0 ) = " << c1 << endl;
   cout << "c2 = polar ( 5.0 , pi / 6 ) = " << c2 << endl;
   cout << "c3 = polar ( 5.0 , 13 * pi / 6 ) = " << c3 << endl;

   if ( (arg ( c2 ) <= ( arg ( c3 ) + .00000001) ) ||
        (arg ( c2 ) >= ( arg ( c3 ) - .00000001) ) )
      cout << "The complex numbers c2 & c3 have the "
           << "same principal arguments."<< endl;
   else
      cout << "The complex numbers c2 & c3 don't have the "
           << "same principal arguments." << endl;

   // the modulus and argument of a complex number can be rcovered
   double absc2 = abs ( c2 );
   double argc2 = arg ( c2 );
   cout << "The modulus of c2 is recovered from c2 using: abs ( c2 ) = "
        << absc2 << endl;
   cout << "Argument of c2 is recovered from c2 using:\n arg ( c2 ) = "
        << argc2 << " radians, which is " << argc2 * 180 / pi
        << " degrees." << endl;
}

c1 = polar ( 5.0 ) = (5,0)
c2 = polar ( 5.0 , pi / 6 ) = (4.33013,2.5)
c3 = polar ( 5.0 , 13 * pi / 6 ) = (4.33013,2.5)
The complex numbers c2 & c3 have the same principal arguments.
The modulus of c2 is recovered from c2 using: abs ( c2 ) = 5
Argument of c2 is recovered from c2 using:
arg ( c2 ) = 0.523599 radians, which is 30 degrees.

pow

计算通过进行底数为复数的另一个复数次幂运算获得的复数。

template <class Type>
complex<Type> pow(const complex<Type>& _Base, int _Power);

template <class Type>
complex<Type> pow(const complex<Type>& _Base, const Type& _Power);

template <class Type>
complex<Type> pow(const complex<Type>& _Base, const complex<Type>& _Power);

template <class Type>
complex<Type> pow(const Type& _Base, const complex<Type>& _Power);

参数

_Base
复数或属于复数参数类型的数是基数由成员函数升幂的基数。

_Power
整数或复数或属于复数参数类型的数是由成员函数升底数的幂。

返回值

通过提升指定幂的指定基数获取复数。

备注

这些函数各自有效地将这两个操作转换为返回类型，并将转换后的 left 返回到幂 right。

沿负实轴的分支剪切。

示例

// complex_pow.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;

   // First member function
   // type complex<double> base & type integer power
   complex <double> cb1 ( 3 , 4);
   int cp1 = 2;
   complex <double> ce1 = pow ( cb1 ,cp1 );

   cout << "Complex number for base cb1 = " << cb1 << endl;
   cout << "Integer for power = " << cp1 << endl;
   cout << "Complex number returned from complex base and integer power:"
        << "\n ce1 = cb1 ^ cp1 = " << ce1 << endl;
   double absce1 = abs ( ce1 );
   double argce1 = arg ( ce1 );
   cout << "The modulus of ce1 is: " << absce1 << endl;
   cout << "The argument of ce1 is: "<< argce1 << " radians, which is "
        << argce1 * 180 / pi << " degrees." << endl << endl;

   // Second member function
   // type complex<double> base & type double power
   complex <double> cb2 ( 3 , 4 );
   double cp2 = pi;
   complex <double> ce2 = pow ( cb2 ,cp2 );

   cout << "Complex number for base cb2 = " << cb2 << endl;
   cout << "Type double for power cp2 = pi = " << cp2 << endl;
   cout << "Complex number returned from complex base and double power:"
        << "\n ce2 = cb2 ^ cp2 = " << ce2 << endl;
   double absce2 = abs ( ce2 );
   double argce2 = arg ( ce2 );
   cout << "The modulus of ce2 is: " << absce2 << endl;
   cout << "The argument of ce2 is: "<< argce2 << " radians, which is "
        << argce2 * 180 / pi << " degrees." << endl << endl;

   // Third member function
   // type complex<double> base & type complex<double> power
   complex <double> cb3 ( 3 , 4 );
   complex <double> cp3 ( -2 , 1 );
   complex <double> ce3 = pow ( cb3 ,cp3 );

   cout << "Complex number for base cb3 = " << cb3 << endl;
   cout << "Complex number for power cp3= " << cp3 << endl;
   cout << "Complex number returned from complex base and complex power:"
        << "\n ce3 = cb3 ^ cp3 = " << ce3 << endl;
   double absce3 = abs ( ce3 );
   double argce3 = arg ( ce3 );
   cout << "The modulus of ce3 is: " << absce3 << endl;
   cout << "The argument of ce3 is: "<< argce3 << " radians, which is "
        << argce3 * 180 / pi << " degrees." << endl << endl;

   // Fourth member function
   // type double base & type complex<double> power
   double cb4 = pi;
   complex <double> cp4 ( 2 , -1 );
   complex <double> ce4 = pow ( cb4 ,cp4 );

   cout << "Type double for base cb4 = pi = " << cb4 << endl;
   cout << "Complex number for power cp4 = " << cp4 << endl;
   cout << "Complex number returned from double base and complex power:"
        << "\n ce4 = cb4 ^ cp4 = " << ce4 << endl;
   double absce4 = abs ( ce4 );
   double argce4 = arg ( ce4 );
   cout << "The modulus of ce4 is: " << absce4 << endl;
   cout << "The argument of ce4 is: "<< argce4 << " radians, which is "
        << argce4 * 180 / pi << " degrees." << endl << endl;
}

Complex number for base cb1 = (3,4)
Integer for power = 2
Complex number returned from complex base and integer power:
ce1 = cb1 ^ cp1 = (-7,24)
The modulus of ce1 is: 25
The argument of ce1 is: 1.85459 radians, which is 106.26 degrees.

Complex number for base cb2 = (3,4)
Type double for power cp2 = pi = 3.14159
Complex number returned from complex base and double power:
ce2 = cb2 ^ cp2 = (-152.915,35.5475)
The modulus of ce2 is: 156.993
The argument of ce2 is: 2.91318 radians, which is 166.913 degrees.

Complex number for base cb3 = (3,4)
Complex number for power cp3= (-2,1)
Complex number returned from complex base and complex power:
ce3 = cb3 ^ cp3 = (0.0153517,-0.00384077)
The modulus of ce3 is: 0.0158249
The argument of ce3 is: -0.245153 radians, which is -14.0462 degrees.

Type double for base cb4 = pi = 3.14159
Complex number for power cp4 = (2,-1)
Complex number returned from double base and complex power:
ce4 = cb4 ^ cp4 = (4.07903,-8.98725)
The modulus of ce4 is: 9.8696
The argument of ce4 is: -1.14473 radians, which is -65.5882 degrees.

proj

template<class T> complex<T> proj(const complex<T>&);

real

提取复数的实分量。

template <class Type>
Type real(const complex<Type>& complexNum);

参数

complexNum
要提取其实部的复数。

返回值

作为全局函数的复数的实部。

备注

此模板函数无法用于修改复数的实部。要更改实部，必须为新复数分配分量值。

示例

// complex_real.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   complex <double> c1 ( 4.0 , 3.0 );
   cout << "The complex number c1 = " << c1 << endl;

   double dr1 = real ( c1 );
   cout << "The real part of c1 is real ( c1 ) = "
        << dr1 << "." << endl;

   double di1 = imag ( c1 );
   cout << "The imaginary part of c1 is imag ( c1 ) = "
        << di1 << "." << endl;
}

The complex number c1 = (4,3)
The real part of c1 is real ( c1 ) = 4.
The imaginary part of c1 is imag ( c1 ) = 3.

sin

返回复数的正弦值。

template <class Type>
complex<Type> sin(const complex<Type>& complexNum);

参数

complexNum
要确定其正弦的复数。

返回值

输入复数的正弦的复数。

备注

定义复正弦的标识：

sin (z) = (1/2 i)*( exp (iz) - exp (- iz) )

sin (z) = sin (a + bi) = sin (a) cosh (b) + icos (a) sinh (b)

示例

// complex_sin.cpp
// compile with: /EHsc
#include <vector>
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;
   complex <double> c1 ( 3.0 , 4.0 );
   cout << "Complex number c1 = " << c1 << endl;

   // Values of sine of a complex number c1
   complex <double> c2 = sin ( c1 );
   cout << "Complex number c2 = sin ( c1 ) = " << c2 << endl;
   double absc2 = abs ( c2 );
   double argc2 = arg ( c2 );
   cout << "The modulus of c2 is: " << absc2 << endl;
   cout << "The argument of c2 is: "<< argc2 << " radians, which is "
        << argc2 * 180 / pi << " degrees." << endl << endl;

   // sines of the standard angles in the first
   // two quadrants of the complex plane
   vector <complex <double> > v1;
   vector <complex <double> >::iterator Iter1;
   complex <double> vc1  ( polar ( 1.0, pi / 6 ) );
   v1.push_back( sin ( vc1 ) );
   complex <double> vc2  ( polar ( 1.0, pi / 3 ) );
   v1.push_back( sin ( vc2 ) );
   complex <double> vc3  ( polar ( 1.0, pi / 2 ) );
   v1.push_back( sin ( vc3 ) );
   complex <double> vc4  ( polar ( 1.0, 2 * pi / 3 ) );
   v1.push_back( sin ( vc4 ) );
   complex <double> vc5  ( polar ( 1.0, 5 * pi / 6 ) );
   v1.push_back( sin ( vc5 ) );
   complex <double> vc6  ( polar ( 1.0, pi ) );
   v1.push_back( sin ( vc6 ) );

   cout << "The complex components sin (vci), where abs (vci) = 1"
        << "\n& arg (vci) = i * pi / 6 of the vector v1 are:\n" ;
   for ( Iter1 = v1.begin( ) ; Iter1 != v1.end( ) ; Iter1++ )
      cout << *Iter1 << endl;
}

Complex number c1 = (3,4)
Complex number c2 = sin ( c1 ) = (3.85374,-27.0168)
The modulus of c2 is: 27.2903
The argument of c2 is: -1.42911 radians, which is -81.882 degrees.

The complex components sin (vci), where abs (vci) = 1
& arg (vci) = i * pi / 6 of the vector v1 are:
(0.85898,0.337596)
(0.670731,0.858637)
(-1.59572e-013,1.1752)
(-0.670731,0.858637)
(-0.85898,0.337596)
(-0.841471,-1.11747e-013)

sinh

返回复数的双曲正弦值。

template <class Type>
complex<Type> sinh(const complex<Type>& complexNum);

参数

complexNum
要确定其双曲正弦的复数。

返回值

输入复数的双曲正弦的复数。

注解

定义复双曲正弦的标识：

sinh (z) = (1/2)*( exp (z) - exp (- z) )

sinh (z) = sinh (a + bi) = sinh (a) cos (b) + icosh (a) sin (b)

示例

// complex_sinh.cpp
// compile with: /EHsc
#include <vector>
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;
   complex <double> c1 ( 3.0 , 4.0 );
   cout << "Complex number c1 = " << c1 << endl;

   // Values of sine of a complex number c1
   complex <double> c2 = sinh ( c1 );
   cout << "Complex number c2 = sinh ( c1 ) = " << c2 << endl;
   double absc2 = abs ( c2 );
   double argc2 = arg ( c2 );
   cout << "The modulus of c2 is: " << absc2 << endl;
   cout << "The argument of c2 is: "<< argc2 << " radians, which is "
        << argc2 * 180 / pi << " degrees." << endl << endl;

   // Hyperbolic sines of the standard angles in
   // the first two quadrants of the complex plane
   vector <complex <double> > v1;
   vector <complex <double> >::iterator Iter1;
   complex <double> vc1  ( polar ( 1.0, pi / 6 ) );
   v1.push_back( sinh ( vc1 ) );
   complex <double> vc2  ( polar ( 1.0, pi / 3 ) );
   v1.push_back( sinh ( vc2 ) );
   complex <double> vc3  ( polar ( 1.0, pi / 2 ) );
   v1.push_back( sinh ( vc3) );
   complex <double> vc4  ( polar ( 1.0, 2 * pi / 3 ) );
   v1.push_back( sinh ( vc4 ) );
   complex <double> vc5  ( polar ( 1.0, 5 * pi / 6 ) );
   v1.push_back( sinh ( vc5 ) );
   complex <double> vc6  ( polar ( 1.0, pi ) );
   v1.push_back( sinh ( vc6 ) );

   cout << "The complex components sinh (vci), where abs (vci) = 1"
        << "\n& arg (vci) = i * pi / 6 of the vector v1 are:\n" ;
   for ( Iter1 = v1.begin( ) ; Iter1 != v1.end( ) ; Iter1++ )
      cout << *Iter1 << endl;
}

Complex number c1 = (3,4)
Complex number c2 = sinh ( c1 ) = (-6.54812,-7.61923)
The modulus of c2 is: 10.0464
The argument of c2 is: -2.28073 radians, which is -130.676 degrees.

The complex components sinh (vci), where abs (vci) = 1
& arg (vci) = i * pi / 6 of the vector v1 are:
(0.858637,0.670731)
(0.337596,0.85898)
(-5.58735e-014,0.841471)
(-0.337596,0.85898)
(-0.858637,0.670731)
(-1.1752,-3.19145e-013)

sqrt

计算复数的平方根。

template <class Type>
complex<Type> sqrt(const complex<Type>& complexNum);

参数

complexNum
将查找其平方根的复数。

返回值

复数的平方根。

注解

平方根将在半开放间隔中具有一个阶段角度 (-pi/2，pi/2]。

沿负实轴的复平面中的分支剪切。

复数的平方根将具有输入数的平方根的取模，以及输入数一半数的参数。

示例

// complex_sqrt.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;

   // Complex numbers can be entered in polar form with
   // modulus and argument parameter inputs but are
   // stored in Cartesian form as real & imag coordinates
   complex <double> c1 ( polar ( 25.0 , pi / 2 ) );
   complex <double> c2 = sqrt ( c1 );
   cout << "c1 = polar ( 5.0 ) = " << c1 << endl;
   cout << "c2 = sqrt ( c1 ) = " << c2 << endl;

   // The modulus and argument of a complex number can be recovered
   double absc2 = abs ( c2 );
   double argc2 = arg ( c2 );
   cout << "The modulus of c2 is recovered from c2 using: abs ( c2 ) = "
        << absc2 << endl;
   cout << "Argument of c2 is recovered from c2 using:\n arg ( c2 ) = "
        << argc2 << " radians, which is " << argc2 * 180 / pi
        << " degrees." << endl;

   // The modulus and argument of c2 can be directly calculated
   absc2 = sqrt( abs ( c1 ) );
   argc2 = 0.5 * arg ( c1 );
   cout << "The modulus of c2 = sqrt( abs ( c1 ) ) =" << absc2 << endl;
   cout << "The argument of c2 = ( 1 / 2 ) * arg ( c1 ) ="
        << argc2 << " radians,\n which is " << argc2 * 180 / pi
        << " degrees." << endl;
}

c1 = polar ( 5.0 ) = (-2.58529e-012,25)
c2 = sqrt ( c1 ) = (3.53553,3.53553)
The modulus of c2 is recovered from c2 using: abs ( c2 ) = 5
Argument of c2 is recovered from c2 using:
arg ( c2 ) = 0.785398 radians, which is 45 degrees.
The modulus of c2 = sqrt( abs ( c1 ) ) =5
The argument of c2 = ( 1 / 2 ) * arg ( c1 ) =0.785398 radians,
which is 45 degrees.

tan

返回复数的正切值。

template <class Type>
complex<Type> tan(const complex<Type>& complexNum);

参数

complexNum
要确定其正切的复数。

返回值

输入复数的正切的复数。

备注

定义复正切的标识：

tan (z) = sin (z) / cos (z) = ( exp (iz) - exp (- iz) ) / i( exp (iz) + exp (- iz) )

示例

// complex_tan.cpp
// compile with: /EHsc
#include <vector>
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;
   complex <double> c1 ( 3.0 , 4.0 );
   cout << "Complex number c1 = " << c1 << endl;

   // Values of cosine of a complex number c1
   complex <double> c2 = tan ( c1 );
   cout << "Complex number c2 = tan ( c1 ) = " << c2 << endl;
   double absc2 = abs ( c2 );
   double argc2 = arg ( c2 );
   cout << "The modulus of c2 is: " << absc2 << endl;
   cout << "The argument of c2 is: "<< argc2 << " radians, which is "
        << argc2 * 180 / pi << " degrees." << endl << endl;

   // Hyperbolic tangent of the standard angles
   // in the first two quadrants of the complex plane
   vector <complex <double> > v1;
   vector <complex <double> >::iterator Iter1;
   complex <double> vc1  ( polar ( 1.0, pi / 6 ) );
   v1.push_back( tan ( vc1 ) );
   complex <double> vc2  ( polar ( 1.0, pi / 3 ) );
   v1.push_back( tan ( vc2 ) );
   complex <double> vc3  ( polar ( 1.0, pi / 2 ) );
   v1.push_back( tan ( vc3) );
   complex <double> vc4  ( polar ( 1.0, 2 * pi / 3 ) );
   v1.push_back( tan ( vc4 ) );
   complex <double> vc5  ( polar ( 1.0, 5 * pi / 6 ) );
   v1.push_back( tan ( vc5 ) );
   complex <double> vc6  ( polar ( 1.0,  pi ) );
   v1.push_back( tan ( vc6 ) );

   cout << "The complex components tan (vci), where abs (vci) = 1"
        << "\n& arg (vci) = i * pi / 6 of the vector v1 are:\n" ;
   for ( Iter1 = v1.begin() ; Iter1 != v1.end() ; Iter1++ )
      cout << *Iter1 << endl;
}

Complex number c1 = (3,4)
Complex number c2 = tan ( c1 ) = (-0.000187346,0.999356)
The modulus of c2 is: 0.999356
The argument of c2 is: 1.57098 radians, which is 90.0107 degrees.

The complex components tan (vci), where abs (vci) = 1
& arg (vci) = i * pi / 6 of the vector v1 are:
(0.713931,0.85004)
(0.24356,0.792403)
(-4.34302e-014,0.761594)
(-0.24356,0.792403)
(-0.713931,0.85004)
(-1.55741,-7.08476e-013)

tanh

返回复数的双曲正切值。

template <class Type>
complex<Type> tanh(const complex<Type>& complexNum);

参数

complexNum
要确定其双曲正切的复数。

返回值

输入复数的双曲正切的复数。

备注

定义复双曲余切的标识：

tanh (z) = sinh (z) / cosh (z) = ( exp (z) - exp (- z) ) / ( exp (z) + exp (- z) )

示例

// complex_tanh.cpp
// compile with: /EHsc
#include <vector>
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;
   complex <double> c1 ( 3.0 , 4.0 );
   cout << "Complex number c1 = " << c1 << endl;

   // Values of cosine of a complex number c1
   complex <double> c2 = tanh ( c1 );
   cout << "Complex number c2 = tanh ( c1 ) = " << c2 << endl;
   double absc2 = abs ( c2 );
   double argc2 = arg ( c2 );
   cout << "The modulus of c2 is: " << absc2 << endl;
   cout << "The argument of c2 is: "<< argc2 << " radians, which is "
        << argc2 * 180 / pi << " degrees." << endl << endl;

   // Hyperbolic tangents of the standard angles
   // in the first two quadrants of the complex plane
   vector <complex <double> > v1;
   vector <complex <double> >::iterator Iter1;
   complex <double> vc1  ( polar ( 1.0, pi / 6 ) );
   v1.push_back( tanh ( vc1 ) );
   complex <double> vc2  ( polar ( 1.0, pi / 3 ) );
   v1.push_back( tanh ( vc2 ) );
   complex <double> vc3  ( polar ( 1.0, pi / 2 ) );
   v1.push_back( tanh ( vc3 ) );
   complex <double> vc4  ( polar ( 1.0, 2 * pi / 3 ) );
   v1.push_back( tanh ( vc4 ) );
   complex <double> vc5  ( polar ( 1.0, 5 * pi / 6 ) );
   v1.push_back( tanh ( vc5 ) );
   complex <double> vc6  ( polar ( 1.0, pi ) );
   v1.push_back( tanh ( vc6 ) );

   cout << "The complex components tanh (vci), where abs (vci) = 1"
        << "\n& arg (vci) = i * pi / 6 of the vector v1 are:\n" ;
   for ( Iter1 = v1.begin( ) ; Iter1 != v1.end( ) ; Iter1++ )
      cout << *Iter1 << endl;
}

Complex number c1 = (3,4)
Complex number c2 = tanh ( c1 ) = (1.00071,0.00490826)
The modulus of c2 is: 1.00072
The argument of c2 is: 0.00490474 radians, which is 0.281021 degrees.

The complex components tanh (vci), where abs (vci) = 1
& arg (vci) = i * pi / 6 of the vector v1 are:
(0.792403,0.24356)
(0.85004,0.713931)
(-3.54238e-013,1.55741)
(-0.85004,0.713931)
(-0.792403,0.24356)
(-0.761594,-8.68604e-014)

<complex> 函数

abs

参数

返回值

备注

示例

acos

acosh

arg

参数

返回值

注解

示例

asin

asinh

atan

atanh

conj

参数

返回值

备注

示例

cos

参数

返回值

备注

示例

cosh

参数

返回值

注解

示例

exp

参数

返回值

示例

imag

参数

返回值

备注

示例

log

参数

返回值

注解

示例

log10

参数

返回值

注解

示例

norm

参数

返回值

备注

示例

polar

参数

返回值

备注

示例

pow

参数

返回值

备注

示例

proj

real

参数

返回值

备注

示例

sin

参数

返回值

备注

示例

sinh

参数

返回值

`<complex>` 函数