HashSet<T>.IsSupersetOf(IEnumerable<T>) HashSet<T>.IsSupersetOf(IEnumerable<T>) HashSet<T>.IsSupersetOf(IEnumerable<T>) HashSet<T>.IsSupersetOf(IEnumerable<T>) Method

Definition

Bestimmt, ob ein HashSet<T>-Objekt eine Obermenge der angegebenen Auflistung ist.Determines whether a HashSet<T> object is a superset of the specified collection.

public:
 bool IsSupersetOf(System::Collections::Generic::IEnumerable<T> ^ other);
public bool IsSupersetOf (System.Collections.Generic.IEnumerable<T> other);
member this.IsSupersetOf : seq<'T> -> bool
Public Function IsSupersetOf (other As IEnumerable(Of T)) As Boolean

Parameter

other
IEnumerable<T> IEnumerable<T> IEnumerable<T> IEnumerable<T>

Die Auflistung, die mit dem aktuellen HashSet<T>-Objekt verglichen werden soll.The collection to compare to the current HashSet<T> object.

Gibt zurück

true, wenn das aktuelle HashSet<T>-Objekt eine Obermenge von other ist, andernfalls false.true if the HashSet<T> object is a superset of other; otherwise, false.

Implementiert

Ausnahmen

Beispiele

Im folgenden Beispiel werden zwei unter HashSet<T> schiedliche-Objekte erstellt und miteinander verglichen.The following example creates two disparate HashSet<T> objects and compares them to each other. In diesem allNumbers Beispiel ist sowohl eine supermenge als auch eine ordnungsgemäße supermenge lowNumbers von allNumbers , bis mit der IntersectWith -Methode geändert wird, um nur die Werte zu enthalten, die in beiden Sätzen vorhanden sind.In this example, allNumbers is both a superset and a proper superset of lowNumbers until allNumbers is modified, using the IntersectWith method, to contain only values that are present in both sets. Sobald allNumbers allNumbers lowNumbers und lowNumbers identisch sind, ist immer noch eine supermenge von, aber keine ordnungsgemäße supermenge mehr.Once allNumbers and lowNumbers are identical, allNumbers is still a superset of lowNumbers but is no longer a proper superset.

HashSet<int> lowNumbers = new HashSet<int>();
HashSet<int> allNumbers = new HashSet<int>();

for (int i = 1; i < 5; i++)
{
    lowNumbers.Add(i);
}

for (int i = 0; i < 10; i++)
{
    allNumbers.Add(i);
}

Console.Write("lowNumbers contains {0} elements: ", lowNumbers.Count);
DisplaySet(lowNumbers);

Console.Write("allNumbers contains {0} elements: ", allNumbers.Count);
DisplaySet(allNumbers);

Console.WriteLine("lowNumbers overlaps allNumbers: {0}",
    lowNumbers.Overlaps(allNumbers));

Console.WriteLine("allNumbers and lowNumbers are equal sets: {0}",
    allNumbers.SetEquals(lowNumbers));

// Show the results of sub/superset testing
Console.WriteLine("lowNumbers is a subset of allNumbers: {0}",
    lowNumbers.IsSubsetOf(allNumbers));
Console.WriteLine("allNumbers is a superset of lowNumbers: {0}",
    allNumbers.IsSupersetOf(lowNumbers));
Console.WriteLine("lowNumbers is a proper subset of allNumbers: {0}",
    lowNumbers.IsProperSubsetOf(allNumbers));
Console.WriteLine("allNumbers is a proper superset of lowNumbers: {0}",
    allNumbers.IsProperSupersetOf(lowNumbers));

// Modify allNumbers to remove numbers that are not in lowNumbers.
allNumbers.IntersectWith(lowNumbers);
Console.Write("allNumbers contains {0} elements: ", allNumbers.Count);
DisplaySet(allNumbers);

Console.WriteLine("allNumbers and lowNumbers are equal sets: {0}",
    allNumbers.SetEquals(lowNumbers));

// Show the results of sub/superset testing with the modified set.
Console.WriteLine("lowNumbers is a subset of allNumbers: {0}",
    lowNumbers.IsSubsetOf(allNumbers));
Console.WriteLine("allNumbers is a superset of lowNumbers: {0}",
    allNumbers.IsSupersetOf(lowNumbers));
Console.WriteLine("lowNumbers is a proper subset of allNumbers: {0}",
    lowNumbers.IsProperSubsetOf(allNumbers));
Console.WriteLine("allNumbers is a proper superset of lowNumbers: {0}",
    allNumbers.IsProperSupersetOf(lowNumbers));

void DisplaySet(HashSet<int> set)
{
    Console.Write("{");
    foreach (int i in set)
    {
        Console.Write(" {0}", i);
    }
    Console.WriteLine(" }");
}

/* This code example produces output similar to the following:
* lowNumbers contains 4 elements: { 1 2 3 4 }
* allNumbers contains 10 elements: { 0 1 2 3 4 5 6 7 8 9 }
* lowNumbers overlaps allNumbers: True
* allNumbers and lowNumbers are equal sets: False
* lowNumbers is a subset of allNumbers: True
* allNumbers is a superset of lowNumbers: True
* lowNumbers is a proper subset of allNumbers: True
* allNumbers is a proper superset of lowNumbers: True
* allNumbers contains 4 elements: { 1 2 3 4 }
* allNumbers and lowNumbers are equal sets: True
* lowNumbers is a subset of allNumbers: True
* allNumbers is a superset of lowNumbers: True
* lowNumbers is a proper subset of allNumbers: False
* allNumbers is a proper superset of lowNumbers: False
*/
Shared Sub Main()

    Dim lowNumbers As HashSet(Of Integer) = New HashSet(Of Integer)()
    Dim allNumbers As HashSet(Of Integer) = New HashSet(Of Integer)()

    For i As Integer = 1 To 4
        lowNumbers.Add(i)
    Next i

    For i As Integer = 0 To 9
        allNumbers.Add(i)
    Next i


    Console.Write("lowNumbers contains {0} elements: ", lowNumbers.Count)
    DisplaySet(lowNumbers)

    Console.Write("allNumbers contains {0} elements: ", allNumbers.Count)
    DisplaySet(allNumbers)

    Console.WriteLine("lowNumbers overlaps allNumbers: {0}", _
        lowNumbers.Overlaps(allNumbers))

    Console.WriteLine("allNumbers and lowNumbers are equal sets: {0}", _
        allNumbers.SetEquals(lowNumbers))

    ' Show the results of sub/superset testing
    Console.WriteLine("lowNumbers is a subset of allNumbers: {0}", _
        lowNumbers.IsSubsetOf(allNumbers))
    Console.WriteLine("allNumbers is a superset of lowNumbers: {0}", _
        allNumbers.IsSupersetOf(lowNumbers))
    Console.WriteLine("lowNumbers is a proper subset of allNumbers: {0}", _
        lowNumbers.IsProperSubsetOf(allNumbers))
    Console.WriteLine("allNumbers is a proper superset of lowNumbers: {0}", _
        allNumbers.IsProperSupersetOf(lowNumbers))

    ' Modify allNumbers to remove numbers that are not in lowNumbers.
    allNumbers.IntersectWith(lowNumbers)
    Console.Write("allNumbers contains {0} elements: ", allNumbers.Count)
    DisplaySet(allNumbers)

    Console.WriteLine("allNumbers and lowNumbers are equal sets: {0}", _
        allNumbers.SetEquals(lowNumbers))

    ' Show the results of sub/superset testing with the modified set.
    Console.WriteLine("lowNumbers is a subset of allNumbers: {0}", _
        lowNumbers.IsSubsetOf(allNumbers))
    Console.WriteLine("allNumbers is a superset of lowNumbers: {0}", _
        allNumbers.IsSupersetOf(lowNumbers))
    Console.WriteLine("lowNumbers is a proper subset of allNumbers: {0}", _
        lowNumbers.IsProperSubsetOf(allNumbers))
    Console.WriteLine("allNumbers is a proper superset of lowNumbers: {0}", _
        allNumbers.IsProperSupersetOf(lowNumbers))
End Sub
' This code example produces output similar to the following:
' lowNumbers contains 4 elements: { 1 2 3 4 }
' allNumbers contains 10 elements: { 0 1 2 3 4 5 6 7 8 9 }
' lowNumbers overlaps allNumbers: True
' allNumbers and lowNumbers are equal sets: False
' lowNumbers is a subset of allNumbers: True
' allNumbers is a superset of lowNumbers: True
' lowNumbers is a proper subset of allNumbers: True
' allNumbers is a proper superset of lowNumbers: True
' allNumbers contains 4 elements: { 1 2 3 4 }
' allNumbers and lowNumbers are equal sets: True
' lowNumbers is a subset of allNumbers: True
' allNumbers is a superset of lowNumbers: True
' lowNumbers is a proper subset of allNumbers: False
' allNumbers is a proper superset of lowNumbers: False

Hinweise

Alle Auflistungen, einschließlich des leeren Satzes, sind übergeordnete Mengen des leeren Satzes.All collections, including the empty set, are supersets of the empty set. Daher gibt diese Methode zurück true , wenn die durch den other -Parameter dargestellte Auflistung leer ist, auch HashSet<T> wenn das aktuelle-Objekt leer ist.Therefore, this method returns true if the collection represented by the other parameter is empty, even if the current HashSet<T> object is empty.

Diese Methode gibt immer false zurück Count , wenn kleiner als die Anzahl der Elemente otherin ist.This method always returns false if Count is less than the number of elements in other.

Wenn die durch other dargestellte Auflistung eine HashSet<T> Auflistung mit demselben Gleichheits Vergleich wie das aktuelle HashSet<T> -Objekt ist, ist diese Methode ein On()-Vorgang.If the collection represented by other is a HashSet<T> collection with the same equality comparer as the current HashSet<T> object, this method is an O(n) operation. Andernfalls ist diesenMethode ein O ( + m)-Vorgang, wobei n die Anzahl der Elemente in other und m Countgleich ist.Otherwise, this method is an O(n + m) operation, where n is the number of elements in other and m is Count.

Gilt für: