SqlInt16.Subtraction(SqlInt16, SqlInt16) SqlInt16.Subtraction(SqlInt16, SqlInt16) SqlInt16.Subtraction(SqlInt16, SqlInt16) SqlInt16.Subtraction(SqlInt16, SqlInt16) Operator

Definition

Subtrahiert den zweiten SqlInt16-Parameter vom ersten.Subtracts the second SqlInt16 parameter from the first.

public:
 static System::Data::SqlTypes::SqlInt16 operator -(System::Data::SqlTypes::SqlInt16 x, System::Data::SqlTypes::SqlInt16 y);
public static System.Data.SqlTypes.SqlInt16 operator - (System.Data.SqlTypes.SqlInt16 x, System.Data.SqlTypes.SqlInt16 y);
static member ( - ) : System.Data.SqlTypes.SqlInt16 * System.Data.SqlTypes.SqlInt16 -> System.Data.SqlTypes.SqlInt16
Public Shared Operator - (x As SqlInt16, y As SqlInt16) As SqlInt16

Parameter

x
SqlInt16 SqlInt16 SqlInt16 SqlInt16

Eine SqlInt16-Struktur.A SqlInt16 structure.

y
SqlInt16 SqlInt16 SqlInt16 SqlInt16

Eine SqlInt16-Struktur.A SqlInt16 structure.

Gibt zurück

Eine SqlInt16-Struktur, deren Value-Eigenschaft die Ergebnisse der Subtraktion enthält.A SqlInt16 structure whose Value property contains the results of the subtraction.

Hinweise

Die äquivalente-Methode für diesen SqlInt16.Subtract(SqlInt16, SqlInt16)Operator ist.The equivalent method for this operator is SqlInt16.Subtract(SqlInt16, SqlInt16).

Gilt für:

Siehe auch