Uri.SchemeDelimiter Uri.SchemeDelimiter Uri.SchemeDelimiter Uri.SchemeDelimiter Field

Definition

Gibt die Zeichen an, die das Schema des Kommunikationsprotokolls vom Adressteil des URIs trennen.Specifies the characters that separate the communication protocol scheme from the address portion of the URI. Dieses Feld ist schreibgeschützt.This field is read-only.

public: static initonly System::String ^ SchemeDelimiter;
public static readonly string SchemeDelimiter;
 staticval mutable SchemeDelimiter : string
Public Shared ReadOnly SchemeDelimiter As String 

Feldwert

Beispiele

Das folgende Beispiel erstellt eine Zeichenfolge mit UriSchemeHttp, SchemeDelimiter, und eine Adresse.The following example creates a string from UriSchemeHttp, SchemeDelimiter, and an address. Ein Uri Instanz wird dann aus der Zeichenfolge erstellt.A Uri instance is then created from the string.

         String^ address = "www.contoso.com";
         String^ uriString = String::Format( "{0}{1}{2}",
            Uri::UriSchemeHttp, Uri::SchemeDelimiter, address );

#if OLDMETHOD           
         Uri^ result;
         if ( Uri::TryParse( uriString, false, false, result ) == true )
         {
            Console::WriteLine( "{0} is a valid Uri", result );
         }
         else
         {
            Console::WriteLine( "Uri not created" );
         }
#endif
         Uri ^result = gcnew Uri(uriString);
         if (result->IsWellFormedOriginalString())
             Console::WriteLine("{0} is a well formed Uri", uriString);
         else
             Console::WriteLine("{0} is not a well formed Uri", uriString);
            string address = "www.contoso.com";
            string uriString = String.Format("{0}{1}{2}/", Uri.UriSchemeHttp, Uri.SchemeDelimiter, address); 
 #if OLDMETHOD           
            Uri result;
            if (Uri.TryParse(uriString, false, false, out result) == true)
                Console.WriteLine("{0} is a valid Uri", result.ToString());
            else
                Console.WriteLine("Uri not created");
#endif
            Uri result = new Uri(uriString);
            if (result.IsWellFormedOriginalString())
                Console.WriteLine("{0} is a well formed Uri", uriString);
            else
                Console.WriteLine("{0} is not a well formed Uri", uriString);
Dim address As String = "www.contoso.com"
Dim uriString As String = String.Format("{0}{1}{2}", Uri.UriSchemeHttp, Uri.SchemeDelimiter, address)

Dim result As Uri = New Uri(uriString)

If result.IsWellFormedOriginalString() = True Then
    Console.WriteLine("{0} is a well formed Uri", uriString)
else
    Console.WriteLine("{0} is not a well formed Uri", uriString)
End If

Gilt für: