Complex.Sin(Complex) Method
Definition
Returns the sine of the specified complex number.
public:
static System::Numerics::Complex Sin(System::Numerics::Complex value);
public static System.Numerics.Complex Sin (System.Numerics.Complex value);
static member Sin : System.Numerics.Complex -> System.Numerics.Complex
Public Shared Function Sin (value As Complex) As Complex
Parameters
- value
- Complex
A complex number.
Returns
The sine of value
.
Examples
The following example illustrates the Sin method. It shows that passing the value returned by the Asin method to the Sin method returns the original Complex value.
using System;
using System.Numerics;
public class Example
{
public static void Main()
{
Complex[] values = { new Complex(2.3, 1.4),
new Complex(-2.3, 1.4),
new Complex(-2.3, -1.4),
new Complex(2.3, -1.4) };
foreach (Complex value in values)
Console.WriteLine("Sin(Asin({0})) = {1}",
value, Complex.Sin(Complex.Asin(value)));
}
}
// The example displays the following output:
// Sin(Asin((2.3, 1.4))) = (2.3, 1.4)
// Sin(Asin((-2.3, 1.4))) = (-2.3, 1.4)
// Sin(Asin((-2.3, -1.4))) = (-2.3, -1.4)
// Sin(Asin((2.3, -1.4))) = (2.3, -1.4)
Imports System.Numerics
Module Example
Public Sub Main()
Dim values() As Complex = { New Complex(2.3, 1.4),
New Complex(-2.3, 1.4),
New Complex(-2.3, -1.4),
New Complex(2.3, -1.4) }
For Each value As Complex In values
Console.WriteLine("Sin(Asin({0})) = {1}",
value, Complex.Sin(Complex.Asin(value)))
Next
End Sub
End Module
' The example displays the following output:
' Sin(Asin((2.3, 1.4))) = (2.3, 1.4)
' Sin(Asin((-2.3, 1.4))) = (-2.3, 1.4)
' Sin(Asin((-2.3, -1.4))) = (-2.3, -1.4)
' Sin(Asin((2.3, -1.4))) = (2.3, -1.4)
Remarks
The Sin method for complex numbers corresponds to the Math.Sin method for real numbers.
The Sin method uses the following formula to calculate the sine of the complex number a + bi:
(Sin(a) * Cosh(b), Cos(a) * Sinh(b))