# Vector<T>.BitwiseAnd(Vector<T>, Vector<T>) Operator

## Definition

Important

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Returns a new vector by performing a bitwise `And`

operation on each of the elements in two vectors.

```
public:
static System::Numerics::Vector<T> operator &(System::Numerics::Vector<T> left, System::Numerics::Vector<T> right);
```

`public static System.Numerics.Vector<T> operator & (System.Numerics.Vector<T> left, System.Numerics.Vector<T> right);`

`static member ( &&& ) : System.Numerics.Vector<'T (requires 'T : struct)> * System.Numerics.Vector<'T (requires 'T : struct)> -> System.Numerics.Vector<'T (requires 'T : struct)>`

`Public Shared Operator And (left As Vector(Of T), right As Vector(Of T)) As Vector(Of T)`

#### Parameters

- left
- Vector<T>

The first vector.

- right
- Vector<T>

The second vector.

#### Returns

The vector that results from the bitwise `And`

of `left`

and `right`

.

#### Exceptions

.NET 5.0 and later: Type `T`

is not supported.

## Remarks

The BitwiseAnd method defines the bitwise `And`

operation for Vector<T> objects.