how to deserialize a json array with newton json

Question

Hi, I am trying to deserialize the below json array with newton json, however I got some trouble, please help.

 static void Main(string[] args)
        {
            string json = @"{
  'firstname': 'james',
  'lastname': 'james',
  'gender': 'M',
  'address': [
    'address1','1'
    'address2','2'
  ]
}";

            List<ShippingInfo> shippingInfo = JsonConvert.DeserializeObject<List<ShippingInfo>>(json);
            Console.WriteLine("success");

        }

        public class ShippingInfo
        {
            public string firstname { get; set; }
            public string lastname { get; set; }
            public string gender { get; set; }

            public IList<address> address { get; set; }
        }

        public class address
        {
            public string address1 { get; set; }
            public string address2 { get; set; }
        }

Error: Cannot deserialize the current JSON object (e.g. {"name":"value"}) into type 'System.Collections.Generic.List`1[JsonTest.Program+ShippingInfo]' because the type requires a JSON array (e.g. [1,2,3]) to deserialize correctly.
To fix this error either change the JSON to a JSON array (e.g. [1,2,3]) or change the deserialized type so that it is a normal .NET type (e.g. not a primitive type like integer, not a collection type like an array or List<T>) that can be deserialized from a JSON object. JsonObjectAttribute can also be added to the type to force it to deserialize from a JSON object.

Answer 1

There are several issues, which were eliminated in the next sample:

public class ShippingInfo
{
    public string firstname { get; set; }
    public string lastname { get; set; }
    public string gender { get; set; }

    public address address { get; set; }
}

public class address
{
    public string address1 { get; set; }
    public string address2 { get; set; }
}

. . .

string json = @"{
   'firstname': 'james',
   'lastname': 'james',
   'gender': 'M',
   'address': {
      'address1':'1',
      'address2':'2'
   }
}";

ShippingInfo shippingInfo = JsonConvert.DeserializeObject<ShippingInfo>( json );