An "is" operator puzzle, part one
It is possible for a program with some local variable x:
bool b = x is FooBar;
to assign true to b at runtime, even though there is no conversion, implicit or explicit, from x to FooBar allowed by the compiler! That is,
FooBar foobar = (FooBar)x;
would not be allowed by the compiler in that same program.
Can you create a program to demonstrate this fact? This is not a particularly hard puzzle but it does illustrate some of the subtleties of the "is" operator that we'll discuss in the next episode.