series_fill_backward()
Performs a backward fill interpolation of missing values in a series.
An expression containing dynamic numerical array is the input. The function replaces all instances of missing_value_placeholder with the nearest value from its right side (other than missing_value_placeholder), and returns the resulting array. The rightmost instances of missing_value_placeholder are preserved.
Syntax
series_fill_backward(x[, missing_value_placeholder])
- Will return series x with all instances of missing_value_placeholder filled backwards.
Arguments
- x: dynamic array scalar expression, which is an array of numeric values.
- missing_value_placeholder: this optional parameter specifies a placeholder for missing values. The default value is
double(null).
Notes
- Specify null as the default value to apply any interpolation functions after make-series:
make-series num=count() default=long(null) on TimeStamp from ago(1d) to ago(1h) step 1h by Os, Browser
- The missing_value_placeholder can be of any type that will be converted to actual element types. Both
double(null),long(null) andint(null) have the same meaning. - If missing_value_placeholder is
double(null), (or omitted, which have the same meaning) then a result may contain null values. To fill these null values, use other interpolation functions. Currently only series_outliers() support null values in input arrays. - The function preserves original type of array elements.
Example
let data = datatable(arr: dynamic)
[
dynamic([111,null,36,41,null,null,16,61,33,null,null])
];
data
| project arr,
fill_backward = series_fill_backward(arr)
arr |
fill_backward |
|---|---|
| [111,null,36,41,null,null,16,61,33,null,null] | [111,36,36,41,16,16,16,61,33,null,null] |
Use series_fill_forward or series-fill-const to complete interpolation of the above array.
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