# Default Arguments

In many cases, functions have arguments that are used so infrequently that a default value would suffice. To address this, the default-argument facility allows for specifying only those arguments to a function that are meaningful in a given call. To illustrate this concept, consider the example presented in Function Overloading.

``````// Prototype three print functions.
int print( char *s );                  // Print a string.
int print( double dvalue );            // Print a double.
int print( double dvalue, int prec );  // Print a double with a
//  given precision.
``````

In many applications, a reasonable default can be supplied for `prec`, eliminating the need for two functions:

``````// Prototype two print functions.
int print( char *s );                    // Print a string.
int print( double dvalue, int prec=2 );  // Print a double with a
//  given precision.
``````

The implementation of the `print` function is changed slightly to reflect the fact that only one such function exists for type double:

``````// default_arguments.cpp
// compile with: /EHsc /c

// Print a double in specified precision.
//  Positive numbers for precision indicate how many digits
//  precision after the decimal point to show. Negative
//  numbers for precision indicate where to round the number
//  to the left of the decimal point.

#include <iostream>
#include <math.h>
using namespace std;

int print( double dvalue, int prec ) {
// Use table-lookup for rounding/truncation.
static const double rgPow10[] = {
10E-7, 10E-6, 10E-5, 10E-4, 10E-3, 10E-2, 10E-1, 10E0,
10E1,  10E2,  10E3,  10E4, 10E5,  10E6
};
const int iPowZero = 6;
// If precision out of range, just print the number.
if( prec >= -6 && prec <= 7 )
// Scale, truncate, then rescale.
dvalue = floor( dvalue / rgPow10[iPowZero - prec] ) *
rgPow10[iPowZero - prec];
cout << dvalue << endl;
return cout.good();
}
``````

To invoke the new `print` function, use code such as the following:

``````print( d );    // Precision of 2 supplied by default argument.
print( d, 0 ); // Override default argument to achieve other
//  results.
``````

Note these points when using default arguments:

• Default arguments are used only in function calls where trailing arguments are omitted — they must be the last argument(s). Therefore, the following code is illegal:

``````int print( double dvalue = 0.0, int prec );
``````
• A default argument cannot be redefined in later declarations even if the redefinition is identical to the original. Therefore, the following code produces an error:

``````// Prototype for print function.
int print( double dvalue, int prec = 2 );

...

// Definition for print function.
int print( double dvalue, int prec = 2 )
{
...
}
``````

The problem with this code is that the function declaration in the definition redefines the default argument for `prec`.

``````int (*pShowIntVal)( int i = 0 );