# Enumerable.Average Method

## Definition

Computes the average of a sequence of numeric values.

## Overloads

Average(IEnumerable<Single>) |
Computes the average of a sequence of Single values. |

Average(IEnumerable<Nullable<Single>>) |
Computes the average of a sequence of nullable Single values. |

Average(IEnumerable<Nullable<Int64>>) |
Computes the average of a sequence of nullable Int64 values. |

Average(IEnumerable<Nullable<Int32>>) |
Computes the average of a sequence of nullable Int32 values. |

Average(IEnumerable<Nullable<Double>>) |
Computes the average of a sequence of nullable Double values. |

Average(IEnumerable<Int64>) |
Computes the average of a sequence of Int64 values. |

Average(IEnumerable<Int32>) |
Computes the average of a sequence of Int32 values. |

Average(IEnumerable<Double>) |
Computes the average of a sequence of Double values. |

Average(IEnumerable<Decimal>) |
Computes the average of a sequence of Decimal values. |

Average(IEnumerable<Nullable<Decimal>>) |
Computes the average of a sequence of nullable Decimal values. |

Average<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) |
Computes the average of a sequence of nullable Int32 values that are obtained by invoking a transform function on each element of the input sequence. |

Average<TSource>(IEnumerable<TSource>, Func<TSource,Single>) |
Computes the average of a sequence of Single values that are obtained by invoking a transform function on each element of the input sequence. |

Average<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) |
Computes the average of a sequence of nullable Single values that are obtained by invoking a transform function on each element of the input sequence. |

Average<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) |
Computes the average of a sequence of nullable Int64 values that are obtained by invoking a transform function on each element of the input sequence. |

Average<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) |
Computes the average of a sequence of nullable Double values that are obtained by invoking a transform function on each element of the input sequence. |

Average<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) |
Computes the average of a sequence of nullable Decimal values that are obtained by invoking a transform function on each element of the input sequence. |

Average<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) |
Computes the average of a sequence of Int64 values that are obtained by invoking a transform function on each element of the input sequence. |

Average<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) |
Computes the average of a sequence of Int32 values that are obtained by invoking a transform function on each element of the input sequence. |

Average<TSource>(IEnumerable<TSource>, Func<TSource,Double>) |
Computes the average of a sequence of Double values that are obtained by invoking a transform function on each element of the input sequence. |

Average<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) |
Computes the average of a sequence of Decimal values that are obtained by invoking a transform function on each element of the input sequence. |

## Average(IEnumerable<Single>)

Computes the average of a sequence of Single values.

```
public:
[System::Runtime::CompilerServices::Extension]
static float Average(System::Collections::Generic::IEnumerable<float> ^ source);
```

`public static float Average (this System.Collections.Generic.IEnumerable<float> source);`

`static member Average : seq<single> -> single`

```
<Extension()>
Public Function Average (source As IEnumerable(Of Single)) As Single
```

#### Parameters

- source
- IEnumerable<Single>

A sequence of Single values to calculate the average of.

#### Returns

The average of the sequence of values.

#### Exceptions

`source`

is `null`

.

`source`

contains no elements.

### Examples

The following code example demonstrates how to use Average(IEnumerable<Int32>) to calculate an average.

Note

This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

```
List<int> grades = new List<int> { 78, 92, 100, 37, 81 };
double average = grades.Average();
Console.WriteLine("The average grade is {0}.", average);
// This code produces the following output:
//
// The average grade is 77.6.
```

```
' Create a list of integers.
Dim grades As New List(Of Integer)(New Integer() {78, 92, 100, 37, 81})
' Determine the average value in the list.
Dim avg As Double = grades.Average()
' Display the output.
MsgBox("The average grade is " & avg)
' This code produces the following output:
'
' The average grade is 77.6
```

### Remarks

In Visual Basic query expression syntax, an `Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average(IEnumerable<Nullable<Single>>)

Computes the average of a sequence of nullable Single values.

```
public:
[System::Runtime::CompilerServices::Extension]
static Nullable<float> Average(System::Collections::Generic::IEnumerable<Nullable<float>> ^ source);
```

`public static Nullable<float> Average (this System.Collections.Generic.IEnumerable<Nullable<float>> source);`

`static member Average : seq<Nullable<single>> -> Nullable<single>`

```
<Extension()>
Public Function Average (source As IEnumerable(Of Nullable(Of Single))) As Nullable(Of Single)
```

#### Parameters

- source
- IEnumerable<Nullable<Single>>

A sequence of nullable Single values to calculate the average of.

#### Returns

The average of the sequence of values, or `null`

if the source sequence is empty or contains only values that are `null`

.

#### Exceptions

`source`

is `null`

.

### Examples

The following code example demonstrates how to use Average(IEnumerable<Nullable<Int64>>) to calculate an average.

Note

This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

```
long?[] longs = { null, 10007L, 37L, 399846234235L };
double? average = longs.Average();
Console.WriteLine("The average is {0}.", average);
// This code produces the following output:
//
// The average is 133282081426.333.
```

```
' Create an array of nullable long values.
Dim longs() As Nullable(Of Long) = {Nothing, 10007L, 37L, 399846234235L}
' Determine the average value in the array.
Dim avg As Nullable(Of Double) = longs.Average()
' Display the output.
MsgBox("The average is " & avg.ToString)
' This code produces the following output:
'
' The average is 133282081426.333
```

### Remarks

In Visual Basic query expression syntax, an `Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average(IEnumerable<Nullable<Int64>>)

Computes the average of a sequence of nullable Int64 values.

```
public:
[System::Runtime::CompilerServices::Extension]
static Nullable<double> Average(System::Collections::Generic::IEnumerable<Nullable<long>> ^ source);
```

`public static Nullable<double> Average (this System.Collections.Generic.IEnumerable<Nullable<long>> source);`

`static member Average : seq<Nullable<int64>> -> Nullable<double>`

```
<Extension()>
Public Function Average (source As IEnumerable(Of Nullable(Of Long))) As Nullable(Of Double)
```

#### Parameters

- source
- IEnumerable<Nullable<Int64>>

A sequence of nullable Int64 values to calculate the average of.

#### Returns

The average of the sequence of values, or `null`

if the source sequence is empty or contains only values that are `null`

.

#### Exceptions

`source`

is `null`

.

The sum of the elements in the sequence is larger than MaxValue.

### Examples

The following code example demonstrates how to use Average(IEnumerable<Nullable<Int64>>) to calculate an average.

```
long?[] longs = { null, 10007L, 37L, 399846234235L };
double? average = longs.Average();
Console.WriteLine("The average is {0}.", average);
// This code produces the following output:
//
// The average is 133282081426.333.
```

```
' Create an array of nullable long values.
Dim longs() As Nullable(Of Long) = {Nothing, 10007L, 37L, 399846234235L}
' Determine the average value in the array.
Dim avg As Nullable(Of Double) = longs.Average()
' Display the output.
MsgBox("The average is " & avg.ToString)
' This code produces the following output:
'
' The average is 133282081426.333
```

### Remarks

In Visual Basic query expression syntax, an `Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average(IEnumerable<Nullable<Int32>>)

Computes the average of a sequence of nullable Int32 values.

```
public:
[System::Runtime::CompilerServices::Extension]
static Nullable<double> Average(System::Collections::Generic::IEnumerable<Nullable<int>> ^ source);
```

`public static Nullable<double> Average (this System.Collections.Generic.IEnumerable<Nullable<int>> source);`

`static member Average : seq<Nullable<int>> -> Nullable<double>`

```
<Extension()>
Public Function Average (source As IEnumerable(Of Nullable(Of Integer))) As Nullable(Of Double)
```

#### Parameters

- source
- IEnumerable<Nullable<Int32>>

A sequence of nullable Int32 values to calculate the average of.

#### Returns

The average of the sequence of values, or `null`

if the source sequence is empty or contains only values that are `null`

.

#### Exceptions

`source`

is `null`

.

The sum of the elements in the sequence is larger than MaxValue.

### Examples

The following code example demonstrates how to use Average(IEnumerable<Nullable<Int64>>) to calculate an average.

Note

This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

```
long?[] longs = { null, 10007L, 37L, 399846234235L };
double? average = longs.Average();
Console.WriteLine("The average is {0}.", average);
// This code produces the following output:
//
// The average is 133282081426.333.
```

```
' Create an array of nullable long values.
Dim longs() As Nullable(Of Long) = {Nothing, 10007L, 37L, 399846234235L}
' Determine the average value in the array.
Dim avg As Nullable(Of Double) = longs.Average()
' Display the output.
MsgBox("The average is " & avg.ToString)
' This code produces the following output:
'
' The average is 133282081426.333
```

### Remarks

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average(IEnumerable<Nullable<Double>>)

Computes the average of a sequence of nullable Double values.

```
public:
[System::Runtime::CompilerServices::Extension]
static Nullable<double> Average(System::Collections::Generic::IEnumerable<Nullable<double>> ^ source);
```

`public static Nullable<double> Average (this System.Collections.Generic.IEnumerable<Nullable<double>> source);`

`static member Average : seq<Nullable<double>> -> Nullable<double>`

```
<Extension()>
Public Function Average (source As IEnumerable(Of Nullable(Of Double))) As Nullable(Of Double)
```

#### Parameters

- source
- IEnumerable<Nullable<Double>>

A sequence of nullable Double values to calculate the average of.

#### Returns

`null`

if the source sequence is empty or contains only values that are `null`

.

#### Exceptions

`source`

is `null`

.

### Examples

Note

```
long?[] longs = { null, 10007L, 37L, 399846234235L };
double? average = longs.Average();
Console.WriteLine("The average is {0}.", average);
// This code produces the following output:
//
// The average is 133282081426.333.
```

```
' Create an array of nullable long values.
Dim longs() As Nullable(Of Long) = {Nothing, 10007L, 37L, 399846234235L}
' Determine the average value in the array.
Dim avg As Nullable(Of Double) = longs.Average()
' Display the output.
MsgBox("The average is " & avg.ToString)
' This code produces the following output:
'
' The average is 133282081426.333
```

### Remarks

If the sum of the elements is too large to represent as a Double, this method returns positive or negative infinity.

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average(IEnumerable<Int64>)

Computes the average of a sequence of Int64 values.

```
public:
[System::Runtime::CompilerServices::Extension]
static double Average(System::Collections::Generic::IEnumerable<long> ^ source);
```

`public static double Average (this System.Collections.Generic.IEnumerable<long> source);`

`static member Average : seq<int64> -> double`

```
<Extension()>
Public Function Average (source As IEnumerable(Of Long)) As Double
```

#### Parameters

- source
- IEnumerable<Int64>

A sequence of Int64 values to calculate the average of.

#### Returns

The average of the sequence of values.

#### Exceptions

`source`

is `null`

.

`source`

contains no elements.

### Examples

The following code example demonstrates how to use Average(IEnumerable<Int32>) to calculate an average.

Note

```
List<int> grades = new List<int> { 78, 92, 100, 37, 81 };
double average = grades.Average();
Console.WriteLine("The average grade is {0}.", average);
// This code produces the following output:
//
// The average grade is 77.6.
```

```
' Create a list of integers.
Dim grades As New List(Of Integer)(New Integer() {78, 92, 100, 37, 81})
' Determine the average value in the list.
Dim avg As Double = grades.Average()
' Display the output.
MsgBox("The average grade is " & avg)
' This code produces the following output:
'
' The average grade is 77.6
```

### Remarks

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average(IEnumerable<Int32>)

Computes the average of a sequence of Int32 values.

```
public:
[System::Runtime::CompilerServices::Extension]
static double Average(System::Collections::Generic::IEnumerable<int> ^ source);
```

`public static double Average (this System.Collections.Generic.IEnumerable<int> source);`

`static member Average : seq<int> -> double`

```
<Extension()>
Public Function Average (source As IEnumerable(Of Integer)) As Double
```

#### Parameters

- source
- IEnumerable<Int32>

A sequence of Int32 values to calculate the average of.

#### Returns

The average of the sequence of values.

#### Exceptions

`source`

is `null`

.

`source`

contains no elements.

### Examples

The following code example demonstrates how to use Average(IEnumerable<Int32>) to calculate an average.

```
List<int> grades = new List<int> { 78, 92, 100, 37, 81 };
double average = grades.Average();
Console.WriteLine("The average grade is {0}.", average);
// This code produces the following output:
//
// The average grade is 77.6.
```

```
' Create a list of integers.
Dim grades As New List(Of Integer)(New Integer() {78, 92, 100, 37, 81})
' Determine the average value in the list.
Dim avg As Double = grades.Average()
' Display the output.
MsgBox("The average grade is " & avg)
' This code produces the following output:
'
' The average grade is 77.6
```

### Remarks

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average(IEnumerable<Double>)

Computes the average of a sequence of Double values.

```
public:
[System::Runtime::CompilerServices::Extension]
static double Average(System::Collections::Generic::IEnumerable<double> ^ source);
```

`public static double Average (this System.Collections.Generic.IEnumerable<double> source);`

`static member Average : seq<double> -> double`

```
<Extension()>
Public Function Average (source As IEnumerable(Of Double)) As Double
```

#### Parameters

- source
- IEnumerable<Double>

A sequence of Double values to calculate the average of.

#### Returns

The average of the sequence of values.

#### Exceptions

`source`

is `null`

.

`source`

contains no elements.

### Examples

Note

```
List<int> grades = new List<int> { 78, 92, 100, 37, 81 };
double average = grades.Average();
Console.WriteLine("The average grade is {0}.", average);
// This code produces the following output:
//
// The average grade is 77.6.
```

```
' Create a list of integers.
Dim grades As New List(Of Integer)(New Integer() {78, 92, 100, 37, 81})
' Determine the average value in the list.
Dim avg As Double = grades.Average()
' Display the output.
MsgBox("The average grade is " & avg)
' This code produces the following output:
'
' The average grade is 77.6
```

### Remarks

If the sum of the elements is too large to represent as a Double, this method returns positive or negative infinity.

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average(IEnumerable<Decimal>)

Computes the average of a sequence of Decimal values.

```
public:
[System::Runtime::CompilerServices::Extension]
static System::Decimal Average(System::Collections::Generic::IEnumerable<System::Decimal> ^ source);
```

`public static decimal Average (this System.Collections.Generic.IEnumerable<decimal> source);`

`static member Average : seq<decimal> -> decimal`

```
<Extension()>
Public Function Average (source As IEnumerable(Of Decimal)) As Decimal
```

#### Parameters

- source
- IEnumerable<Decimal>

A sequence of Decimal values to calculate the average of.

#### Returns

The average of the sequence of values.

#### Exceptions

`source`

is `null`

.

`source`

contains no elements.

### Examples

The following code example demonstrates how to use Average(IEnumerable<Int32>) to calculate the average of a sequence of values.

Note

```
List<int> grades = new List<int> { 78, 92, 100, 37, 81 };
double average = grades.Average();
Console.WriteLine("The average grade is {0}.", average);
// This code produces the following output:
//
// The average grade is 77.6.
```

```
' Create a list of integers.
Dim grades As New List(Of Integer)(New Integer() {78, 92, 100, 37, 81})
' Determine the average value in the list.
Dim avg As Double = grades.Average()
' Display the output.
MsgBox("The average grade is " & avg)
' This code produces the following output:
'
' The average grade is 77.6
```

### Remarks

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average(IEnumerable<Nullable<Decimal>>)

Computes the average of a sequence of nullable Decimal values.

```
public:
[System::Runtime::CompilerServices::Extension]
static Nullable<System::Decimal> Average(System::Collections::Generic::IEnumerable<Nullable<System::Decimal>> ^ source);
```

`public static Nullable<decimal> Average (this System.Collections.Generic.IEnumerable<Nullable<decimal>> source);`

`static member Average : seq<Nullable<decimal>> -> Nullable<decimal>`

```
<Extension()>
Public Function Average (source As IEnumerable(Of Nullable(Of Decimal))) As Nullable(Of Decimal)
```

#### Parameters

- source
- IEnumerable<Nullable<Decimal>>

A sequence of nullable Decimal values to calculate the average of.

#### Returns

`null`

if the source sequence is empty or contains only values that are `null`

.

#### Exceptions

`source`

is `null`

.

The sum of the elements in the sequence is larger than MaxValue.

### Examples

Note

```
long?[] longs = { null, 10007L, 37L, 399846234235L };
double? average = longs.Average();
Console.WriteLine("The average is {0}.", average);
// This code produces the following output:
//
// The average is 133282081426.333.
```

```
' Create an array of nullable long values.
Dim longs() As Nullable(Of Long) = {Nothing, 10007L, 37L, 399846234235L}
' Determine the average value in the array.
Dim avg As Nullable(Of Double) = longs.Average()
' Display the output.
MsgBox("The average is " & avg.ToString)
' This code produces the following output:
'
' The average is 133282081426.333
```

### Remarks

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>)

Computes the average of a sequence of nullable Int32 values that are obtained by invoking a transform function on each element of the input sequence.

```
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static Nullable<double> Average(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<int>> ^ selector);
```

`public static Nullable<double> Average<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<int>> selector);`

`static member Average : seq<'Source> * Func<'Source, Nullable<int>> -> Nullable<double>`

```
<Extension()>
Public Function Average(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Integer))) As Nullable(Of Double)
```

#### Type Parameters

- TSource

The type of the elements of `source`

.

#### Parameters

- source
- IEnumerable<TSource>

A sequence of values to calculate the average of.

#### Returns

`null`

if the source sequence is empty or contains only values that are `null`

.

#### Exceptions

`source`

or `selector`

is `null`

.

The sum of the elements in the sequence is larger than MaxValue.

### Examples

The following code example demonstrates how to use Average<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to calculate an average.

Note

This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, change the body of the `selector`

function.

```
string[] fruits = { "apple", "banana", "mango", "orange", "passionfruit", "grape" };
double average = fruits.Average(s => s.Length);
Console.WriteLine("The average string length is {0}.", average);
// This code produces the following output:
//
// The average string length is 6.5.
```

```
' Create an array of strings.
Dim fruits() As String =
{"apple", "banana", "mango", "orange", "passionfruit", "grape"}
' Determine the average length of the strings in the array.
Dim avg As Double = fruits.Average(Function(s) s.Length)
' Display the output.
MsgBox("The average string length is " & avg)
' This code produces the following output:
'
' The average string length is 6.5
```

### Remarks

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average<TSource>(IEnumerable<TSource>, Func<TSource,Single>)

Computes the average of a sequence of Single values that are obtained by invoking a transform function on each element of the input sequence.

```
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static float Average(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, float> ^ selector);
```

`public static float Average<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,float> selector);`

`static member Average : seq<'Source> * Func<'Source, single> -> single`

```
<Extension()>
Public Function Average(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Single)) As Single
```

#### Type Parameters

- TSource

The type of the elements of `source`

.

#### Parameters

- source
- IEnumerable<TSource>

A sequence of values to calculate the average of.

#### Returns

The average of the sequence of values.

#### Exceptions

`source`

or `selector`

is `null`

.

`source`

contains no elements.

### Examples

The following code example demonstrates how to use Average<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to calculate an average.

Note

This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, change the body of the `selector`

function.

```
string[] fruits = { "apple", "banana", "mango", "orange", "passionfruit", "grape" };
double average = fruits.Average(s => s.Length);
Console.WriteLine("The average string length is {0}.", average);
// This code produces the following output:
//
// The average string length is 6.5.
```

```
' Create an array of strings.
Dim fruits() As String =
{"apple", "banana", "mango", "orange", "passionfruit", "grape"}
' Determine the average length of the strings in the array.
Dim avg As Double = fruits.Average(Function(s) s.Length)
' Display the output.
MsgBox("The average string length is " & avg)
' This code produces the following output:
'
' The average string length is 6.5
```

### Remarks

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>)

Computes the average of a sequence of nullable Single values that are obtained by invoking a transform function on each element of the input sequence.

```
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static Nullable<float> Average(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<float>> ^ selector);
```

`public static Nullable<float> Average<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<float>> selector);`

`static member Average : seq<'Source> * Func<'Source, Nullable<single>> -> Nullable<single>`

```
<Extension()>
Public Function Average(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Single))) As Nullable(Of Single)
```

#### Type Parameters

- TSource

The type of the elements of `source`

.

#### Parameters

- source
- IEnumerable<TSource>

A sequence of values to calculate the average of.

#### Returns

`null`

if the source sequence is empty or contains only values that are `null`

.

#### Exceptions

`source`

or `selector`

is `null`

.

### Examples

The following code example demonstrates how to use Average<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to calculate an average.

Note

This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, change the body of the `selector`

function.

```
string[] fruits = { "apple", "banana", "mango", "orange", "passionfruit", "grape" };
double average = fruits.Average(s => s.Length);
Console.WriteLine("The average string length is {0}.", average);
// This code produces the following output:
//
// The average string length is 6.5.
```

```
' Create an array of strings.
Dim fruits() As String =
{"apple", "banana", "mango", "orange", "passionfruit", "grape"}
' Determine the average length of the strings in the array.
Dim avg As Double = fruits.Average(Function(s) s.Length)
' Display the output.
MsgBox("The average string length is " & avg)
' This code produces the following output:
'
' The average string length is 6.5
```

### Remarks

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>)

Computes the average of a sequence of nullable Int64 values that are obtained by invoking a transform function on each element of the input sequence.

```
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static Nullable<double> Average(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<long>> ^ selector);
```

`public static Nullable<double> Average<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<long>> selector);`

`static member Average : seq<'Source> * Func<'Source, Nullable<int64>> -> Nullable<double>`

```
<Extension()>
Public Function Average(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Long))) As Nullable(Of Double)
```

#### Type Parameters

- TSource

The type of the elements of `source`

.

#### Parameters

- source
- IEnumerable<TSource>

A sequence of values to calculate the average of.

#### Returns

`null`

if the source sequence is empty or contains only values that are `null`

.

### Examples

The following code example demonstrates how to use Average<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) to calculate an average.

Note

`selector`

function.

```
string[] numbers = { "10007", "37", "299846234235" };
double average = numbers.Average(num => Convert.ToInt64(num));
Console.WriteLine("The average is {0}.", average);
// This code produces the following output:
//
// The average is 99948748093.
```

```
' Create an array of strings.
Dim numbers() As String = {"10007", "37", "299846234235"}
' Determine the average number after converting each
' string to an Int64 value.
Dim avg As Double =
numbers.Average(Function(number) Convert.ToInt64(number))
' Display the output.
MsgBox("The average is " & avg)
' This code produces the following output:
'
' The average is 99948748093
```

### Remarks

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>)

Computes the average of a sequence of nullable Double values that are obtained by invoking a transform function on each element of the input sequence.

```
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static Nullable<double> Average(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<double>> ^ selector);
```

`public static Nullable<double> Average<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<double>> selector);`

`static member Average : seq<'Source> * Func<'Source, Nullable<double>> -> Nullable<double>`

```
<Extension()>
Public Function Average(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Double))) As Nullable(Of Double)
```

#### Type Parameters

- TSource

The type of the elements of `source`

.

#### Parameters

- source
- IEnumerable<TSource>

A sequence of values to calculate the average of.

#### Returns

`null`

if the source sequence is empty or contains only values that are `null`

.

#### Exceptions

`source`

or `selector`

is `null`

.

### Examples

The following code example demonstrates how to use Average<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) to calculate an average.

Note

`selector`

function.

```
string[] numbers = { "10007", "37", "299846234235" };
double average = numbers.Average(num => Convert.ToInt64(num));
Console.WriteLine("The average is {0}.", average);
// This code produces the following output:
//
// The average is 99948748093.
```

```
' Create an array of strings.
Dim numbers() As String = {"10007", "37", "299846234235"}
' Determine the average number after converting each
' string to an Int64 value.
Dim avg As Double =
numbers.Average(Function(number) Convert.ToInt64(number))
' Display the output.
MsgBox("The average is " & avg)
' This code produces the following output:
'
' The average is 99948748093
```

### Remarks

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>)

Computes the average of a sequence of nullable Decimal values that are obtained by invoking a transform function on each element of the input sequence.

```
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static Nullable<System::Decimal> Average(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<System::Decimal>> ^ selector);
```

`public static Nullable<decimal> Average<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<decimal>> selector);`

`static member Average : seq<'Source> * Func<'Source, Nullable<decimal>> -> Nullable<decimal>`

```
<Extension()>
Public Function Average(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Decimal))) As Nullable(Of Decimal)
```

#### Type Parameters

- TSource

The type of the elements of `source`

.

#### Parameters

- source
- IEnumerable<TSource>

A sequence of values to calculate the average of.

#### Returns

`null`

if the source sequence is empty or contains only values that are `null`

.

#### Exceptions

`source`

or `selector`

is `null`

.

The sum of the elements in the sequence is larger than MaxValue.

### Examples

The following code example demonstrates how to use Average<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) to calculate an average.

Note

`selector`

function.

```
string[] numbers = { "10007", "37", "299846234235" };
double average = numbers.Average(num => Convert.ToInt64(num));
Console.WriteLine("The average is {0}.", average);
// This code produces the following output:
//
// The average is 99948748093.
```

```
' Create an array of strings.
Dim numbers() As String = {"10007", "37", "299846234235"}
' Determine the average number after converting each
' string to an Int64 value.
Dim avg As Double =
numbers.Average(Function(number) Convert.ToInt64(number))
' Display the output.
MsgBox("The average is " & avg)
' This code produces the following output:
'
' The average is 99948748093
```

### Remarks

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average<TSource>(IEnumerable<TSource>, Func<TSource,Int64>)

Computes the average of a sequence of Int64 values that are obtained by invoking a transform function on each element of the input sequence.

```
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static double Average(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, long> ^ selector);
```

`public static double Average<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,long> selector);`

`static member Average : seq<'Source> * Func<'Source, int64> -> double`

```
<Extension()>
Public Function Average(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Long)) As Double
```

#### Type Parameters

- TSource

The type of the elements of source.

#### Parameters

- source
- IEnumerable<TSource>

A sequence of values to calculate the average of.

#### Returns

The average of the sequence of values.

#### Exceptions

`source`

or `selector`

is `null`

.

`source`

contains no elements.

The sum of the elements in the sequence is larger than MaxValue.

### Examples

```
string[] numbers = { "10007", "37", "299846234235" };
double average = numbers.Average(num => Convert.ToInt64(num));
Console.WriteLine("The average is {0}.", average);
// This code produces the following output:
//
// The average is 99948748093.
```

```
' Create an array of strings.
Dim numbers() As String = {"10007", "37", "299846234235"}
' Determine the average number after converting each
' string to an Int64 value.
Dim avg As Double =
numbers.Average(Function(number) Convert.ToInt64(number))
' Display the output.
MsgBox("The average is " & avg)
' This code produces the following output:
'
' The average is 99948748093
```

### Remarks

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average<TSource>(IEnumerable<TSource>, Func<TSource,Int32>)

Computes the average of a sequence of Int32 values that are obtained by invoking a transform function on each element of the input sequence.

```
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static double Average(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, int> ^ selector);
```

`public static double Average<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,int> selector);`

`static member Average : seq<'Source> * Func<'Source, int> -> double`

```
<Extension()>
Public Function Average(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Integer)) As Double
```

#### Type Parameters

- TSource

The type of the elements of `source`

.

#### Parameters

- source
- IEnumerable<TSource>

A sequence of values to calculate the average of.

#### Returns

The average of the sequence of values.

#### Exceptions

`source`

or `selector`

is `null`

.

`source`

contains no elements.

The sum of the elements in the sequence is larger than MaxValue.

### Examples

```
string[] fruits = { "apple", "banana", "mango", "orange", "passionfruit", "grape" };
double average = fruits.Average(s => s.Length);
Console.WriteLine("The average string length is {0}.", average);
// This code produces the following output:
//
// The average string length is 6.5.
```

```
' Create an array of strings.
Dim fruits() As String =
{"apple", "banana", "mango", "orange", "passionfruit", "grape"}
' Determine the average length of the strings in the array.
Dim avg As Double = fruits.Average(Function(s) s.Length)
' Display the output.
MsgBox("The average string length is " & avg)
' This code produces the following output:
'
' The average string length is 6.5
```

### Remarks

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average<TSource>(IEnumerable<TSource>, Func<TSource,Double>)

Computes the average of a sequence of Double values that are obtained by invoking a transform function on each element of the input sequence.

```
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static double Average(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, double> ^ selector);
```

`public static double Average<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,double> selector);`

`static member Average : seq<'Source> * Func<'Source, double> -> double`

```
<Extension()>
Public Function Average(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Double)) As Double
```

#### Type Parameters

- TSource

The type of the elements of `source`

.

#### Parameters

- source
- IEnumerable<TSource>

A sequence of values to calculate the average of.

#### Returns

The average of the sequence of values.

#### Exceptions

`source`

or `selector`

is `null`

.

`source`

contains no elements.

### Examples

Note

`selector`

function.

```
string[] numbers = { "10007", "37", "299846234235" };
double average = numbers.Average(num => Convert.ToInt64(num));
Console.WriteLine("The average is {0}.", average);
// This code produces the following output:
//
// The average is 99948748093.
```

```
' Create an array of strings.
Dim numbers() As String = {"10007", "37", "299846234235"}
' Determine the average number after converting each
' string to an Int64 value.
Dim avg As Double =
numbers.Average(Function(number) Convert.ToInt64(number))
' Display the output.
MsgBox("The average is " & avg)
' This code produces the following output:
'
' The average is 99948748093
```

### Remarks

`Aggregate Into Average()`

clause translates to an invocation of Average.

### See also

## Average<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>)

Computes the average of a sequence of Decimal values that are obtained by invoking a transform function on each element of the input sequence.

```
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static System::Decimal Average(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, System::Decimal> ^ selector);
```

`public static decimal Average<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,decimal> selector);`

`static member Average : seq<'Source> * Func<'Source, decimal> -> decimal`

```
<Extension()>
Public Function Average(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Decimal)) As Decimal
```

#### Type Parameters

- TSource

The type of the elements of `source`

.

#### Parameters

- source
- IEnumerable<TSource>

A sequence of values that are used to calculate an average.

#### Returns

The average of the sequence of values.

#### Exceptions

`source`

or `selector`

is `null`

.

`source`

contains no elements.

The sum of the elements in the sequence is larger than MaxValue.

### Examples

Note

`selector`

function.

```
string[] numbers = { "10007", "37", "299846234235" };
double average = numbers.Average(num => Convert.ToInt64(num));
Console.WriteLine("The average is {0}.", average);
// This code produces the following output:
//
// The average is 99948748093.
```

```
' Create an array of strings.
Dim numbers() As String = {"10007", "37", "299846234235"}
' Determine the average number after converting each
' string to an Int64 value.
Dim avg As Double =
numbers.Average(Function(number) Convert.ToInt64(number))
' Display the output.
MsgBox("The average is " & avg)
' This code produces the following output:
'
' The average is 99948748093
```

### Remarks

`Aggregate Into Average()`

clause translates to an invocation of Average.