Enumerable.Last Enumerable.Last Enumerable.Last Enumerable.Last Method

Definition

Returns the last element of a sequence.

Overloads

Last<TSource>(IEnumerable<TSource>) Last<TSource>(IEnumerable<TSource>) Last<TSource>(IEnumerable<TSource>) Last<TSource>(IEnumerable<TSource>)

Returns the last element of a sequence.

Last<TSource>(IEnumerable<TSource>, Func<TSource,Boolean>) Last<TSource>(IEnumerable<TSource>, Func<TSource,Boolean>) Last<TSource>(IEnumerable<TSource>, Func<TSource,Boolean>) Last<TSource>(IEnumerable<TSource>, Func<TSource,Boolean>)

Returns the last element of a sequence that satisfies a specified condition.

Last<TSource>(IEnumerable<TSource>) Last<TSource>(IEnumerable<TSource>) Last<TSource>(IEnumerable<TSource>) Last<TSource>(IEnumerable<TSource>)

Returns the last element of a sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static TSource Last(System::Collections::Generic::IEnumerable<TSource> ^ source);
public static TSource Last<TSource> (this System.Collections.Generic.IEnumerable<TSource> source);
static member Last : seq<'Source> -> 'Source
<Extension()>
Public Function Last(Of TSource) (source As IEnumerable(Of TSource)) As TSource
Type Parameters
TSource

The type of the elements of source.

Parameters
source
IEnumerable<TSource>

An IEnumerable<T> to return the last element of.

Returns

The value at the last position in the source sequence.

Exceptions

Examples

The following code example demonstrates how to use Last<TSource>(IEnumerable<TSource>) to return the last element of an array.

int[] numbers = { 9, 34, 65, 92, 87, 435, 3, 54, 
                    83, 23, 87, 67, 12, 19 };

int last = numbers.Last();

Console.WriteLine(last);

/*
 This code produces the following output:

 19
*/

' Create an array of integers.
Dim numbers() As Integer =
{9, 34, 65, 92, 87, 435, 3, 54, 83, 23, 87, 67, 12, 19}

' Get the last item in the array.
Dim last As Integer = numbers.Last()

' Display the result.
MsgBox(last)

' This code produces the following output:
'
' 19

Remarks

The Last<TSource>(IEnumerable<TSource>) method throws an exception if source contains no elements. To instead return a default value when the source sequence is empty, use the LastOrDefault method.

Last<TSource>(IEnumerable<TSource>, Func<TSource,Boolean>) Last<TSource>(IEnumerable<TSource>, Func<TSource,Boolean>) Last<TSource>(IEnumerable<TSource>, Func<TSource,Boolean>) Last<TSource>(IEnumerable<TSource>, Func<TSource,Boolean>)

Returns the last element of a sequence that satisfies a specified condition.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static TSource Last(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, bool> ^ predicate);
public static TSource Last<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,bool> predicate);
static member Last : seq<'Source> * Func<'Source, bool> -> 'Source
<Extension()>
Public Function Last(Of TSource) (source As IEnumerable(Of TSource), predicate As Func(Of TSource, Boolean)) As TSource
Type Parameters
TSource

The type of the elements of source.

Parameters
source
IEnumerable<TSource>

An IEnumerable<T> to return an element from.

predicate
Func<TSource,Boolean>

A function to test each element for a condition.

Returns

The last element in the sequence that passes the test in the specified predicate function.

Exceptions

No element satisfies the condition in predicate.

-or-

The source sequence is empty.

Examples

The following code example demonstrates how to use Last<TSource>(IEnumerable<TSource>, Func<TSource,Boolean>) to return the last element of an array that satisfies a condition.

int[] numbers = { 9, 34, 65, 92, 87, 435, 3, 54, 
                    83, 23, 87, 67, 12, 19 };

int last = numbers.Last(num => num > 80);

Console.WriteLine(last);

/*
 This code produces the following output:

 87
*/

' Create an array of integers.
Dim numbers() As Integer =
{9, 34, 65, 92, 87, 435, 3, 54, 83, 23, 87, 67, 12, 19}

' Get the last element in the array whose value is
' greater than 80.
Dim last As Integer = numbers.Last(Function(num) num > 80)

' Display the result.
MsgBox(last)

' This code produces the following output:
'
' 87

Remarks

The Last<TSource>(IEnumerable<TSource>, Func<TSource,Boolean>) method throws an exception if no matching element is found in source. To instead return a default value when no matching element is found, use the LastOrDefault method.

Applies to