Vector<T>.BitwiseAnd(Vector<T>, Vector<T>) Operator

Definition

Returns a new vector by performing a bitwise And operation on each of the elements in two vectors.

public:
 static System::Numerics::Vector<T> operator &(System::Numerics::Vector<T> left, System::Numerics::Vector<T> right);
public static System.Numerics.Vector<T> operator & (System.Numerics.Vector<T> left, System.Numerics.Vector<T> right);
static member ( &&& ) : System.Numerics.Vector<'T (requires 'T : struct)> * System.Numerics.Vector<'T (requires 'T : struct)> -> System.Numerics.Vector<'T (requires 'T : struct)>
static member ( &&& ) : System.Numerics.Vector<'T> * System.Numerics.Vector<'T> -> System.Numerics.Vector<'T>
Public Shared Operator And (left As Vector(Of T), right As Vector(Of T)) As Vector(Of T)

Parameters

left
Vector<T>

The first vector.

right
Vector<T>

The second vector.

Returns

The vector that results from the bitwise And of left and right.

Exceptions

.NET 5 and later: Type T is not supported.

Remarks

The BitwiseAnd method defines the bitwise And operation for Vector<T> objects.

Applies to