OpCodes.Rem OpCodes.Rem OpCodes.Rem OpCodes.Rem Field

Definition

Divides two values and pushes the remainder onto the evaluation stack.

public: static initonly System::Reflection::Emit::OpCode Rem;
public static readonly System.Reflection.Emit.OpCode Rem;
 staticval mutable Rem : System.Reflection.Emit.OpCode
Public Shared ReadOnly Rem As OpCode 
Field Value

Remarks

The following table lists the instruction's hexadecimal and Microsoft Intermediate Language (MSIL) assembly format, along with a brief reference summary:

Format Assembly Format Description
5D rem Pushes the remainder of dividing value1 by value2 onto the stack.

Note

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The stack transitional behavior, in sequential order, is:

  1. A value1 is pushed onto the stack.

  2. value2 is pushed onto the stack.

  3. value2 and value1 are popped from the stack and the remainder of value1 div value2 computed.

  4. The result is pushed onto the stack.

result = value1 rem value2 satisfies the following conditions:

result = value1 - value2 × (value1 div value2), and:

0 = | result | < | value2 |, sign(result) = sign(value1), where div is the division instruction that truncates towards zero.

If value2 is zero or value1 is infinity the result is NaN. If value2 is infinity, the result is value1 (negated for -infinity).

Integral operations throw DivideByZeroException if value2 is zero.

Note that on the Intel-based platforms an OverflowException is thrown when computing (minint rem -1).

The following Emit method overload can use the rem opcode:

  • ILGenerator.Emit(OpCode)

Applies to