IUIService.ShowToolWindow(Guid) Method

Definition

Namespace:

System.Windows.Forms.Design

Assembly:

System.Windows.Forms.dll

Displays the specified tool window.

public:
 bool ShowToolWindow(Guid toolWindow);

public bool ShowToolWindow (Guid toolWindow);

abstract member ShowToolWindow : Guid -> bool

Public Function ShowToolWindow (toolWindow As Guid) As Boolean

Parameters

toolWindow

Guid

A Guid identifier for the tool window. This can be a custom Guid or one of the predefined values from StandardToolWindows.

Returns

Boolean

true if the tool window was successfully shown; false if it could not be shown or found.

Examples

The following code example attempts to obtain an instance of the IUIService and invoke the service's ShowToolWindow method.

IUIService^ UIservice = dynamic_cast<IUIService^>(this->GetService( System::Windows::Forms::Design::IUIService::typeid ));
if ( UIservice != nullptr )
      UIservice->ShowToolWindow( StandardToolWindows::TaskList );

IUIService UIservice = (IUIService)this.GetService( 
    typeof( System.Windows.Forms.Design.IUIService ) );
if( UIservice != null )            
    UIservice.ShowToolWindow(StandardToolWindows.TaskList);

Dim UIservice As IUIService = CType(Me.GetService( _
    GetType(System.Windows.Forms.Design.IUIService)), IUIService)
If (UIservice IsNot Nothing) Then
    UIservice.ShowToolWindow(StandardToolWindows.TaskList)
End If

See also

• StandardToolWindows