TreeNodeCollection.Contains(TreeNode) TreeNodeCollection.Contains(TreeNode) TreeNodeCollection.Contains(TreeNode) TreeNodeCollection.Contains(TreeNode) Method

Definition

Determines whether the specified tree node is a member of the collection.

public:
 bool Contains(System::Windows::Forms::TreeNode ^ node);
public bool Contains (System.Windows.Forms.TreeNode node);
member this.Contains : System.Windows.Forms.TreeNode -> bool
Public Function Contains (node As TreeNode) As Boolean

Parameters

node
TreeNode TreeNode TreeNode TreeNode

The TreeNode to locate in the collection.

Returns

true if the TreeNode is a member of the collection; otherwise, false.

Examples

The following code example determines if a specified TreeNode is within a TreeNodeCollection, and then enumerates the collection. This example requires that you have a Form with a TreeView that has a TreeNodeCollection that contains a TreeNode named myTreeNode2.

void EnumerateTreeNodes()
{
   TreeNodeCollection^ myNodeCollection = myTreeView->Nodes;

   // Check for a node in the collection.
   if ( myNodeCollection->Contains( myTreeNode2 ) )
   {
      myLabel->Text = myLabel->Text + "Node2 is at index: " + myNodeCollection->IndexOf( myTreeNode2 );
   }

   myLabel->Text = myLabel->Text + "\n\nElements of the TreeNodeCollection:\n";

   // Create an enumerator for the collection.
   IEnumerator^ myEnumerator = myNodeCollection->GetEnumerator();
   while ( myEnumerator->MoveNext() )
   {
      myLabel->Text = myLabel->Text + (dynamic_cast<TreeNode^>(myEnumerator->Current))->Text + "\n";
   }
}
private void EnumerateTreeNodes()
{
   TreeNodeCollection myNodeCollection = myTreeView.Nodes;
   // Check for a node in the collection.
   if (myNodeCollection.Contains(myTreeNode2))
   {
      myLabel.Text += "Node2 is at index: " + myNodeCollection.IndexOf(myTreeNode2);
   }
   myLabel.Text += "\n\nElements of the TreeNodeCollection:\n";

   // Create an enumerator for the collection.
   IEnumerator myEnumerator = myNodeCollection.GetEnumerator();
   while(myEnumerator.MoveNext())
   {
      myLabel.Text += ((TreeNode)myEnumerator.Current).Text +"\n";
   }
}
Private Sub EnumerateTreeNodes()
   Dim myNodeCollection As TreeNodeCollection = myTreeView.Nodes
   ' Check for a node in the collection.
   If myNodeCollection.Contains(myTreeNode2) Then
      myLabel.Text += "Node2 is at index: " + myNodeCollection.IndexOf(myTreeNode2)
   End If
   myLabel.Text += ControlChars.Cr + ControlChars.Cr + _
     "Elements of the TreeNodeCollection:" + ControlChars.Cr
   
   ' Create an enumerator for the collection.
   Dim myEnumerator As IEnumerator = myNodeCollection.GetEnumerator()
   While myEnumerator.MoveNext()
      myLabel.Text += CType(myEnumerator.Current, TreeNode).Text + ControlChars.Cr
   End While
End Sub 

Remarks

This method enables you to determine whether a TreeNode is a member of the collection before attempting to perform operations on the TreeNode. You can use this method to confirm that a TreeNode has been added to or is still a member of the collection.

The amount of time this method takes is proportional to the size of the node collection, so you may want to avoid using it with large collections.

This method checks for reference equality only. You cannot use it to determine whether an equivalent but different node is in the collection.

Note

One implication of the reference-equality requirement is that you cannot customize the behavior of this method for derived TreeNode types by overriding the Equals method of the TreeNode class.

Applies to