XmlDocument.DocumentType Property

Definition

Gets the node containing the DOCTYPE declaration.

public:
 virtual property System::Xml::XmlDocumentType ^ DocumentType { System::Xml::XmlDocumentType ^ get(); };
public virtual System.Xml.XmlDocumentType DocumentType { get; }
member this.DocumentType : System.Xml.XmlDocumentType
Public Overridable ReadOnly Property DocumentType As XmlDocumentType

Property Value

XmlDocumentType

The XmlNode containing the DocumentType (DOCTYPE declaration).

Examples

The following example gets and displays the DOCTYPE declaration for the document.

#using <System.Xml.dll>

using namespace System;
using namespace System::IO;
using namespace System::Xml;
int main()
{
   
   // Create the XmlDocument.
   XmlDocument^ doc = gcnew XmlDocument;
   doc->LoadXml( "<!DOCTYPE book [<!ENTITY h 'hardcover'>]>"
   "<book genre='novel' ISBN='1-861001-57-5'>"
   "<title>Pride And Prejudice</title>"
   "<style>&h;</style>"
   "</book>" );
   
   // Display the DocumentType.
   Console::WriteLine( doc->DocumentType->OuterXml );
}

using System;
using System.IO;
using System.Xml;

public class Sample
{
  public static void Main()
  {
    // Create the XmlDocument.
    XmlDocument doc = new XmlDocument();
    doc.LoadXml("<!DOCTYPE book [<!ENTITY h 'hardcover'>]>" +
                "<book genre='novel' ISBN='1-861001-57-5'>" +
                "<title>Pride And Prejudice</title>" +
                "<style>&h;</style>" +
                "</book>");

    // Display the DocumentType.
    Console.WriteLine(doc.DocumentType.OuterXml);
  }
}
Option Explicit
Option Strict

Imports System.IO
Imports System.Xml

Public Class Sample
    Public Shared Sub Main()
        ' Create the XmlDocument.
        Dim doc As New XmlDocument()
        doc.LoadXml("<!DOCTYPE book [<!ENTITY h 'hardcover'>]>" & _
                    "<book genre='novel' ISBN='1-861001-57-5'>" & _
                    "<title>Pride And Prejudice</title>" & _
                    "<style>&h;</style>" & _
                    "</book>")
        
        ' Display the DocumentType.
        Console.WriteLine(doc.DocumentType.OuterXml)
    End Sub
End Class

Remarks

An XmlDocument can have one and only one child with XmlNodeType equal to DocumentType.

Note

This property is read-only. To change the DocumentType node, delete the existing node, create a new one using the CreateDocumentType method, and add the new node to the document.

Applies to

See also