Binding.Create<TSource> Method
Definition
Important
Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.
Caution
This API is now deprecated.
This is a convenient factory method to create a binding from an expression, instead of a property name. This api is more resilient to refactoring.
[System.ComponentModel.EditorBrowsable(System.ComponentModel.EditorBrowsableState.Never)]
[System.Obsolete]
public static Xamarin.Forms.Binding Create<TSource> (System.Linq.Expressions.Expression<Func<TSource,object>> propertyGetter, Xamarin.Forms.BindingMode mode = Xamarin.Forms.BindingMode.Default, Xamarin.Forms.IValueConverter converter = default, object converterParameter = default, string stringFormat = default);static member Create : System.Linq.Expressions.Expression<Func<'Source, obj>> * Xamarin.Forms.BindingMode * Xamarin.Forms.IValueConverter * obj * string -> Xamarin.Forms.BindingType Parameters
- TSource
The type of the source of the binding.
Parameters
- propertyGetter
- Expression<Func<TSource,Object>>
An expression used to retrieve the binding path.
- mode
- BindingMode
The binding mode. This property is optional. Default is Default.
- converter
- IValueConverter
The converter. This parameter is optional. Default is null.
- converterParameter
- Object
An user-defined parameter to pass to the converter. This parameter is optional. Default is null.
- stringFormat
- String
A String format. This parameter is optional. Default is null.
Returns
A newly created binding.
- Attributes
Remarks
The following example shows how to set a binding to a property :
public class PersonViewModel
{
public string Name { get; set; }
public string Company { get; set; }
}
var label = new Label ();
PersonViewModel person;
label.BindingContext = person = new PersonViewModel { Name = "John Doe", Company = "Microsoft" };
label.SetBinding (Label.TextProperty, Binding.Create<PersonViewModel> (vm => vm.Name));
Debug.WriteLine (label.Text); //prints "John Doe".