# POWER Function (Decimal, Integer, BigInteger)

Raises a number to a power. For example, you can use this function to square the number 2 to get the result of 4.

## Syntax

```
NewNumber := POWER(Number, Power)
```

#### Parameters

*Number*

Type: Integer or Decimal

The number you want to raise exponentially. This number is the base in the exponential function.

*Power*

Type: Integer or Decimal

The exponent in the exponential function.

## Property Value/Return Value

Type: Decimal

The result of raising *Number* by *Power*.

## Example

This example requires that you create the following variables and text constants in the **C/AL Globals** window.

Variable name | DataType |
---|---|

Number1 | Decimal |

Power1 | Decimal |

Result1 | Decimal |

Text constant name | Constant value |
---|---|

Text000 | %1 raised to the power of %2 = %3 |

```
Number1 := 64;
Power1 := 0.5;
Result1 := POWER(Number1, Power1);
MESSAGE(Text000, Number1, Power1, Result1)
```

On a computer that has the regional format set to English (United States), the first message window displays the following:

**64 raised to the power of 0.5 = 8**

This example shows that raising a number to the power of 0.5 corresponds to the square root of the number.

## Example

This example shows a typical use for the POWER function.

If a principal amount P is deposited at interest rate R and compounded annually, then at the end of N years, the accumulated amount (A) is:

A = P(1 + R)^{N}

For example, you put LCY 2800 into a bank account that pays 5 percent, which is compounded quarterly. To determine what the amount will be in eight years, you must consider:

N = 32 payment periods (8 years times 4 quarterly periods)

R = 0.0125 per period (5 percent divided by 4 quarterly periods)

The accumulated amount A is:

A = LCY 2800(1 + 0.0125)^{32} =LCY 2800(1.4881) = LCY 4166.77

If a principal amount P is deposited at the end of each year at interest rate R (in decimal notation) compounded annually, then at the end of N years, the accumulated amount is:

A = P[((1 + R)^{N} - 1)/R]

This is typically called an *annuity*.

For example, you have an annuity in which a payment of LCY 500 is made at the end of each year. The interest on this annuity is 4 percent, which is compounded annually. To determine what the annuity will be worth in 20 years, you must consider:

R = 0.04

N = 20

The amount of the annuity A will be:

A = LCY 500[((1 + 0.04)^{20} - 1)/0.04 = LCY 14,889.04

This example requires that you create the following variables and text constants in the **C/AL Globals** window.

Variable name | DataType |
---|---|

P | Decimal |

R | Decimal |

N | Decimal |

A | Decimal |

FormatString | Text |

Text constant name | Constant value |
---|---|

Text000 | Principal $%1 at a 5 percent interest rate is compounded quarterly.\ |

Text001 | (Rate = %2)\ |

Text002 | The amount after %3 years = $%4. |

Text003 | Principal $%1 is deposited at the end of each year at a 4 percent interest rate, compounded annually.\ |

Text004 | (Rate = %2)\ |

Text005 | The amount after %3 years = $%4. |

```
FormatString := '<Precision,2><Standard Format,1>';
// Example 1
P := 2800;
R := 0.0125;
N := 32;
A = P * (POWER(1 + R, N));
MESSAGE(Text000 + Text001 + Text002, P, R, N, FORMAT(A,0,FormatString);
// Example 2
P = 500;
R = 0.04;
N = 20;
A = P * ((POWER(1 + R, N) - 1)/R);
MESSAGE(Text001, P, R, N, FORMAT(A,0,FormatString));
```

On a computer that has the regional format set to English (United States), the first message window displays the following:

**Principal $2,800 at a 5 percent interest rate is compounded quarterly.**

**(Rate = 0.0125)**

**The amount after 32 years = $4166.77.**

The second message window displays the following:

**Principal $500 is deposited at the end of each year at a 4 percent interest rate, compounded annually.**

**(Rate = 0.04)**

**The amount after 20 years = $14889.04.**

## See Also

ABS Function (Decimal, Integer, BigInteger)

RANDOM Function (Integer)

RANDOMIZE Function (Integer)

ROUND Function (Decimal)