# WorksheetFunction.Rank_Eq method (Excel)

Returns the rank of a number in a list of numbers. The rank of a number is its size relative to other values in a list. If you were to sort the list, the rank of the number would be its position.

## Syntax

expression.Rank_Eq (Arg1, Arg2, Arg3)

expression A variable that represents a WorksheetFunction object.

## Parameters

Name Required/Optional Data type Description
Arg1 Required Double Number - The number whose rank you want to find.
Arg2 Required Range Ref - An array of, or a reference to, a list of numbers. Non-numeric values in reference are ignored.
Arg3 Optional Variant Order - A number that specifies how to rank the number.

Double

## Remarks

If the order is 0 (zero) or omitted, Microsoft Excel ranks the number as if the reference were a list sorted in descending order.

If the order is any non-zero value, Excel ranks the number as if the reference were a list sorted in ascending order.

Rank_Eq gives duplicate numbers the same rank. However, the presence of duplicate numbers affects the ranks of subsequent numbers. For example, in a list of integers sorted in ascending order, if the number 10 appears twice and has a rank of 5, 11 would have a rank of 7 (no number would have a rank of 6).

For some purposes you might want to use a definition of rank that takes ties into account. In the previous example, you would want a revised rank of 5.5 for the number 10. To do this, add the following correction factor to the value returned by Rank_Eq. This correction factor is appropriate both for the case where rank is computed in descending order (order = 0 or omitted) or ascending order (order = nonzero value).

• Correction factor for tied ranks =[COUNT(ref) + 1 – RANK_EQ(number, ref, 0) – RANK_EQ(number, ref, 1)]/2.

• In the following example, RANK_EQ(A2,A1:A5,1) equals 3. The correction factor is (5 + 1 – 2 – 3)/2 = 0.5, and the revised rank that takes ties into account is 3 + 0.5 = 3.5.

• If number occurs only once in ref, the correction factor will be 0 because Rank_Eq would not have to be adjusted for a tie.

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