XmlReader.ReadElementContentAsDateTime Method

Reads the current element and returns the contents as a DateTime object.

Namespace:  System.Xml
Assembly:  System.Xml (in System.Xml.dll)

Syntax

'Declaration
Public Overridable Function ReadElementContentAsDateTime As DateTime
public virtual DateTime ReadElementContentAsDateTime()

Return Value

Type: System.DateTime
The element content as a DateTime object.

Exceptions

Exception Condition
InvalidOperationException

The XmlReader is not positioned on an element.

XmlException

The current element contains child elements.

-or-

The element content cannot be converted to a DateTime object.

ArgumentNullException

The method is called with nulla null reference (Nothing in Visual Basic) arguments.

Remarks

This method reads the start tag, the contents of the element, and moves the reader past the end element tag. It expands entities and ignores processing instructions and comments. The element can only contain simple content. That is, it cannot have child elements.

Examples

Dim output As New StringBuilder()

Dim xmlString As String = _
            "<root>" & _
            "<stringValue><!--comment-->" & _
            "<?some pi?>text value of the element." & _
            "</stringValue>" & _
            "<longValue>270000000000001</longValue><number>0</number>" & _
            "<double>2E10</double><date>2003-01-08T15:00:00-00:00</date>" & _
            "</root>"

Using reader As XmlReader = XmlReader.Create(New StringReader(xmlString))

    reader.ReadToFollowing("date")
    Dim [date] As DateTime = reader.ReadElementContentAsDateTime()

    ' If the current culture is "en-US",
    ' this writes "Wednesday, January 8, 2003".
    output.AppendLine([date].ToLongDateString())

    OutputTextBlock.Text = output.ToString()
End Using

StringBuilder output = new StringBuilder();

String xmlString =
    @"<root>
    <stringValue>
    <!--comment-->
    <?some pi?>
        text value of the element.
    </stringValue>
    <longValue>270000000000001</longValue>
    <number>0</number>
    <double>2E10</double>
    <date>2003-01-08T15:00:00-00:00</date>
</root>";

using (XmlReader reader = XmlReader.Create(new StringReader(xmlString)))
{
    reader.ReadToFollowing("date");
    DateTime date = reader.ReadElementContentAsDateTime();

    // If the current culture is "en-US",
    // this writes "Wednesday, January 8, 2003".
    output.AppendLine(date.ToLongDateString());
}

OutputTextBlock.Text = output.ToString();

Version Information

Silverlight

Supported in: 5, 4, 3

Silverlight for Windows Phone

Supported in: Windows Phone OS 7.1, Windows Phone OS 7.0

XNA Framework

Supported in: Xbox 360, Windows Phone OS 7.0

Platforms

For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.

See Also

Reference

XmlReader Class

ReadElementContentAsDateTime Overload

System.Xml Namespace

Other Resources

XML Data

Processing XML Data with XmlReader and XmlWriter (Silverlight)