Enumerable.Max Method (IEnumerable<(Of <(Single>)>))

[ This article is for Windows Phone 8 developers. If you’re developing for Windows 10, see the latest documentation. ]

Returns the maximum value in a sequence of Single values.

Namespace: System.Linq
Assembly: System.Core (in System.Core.dll)

Syntax

<ExtensionAttribute> _
Public Shared Function Max ( _
    source As IEnumerable(Of Single) _
) As Single
public static float Max(
    this IEnumerable<float> source
)

Parameters

Return Value

Type: System..::.Single
The maximum value in the sequence.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<(Of <(Single>)>). When you use instance method syntax to call this method, omit the first parameter.

Exceptions

Exception Condition
ArgumentNullException

source is nullNothingnullptra null reference (Nothing in Visual Basic).

InvalidOperationException

source contains no elements.

Remarks

The Max(IEnumerable<(Of <(Single>)>)) method uses the Single implementation of IComparable<(Of <(T>)>) to compare values.

In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Enumerable.Max.

Examples

The following code example demonstrates how to use Max(IEnumerable<(Of <(Int64>)>)) to determine the maximum value in a sequence.

Note

This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

      ' Create a list of Long values.
      Dim longs As New List(Of Long)(New Long() _
                                     {4294967296L, 466855135L, 81125L})

      ' Get the maximum value in the list.
      Dim max As Long = longs.Max()

      ' Display the result.
      outputBlock.Text &= "The largest number is " & max & vbCrLf

      ' This code produces the following output:
      '
      ' The largest number is 4294967296
      List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

      long max = longs.Max();

      outputBlock.Text += String.Format("The largest number is {0}.", max) + "\n";

      /*
       This code produces the following output:

       The largest number is 4294967296.
      */

Version Information

Windows Phone OS

Supported in: 8.1, 8.0, 7.1, 7.0

Platforms

Windows Phone

See Also

Reference

Enumerable Class

Max Overload

System.Linq Namespace