Enumerable.Range Method

Generates a sequence of integral numbers within a specified range.

Namespace:  System.Linq
Assembly:  System.Core (in System.Core.dll)

Syntax

'Declaration
Public Shared Function Range ( _
    start As Integer, _
    count As Integer _
) As IEnumerable(Of Integer)
public static IEnumerable<int> Range(
    int start,
    int count
)

Parameters

  • start
    Type: System.Int32
    The value of the first integer in the sequence.
  • count
    Type: System.Int32
    The number of sequential integers to generate.

Return Value

Type: System.Collections.Generic.IEnumerable<Int32>
An IEnumerable<Int32> in C# or IEnumerable(Of Int32) in Visual Basic that contains a range of sequential integral numbers.

Exceptions

Exception Condition
ArgumentOutOfRangeException

count is less than 0.

-or-

start + count -1 is larger than MaxValue.

Remarks

This method is implemented by using deferred execution. The immediate return value is an object that stores all the information that is required to perform the action. The query represented by this method is not executed until the object is enumerated either by calling its GetEnumerator method directly or by using foreach in Visual C# or For Each in Visual Basic.

Examples

The following code example demonstrates how to use Range to generate a sequence of values.

      ' Generate a sequence of integers from 1 to 10 
      ' and project their squares.
      Dim squares As IEnumerable(Of Integer) = _
          Enumerable.Range(1, 10).Select(Function(x) x * x)

      Dim output As New System.Text.StringBuilder
      For Each num As Integer In squares
         output.AppendLine(num)
      Next

      ' Display the output.
      outputBlock.Text &= output.ToString() & vbCrLf

      ' This code produces the following output:
      '
      ' 1
      ' 4
      ' 9
      ' 16
      ' 25
      ' 36
      ' 49
      ' 64
      ' 81
      ' 100

      // Generate a sequence of integers from 1 to 10 
      // and then select their squares.
      IEnumerable<int> squares = Enumerable.Range(1, 10).Select(x => x * x);

      foreach (int num in squares)
      {
         outputBlock.Text += num + "\n";
      }

      /*
       This code produces the following output:

       1
       4
       9
       16
       25
       36
       49
       64
       81
       100
      */

Version Information

Silverlight

Supported in: 5, 4, 3

Silverlight for Windows Phone

Supported in: Windows Phone OS 7.1, Windows Phone OS 7.0

XNA Framework

Supported in: Xbox 360, Windows Phone OS 7.0

Platforms

For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.