Color.FromArgb Method

Creates a new Color structure by using the specified sRGB alpha channel and color channel values.

Namespace:  System.Windows.Media
Assembly:  System.Windows (in System.Windows.dll)

Syntax

'Declaration
Public Shared Function FromArgb ( _
    a As Byte, _
    r As Byte, _
    g As Byte, _
    b As Byte _
) As Color
public static Color FromArgb(
    byte a,
    byte r,
    byte g,
    byte b
)

Parameters

  • a
    Type: System.Byte
    The alpha channel, A, of the new color. The value must be between 0 and 255.
  • r
    Type: System.Byte
    The red channel, R, of the new color. The value must be between 0 and 255.
  • g
    Type: System.Byte
    The green channel, G, of the new color. The value must be between 0 and 255.
  • b
    Type: System.Byte
    The blue channel, B, of the new color. The value must be between 0 and 255.

Return Value

Type: System.Windows.Media.Color
A Color structure with the specified values.

Remarks

The FromArgb method requires you to specify the alpha channel; the Silverlight 5 implementation of Color does not support Color.FromRgb. The alpha channel of a color determines the amount of transparency of the color. An alpha value of 255 indicates that the color is completely opaque, and a value of 0 indicates that the color is completely transparent.

Version Information

Silverlight

Supported in: 5, 4, 3

Silverlight for Windows Phone

Supported in: Windows Phone OS 7.1, Windows Phone OS 7.0

Platforms

For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.