SqlInt16.Modulus(SqlInt16, SqlInt16) SqlInt16.Modulus(SqlInt16, SqlInt16) SqlInt16.Modulus(SqlInt16, SqlInt16) SqlInt16.Modulus(SqlInt16, SqlInt16) Method

Definición

Divide dos valores de SqlInt16 y devuelve el resto.Divides two SqlInt16 values and returns the remainder.

public:
 static System::Data::SqlTypes::SqlInt16 Modulus(System::Data::SqlTypes::SqlInt16 x, System::Data::SqlTypes::SqlInt16 y);
public static System.Data.SqlTypes.SqlInt16 Modulus (System.Data.SqlTypes.SqlInt16 x, System.Data.SqlTypes.SqlInt16 y);
static member Modulus : System.Data.SqlTypes.SqlInt16 * System.Data.SqlTypes.SqlInt16 -> System.Data.SqlTypes.SqlInt16
Public Shared Function Modulus (x As SqlInt16, y As SqlInt16) As SqlInt16

Parámetros

Devoluciones

El resto resultante de la división de x por y.The remainder left after division is performed on x and y.

Comentarios

Si alguna de las instancias de x o y es null, el valor es null.If either instance of x or y is null, the value is null.

Se aplica a

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