SqlInt16.Subtraction(SqlInt16, SqlInt16) SqlInt16.Subtraction(SqlInt16, SqlInt16) SqlInt16.Subtraction(SqlInt16, SqlInt16) SqlInt16.Subtraction(SqlInt16, SqlInt16) Operator

Definición

Resta el segundo parámetro SqlInt16 del primero.Subtracts the second SqlInt16 parameter from the first.

public:
 static System::Data::SqlTypes::SqlInt16 operator -(System::Data::SqlTypes::SqlInt16 x, System::Data::SqlTypes::SqlInt16 y);
public static System.Data.SqlTypes.SqlInt16 operator - (System.Data.SqlTypes.SqlInt16 x, System.Data.SqlTypes.SqlInt16 y);
static member ( - ) : System.Data.SqlTypes.SqlInt16 * System.Data.SqlTypes.SqlInt16 -> System.Data.SqlTypes.SqlInt16
Public Shared Operator - (x As SqlInt16, y As SqlInt16) As SqlInt16

Parámetros

x
SqlInt16 SqlInt16 SqlInt16 SqlInt16

Estructura SqlInt16.A SqlInt16 structure.

y
SqlInt16 SqlInt16 SqlInt16 SqlInt16

Estructura SqlInt16.A SqlInt16 structure.

Devoluciones

Una estructura SqlInt16 cuya propiedad Value contiene el resultado de la resta.A SqlInt16 structure whose Value property contains the results of the subtraction.

Comentarios

El método equivalente para este operador es SqlInt16.Subtract(SqlInt16, SqlInt16).The equivalent method for this operator is SqlInt16.Subtract(SqlInt16, SqlInt16).

Se aplica a

Consulte también: