DateTime.Subtraction DateTime.Subtraction DateTime.Subtraction DateTime.Subtraction Operator

Definición

Sobrecargas

Subtraction(DateTime, TimeSpan) Subtraction(DateTime, TimeSpan) Subtraction(DateTime, TimeSpan) Subtraction(DateTime, TimeSpan)

Resta un intervalo de tiempo especificado de un valor de fecha y hora especificado y devuelve un nuevo valor de fecha y hora.Subtracts a specified time interval from a specified date and time and returns a new date and time.

Subtraction(DateTime, DateTime) Subtraction(DateTime, DateTime) Subtraction(DateTime, DateTime) Subtraction(DateTime, DateTime)

Resta una fecha y hora especificadas de otra fecha y hora especificadas y devuelve un intervalo de tiempo.Subtracts a specified date and time from another specified date and time and returns a time interval.

Subtraction(DateTime, TimeSpan) Subtraction(DateTime, TimeSpan) Subtraction(DateTime, TimeSpan) Subtraction(DateTime, TimeSpan)

Resta un intervalo de tiempo especificado de un valor de fecha y hora especificado y devuelve un nuevo valor de fecha y hora.Subtracts a specified time interval from a specified date and time and returns a new date and time.

public:
 static DateTime operator -(DateTime d, TimeSpan t);
public static DateTime operator - (DateTime d, TimeSpan t);
static member ( - ) : DateTime * TimeSpan -> DateTime
Public Shared Operator - (d As DateTime, t As TimeSpan) As DateTime

Parámetros

d
DateTime DateTime DateTime DateTime

Valor de fecha y hora del que se va a restar.The date and time value to subtract from.

t
TimeSpan TimeSpan TimeSpan TimeSpan

Intervalo de hora que se van a restar.The time interval to subtract.

Devoluciones

Objeto cuyo valor es el valor de d menos el valor de t.An object whose value is the value of d minus the value of t.

Excepciones

Ejemplos

En el ejemplo siguiente se muestra el Subtract método y el operador de resta.The following example demonstrates the Subtract method and the subtraction operator.

System::DateTime date1 = System::DateTime( 1996, 6, 3, 22, 15, 0 );
System::DateTime date2 = System::DateTime( 1996, 12, 6, 13, 2, 0 );
System::DateTime date3 = System::DateTime( 1996, 10, 12, 8, 42, 0 );

// diff1 gets 185 days, 14 hours, and 47 minutes.
System::TimeSpan diff1 = date2.Subtract( date1 );

// date4 gets 4/9/1996 5:55:00 PM.
System::DateTime date4 = date3.Subtract( diff1 );

// diff2 gets 55 days 4 hours and 20 minutes.
System::TimeSpan diff2 = date2 - date3;

// date5 gets 4/9/1996 5:55:00 PM.
System::DateTime date5 = date1 - diff2;
System.DateTime date1 = new System.DateTime(1996, 6, 3, 22, 15, 0);
System.DateTime date2 = new System.DateTime(1996, 12, 6, 13, 2, 0);
System.DateTime date3 = new System.DateTime(1996, 10, 12, 8, 42, 0);

// diff1 gets 185 days, 14 hours, and 47 minutes.
System.TimeSpan diff1 = date2.Subtract(date1);

// date4 gets 4/9/1996 5:55:00 PM.
System.DateTime date4 = date3.Subtract(diff1);

// diff2 gets 55 days 4 hours and 20 minutes.
System.TimeSpan diff2 = date2 - date3;

// date5 gets 4/9/1996 5:55:00 PM.
System.DateTime date5 = date1 - diff2;
Dim date1 As New System.DateTime(1996, 6, 3, 22, 15, 0)
Dim date2 As New System.DateTime(1996, 12, 6, 13, 2, 0)
Dim date3 As New System.DateTime(1996, 10, 12, 8, 42, 0)

Dim diff1 As System.TimeSpan
' diff1 gets 185 days, 14 hours, and 47 minutes.
diff1 = date2.Subtract(date1)

Dim date4 As System.DateTime
' date4 gets 4/9/1996 5:55:00 PM.
date4 = date3.Subtract(diff1)

Dim diff2 As System.TimeSpan
' diff2 gets 55 days 4 hours and 20 minutes.
diff2 = System.DateTime.op_Subtraction(date2, date3)

Dim date5 As System.DateTime
' date5 gets 4/9/1996 5:55:00 PM.
date5 = System.DateTime.op_Subtraction(date1, diff2)

Comentarios

Este método resta el valor de pasos de t el valor en pasos de d.This method subtracts the ticks value of t from the ticks value of d.

Es el método equivalente para este operador DateTime.Subtract(DateTime)The equivalent method for this operator is DateTime.Subtract(DateTime)

Consulte también:

Subtraction(DateTime, DateTime) Subtraction(DateTime, DateTime) Subtraction(DateTime, DateTime) Subtraction(DateTime, DateTime)

Resta una fecha y hora especificadas de otra fecha y hora especificadas y devuelve un intervalo de tiempo.Subtracts a specified date and time from another specified date and time and returns a time interval.

public:
 static TimeSpan operator -(DateTime d1, DateTime d2);
public static TimeSpan operator - (DateTime d1, DateTime d2);
static member ( - ) : DateTime * DateTime -> TimeSpan
Public Shared Operator - (d1 As DateTime, d2 As DateTime) As TimeSpan

Parámetros

d1
DateTime DateTime DateTime DateTime

Valor de fecha y hora del que restar (minuendo).The date and time value to subtract from (the minuend).

d2
DateTime DateTime DateTime DateTime

Valor de fecha y hora que se resta (sustraendo).The date and time value to subtract (the subtrahend).

Devoluciones

Intervalo de horas entre d1 y d2; es decir, d1 menos d2.The time interval between d1 and d2; that is, d1 minus d2.

Ejemplos

En el ejemplo siguiente se muestra el Subtract método y el operador de resta.The following example demonstrates the Subtract method and the subtraction operator.

System::DateTime date1 = System::DateTime( 1996, 6, 3, 22, 15, 0 );
System::DateTime date2 = System::DateTime( 1996, 12, 6, 13, 2, 0 );
System::DateTime date3 = System::DateTime( 1996, 10, 12, 8, 42, 0 );

// diff1 gets 185 days, 14 hours, and 47 minutes.
System::TimeSpan diff1 = date2.Subtract( date1 );

// date4 gets 4/9/1996 5:55:00 PM.
System::DateTime date4 = date3.Subtract( diff1 );

// diff2 gets 55 days 4 hours and 20 minutes.
System::TimeSpan diff2 = date2 - date3;

// date5 gets 4/9/1996 5:55:00 PM.
System::DateTime date5 = date1 - diff2;
System.DateTime date1 = new System.DateTime(1996, 6, 3, 22, 15, 0);
System.DateTime date2 = new System.DateTime(1996, 12, 6, 13, 2, 0);
System.DateTime date3 = new System.DateTime(1996, 10, 12, 8, 42, 0);

// diff1 gets 185 days, 14 hours, and 47 minutes.
System.TimeSpan diff1 = date2.Subtract(date1);

// date4 gets 4/9/1996 5:55:00 PM.
System.DateTime date4 = date3.Subtract(diff1);

// diff2 gets 55 days 4 hours and 20 minutes.
System.TimeSpan diff2 = date2 - date3;

// date5 gets 4/9/1996 5:55:00 PM.
System.DateTime date5 = date1 - diff2;
Dim date1 As New System.DateTime(1996, 6, 3, 22, 15, 0)
Dim date2 As New System.DateTime(1996, 12, 6, 13, 2, 0)
Dim date3 As New System.DateTime(1996, 10, 12, 8, 42, 0)

Dim diff1 As System.TimeSpan
' diff1 gets 185 days, 14 hours, and 47 minutes.
diff1 = date2.Subtract(date1)

Dim date4 As System.DateTime
' date4 gets 4/9/1996 5:55:00 PM.
date4 = date3.Subtract(diff1)

Dim diff2 As System.TimeSpan
' diff2 gets 55 days 4 hours and 20 minutes.
diff2 = System.DateTime.op_Subtraction(date2, date3)

Dim date5 As System.DateTime
' date5 gets 4/9/1996 5:55:00 PM.
date5 = System.DateTime.op_Subtraction(date1, diff2)

Comentarios

El Subtraction(DateTime, DateTime) método no tiene en cuenta el valor de la Kind propiedad de los dos DateTime valores al realizar la resta.The Subtraction(DateTime, DateTime) method does not consider the value of the Kind property of the two DateTime values when performing the subtraction. Antes de restar DateTime objetos, asegúrese de que los objetos representan horas en la misma zona horaria.Before subtracting DateTime objects, ensure that the objects represent times in the same time zone. En caso contrario, el resultado incluirá la diferencia entre zonas horarias.Otherwise, the result will include the difference between time zones.

Nota

El DateTimeOffset.Subtraction(DateTimeOffset, DateTimeOffset) método tiene en cuenta la diferencia entre las zonas horarias al realizar la resta.The DateTimeOffset.Subtraction(DateTimeOffset, DateTimeOffset) method does consider the difference between time zones when performing the subtraction.

Es el método equivalente para este operador DateTime.Subtract(DateTime)The equivalent method for this operator is DateTime.Subtract(DateTime)

Consulte también:

Se aplica a