# Enumerable.Sum Método

## Definición

Calcula la suma de una secuencia de valores numéricos.Computes the sum of a sequence of numeric values.

## Sum(IEnumerable<Nullable<Int32>>)

Calcula la suma de una secuencia de valores Int32 que aceptan valores NULL.Computes the sum of a sequence of nullable Int32 values.

``````public:
[System::Runtime::CompilerServices::Extension]
static Nullable<int> Sum(System::Collections::Generic::IEnumerable<Nullable<int>> ^ source);``````
``public static int? Sum (this System.Collections.Generic.IEnumerable<int?> source);``
``static member Sum : seq<Nullable<int>> -> Nullable<int>``
``````<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Integer))) As Nullable(Of Integer)``````

#### Parámetros

source
IEnumerable<Nullable<Int32>>

Secuencia de valores Int32 que aceptan valores NULL cuya suma se va a calcular.A sequence of nullable Int32 values to calculate the sum of.

#### Devoluciones

Nullable<Int32>

Suma de los valores de la secuencia.The sum of the values in the sequence.

#### Excepciones

`source` es `null`.`source` is `null`.

La suma es mayor que MaxValue.The sum is larger than MaxValue.

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

El resultado no incluye los valores que son `null` .The result does not include values that are `null`.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum(IEnumerable<Nullable<Single>>)

Calcula la suma de una secuencia de valores Single que aceptan valores NULL.Computes the sum of a sequence of nullable Single values.

``````public:
[System::Runtime::CompilerServices::Extension]
static Nullable<float> Sum(System::Collections::Generic::IEnumerable<Nullable<float>> ^ source);``````
``public static float? Sum (this System.Collections.Generic.IEnumerable<float?> source);``
``static member Sum : seq<Nullable<single>> -> Nullable<single>``
``````<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Single))) As Nullable(Of Single)``````

#### Parámetros

source
IEnumerable<Nullable<Single>>

Secuencia de valores Single que aceptan valores NULL cuya suma se va a calcular.A sequence of nullable Single values to calculate the sum of.

#### Devoluciones

Nullable<Single>

Suma de los valores de la secuencia.The sum of the values in the sequence.

#### Excepciones

`source` es `null`.`source` is `null`.

### Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum(IEnumerable<Nullable<Single>>) para sumar los valores de una secuencia.The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

``````float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
This code produces the following output:

Total points earned: 311.39
*/
``````
``````' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
Console.WriteLine(\$"Total points earned: {sum}")

' This code produces the following output:
'
' Total points earned: 311.39
``````

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

El resultado no incluye los valores que son `null` .The result does not include values that are `null`.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum(IEnumerable<Nullable<Int64>>)

Calcula la suma de una secuencia de valores Int64 que aceptan valores NULL.Computes the sum of a sequence of nullable Int64 values.

``````public:
[System::Runtime::CompilerServices::Extension]
static Nullable<long> Sum(System::Collections::Generic::IEnumerable<Nullable<long>> ^ source);``````
``public static long? Sum (this System.Collections.Generic.IEnumerable<long?> source);``
``static member Sum : seq<Nullable<int64>> -> Nullable<int64>``
``````<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Long))) As Nullable(Of Long)``````

#### Parámetros

source
IEnumerable<Nullable<Int64>>

Secuencia de valores Int64 que aceptan valores NULL cuya suma se va a calcular.A sequence of nullable Int64 values to calculate the sum of.

#### Devoluciones

Nullable<Int64>

Suma de los valores de la secuencia.The sum of the values in the sequence.

#### Excepciones

`source` es `null`.`source` is `null`.

La suma es mayor que MaxValue.The sum is larger than MaxValue.

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

El resultado no incluye los valores que son `null` .The result does not include values that are `null`.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum(IEnumerable<Single>)

Calcula la suma de una secuencia de valores Single.Computes the sum of a sequence of Single values.

``````public:
[System::Runtime::CompilerServices::Extension]
static float Sum(System::Collections::Generic::IEnumerable<float> ^ source);``````
``public static float Sum (this System.Collections.Generic.IEnumerable<float> source);``
``static member Sum : seq<single> -> single``
``````<Extension()>
Public Function Sum (source As IEnumerable(Of Single)) As Single``````

#### Parámetros

source
IEnumerable<Single>

Secuencia de valores Single cuya suma se va a calcular.A sequence of Single values to calculate the sum of.

#### Devoluciones

Single

Suma de los valores de la secuencia.The sum of the values in the sequence.

#### Excepciones

`source` es `null`.`source` is `null`.

### Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum(IEnumerable<Single>) para sumar los valores de una secuencia.The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

``````List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
This code produces the following output:

The sum of the numbers is 635.13.
*/
``````
``````' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
{43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
Console.WriteLine(\$"The sum of the numbers is {sum}")

' This code produces the following output:
'
' The sum of the numbers is 635.13
``````

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum(IEnumerable<Nullable<Double>>)

Calcula la suma de una secuencia de valores Double que aceptan valores NULL.Computes the sum of a sequence of nullable Double values.

``````public:
[System::Runtime::CompilerServices::Extension]
static Nullable<double> Sum(System::Collections::Generic::IEnumerable<Nullable<double>> ^ source);``````
``public static double? Sum (this System.Collections.Generic.IEnumerable<double?> source);``
``static member Sum : seq<Nullable<double>> -> Nullable<double>``
``````<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Double))) As Nullable(Of Double)``````

#### Parámetros

source
IEnumerable<Nullable<Double>>

Secuencia de valores Double que aceptan valores NULL cuya suma se va a calcular.A sequence of nullable Double values to calculate the sum of.

#### Devoluciones

Nullable<Double>

Suma de los valores de la secuencia.The sum of the values in the sequence.

#### Excepciones

`source` es `null`.`source` is `null`.

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

El resultado no incluye los valores que son `null` .The result does not include values that are `null`.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum(IEnumerable<Int32>)

Calcula la suma de una secuencia de valores Int32.Computes the sum of a sequence of Int32 values.

``````public:
[System::Runtime::CompilerServices::Extension]
static int Sum(System::Collections::Generic::IEnumerable<int> ^ source);``````
``public static int Sum (this System.Collections.Generic.IEnumerable<int> source);``
``static member Sum : seq<int> -> int``
``````<Extension()>
Public Function Sum (source As IEnumerable(Of Integer)) As Integer``````

#### Parámetros

source
IEnumerable<Int32>

Secuencia de valores Int32 cuya suma se va a calcular.A sequence of Int32 values to calculate the sum of.

#### Devoluciones

Int32

Suma de los valores de la secuencia.The sum of the values in the sequence.

#### Excepciones

`source` es `null`.`source` is `null`.

La suma es mayor que MaxValue.The sum is larger than MaxValue.

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum(IEnumerable<Int64>)

Calcula la suma de una secuencia de valores Int64.Computes the sum of a sequence of Int64 values.

``````public:
[System::Runtime::CompilerServices::Extension]
static long Sum(System::Collections::Generic::IEnumerable<long> ^ source);``````
``public static long Sum (this System.Collections.Generic.IEnumerable<long> source);``
``static member Sum : seq<int64> -> int64``
``````<Extension()>
Public Function Sum (source As IEnumerable(Of Long)) As Long``````

#### Parámetros

source
IEnumerable<Int64>

Secuencia de valores Int64 cuya suma se va a calcular.A sequence of Int64 values to calculate the sum of.

#### Devoluciones

Int64

Suma de los valores de la secuencia.The sum of the values in the sequence.

#### Excepciones

`source` es `null`.`source` is `null`.

La suma es mayor que MaxValue.The sum is larger than MaxValue.

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum(IEnumerable<Double>)

Calcula la suma de una secuencia de valores Double.Computes the sum of a sequence of Double values.

``````public:
[System::Runtime::CompilerServices::Extension]
static double Sum(System::Collections::Generic::IEnumerable<double> ^ source);``````
``public static double Sum (this System.Collections.Generic.IEnumerable<double> source);``
``static member Sum : seq<double> -> double``
``````<Extension()>
Public Function Sum (source As IEnumerable(Of Double)) As Double``````

#### Parámetros

source
IEnumerable<Double>

Secuencia de valores Double cuya suma se va a calcular.A sequence of Double values to calculate the sum of.

#### Devoluciones

Double

Suma de los valores de la secuencia.The sum of the values in the sequence.

#### Excepciones

`source` es `null`.`source` is `null`.

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum(IEnumerable<Decimal>)

Calcula la suma de una secuencia de valores Decimal.Computes the sum of a sequence of Decimal values.

``````public:
[System::Runtime::CompilerServices::Extension]
static System::Decimal Sum(System::Collections::Generic::IEnumerable<System::Decimal> ^ source);``````
``public static decimal Sum (this System.Collections.Generic.IEnumerable<decimal> source);``
``static member Sum : seq<decimal> -> decimal``
``````<Extension()>
Public Function Sum (source As IEnumerable(Of Decimal)) As Decimal``````

#### Parámetros

source
IEnumerable<Decimal>

Secuencia de valores Decimal cuya suma se va a calcular.A sequence of Decimal values to calculate the sum of.

#### Devoluciones

Decimal

Suma de los valores de la secuencia.The sum of the values in the sequence.

#### Excepciones

`source` es `null`.`source` is `null`.

La suma es mayor que MaxValue.The sum is larger than MaxValue.

### Comentarios

El Sum(IEnumerable<Decimal>) método devuelve cero si `source` no contiene ningún elemento.The Sum(IEnumerable<Decimal>) method returns zero if `source` contains no elements.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum(IEnumerable<Nullable<Decimal>>)

Calcula la suma de una secuencia de valores Decimal que aceptan valores NULL.Computes the sum of a sequence of nullable Decimal values.

``````public:
[System::Runtime::CompilerServices::Extension]
static Nullable<System::Decimal> Sum(System::Collections::Generic::IEnumerable<Nullable<System::Decimal>> ^ source);``````
``public static decimal? Sum (this System.Collections.Generic.IEnumerable<decimal?> source);``
``static member Sum : seq<Nullable<decimal>> -> Nullable<decimal>``
``````<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Decimal))) As Nullable(Of Decimal)``````

#### Parámetros

source
IEnumerable<Nullable<Decimal>>

Secuencia de valores Decimal que aceptan valores NULL cuya suma se va a calcular.A sequence of nullable Decimal values to calculate the sum of.

#### Devoluciones

Nullable<Decimal>

Suma de los valores de la secuencia.The sum of the values in the sequence.

#### Excepciones

`source` es `null`.`source` is `null`.

La suma es mayor que MaxValue.The sum is larger than MaxValue.

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

El resultado no incluir valores que son `null` .The result doesnot include values that are `null`.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>)

Calcula la suma de una secuencia de valores Single que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of Single values that are obtained by invoking a transform function on each element of the input sequence.

``````public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static float Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, float> ^ selector);``````
``public static float Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,float> selector);``
``static member Sum : seq<'Source> * Func<'Source, single> -> single``
``````<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Single)) As Single``````

#### Parámetros de tipo

TSource

Tipo de los elementos de `source`.The type of the elements of `source`.

#### Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Single>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

#### Devoluciones

Single

Suma de los valores proyectados.The sum of the projected values.

#### Excepciones

`source` o `selector` es `null`.`source` or `selector` is `null`.

### Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función `selector`.To extend the example to this topic, change the body of the `selector` function.

``````class Package
{
public string Company { get; set; }
public double Weight { get; set; }
}

public static void SumEx1()
{
List<Package> packages =
new List<Package>
{ new Package { Company = "Coho Vineyard", Weight = 25.2 },
new Package { Company = "Lucerne Publishing", Weight = 18.7 },
new Package { Company = "Wingtip Toys", Weight = 6.0 },
new Package { Company = "Adventure Works", Weight = 33.8 } };

double totalWeight = packages.Sum(pkg => pkg.Weight);

Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
This code produces the following output:

The total weight of the packages is: 83.7
*/
``````
``````Structure Package
Public Company As String
Public Weight As Double
End Structure

Sub SumEx1()
' Create a list of Package values.
Dim packages As New List(Of Package)(New Package() _
{New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
New Package With {.Company = "Adventure Works", .Weight = 33.8}})

' Sum the values from each item's Weight property.
Dim totalWeight As Double = packages.Sum(Function(pkg) _
pkg.Weight)

' Display the result.
Console.WriteLine(\$"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7
``````

### Comentarios

El Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) método devuelve cero si `source` no contiene ningún elemento.The Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) method returns zero if `source` contains no elements.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, `selector` , que proyecta los miembros de `source` en un tipo numérico, en concreto Single .You can apply this method to a sequence of arbitrary values if you provide a function, `selector`, that projects the members of `source` into a numeric type, specifically Single.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>)

Calcula la suma de una secuencia de valores Single que aceptan valores NULL que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of nullable Single values that are obtained by invoking a transform function on each element of the input sequence.

``````public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static Nullable<float> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<float>> ^ selector);``````
``public static float? Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,float?> selector);``
``static member Sum : seq<'Source> * Func<'Source, Nullable<single>> -> Nullable<single>``
``````<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Single))) As Nullable(Of Single)``````

#### Parámetros de tipo

TSource

Tipo de los elementos de `source`.The type of the elements of `source`.

#### Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Single>>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

#### Devoluciones

Nullable<Single>

Suma de los valores proyectados.The sum of the projected values.

#### Excepciones

`source` o `selector` es `null`.`source` or `selector` is `null`.

### Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función `selector`.To extend the example to this topic, change the body of the `selector` function.

``````class Package
{
public string Company { get; set; }
public double Weight { get; set; }
}

public static void SumEx1()
{
List<Package> packages =
new List<Package>
{ new Package { Company = "Coho Vineyard", Weight = 25.2 },
new Package { Company = "Lucerne Publishing", Weight = 18.7 },
new Package { Company = "Wingtip Toys", Weight = 6.0 },
new Package { Company = "Adventure Works", Weight = 33.8 } };

double totalWeight = packages.Sum(pkg => pkg.Weight);

Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
This code produces the following output:

The total weight of the packages is: 83.7
*/
``````
``````Structure Package
Public Company As String
Public Weight As Double
End Structure

Sub SumEx1()
' Create a list of Package values.
Dim packages As New List(Of Package)(New Package() _
{New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
New Package With {.Company = "Adventure Works", .Weight = 33.8}})

' Sum the values from each item's Weight property.
Dim totalWeight As Double = packages.Sum(Function(pkg) _
pkg.Weight)

' Display the result.
Console.WriteLine(\$"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7
``````

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

El resultado no incluye los valores que son `null` .The result does not include values that are `null`.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, `selector` , que proyecta los miembros de `source` en un tipo numérico, específicamente `Nullable<Single>` en C# o `Nullable(Of Single)` en Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, `selector`, that projects the members of `source` into a numeric type, specifically `Nullable<Single>` in C# or `Nullable(Of Single)` in Visual Basic.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>)

Calcula la suma de una secuencia de valores Int64 que aceptan valores NULL que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of nullable Int64 values that are obtained by invoking a transform function on each element of the input sequence.

``````public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static Nullable<long> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<long>> ^ selector);``````
``public static long? Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,long?> selector);``
``static member Sum : seq<'Source> * Func<'Source, Nullable<int64>> -> Nullable<int64>``
``````<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Long))) As Nullable(Of Long)``````

#### Parámetros de tipo

TSource

Tipo de los elementos de `source`.The type of the elements of `source`.

#### Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Int64>>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

#### Devoluciones

Nullable<Int64>

Suma de los valores proyectados.The sum of the projected values.

#### Excepciones

`source` o `selector` es `null`.`source` or `selector` is `null`.

La suma es mayor que MaxValue.The sum is larger than MaxValue.

### Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función `selector`.To extend the example to this topic, change the body of the `selector` function.

``````class Package
{
public string Company { get; set; }
public double Weight { get; set; }
}

public static void SumEx1()
{
List<Package> packages =
new List<Package>
{ new Package { Company = "Coho Vineyard", Weight = 25.2 },
new Package { Company = "Lucerne Publishing", Weight = 18.7 },
new Package { Company = "Wingtip Toys", Weight = 6.0 },
new Package { Company = "Adventure Works", Weight = 33.8 } };

double totalWeight = packages.Sum(pkg => pkg.Weight);

Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
This code produces the following output:

The total weight of the packages is: 83.7
*/
``````
``````Structure Package
Public Company As String
Public Weight As Double
End Structure

Sub SumEx1()
' Create a list of Package values.
Dim packages As New List(Of Package)(New Package() _
{New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
New Package With {.Company = "Adventure Works", .Weight = 33.8}})

' Sum the values from each item's Weight property.
Dim totalWeight As Double = packages.Sum(Function(pkg) _
pkg.Weight)

' Display the result.
Console.WriteLine(\$"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7
``````

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

El resultado no incluye los valores que son `null` .The result does not include values that are `null`.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, `selector` , que proyecta los miembros de `source` en un tipo numérico, específicamente `Nullable<Int64>` en C# o `Nullable(Of Int64)` en Visual BasicYou can apply this method to a sequence of arbitrary values if you provide a function, `selector`, that projects the members of `source` into a numeric type, specifically `Nullable<Int64>` in C# or `Nullable(Of Int64)` in Visual Basic

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>)

Calcula la suma de una secuencia de valores Int32 que aceptan valores NULL que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of nullable Int32 values that are obtained by invoking a transform function on each element of the input sequence.

``````public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static Nullable<int> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<int>> ^ selector);``````
``public static int? Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,int?> selector);``
``static member Sum : seq<'Source> * Func<'Source, Nullable<int>> -> Nullable<int>``
``````<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Integer))) As Nullable(Of Integer)``````

#### Parámetros de tipo

TSource

Tipo de los elementos de `source`.The type of the elements of `source`.

#### Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Int32>>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

#### Devoluciones

Nullable<Int32>

Suma de los valores proyectados.The sum of the projected values.

#### Excepciones

`source` o `selector` es `null`.`source` or `selector` is `null`.

La suma es mayor que MaxValue.The sum is larger than MaxValue.

### Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función `selector`.To extend the example to this topic, change the body of the `selector` function.

``````class Package
{
public string Company { get; set; }
public double Weight { get; set; }
}

public static void SumEx1()
{
List<Package> packages =
new List<Package>
{ new Package { Company = "Coho Vineyard", Weight = 25.2 },
new Package { Company = "Lucerne Publishing", Weight = 18.7 },
new Package { Company = "Wingtip Toys", Weight = 6.0 },
new Package { Company = "Adventure Works", Weight = 33.8 } };

double totalWeight = packages.Sum(pkg => pkg.Weight);

Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
This code produces the following output:

The total weight of the packages is: 83.7
*/
``````
``````Structure Package
Public Company As String
Public Weight As Double
End Structure

Sub SumEx1()
' Create a list of Package values.
Dim packages As New List(Of Package)(New Package() _
{New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
New Package With {.Company = "Adventure Works", .Weight = 33.8}})

' Sum the values from each item's Weight property.
Dim totalWeight As Double = packages.Sum(Function(pkg) _
pkg.Weight)

' Display the result.
Console.WriteLine(\$"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7
``````

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

El resultado no incluye los valores que son `null` .The result does not include values that are `null`.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, `selector` , que proyecta los miembros de `source` en un tipo numérico, específicamente `Nullable<Int32>` en C# o `Nullable(Of Int32)` en Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, `selector`, that projects the members of `source` into a numeric type, specifically `Nullable<Int32>` in C# or `Nullable(Of Int32)` in Visual Basic.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>)

Calcula la suma de una secuencia de valores Double que aceptan valores NULL que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of nullable Double values that are obtained by invoking a transform function on each element of the input sequence.

``````public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static Nullable<double> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<double>> ^ selector);``````
``public static double? Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,double?> selector);``
``static member Sum : seq<'Source> * Func<'Source, Nullable<double>> -> Nullable<double>``
``````<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Double))) As Nullable(Of Double)``````

#### Parámetros de tipo

TSource

Tipo de los elementos de `source`.The type of the elements of `source`.

#### Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Double>>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

#### Devoluciones

Nullable<Double>

Suma de los valores proyectados.The sum of the projected values.

#### Excepciones

`source` o `selector` es `null`.`source` or `selector` is `null`.

### Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función `selector`.To extend the example to this topic, change the body of the `selector` function.

``````class Package
{
public string Company { get; set; }
public double Weight { get; set; }
}

public static void SumEx1()
{
List<Package> packages =
new List<Package>
{ new Package { Company = "Coho Vineyard", Weight = 25.2 },
new Package { Company = "Lucerne Publishing", Weight = 18.7 },
new Package { Company = "Wingtip Toys", Weight = 6.0 },
new Package { Company = "Adventure Works", Weight = 33.8 } };

double totalWeight = packages.Sum(pkg => pkg.Weight);

Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
This code produces the following output:

The total weight of the packages is: 83.7
*/
``````
``````Structure Package
Public Company As String
Public Weight As Double
End Structure

Sub SumEx1()
' Create a list of Package values.
Dim packages As New List(Of Package)(New Package() _
{New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
New Package With {.Company = "Adventure Works", .Weight = 33.8}})

' Sum the values from each item's Weight property.
Dim totalWeight As Double = packages.Sum(Function(pkg) _
pkg.Weight)

' Display the result.
Console.WriteLine(\$"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7
``````

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

El resultado no incluye los valores que son `null` .The result does not include values that are `null`.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, `selector` , que proyecta los miembros de `source` en un tipo numérico, específicamente `Nullable<Double>` en C# o `Nullable(Of Double)` en Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, `selector`, that projects the members of `source` into a numeric type, specifically `Nullable<Double>` in C# or `Nullable(Of Double)` in Visual Basic.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>)

Calcula la suma de una secuencia de valores Decimal que aceptan valores NULL que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of nullable Decimal values that are obtained by invoking a transform function on each element of the input sequence.

``````public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static Nullable<System::Decimal> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<System::Decimal>> ^ selector);``````
``public static decimal? Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,decimal?> selector);``
``static member Sum : seq<'Source> * Func<'Source, Nullable<decimal>> -> Nullable<decimal>``
``````<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Decimal))) As Nullable(Of Decimal)``````

#### Parámetros de tipo

TSource

Tipo de los elementos de `source`.The type of the elements of `source`.

#### Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Decimal>>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

#### Devoluciones

Nullable<Decimal>

Suma de los valores proyectados.The sum of the projected values.

#### Excepciones

`source` o `selector` es `null`.`source` or `selector` is `null`.

La suma es mayor que MaxValue.The sum is larger than MaxValue.

### Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función `selector`.To extend the example to this topic, change the body of the `selector` function.

``````class Package
{
public string Company { get; set; }
public double Weight { get; set; }
}

public static void SumEx1()
{
List<Package> packages =
new List<Package>
{ new Package { Company = "Coho Vineyard", Weight = 25.2 },
new Package { Company = "Lucerne Publishing", Weight = 18.7 },
new Package { Company = "Wingtip Toys", Weight = 6.0 },
new Package { Company = "Adventure Works", Weight = 33.8 } };

double totalWeight = packages.Sum(pkg => pkg.Weight);

Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
This code produces the following output:

The total weight of the packages is: 83.7
*/
``````
``````Structure Package
Public Company As String
Public Weight As Double
End Structure

Sub SumEx1()
' Create a list of Package values.
Dim packages As New List(Of Package)(New Package() _
{New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
New Package With {.Company = "Adventure Works", .Weight = 33.8}})

' Sum the values from each item's Weight property.
Dim totalWeight As Double = packages.Sum(Function(pkg) _
pkg.Weight)

' Display the result.
Console.WriteLine(\$"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7
``````

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

El resultado no incluye los valores que son `null` .The result does not included values that are `null`.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, `selector` , que proyecta los miembros de `source` en un tipo numérico, específicamente `Nullable<Decimal>` en C# o `Nullable(Of Decimal)` en Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, `selector`, that projects the members of `source` into a numeric type, specifically `Nullable<Decimal>` in C# or `Nullable(Of Decimal)` in Visual Basic.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>)

Calcula la suma de una secuencia de valores Int64 que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of Int64 values that are obtained by invoking a transform function on each element of the input sequence.

``````public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static long Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, long> ^ selector);``````
``public static long Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,long> selector);``
``static member Sum : seq<'Source> * Func<'Source, int64> -> int64``
``````<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Long)) As Long``````

#### Parámetros de tipo

TSource

Tipo de los elementos de `source`.The type of the elements of `source`.

#### Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Int64>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

#### Devoluciones

Int64

Suma de los valores proyectados.The sum of the projected values.

#### Excepciones

`source` o `selector` es `null`.`source` or `selector` is `null`.

La suma es mayor que MaxValue.The sum is larger than MaxValue.

### Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función `selector`.To extend the example to this topic, change the body of the `selector` function.

``````class Package
{
public string Company { get; set; }
public double Weight { get; set; }
}

public static void SumEx1()
{
List<Package> packages =
new List<Package>
{ new Package { Company = "Coho Vineyard", Weight = 25.2 },
new Package { Company = "Lucerne Publishing", Weight = 18.7 },
new Package { Company = "Wingtip Toys", Weight = 6.0 },
new Package { Company = "Adventure Works", Weight = 33.8 } };

double totalWeight = packages.Sum(pkg => pkg.Weight);

Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
This code produces the following output:

The total weight of the packages is: 83.7
*/
``````
``````Structure Package
Public Company As String
Public Weight As Double
End Structure

Sub SumEx1()
' Create a list of Package values.
Dim packages As New List(Of Package)(New Package() _
{New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
New Package With {.Company = "Adventure Works", .Weight = 33.8}})

' Sum the values from each item's Weight property.
Dim totalWeight As Double = packages.Sum(Function(pkg) _
pkg.Weight)

' Display the result.
Console.WriteLine(\$"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7
``````

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, `selector` , que proyecta los miembros de `source` en un tipo numérico, en concreto Int64 .You can apply this method to a sequence of arbitrary values if you provide a function, `selector`, that projects the members of `source` into a numeric type, specifically Int64.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>)

Calcula la suma de una secuencia de valores Int32 que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of Int32 values that are obtained by invoking a transform function on each element of the input sequence.

``````public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static int Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, int> ^ selector);``````
``public static int Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,int> selector);``
``static member Sum : seq<'Source> * Func<'Source, int> -> int``
``````<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Integer)) As Integer``````

#### Parámetros de tipo

TSource

Tipo de los elementos de `source`.The type of the elements of `source`.

#### Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Int32>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

#### Devoluciones

Int32

Suma de los valores proyectados.The sum of the projected values.

#### Excepciones

`source` o `selector` es `null`.`source` or `selector` is `null`.

La suma es mayor que MaxValue.The sum is larger than MaxValue.

### Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función `selector`.To extend the example to this topic, change the body of the `selector` function.

``````class Package
{
public string Company { get; set; }
public double Weight { get; set; }
}

public static void SumEx1()
{
List<Package> packages =
new List<Package>
{ new Package { Company = "Coho Vineyard", Weight = 25.2 },
new Package { Company = "Lucerne Publishing", Weight = 18.7 },
new Package { Company = "Wingtip Toys", Weight = 6.0 },
new Package { Company = "Adventure Works", Weight = 33.8 } };

double totalWeight = packages.Sum(pkg => pkg.Weight);

Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
This code produces the following output:

The total weight of the packages is: 83.7
*/
``````
``````Structure Package
Public Company As String
Public Weight As Double
End Structure

Sub SumEx1()
' Create a list of Package values.
Dim packages As New List(Of Package)(New Package() _
{New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
New Package With {.Company = "Adventure Works", .Weight = 33.8}})

' Sum the values from each item's Weight property.
Dim totalWeight As Double = packages.Sum(Function(pkg) _
pkg.Weight)

' Display the result.
Console.WriteLine(\$"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7
``````

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, `selector` , que proyecta los miembros de `source` en un tipo numérico, en concreto Int32 .You can apply this method to a sequence of arbitrary values if you provide a function, `selector`, that projects the members of `source` into a numeric type, specifically Int32.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)

Calcula la suma de una secuencia de valores Double que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of Double values that are obtained by invoking a transform function on each element of the input sequence.

``````public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static double Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, double> ^ selector);``````
``public static double Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,double> selector);``
``static member Sum : seq<'Source> * Func<'Source, double> -> double``
``````<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Double)) As Double``````

#### Parámetros de tipo

TSource

Tipo de los elementos de `source`.The type of the elements of `source`.

#### Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Double>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

#### Devoluciones

Double

Suma de los valores proyectados.The sum of the projected values.

#### Excepciones

`source` o `selector` es `null`.`source` or `selector` is `null`.

### Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

``````class Package
{
public string Company { get; set; }
public double Weight { get; set; }
}

public static void SumEx1()
{
List<Package> packages =
new List<Package>
{ new Package { Company = "Coho Vineyard", Weight = 25.2 },
new Package { Company = "Lucerne Publishing", Weight = 18.7 },
new Package { Company = "Wingtip Toys", Weight = 6.0 },
new Package { Company = "Adventure Works", Weight = 33.8 } };

double totalWeight = packages.Sum(pkg => pkg.Weight);

Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
This code produces the following output:

The total weight of the packages is: 83.7
*/
``````
``````Structure Package
Public Company As String
Public Weight As Double
End Structure

Sub SumEx1()
' Create a list of Package values.
Dim packages As New List(Of Package)(New Package() _
{New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
New Package With {.Company = "Adventure Works", .Weight = 33.8}})

' Sum the values from each item's Weight property.
Dim totalWeight As Double = packages.Sum(Function(pkg) _
pkg.Weight)

' Display the result.
Console.WriteLine(\$"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7
``````

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, `selector` , que proyecta los miembros de `source` en un tipo numérico, en concreto Double .You can apply this method to a sequence of arbitrary values if you provide a function, `selector`, that projects the members of `source` into a numeric type, specifically Double.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.

## Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>)

Calcula la suma de una secuencia de valores Decimal que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of Decimal values that are obtained by invoking a transform function on each element of the input sequence.

``````public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static System::Decimal Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, System::Decimal> ^ selector);``````
``public static decimal Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,decimal> selector);``
``static member Sum : seq<'Source> * Func<'Source, decimal> -> decimal``
``````<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Decimal)) As Decimal``````

#### Parámetros de tipo

TSource

Tipo de los elementos de `source`.The type of the elements of `source`.

#### Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Decimal>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

#### Devoluciones

Decimal

Suma de los valores proyectados.The sum of the projected values.

#### Excepciones

`source` o `selector` es `null`.`source` or `selector` is `null`.

La suma es mayor que MaxValue.The sum is larger than MaxValue.

### Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función `selector`.To extend the example to this topic, change the body of the `selector` function.

``````class Package
{
public string Company { get; set; }
public double Weight { get; set; }
}

public static void SumEx1()
{
List<Package> packages =
new List<Package>
{ new Package { Company = "Coho Vineyard", Weight = 25.2 },
new Package { Company = "Lucerne Publishing", Weight = 18.7 },
new Package { Company = "Wingtip Toys", Weight = 6.0 },
new Package { Company = "Adventure Works", Weight = 33.8 } };

double totalWeight = packages.Sum(pkg => pkg.Weight);

Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
This code produces the following output:

The total weight of the packages is: 83.7
*/
``````
``````Structure Package
Public Company As String
Public Weight As Double
End Structure

Sub SumEx1()
' Create a list of Package values.
Dim packages As New List(Of Package)(New Package() _
{New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
New Package With {.Company = "Adventure Works", .Weight = 33.8}})

' Sum the values from each item's Weight property.
Dim totalWeight As Double = packages.Sum(Function(pkg) _
pkg.Weight)

' Display the result.
Console.WriteLine(\$"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7
``````

### Comentarios

Este método devuelve cero si `source` no contiene ningún elemento.This method returns zero if `source` contains no elements.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, `selector` , que proyecta los miembros de `source` en un tipo numérico, en concreto Decimal .You can apply this method to a sequence of arbitrary values if you provide a function, `selector`, that projects the members of `source` into a numeric type, specifically Decimal.

En Visual Basic sintaxis de expresiones de consulta, una `Aggregate Into Sum()` cláusula se convierte en una invocación de Sum .In Visual Basic query expression syntax, an `Aggregate Into Sum()` clause translates to an invocation of Sum.