Tuple<T1,T2,T3,T4>.Item3 Tuple<T1,T2,T3,T4>.Item3 Tuple<T1,T2,T3,T4>.Item3 Tuple<T1,T2,T3,T4>.Item3 Property

Definición

Obtiene el valor del tercer componente del objeto Tuple<T1,T2,T3,T4> actual.Gets the value of the current Tuple<T1,T2,T3,T4> object's third component.

public:
 property T3 Item3 { T3 get(); };
public T3 Item3 { get; }
member this.Item3 : 'T3
Public ReadOnly Property Item3 As T3

Valor de propiedad

T3 T3 T3 T3

Valor del tercer componente del objeto Tuple<T1,T2,T3,T4> actual.The value of the current Tuple<T1,T2,T3,T4> object's third component.

Ejemplos

En el ejemplo siguiente se define una Tuple<T1,T2,T3,T4> matriz de objetos cuyos componentes contienen el nombre de una ciudad, un mes del año y el promedio de temperaturas máxima y mínima para ese mes.The following example defines an array of Tuple<T1,T2,T3,T4> objects whose components contain the name of a city, a month of the year, and the average high and low temperatures for that month. A continuación, recupera y muestra el valor de cada componente.It then retrieves and displays the value of each component.

using System;
using System.Globalization;

public class Example
{
   public static void Main()
   {
      Tuple<string, int, double, double>[] temperatures = 
            { Tuple.Create("New York, NY", 4, 61.0, 43.0),
              Tuple.Create("Chicago, IL", 2, 34.0, 18.0), 
              Tuple.Create("Newark, NJ", 4, 61.0, 43.0),
              Tuple.Create("Boston, MA", 6, 77.0, 59.0),
              Tuple.Create("Detroit, MI", 9, 74.0, 53.0),
              Tuple.Create("Minneapolis, MN", 8, 81.0, 61.0) }; 
      // Display the array of 4-tuple objects.
      Console.WriteLine("{0,41}", "Temperatures");
      Console.WriteLine("{0,-20} {1,5}    {2,4}  {3,4}\n", 
                        "City", "Month", "High", "Low");
      foreach (var temperature in temperatures)
         Console.WriteLine("{0,-20} {1,5}    {2,4:N1}  {3,4:N1}", 
                           temperature.Item1, 
                           DateTimeFormatInfo.CurrentInfo.GetAbbreviatedMonthName(temperature.Item2 - 1), 
                           temperature.Item3, temperature.Item4);
   }
}
// The example displays the following output:
//                                    Temperatures
//       City                 Month    High   Low
//       
//       New York, NY           Mar    61.0  43.0
//       Chicago, IL            Jan    34.0  18.0
//       Newark, NJ             Mar    61.0  43.0
//       Boston, MA             May    77.0  59.0
//       Detroit, MI            Aug    74.0  53.0
//       Minneapolis, MN        Jul    81.0  61.0
Imports System.Globalization

Module Example
   Public Sub Main()
      Dim temperatures() = 
             { Tuple.Create("New York, NY", 4, 61, 43), _
               Tuple.Create("Chicago, IL", 2, 34, 18), _ 
               Tuple.Create("Newark, NJ", 4, 61, 43), _
               Tuple.Create("Boston, MA", 6, 77, 59), _
               Tuple.Create("Detroit, MI", 9, 74, 53), _
               Tuple.Create("Minneapolis, MN", 8, 81, 61) } 
      ' Display the array of 4-tuples.
      Console.WriteLine("{0,41}", "Temperatures")
      Console.WriteLine("{0,-20} {1,5}    {2,4}  {3,4}", 
                        "City", "Month", "High", "Low")
      Console.WriteLine()
      For Each temperature In temperatures
         Console.WriteLine("{0,-20} {1,5}    {2,4:N1}  {3,4:N1}", 
                           temperature.Item1, 
                           DateTimeFormatInfo.CurrentInfo.GetAbbreviatedMonthName(temperature.Item2 - 1), 
                           temperature.Item3, temperature.Item4)
      Next
   End Sub
End Module
' The example displays the following output:
'                                    Temperatures
'       City                 Month    High   Low
'       
'       New York, NY           Mar    61.0  43.0
'       Chicago, IL            Jan    34.0  18.0
'       Newark, NJ             Mar    61.0  43.0
'       Boston, MA             May    77.0  59.0
'       Detroit, MI            Aug    74.0  53.0
'       Minneapolis, MN        Jul    81.0  61.0

Comentarios

Puede determinar de forma dinámica el tipo de Item3 componente de una de estas dos maneras:You can dynamically determine the type of the Item3 component in one of two ways:

Se aplica a