ContainerControl.IContainerControl.ActivateControl(Control) ContainerControl.IContainerControl.ActivateControl(Control) Method

Definición

Activa el control especificado.Activates the specified control.

 virtual bool System.Windows.Forms.IContainerControl.ActivateControl(System::Windows::Forms::Control ^ control) = System::Windows::Forms::IContainerControl::ActivateControl;
bool IContainerControl.ActivateControl (System.Windows.Forms.Control control);

Parámetros

control
Control Control

Control que se va a activar.The Control to activate.

Devoluciones

true si el control se activa correctamente; en caso contrario, false.true if the control is successfully activated; otherwise, false.

Implementaciones

Ejemplos

El código siguiente muestra cómo heredar de la ScrollableControl clase e implemente el IContainerControl interfaz.The following code example demonstrates how to inherit from the ScrollableControl class and implement the IContainerControl interface. Se agrega a la implementación del ActiveControl propiedad y el ActivateControl método.Implementation is added to the ActiveControl property and the ActivateControl method.

using namespace System;
using namespace System::Windows::Forms;
using namespace System::Drawing;

public ref class MyContainer: public ScrollableControl, public IContainerControl
{
private:
   Control^ activeControl;

public:
   MyContainer()
   {
      // Make the container control Blue so it can be distinguished on the form.
      this->BackColor = Color::Blue;

      // Make the container scrollable.
      this->AutoScroll = true;
   }

   property Control^ ActiveControl 
   {
      // Add implementation to the IContainerControl.ActiveControl property.
      virtual Control^ get()
      {
         return activeControl;
      }

      virtual void set( Control^ value )
      {
         
         // Make sure the control is a member of the ControlCollection.
         if ( this->Controls->Contains( value ) )
         {
            activeControl = value;
         }
      }
   }

   // Add implementations to the IContainerControl.ActivateControl(Control) method.
   virtual bool ActivateControl( Control^ active )
   {
      if ( this->Controls->Contains( active ) )
      {
         // Select the control and scroll the control into view if needed.
         active->Select(  );
         this->ScrollControlIntoView( active );
         this->activeControl = active;
         return true;
      }

      return false;
   }
};
using System;
using System.Windows.Forms;
using System.Drawing;

	public class MyContainer : ScrollableControl, IContainerControl
	{
		private Control activeControl;
		public MyContainer() 
		{
			// Make the container control Blue so it can be distinguished on the form.
			this.BackColor = Color.Blue;
			
			// Make the container scrollable.
			this.AutoScroll = true;
		}

		// Add implementation to the IContainerControl.ActiveControl property.
		public Control ActiveControl
		{
			get
			{
				return activeControl;
			}

			set
			{
				// Make sure the control is a member of the ControlCollection.
				if(this.Controls.Contains(value))
				{
					activeControl = value;
				}
			}
		}

		// Add implementations to the IContainerControl.ActivateControl(Control) method.
		public bool ActivateControl(Control active)
		{
			if(this.Controls.Contains(active))
			{
				// Select the control and scroll the control into view if needed.
				active.Select();
				this.ScrollControlIntoView(active);
				this.activeControl = active;
				return true;
			}
			return false;
		}
	}
Imports System
Imports System.Windows.Forms
Imports System.Drawing

   Public Class MyContainerControl
      Inherits ScrollableControl
      Implements IContainerControl 

      Private myActiveControl As Control
      
      Public Sub New()
         ' Make the container control Blue so it can be distinguished on the form.
         Me.BackColor = Color.Blue
         
         ' Make the container scrollable.
         Me.AutoScroll = True
      End Sub 
      
      ' Add implementation to the IContainerControl.ActiveControl property.
      Public Property ActiveControl() As Control Implements IContainerControl.ActiveControl
         Get
            Return Me.myActiveControl
         End Get
         
         Set
            ' Make sure the control is a member of the ControlCollection.
            If Me.Controls.Contains(value) Then
               Me.myActiveControl = value
            End If
         End Set
      End Property
      
      ' Add implementation to the IContainerControl.ActivateControl(Control) method.
      public Function ActivateControl(active As Control) As Boolean Implements IContainerControl.ActivateControl
         If Me.Controls.Contains(active) Then
            ' Select the control and scroll the control into view if needed.
            active.Select()
            Me.ScrollControlIntoView(active)
            Me.myActiveControl = active
            Return True
         End If
         Return False
      End Function 

   End Class  

Comentarios

El control parámetro debe ser un elemento secundario del control contenedor.The control parameter must be a child of the container control.

Se aplica a

Consulte también: