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Create Método

Crea una tabla en la instancia de SQL Server de acuerdo con la definición del objeto Table.

Espacio de nombres:  Microsoft.SqlServer.Management.Smo
Ensamblado:  Microsoft.SqlServer.Smo (en Microsoft.SqlServer.Smo.dll)

Sintaxis

'Declaración
Public Sub Create
'Uso
Dim instance As Table

instance.Create()

public void Create()

public:
virtual void Create() sealed

abstract Create : unit -> unit 
override Create : unit -> unit 

public final function Create()

Implementa

ICreatable. . :: . .Create() () () ()

Ejemplos

The following code example shows how to create a new table with the Create() method.

C#

Server srv = new Server("(local)");
Database db = srv.Databases["AdventureWorks2008R2"];

Table tb = new Table(db, "Test Table");
Column col1 = new Column(tb, "Name", DataType.NChar(50));
Column col2 = new Column(tb, "ID", DataType.Int);

tb.Columns.Add(col1); 
tb.Columns.Add(col2); 
tb.Create();

Console.WriteLine("The table was created on " + tb.CreateDate.ToString());

Powershell

$srv = new-Object Microsoft.SqlServer.Management.Smo.Server("(local)")
$db = New-Object Microsoft.SqlServer.Management.Smo.Database
$db = $srv.Databases.Item("AdventureWorks2008R2")

#Create the Table
$tb = new-object Microsoft.SqlServer.Management.Smo.Table($db, "Test Table")
$col1 = new-object Microsoft.SqlServer.Management.Smo.Column($tb, "Name", [Microsoft.SqlServer.Management.Smo.DataType]::NChar(50))
$col2 = new-object Microsoft.SqlServer.Management.Smo.Column($tb, "ID", [Microsoft.SqlServer.Management.Smo.DataType]::Int)
$tb.Columns.Add($col1)
$tb.Columns.Add($col2)
$tb.Create()