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  • Artículo

FileGroup Propiedad

Obtiene o establece el grupo de archivos donde se almacena la tabla.

Espacio de nombres:  Microsoft.SqlServer.Management.Smo
Ensamblado:  Microsoft.SqlServer.Smo (en Microsoft.SqlServer.Smo.dll)

Sintaxis

'Declaración
<SfcPropertyAttribute(SfcPropertyFlags.None Or SfcPropertyFlags.ReadOnlyAfterCreation Or SfcPropertyFlags.Standalone)> _
Public Property FileGroup As String
    Get
    Set
'Uso
Dim instance As Table
Dim value As String

value = instance.FileGroup

instance.FileGroup = value

[SfcPropertyAttribute(SfcPropertyFlags.None|SfcPropertyFlags.ReadOnlyAfterCreation|SfcPropertyFlags.Standalone)]
public string FileGroup { get; set; }

[SfcPropertyAttribute(SfcPropertyFlags::None|SfcPropertyFlags::ReadOnlyAfterCreation|SfcPropertyFlags::Standalone)]
public:
property String^ FileGroup {
    String^ get ();
    void set (String^ value);
}

[<SfcPropertyAttribute(SfcPropertyFlags.None|SfcPropertyFlags.ReadOnlyAfterCreation|SfcPropertyFlags.Standalone)>]
member FileGroup : string with get, set

function get FileGroup () : String
function set FileGroup (value : String)

Valor de la propiedad

Tipo: System. . :: . .String
Valor String que especifica el grupo de archivos donde se almacena la tabla.

Comentarios

The FileGroup property is set prior to the creation of the table. After the table is created, the property is read-only.

Ejemplos

The following code example shows how to create a new table and display the time and date that it was created on the console.

C#

Server srv = new Server("(local)");
Database db = srv.Databases["AdventureWorks2008R2"];

Table tb = new Table(db, "Test Table");
Column col1 = new Column(tb, "Name", DataType.NChar(50));
Column col2 = new Column(tb, "ID", DataType.Int);

tb.Columns.Add(col1); 
tb.Columns.Add(col2); 
tb.Create();

Console.WriteLine("The table is part of the " + tb.FileGroup.ToString() + " file group.");

Powershell

$srv = new-Object Microsoft.SqlServer.Management.Smo.Server("(local)")
$db = New-Object Microsoft.SqlServer.Management.Smo.Database
$db = $srv.Databases.Item("AdventureWorks2008R2")

#Create the Table
$tb = new-object Microsoft.SqlServer.Management.Smo.Table($db, "Test Table")
$col1 = new-object Microsoft.SqlServer.Management.Smo.Column($tb, "Name", [Microsoft.SqlServer.Management.Smo.DataType]::NChar(50))
$col2 = new-object Microsoft.SqlServer.Management.Smo.Column($tb, "ID", [Microsoft.SqlServer.Management.Smo.DataType]::Int)
$tb.Columns.Add($col1)
$tb.Columns.Add($col2)
$tb.Create()

Write-Host "The table is part of the" $tb.FileGroup "file group."