XmlSerializer.CanDeserialize(XmlReader) Méthode

Définition

Obtient une valeur qui indique si XmlSerializer peut désérialiser un document XML spécifié.Gets a value that indicates whether this XmlSerializer can deserialize a specified XML document.

public:
 virtual bool CanDeserialize(System::Xml::XmlReader ^ xmlReader);
public virtual bool CanDeserialize (System.Xml.XmlReader xmlReader);
abstract member CanDeserialize : System.Xml.XmlReader -> bool
override this.CanDeserialize : System.Xml.XmlReader -> bool

Paramètres

xmlReader
XmlReader

XmlReader qui pointe vers le document à désérialiser.An XmlReader that points to the document to deserialize.

Retours

true si ce XmlSerializer peut désérialiser l'objet vers lequel XmlReader pointe ; sinon, false.true if this XmlSerializer can deserialize the object that the XmlReader points to; otherwise, false.

Exemples

L’exemple suivant appelle la méthode CanDeserialize pour vérifier si un document XML peut être désérialisé.The following example calls the CanDeserialize method to check whether an XML document can be deserialized.

private:
   void TestDocument( String^ filename, Type^ objType )
   {
      // Using a FileStream, create an XmlTextReader.
      Stream^ fs = gcnew FileStream( filename,FileMode::Open );
      XmlReader^ reader = gcnew XmlTextReader( fs );
      XmlSerializer^ serializer = gcnew XmlSerializer( objType );
      if ( serializer->CanDeserialize( reader ) )
      {
         Object^ o = serializer->Deserialize( reader );
      }
      fs->Close();
   }
private void TestDocument(string filename, Type objType)
{
   // Using a FileStream, create an XmlTextReader.
   Stream fs = new FileStream(filename, FileMode.Open);
   XmlReader reader = new XmlTextReader(fs);
   XmlSerializer serializer = new XmlSerializer(objType);
   if(serializer.CanDeserialize(reader))
      {
         Object o = serializer.Deserialize(reader);
      }
   fs.Close();
}

Private Sub TestDocument _
                (ByVal filename As String, _
                 ByVal objType As Type)
    ' Using a FileStream, create an XmlTextReader.
    Dim fs As New FileStream(filename, FileMode.Open)
    Dim reader As New XmlTextReader(fs)
    Dim serializer As New XmlSerializer(objType)
    If serializer.CanDeserialize(reader) Then
        Dim o As Object = serializer.Deserialize(reader)
    End If
    fs.Close()
End Sub

S’applique à

Voir aussi