Math.Log Math.Log Math.Log Math.Log Method

Definizione

Restituisce il logaritmo del numero specificato.Returns the logarithm of a specified number.

Overload

Log(Double) Log(Double) Log(Double) Log(Double)

Restituisce il logaritmo naturale (in base e) di un numero specificato.Returns the natural (base e) logarithm of a specified number.

Log(Double, Double) Log(Double, Double) Log(Double, Double) Log(Double, Double)

Restituisce il logaritmo del numero specificato in una base specificata.Returns the logarithm of a specified number in a specified base.

Log(Double) Log(Double) Log(Double) Log(Double)

Restituisce il logaritmo naturale (in base e) di un numero specificato.Returns the natural (base e) logarithm of a specified number.

public:
 static double Log(double d);
public static double Log (double d);
static member Log : double -> double
Public Shared Function Log (d As Double) As Double

Parametri

d
Double Double Double Double

Numero di cui è necessario trovare il logaritmo.The number whose logarithm is to be found.

Restituisce

Uno dei valori della tabella seguente.One of the values in the following table.

Parametro d.d parameter Valore restituitoReturn value
PositivoPositive Logaritmo naturale di d: ln d o log e dThe natural logarithm of d; that is, ln d, or log e d
ZeroZero NegativeInfinity
NegativoNegative NaN
Uguale a NaNEqual to NaNNaN
Uguale a PositiveInfinityEqual to PositiveInfinityPositiveInfinity

Esempi

Nell'esempio seguente viene illustrato il Log metodo.The following example illustrates the Log method.

using System;
public class Example
{
   public static void Main()
   {
      Console.WriteLine("  Evaluate this identity with selected values for X:");
      Console.WriteLine("                              ln(x) = 1 / log[X](B)");
      Console.WriteLine();
          
      double[] XArgs = { 1.2, 4.9, 9.9, 0.1 };
   
      foreach (double argX in XArgs)
      {
         // Find natural log of argX.
         Console.WriteLine("                      Math.Log({0}) = {1:E16}",
                           argX, Math.Log(argX));

         // Evaluate 1 / log[X](e).
         Console.WriteLine("             1.0 / Math.Log(e, {0}) = {1:E16}",
                           argX, 1.0 / Math.Log(Math.E, argX));
         Console.WriteLine();
      }
   }   
}
// This example displays the following output:
//         Evaluate this identity with selected values for X:
//                                     ln(x) = 1 / log[X](B)
//       
//                             Math.Log(1.2) = 1.8232155679395459E-001
//                    1.0 / Math.Log(e, 1.2) = 1.8232155679395459E-001
//       
//                             Math.Log(4.9) = 1.5892352051165810E+000
//                    1.0 / Math.Log(e, 4.9) = 1.5892352051165810E+000
//       
//                             Math.Log(9.9) = 2.2925347571405443E+000
//                    1.0 / Math.Log(e, 9.9) = 2.2925347571405443E+000
//       
//                             Math.Log(0.1) = -2.3025850929940455E+000
//                    1.0 / Math.Log(e, 0.1) = -2.3025850929940455E+000
Module Example
   Sub Main()
      Console.WriteLine( _
         "  Evaluate this identity with selected values for X:")
      Console.WriteLine("                              ln(x) = 1 / log[X](B)")
      Console.WriteLine()
          
      Dim XArgs() As Double = { 1.2, 4.9, 9.9, 0.1 }
   
      For Each argX As Double In XArgs
         ' Find natural log of argX.
         Console.WriteLine("                      Math.Log({0}) = {1:E16}", _
                           argX, Math.Log(argX))

         ' Evaluate 1 / log[X](e).
         Console.WriteLine("             1.0 / Math.Log(e, {0}) = {1:E16}", _
                           argX, 1.0 / Math.Log(Math.E, argX))
         Console.WriteLine()
      Next
   End Sub 
End Module
' This example displays the following output:
'         Evaluate this identity with selected values for X:
'                                     ln(x) = 1 / log[X](B)
'       
'                             Math.Log(1.2) = 1.8232155679395459E-001
'                    1.0 / Math.Log(e, 1.2) = 1.8232155679395459E-001
'       
'                             Math.Log(4.9) = 1.5892352051165810E+000
'                    1.0 / Math.Log(e, 4.9) = 1.5892352051165810E+000
'       
'                             Math.Log(9.9) = 2.2925347571405443E+000
'                    1.0 / Math.Log(e, 9.9) = 2.2925347571405443E+000
'       
'                             Math.Log(0.1) = -2.3025850929940455E+000
'                    1.0 / Math.Log(e, 0.1) = -2.3025850929940455E+000

Commenti

Il d parametro viene specificato come numero base 10.Parameter d is specified as a base 10 number.

Vedi anche

Log(Double, Double) Log(Double, Double) Log(Double, Double) Log(Double, Double)

Restituisce il logaritmo del numero specificato in una base specificata.Returns the logarithm of a specified number in a specified base.

public:
 static double Log(double a, double newBase);
public static double Log (double a, double newBase);
static member Log : double * double -> double
Public Shared Function Log (a As Double, newBase As Double) As Double

Parametri

a
Double Double Double Double

Numero di cui è necessario trovare il logaritmo.The number whose logarithm is to be found.

newBase
Double Double Double Double

Base del logaritmo.The base of the logarithm.

Restituisce

Uno dei valori della tabella seguente.One of the values in the following table. (+Infinito indica PositiveInfinity, -Infinito indica NegativeInfinity e NaN indica NaN).(+Infinity denotes PositiveInfinity, -Infinity denotes NegativeInfinity, and NaN denotes NaN.)

anewBase Valore restituitoReturn value
a> 0a> 0 (0 <newBase< 1) -o-(newBase> 1)(0 <newBase< 1) -or-(newBase> 1) lognewBase(a)lognewBase(a)
a< 0a< 0 (qualsiasi valore)(any value) NaNNaN
(qualsiasi valore)(any value) newBase< 0newBase< 0 NaNNaN
a != 1a != 1 newBase = 0newBase = 0 NaNNaN
a != 1a != 1 newBase = +InfinitonewBase = +Infinity NaNNaN
a = NaNa = NaN (qualsiasi valore)(any value) NaNNaN
(qualsiasi valore)(any value) newBase = NaNnewBase = NaN NaNNaN
(qualsiasi valore)(any value) newBase = 1newBase = 1 NaNNaN
a = 0a = 0 0 <newBase< 10 <newBase< 1 +Infinito+Infinity
a = 0a = 0 newBase> 1newBase> 1 -Infinito-Infinity
a = +Infinitoa = +Infinity 0 <newBase< 10 <newBase< 1 -Infinito-Infinity
a = +Infinitoa = +Infinity newBase> 1newBase> 1 +Infinito+Infinity
a = 1a = 1 newBase = 0newBase = 0 00
a = 1a = 1 newBase = +InfinitonewBase = +Infinity 00

Esempi

Nell'esempio seguente viene Log usato per valutare alcune identità logaritmiche per i valori selezionati.The following example uses Log to evaluate certain logarithmic identities for selected values.

// Example for the Math::Log( double ) and Math::Log( double, double ) methods.
using namespace System;

// Evaluate logarithmic identities that are functions of two arguments.
void UseBaseAndArg( double argB, double argX )
{
   
   // Evaluate log(B)[X] == 1 / log(X)[B].
   Console::WriteLine( "\n                     Math::Log({1}, {0}) == {2:E16}"
   "\n               1.0 / Math::Log({0}, {1}) == {3:E16}", argB, argX, Math::Log( argX, argB ), 1.0 / Math::Log( argB, argX ) );
   
   // Evaluate log(B)[X] == ln[X] / ln[B].
   Console::WriteLine( "         Math::Log({1}) / Math::Log({0}) == {2:E16}", argB, argX, Math::Log( argX ) / Math::Log( argB ) );
   
   // Evaluate log(B)[X] == log(B)[e] * ln[X].
   Console::WriteLine( "Math::Log(Math::E, {0}) * Math::Log({1}) == {2:E16}", argB, argX, Math::Log( Math::E, argB ) * Math::Log( argX ) );
}

void main()
{
   Console::WriteLine( "This example of Math::Log( double ) and "
   "Math::Log( double, double )\n"
   "generates the following output.\n" );
   Console::WriteLine( "Evaluate these identities with "
   "selected values for X and B (base):" );
   Console::WriteLine( "   log(B)[X] == 1 / log(X)[B]" );
   Console::WriteLine( "   log(B)[X] == ln[X] / ln[B]" );
   Console::WriteLine( "   log(B)[X] == log(B)[e] * ln[X]" );
   UseBaseAndArg( 0.1, 1.2 );
   UseBaseAndArg( 1.2, 4.9 );
   UseBaseAndArg( 4.9, 9.9 );
   UseBaseAndArg( 9.9, 0.1 );
}

/*
This example of Math::Log( double ) and Math::Log( double, double )
generates the following output.

Evaluate these identities with selected values for X and B (base):
   log(B)[X] == 1 / log(X)[B]
   log(B)[X] == ln[X] / ln[B]
   log(B)[X] == log(B)[e] * ln[X]

                     Math::Log(1.2, 0.1) == -7.9181246047624818E-002
               1.0 / Math::Log(0.1, 1.2) == -7.9181246047624818E-002
         Math::Log(1.2) / Math::Log(0.1) == -7.9181246047624818E-002
Math::Log(Math::E, 0.1) * Math::Log(1.2) == -7.9181246047624804E-002

                     Math::Log(4.9, 1.2) == 8.7166610085093179E+000
               1.0 / Math::Log(1.2, 4.9) == 8.7166610085093161E+000
         Math::Log(4.9) / Math::Log(1.2) == 8.7166610085093179E+000
Math::Log(Math::E, 1.2) * Math::Log(4.9) == 8.7166610085093179E+000

                     Math::Log(9.9, 4.9) == 1.4425396251981288E+000
               1.0 / Math::Log(4.9, 9.9) == 1.4425396251981288E+000
         Math::Log(9.9) / Math::Log(4.9) == 1.4425396251981288E+000
Math::Log(Math::E, 4.9) * Math::Log(9.9) == 1.4425396251981288E+000

                     Math::Log(0.1, 9.9) == -1.0043839404494075E+000
               1.0 / Math::Log(9.9, 0.1) == -1.0043839404494075E+000
         Math::Log(0.1) / Math::Log(9.9) == -1.0043839404494075E+000
Math::Log(Math::E, 9.9) * Math::Log(0.1) == -1.0043839404494077E+000
*/
// Example for the Math.Log( double ) and Math.Log( double, double ) methods.
using System;

class LogDLogDD
{
    public static void Main() 
    {
        Console.WriteLine( 
            "This example of Math.Log( double ) and " +
            "Math.Log( double, double )\n" +
            "generates the following output.\n" );
        Console.WriteLine( 
            "Evaluate these identities with " +
            "selected values for X and B (base):" );
        Console.WriteLine( "   log(B)[X] == 1 / log(X)[B]" );
        Console.WriteLine( "   log(B)[X] == ln[X] / ln[B]" );
        Console.WriteLine( "   log(B)[X] == log(B)[e] * ln[X]" );

        UseBaseAndArg(0.1, 1.2);
        UseBaseAndArg(1.2, 4.9);
        UseBaseAndArg(4.9, 9.9);
        UseBaseAndArg(9.9, 0.1);
    }

    // Evaluate logarithmic identities that are functions of two arguments.
    static void UseBaseAndArg(double argB, double argX)
    {
        // Evaluate log(B)[X] == 1 / log(X)[B].
        Console.WriteLine( 
            "\n                   Math.Log({1}, {0}) == {2:E16}" + 
            "\n             1.0 / Math.Log({0}, {1}) == {3:E16}", 
            argB, argX, Math.Log(argX, argB),
            1.0 / Math.Log(argB, argX) );

        // Evaluate log(B)[X] == ln[X] / ln[B].
        Console.WriteLine( 
            "        Math.Log({1}) / Math.Log({0}) == {2:E16}",
            argB, argX, Math.Log(argX) / Math.Log(argB) );

        // Evaluate log(B)[X] == log(B)[e] * ln[X].
        Console.WriteLine( 
            "Math.Log(Math.E, {0}) * Math.Log({1}) == {2:E16}", 
            argB, argX, Math.Log(Math.E, argB) * Math.Log(argX) );
    }
}

/*
This example of Math.Log( double ) and Math.Log( double, double )
generates the following output.

Evaluate these identities with selected values for X and B (base):
   log(B)[X] == 1 / log(X)[B]
   log(B)[X] == ln[X] / ln[B]
   log(B)[X] == log(B)[e] * ln[X]

                   Math.Log(1.2, 0.1) == -7.9181246047624818E-002
             1.0 / Math.Log(0.1, 1.2) == -7.9181246047624818E-002
        Math.Log(1.2) / Math.Log(0.1) == -7.9181246047624818E-002
Math.Log(Math.E, 0.1) * Math.Log(1.2) == -7.9181246047624804E-002

                   Math.Log(4.9, 1.2) == 8.7166610085093179E+000
             1.0 / Math.Log(1.2, 4.9) == 8.7166610085093161E+000
        Math.Log(4.9) / Math.Log(1.2) == 8.7166610085093179E+000
Math.Log(Math.E, 1.2) * Math.Log(4.9) == 8.7166610085093179E+000

                   Math.Log(9.9, 4.9) == 1.4425396251981288E+000
             1.0 / Math.Log(4.9, 9.9) == 1.4425396251981288E+000
        Math.Log(9.9) / Math.Log(4.9) == 1.4425396251981288E+000
Math.Log(Math.E, 4.9) * Math.Log(9.9) == 1.4425396251981288E+000

                   Math.Log(0.1, 9.9) == -1.0043839404494075E+000
             1.0 / Math.Log(9.9, 0.1) == -1.0043839404494075E+000
        Math.Log(0.1) / Math.Log(9.9) == -1.0043839404494075E+000
Math.Log(Math.E, 9.9) * Math.Log(0.1) == -1.0043839404494077E+000
*/
' Example for the Math.Log( Double ) and Math.Log( Double, Double ) methods.
Module LogDLogDD
   
    Sub Main()
        Console.WriteLine( _
            "This example of Math.Log( Double ) and " + _
            "Math.Log( Double, Double )" & vbCrLf & _
            "generates the following output." & vbCrLf)
        Console.WriteLine( _
            "Evaluate these identities with selected " & _
            "values for X and B (base):")
        Console.WriteLine("   log(B)[X] = 1 / log(X)[B]")
        Console.WriteLine("   log(B)[X] = ln[X] / ln[B]")
        Console.WriteLine("   log(B)[X] = log(B)[e] * ln[X]")
          
        UseBaseAndArg(0.1, 1.2)
        UseBaseAndArg(1.2, 4.9)
        UseBaseAndArg(4.9, 9.9)
        UseBaseAndArg(9.9, 0.1)
    End Sub 'Main
       
    ' Evaluate logarithmic identities that are functions of two arguments.
    Sub UseBaseAndArg(argB As Double, argX As Double)

        ' Evaluate log(B)[X] = 1 / log(X)[B].
        Console.WriteLine( _
            vbCrLf & "                   Math.Log({1}, {0}) = {2:E16}" + _
            vbCrLf & "             1.0 / Math.Log({0}, {1}) = {3:E16}", _
            argB, argX, Math.Log(argX, argB), _
            1.0 / Math.Log(argB, argX))
          
        ' Evaluate log(B)[X] = ln[X] / ln[B].
        Console.WriteLine( _
            "        Math.Log({1}) / Math.Log({0}) = {2:E16}", _
            argB, argX, Math.Log(argX) / Math.Log(argB))
          
        ' Evaluate log(B)[X] = log(B)[e] * ln[X].
        Console.WriteLine( _
            "Math.Log(Math.E, {0}) * Math.Log({1}) = {2:E16}", _
            argB, argX, Math.Log(Math.E, argB) * Math.Log(argX))

    End Sub 'UseBaseAndArg
End Module 'LogDLogDD

' This example of Math.Log( Double ) and Math.Log( Double, Double )
' generates the following output.
' 
' Evaluate these identities with selected values for X and B (base):
'    log(B)[X] = 1 / log(X)[B]
'    log(B)[X] = ln[X] / ln[B]
'    log(B)[X] = log(B)[e] * ln[X]
' 
'                    Math.Log(1.2, 0.1) = -7.9181246047624818E-002
'              1.0 / Math.Log(0.1, 1.2) = -7.9181246047624818E-002
'         Math.Log(1.2) / Math.Log(0.1) = -7.9181246047624818E-002
' Math.Log(Math.E, 0.1) * Math.Log(1.2) = -7.9181246047624804E-002
' 
'                    Math.Log(4.9, 1.2) = 8.7166610085093179E+000
'              1.0 / Math.Log(1.2, 4.9) = 8.7166610085093161E+000
'         Math.Log(4.9) / Math.Log(1.2) = 8.7166610085093179E+000
' Math.Log(Math.E, 1.2) * Math.Log(4.9) = 8.7166610085093179E+000
' 
'                    Math.Log(9.9, 4.9) = 1.4425396251981288E+000
'              1.0 / Math.Log(4.9, 9.9) = 1.4425396251981288E+000
'         Math.Log(9.9) / Math.Log(4.9) = 1.4425396251981288E+000
' Math.Log(Math.E, 4.9) * Math.Log(9.9) = 1.4425396251981288E+000
' 
'                    Math.Log(0.1, 9.9) = -1.0043839404494075E+000
'              1.0 / Math.Log(9.9, 0.1) = -1.0043839404494075E+000
'         Math.Log(0.1) / Math.Log(9.9) = -1.0043839404494075E+000
' Math.Log(Math.E, 9.9) * Math.Log(0.1) = -1.0043839404494077E+000

Si applica a