Uri.SchemeDelimiter Campo

Definizione

Specifica i caratteri che separano lo schema del protocollo di comunicazione dalla parte di indirizzo dell'URI.Specifies the characters that separate the communication protocol scheme from the address portion of the URI. Questo campo è di sola lettura.This field is read-only.

public: static initonly System::String ^ SchemeDelimiter;
public static readonly string SchemeDelimiter;
 staticval mutable SchemeDelimiter : string
Public Shared ReadOnly SchemeDelimiter As String 

Valore del campo

String

Esempio

Nell'esempio seguente viene creata una stringa da UriSchemeHttp , SchemeDelimiter e da un indirizzo.The following example creates a string from UriSchemeHttp, SchemeDelimiter, and an address. UriViene quindi creata un'istanza dalla stringa.A Uri instance is then created from the string.

         String^ address = "www.contoso.com";
         String^ uriString = String::Format( "{0}{1}{2}",
            Uri::UriSchemeHttp, Uri::SchemeDelimiter, address );

#if OLDMETHOD           
         Uri^ result;
         if ( Uri::TryParse( uriString, false, false, result ) == true )
         {
            Console::WriteLine( "{0} is a valid Uri", result );
         }
         else
         {
            Console::WriteLine( "Uri not created" );
         }
#endif
         Uri ^result = gcnew Uri(uriString);
         if (result->IsWellFormedOriginalString())
             Console::WriteLine("{0} is a well formed Uri", uriString);
         else
             Console::WriteLine("{0} is not a well formed Uri", uriString);
            string address = "www.contoso.com";
            string uriString = String.Format("{0}{1}{2}/", Uri.UriSchemeHttp, Uri.SchemeDelimiter, address);
 #if OLDMETHOD
            Uri result;
            if (Uri.TryParse(uriString, false, false, out result) == true)
                Console.WriteLine("{0} is a valid Uri", result.ToString());
            else
                Console.WriteLine("Uri not created");
#endif
            Uri result = new Uri(uriString);
            if (result.IsWellFormedOriginalString())
                Console.WriteLine("{0} is a well formed Uri", uriString);
            else
                Console.WriteLine("{0} is not a well formed Uri", uriString);
Dim address As String = "www.contoso.com"
Dim uriString As String = String.Format("{0}{1}{2}", Uri.UriSchemeHttp, Uri.SchemeDelimiter, address)

Dim result As Uri = New Uri(uriString)

If result.IsWellFormedOriginalString() = True Then
    Console.WriteLine("{0} is a well formed Uri", uriString)
else
    Console.WriteLine("{0} is not a well formed Uri", uriString)
End If

Si applica a