次の方法で共有


OneOf.Medium プロパティ

定義

medium

スキーマ内の次の属性を表します:エマ:medium

[DocumentFormat.OpenXml.SchemaAttr(44, "medium")]
public DocumentFormat.OpenXml.ListValue<DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.EMMA.MediumValues>> Medium { get; set; }
public DocumentFormat.OpenXml.ListValue<DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.EMMA.MediumValues>> Medium { get; set; }
[DocumentFormat.OpenXml.SchemaAttr(44, "medium")]
public DocumentFormat.OpenXml.ListValue<DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.EMMA.MediumValues>>? Medium { get; set; }
[DocumentFormat.OpenXml.SchemaAttr("emma:medium")]
public DocumentFormat.OpenXml.ListValue<DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.EMMA.MediumValues>>? Medium { get; set; }
public DocumentFormat.OpenXml.ListValue<DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.EMMA.MediumValues>>? Medium { get; set; }
member this.Medium : DocumentFormat.OpenXml.ListValue<DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.EMMA.MediumValues>> with get, set
[<DocumentFormat.OpenXml.SchemaAttr(44, "medium")>]
member this.Medium : DocumentFormat.OpenXml.ListValue<DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.EMMA.MediumValues>> with get, set
[<DocumentFormat.OpenXml.SchemaAttr("emma:medium")>]
member this.Medium : DocumentFormat.OpenXml.ListValue<DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.EMMA.MediumValues>> with get, set
Public Property Medium As ListValue(Of EnumValue(Of MediumValues))

プロパティ値

属性

適用対象