# SqlGuid.Inequality(SqlGuid, SqlGuid) 演算子

## 定義

2 つの SqlGuid 構造体の論理比較を実行して、等しくないかどうかを確認します。Performs a logical comparison on two SqlGuid structures to determine whether they are not equal.

``````public:
static System::Data::SqlTypes::SqlBoolean operator !=(System::Data::SqlTypes::SqlGuid x, System::Data::SqlTypes::SqlGuid y);``````
``public static System.Data.SqlTypes.SqlBoolean operator != (System.Data.SqlTypes.SqlGuid x, System.Data.SqlTypes.SqlGuid y);``
``static member op_Inequality : System.Data.SqlTypes.SqlGuid * System.Data.SqlTypes.SqlGuid -> System.Data.SqlTypes.SqlBoolean``
``Public Shared Operator != (x As SqlGuid, y As SqlGuid) As SqlBoolean``

#### パラメーター

x
SqlGuid

SqlGuid 構造。A SqlGuid structure.

y
SqlGuid

SqlGuid 構造。A SqlGuid structure.

#### 戻り値

SqlBoolean

2 つのインスタンスが等しくない場合は SqlBooleanTrue。2 つのインスタンスが等しい場合は FalseA SqlBoolean that is True if the two instances are not equal or False if the two instances are equal. SqlGuid のいずれかのインスタンスが null の場合、ValueSqlBooleanNull になります。If either instance of SqlGuid is null, the Value of the SqlBoolean will be Null.

## 注釈

この演算子の同等のメソッドは SqlGuid.NotEquals(SqlGuid, SqlGuid) です。The equivalent method for this operator is SqlGuid.NotEquals(SqlGuid, SqlGuid).