DateTime.Date DateTime.Date DateTime.Date DateTime.Date Property

定義

このインスタンスの日付の部分を取得します。Gets the date component of this instance.

public:
 property DateTime Date { DateTime get(); };
public DateTime Date { get; }
member this.Date : DateTime
Public ReadOnly Property Date As DateTime

プロパティ値

このインスタンスと日付が同じで、時刻値が深夜の 12 時 (00:00:00) に設定された新しいオブジェクト。A new object with the same date as this instance, and the time value set to 12:00:00 midnight (00:00:00).

次の例では、Dateの日付部分を抽出するプロパティをDateTimeを 0 に設定の時間コンポーネントを持つ値 (0: 00時 00分または午前 0 時)。The following example uses the Date property to extract the date component of a DateTime value with its time component set to zero (or 0:00:00, or midnight). 表示するときに使用される書式指定文字列によっても、説明、DateTime値、書式設定された出力に表示される、時刻部分を続行できます。It also illustrates that, depending on the format string used when displaying the DateTime value, the time component can continue to appear in formatted output.

using namespace System;

void main()
{
   DateTime^ date1 = gcnew DateTime(2008, 6, 1, 7, 47, 0);
   Console::WriteLine(date1->ToString());
   
   // Get date-only portion of date, without its time.
   DateTime dateOnly = date1->Date;
   // Display date using short date string.
   Console::WriteLine(dateOnly.ToString("d"));
   // Display date using 24-hour clock.
   Console::WriteLine(dateOnly.ToString("g"));
   Console::WriteLine(dateOnly.ToString(L"MM/dd/yyyy HH:mm"));   
}
// The example displays the following output to the console:
//       6/1/2008 7:47:00 AM
//       6/1/2008
//       6/1/2008 12:00 AM
//       06/01/2008 00:00
using System;

public class Example
{
   public static void Main()
   {
      DateTime date1 = new DateTime(2008, 6, 1, 7, 47, 0);
      Console.WriteLine(date1.ToString());
      
      // Get date-only portion of date, without its time.
      DateTime dateOnly = date1.Date;
      // Display date using short date string.
      Console.WriteLine(dateOnly.ToString("d"));
      // Display date using 24-hour clock.
      Console.WriteLine(dateOnly.ToString("g"));
      Console.WriteLine(dateOnly.ToString("MM/dd/yyyy HH:mm"));   
   }
}
// The example displays output like the following output:
//       6/1/2008 7:47:00 AM
//       6/1/2008
//       6/1/2008 12:00 AM
//       06/01/2008 00:00
Module Example
   Public Sub Main()
      Dim date1 As Date = #6/1/2008 7:47AM#
      Console.WriteLine(date1.ToString())
      
      ' Get date-only portion of date, without its time.
      Dim dateOnly As Date = date1.Date
      ' Display date using short date string.
      Console.WriteLine(dateOnly.ToString("d"))
      ' Display date using 24-hour clock.
      Console.WriteLine(dateOnly.ToString("g"))
      Console.WriteLine(dateOnly.ToString("MM/dd/yyyy HH:mm"))   
   End Sub
End Module
' The example displays output like the following:
'       6/1/2008 7:47:00 AM                     
'       6/1/2008
'       6/1/2008 12:00 AM
'       06/01/2008 00:00

注釈

値、 Kind 、返されたプロパティDateTime値は、現在のインスタンスの場合と同じです。The value of the Kind property of the returned DateTime value is the same as that of the current instance.

DateTime型は、両方の日付を表すし、時間に 1 つの型が重要ですから返される日付の解釈を回避するために、Dateプロパティとして、日付と時刻。Because the DateTime type represents both dates and times in a single type, it is important to avoid misinterpreting a date returned by the Date property as a date and time.

適用対象