String.Split String.Split String.Split String.Split Method

定義

このインスタンス内の、指定された文字列または Unicode 文字の配列の要素で区切られた部分文字列を格納する文字列配列を返します。Returns a string array that contains the substrings in this instance that are delimited by elements of a specified string or Unicode character array.

オーバーロード

Split(Char[], Int32, StringSplitOptions) Split(Char[], Int32, StringSplitOptions) Split(Char[], Int32, StringSplitOptions) Split(Char[], Int32, StringSplitOptions)

配列内の文字に基づいて文字列を最大数の部分文字列に分割します。Splits a string into a maximum number of substrings based on the characters in an array.

Split(Char, Int32, StringSplitOptions) Split(Char, Int32, StringSplitOptions) Split(Char, Int32, StringSplitOptions)
Split(String, Int32, StringSplitOptions) Split(String, Int32, StringSplitOptions) Split(String, Int32, StringSplitOptions)
Split(String[], StringSplitOptions) Split(String[], StringSplitOptions) Split(String[], StringSplitOptions) Split(String[], StringSplitOptions)

配列内の文字列に基づいて文字列を部分文字列に分割します。Splits a string into substrings based on the strings in an array. 部分文字列が空の配列の要素を含めるかどうかを指定することができます。You can specify whether the substrings include empty array elements.

Split(String[], Int32, StringSplitOptions) Split(String[], Int32, StringSplitOptions) Split(String[], Int32, StringSplitOptions) Split(String[], Int32, StringSplitOptions)

配列内の文字列に基づいて文字列を最大数の部分文字列に分割します。Splits a string into a maximum number of substrings based on the strings in an array. 部分文字列が空の配列の要素を含めるかどうかを指定することができます。You can specify whether the substrings include empty array elements.

Split(Char[], StringSplitOptions) Split(Char[], StringSplitOptions) Split(Char[], StringSplitOptions) Split(Char[], StringSplitOptions)

配列内の文字に基づいて文字列を部分文字列に分割します。Splits a string into substrings based on the characters in an array. 部分文字列が空の配列の要素を含めるかどうかを指定することができます。You can specify whether the substrings include empty array elements.

Split(Char[], Int32) Split(Char[], Int32) Split(Char[], Int32) Split(Char[], Int32)

配列内の文字に基づいて文字列を最大数の部分文字列に分割します。Splits a string into a maximum number of substrings based on the characters in an array. 返される部分文字列の最大数を指定します。You also specify the maximum number of substrings to return.

Split(Char, StringSplitOptions) Split(Char, StringSplitOptions) Split(Char, StringSplitOptions)
Split(Char[]) Split(Char[]) Split(Char[]) Split(Char[])

配列内の文字に基づいて文字列を部分文字列に分割します。Splits a string into substrings that are based on the characters in an array.

Split(String, StringSplitOptions) Split(String, StringSplitOptions) Split(String, StringSplitOptions)

注釈

Split 区切られた文字列を部分文字列に分割に使用されます。Split is used to break a delimited string into substrings. 0、1、または複数の区切り文字を指定する文字配列を使用することができます (、Split(Char[])メソッド)、または 0、1、または複数の区切り記号文字列を指定する文字配列を使用することができます。You can use either a character array to specify zero, one, or multiple delimiting characters (the Split(Char[]) method), or you can use a character array to specify zero, one, or multiple delimiting strings. オーバー ロード、Splitメソッドを使用するメソッドによって返される部分文字列の数を制限できます (、Split(Char[], Int32)メソッド)、空の文字列が返される部分文字列に含まれるかどうかを判断する (、Split(Char[], StringSplitOptions)Split(String[], StringSplitOptions)メソッド、または両方を処理する (、Split(Char[], Int32, StringSplitOptions)Split(String[], Int32, StringSplitOptions)メソッド)。Overloads of the Split method allow you to limit the number of substrings returned by the method (the Split(Char[], Int32) method), to determine whether empty strings are included in the returned substrings (the Split(Char[], StringSplitOptions) and Split(String[], StringSplitOptions) methods, or to do both (the Split(Char[], Int32, StringSplitOptions) and Split(String[], Int32, StringSplitOptions) methods).

注意

この記事の C# 例は、Try.NET インライン コード ランナーとプレイグラウンドで実行されます。The C# examples in this article run in the Try.NET inline code runner and playground. [実行] ボタンを選択すると、対話型ウィンドウで例が実行されます。Select the Run button to run an example in an interactive window. コードを実行したら、コードを変更し、[実行] をもう一度選択して変更後のコードを実行できます。Once you execute the code, you can modify it and run the modified code by selecting Run again. 変更後のコードが対話型ウィンドウで実行されるか、コンパイルできなかった場合、対話型ウィンドウにすべての C# コンパイラ エラー メッセージが表示されます。The modified code either runs in the interactive window or, if compilation fails, the interactive window displays all C# compiler error messages.

String.Split に代わる方法Alternatives to String.Split

Split常に区切られた文字列を部分文字列に分割する最善の方法がメソッドではありません。The Split method is not always the best way to break a delimited string into substrings. 区切られた文字列の部分文字列のすべてを展開したくない場合、または区切り文字のセットではなくパターンに基づいて文字列を解析する場合は、次の代替策を検討してください。If you don't want to extract all of the substrings of a delimited string, or if you want to parse a string based on a pattern instead of a set of delimiter characters, consider the following alternatives.

正規表現Regular expressions

文字列は、一定のパターンに準拠している場合、は、抽出して、要素を処理する正規表現を使用できます。If your strings conform to a fixed pattern, you can use a regular expression to extract and handle their elements. たとえば、次の文字列形式になります"オペランド"を使用することができます、正規を抽出し、処理、文字列の要素。For example, if strings take the form "number operand number" you can use a regular expression to extract and handle the string's elements. 次に例を示します。Here's an example:

   String[] expressions = { "16 + 21", "31 * 3", "28 / 3",
                            "42 - 18", "12 * 7",
                            "2, 4, 6, 8" };
   String pattern = @"(\d+)\s+([-+*/])\s+(\d+)";
   foreach (var expression in expressions)
      foreach (System.Text.RegularExpressions.Match m in 
      System.Text.RegularExpressions.Regex.Matches(expression, pattern)) {
         int value1 = Int32.Parse(m.Groups[1].Value);
         int value2 = Int32.Parse(m.Groups[3].Value);
         switch (m.Groups[2].Value)
         {
            case "+":
               Console.WriteLine("{0} = {1}", m.Value, value1 + value2);
               break;
            case "-":
               Console.WriteLine("{0} = {1}", m.Value, value1 - value2);
               break;
            case "*":
               Console.WriteLine("{0} = {1}", m.Value, value1 * value2);
               break;
            case "/":
               Console.WriteLine("{0} = {1:N2}", m.Value, value1 / value2);
               break;
         }
      }
// The example displays the following output:
//       16 + 21 = 37
//       31 * 3 = 93
//       28 / 3 = 9.33
//       42 - 18 = 24
//       12 * 7 = 84
Imports System.Text.RegularExpressions

Module Example
   Public Sub Main()
      Dim expressions() As String = { "16 + 21", "31 * 3", "28 / 3",
                                      "42 - 18", "12 * 7",
                                      "2, 4, 6, 8" }

      Dim pattern As String = "(\d+)\s+([-+*/])\s+(\d+)"
      For Each expression In expressions
         For Each m As Match in Regex.Matches(expression, pattern)
            Dim value1 As Integer = Int32.Parse(m.Groups(1).Value)
            Dim value2 As Integer = Int32.Parse(m.Groups(3).Value)
            Select Case m.Groups(2).Value
               Case "+"
                  Console.WriteLine("{0} = {1}", m.Value, value1 + value2)
               Case "-"
                  Console.WriteLine("{0} = {1}", m.Value, value1 - value2)
               Case "*"
                  Console.WriteLine("{0} = {1}", m.Value, value1 * value2)
               Case "/"
                  Console.WriteLine("{0} = {1:N2}", m.Value, value1 / value2)
            End Select
         Next
      Next
   End Sub
End Module
' The example displays the following output:
'       16 + 21 = 37
'       31 * 3 = 93
'       28 / 3 = 9.33
'       42 - 18 = 24
'       12 * 7 = 84

正規表現パターン(\d+)\s+([-+*/])\s+(\d+)次のように定義されます。The regular expression pattern (\d+)\s+([-+*/])\s+(\d+) is defined like this:

パターンPattern 説明Description
(\d+) 1 個以上の 10 進数と一致します。Match one or more decimal digits. これが最初のキャプチャ グループです。This is the first capturing group.
\s+ 1 つ以上の空白文字と一致します。Match one or more white-space characters.
([-+*/]) 一致、算術演算子の符号 (+、-、*、または/)。Match an arithmetic operator sign (+, -, *, or /). これが 2 番目のキャプチャ グループです。This is the second capturing group.
\s+ 1 つ以上の空白文字と一致します。Match one or more white-space characters.
(\d+) 1 個以上の 10 進数と一致します。Match one or more decimal digits. これが 3 番目のキャプチャ グループです。This is the third capturing group.

文字の固定セットではなく、パターンに基づく文字列から部分文字列を抽出するのに正規表現を使用することもできます。You can also use a regular expression to extract substrings from a string based on a pattern rather than a fixed set of characters. これは、これらの条件のいずれかが発生したときの一般的なシナリオです。This is a common scenario when either of these conditions occurs:

  • 1 つ以上の区切り文字が常を処理しないで区切り記号として、Stringインスタンス。One or more of the delimiter characters does not always serve as a delimiter in the String instance.

  • 区切り記号文字の数と順序が変数または不明です。The sequence and number of delimiter characters is variable or unknown.

たとえば、Split次の文字列を分割するメソッドを使用できませんの数\n(で C# の場合) またはvbCrLf(Visual Basic) で文字は、変数、および区切り記号として使用され、常にはありません。For example, the Split method cannot be used to split the following string, because the number of \n (in C#) or vbCrLf (in Visual Basic) characters is variable, and they don't always serve as delimiters.

[This is captured\ntext.]\n\n[\n[This is more captured text.]\n]  
\n[Some more captured text:\n   Option1\n   Option2][Terse text.]  

正規表現では、簡単に、次の例はこの文字列を分割できます。A regular expression can split this string easily, as the following example shows.

String input = "[This is captured\ntext.]\n\n[\n" +
               "[This is more captured text.]\n]\n" +
               "[Some more captured text:\n   Option1" +
               "\n   Option2][Terse text.]";
String pattern = @"\[([^\[\]]+)\]";
int ctr = 0;
foreach (System.Text.RegularExpressions.Match m in 
   System.Text.RegularExpressions.Regex.Matches(input, pattern))
   Console.WriteLine("{0}: {1}", ++ctr, m.Groups[1].Value);
// The example displays the following output:
//       1: This is captured
//       text.
//       2: This is more captured text.
//       3: Some more captured text:
//          Option1
//          Option2
//       4: Terse text.
Imports System.Text.RegularExpressions

Module Example
   Public Sub Main()
      Dim input As String = String.Format("[This is captured{0}text.]" +
                                          "{0}{0}[{0}[This is more " +
                                          "captured text.]{0}{0}" +
                                          "[Some more captured text:" +
                                          "{0}   Option1" +
                                          "{0}   Option2][Terse text.]",
                                          vbCrLf)
      Dim pattern As String = "\[([^\[\]]+)\]"
      Dim ctr As Integer = 0
      For Each m As Match In Regex.Matches(input, pattern)
         ctr += 1
         Console.WriteLine("{0}: {1}", ctr, m.Groups(1).Value)
      Next
   End Sub
End Module
' The example displays the following output:
'       1: This is captured
'       text.
'       2: This is more captured text.
'       3: Some more captured text:
'          Option1
'          Option2
'       4: Terse text.

正規表現パターン\[([^\[\]]+)\]次のように定義されます。The regular expression pattern \[([^\[\]]+)\] is defined like this:

パターンPattern 説明Description
\[ 始め角かっこと一致します。Match an opening bracket.
([^\[\]]+) 開始または右角かっこを 1 回以上の任意の文字と一致します。Match any character that is not an opening or a closing bracket one or more times. これが最初のキャプチャ グループです。This is the first capturing group.
\] 右角かっこと一致します。Match a closing bracket.

Regex.Splitメソッドとほぼ同じString.Split、固定された文字セットではなく正規表現パターンに基づく文字列を分割する点が異なります。The Regex.Split method is almost identical to String.Split, except that it splits a string based on a regular expression pattern instead of a fixed character set. たとえば、次の例を使用して、Regex.Splitハイフン、およびその他の文字のさまざまな組み合わせで区切られた部分文字列を格納する文字列を分割します。For example, the following example uses the Regex.Split method to split a string that contains substrings delimited by various combinations of hyphens and other characters.

String input = "abacus -- alabaster - * - atrium -+- " +
               "any -*- actual - + - armoir - - alarm";
String pattern = @"\s-\s?[+*]?\s?-\s";
String[] elements = System.Text.RegularExpressions.Regex.Split(input, pattern);
foreach (var element in elements)
   Console.WriteLine(element);
// The example displays the following output:
//       abacus
//       alabaster
//       atrium
//       any
//       actual
//       armoir
//       alarm
Imports System.Text.RegularExpressions

Module Example
   Public Sub Main()
      Dim input As String = "abacus -- alabaster - * - atrium -+- " +
                            "any -*- actual - + - armoir - - alarm"
      Dim pattern As String = "\s-\s?[+*]?\s?-\s"
      Dim elements() As String = Regex.Split(input, pattern)
      For Each element In elements
         Console.WriteLine(element)
      Next
   End Sub
End Module
' The example displays the following output:
'       abacus
'       alabaster
'       atrium
'       any
'       actual
'       armoir
'       alarm

正規表現パターン\s-\s?[+*]?\s?-\s次のように定義されます。The regular expression pattern \s-\s?[+*]?\s?-\s is defined like this:

パターンPattern 説明Description
\s- ハイフンの後に空白文字と一致します。Match a white-space character followed by a hyphen.
\s? 0 個または 1 個の空白文字と一致します。Match zero or one white-space character.
[+*]? 0 個または 1 つのいずれかに一致、+ または * の文字。Match zero or one occurrence of either the + or * character.
\s? 0 個または 1 個の空白文字と一致します。Match zero or one white-space character.
-\s 空白文字が続くハイフンと一致します。Match a hyphen followed by a white-space character.

検索方法と Substring メソッドSearch methods and the Substring method

文字列から部分文字列のすべてに興味はない場合、一致が開始されるインデックスを返す文字列比較メソッドのいずれかを使用することもできます。If you aren't interested in all of the substrings in a string, you might prefer to work with one of the string comparison methods that returns the index at which the match begins. 呼び出して、Substringメソッドを使用する部分文字列を抽出します。You can then call the Substring method to extract the substring that you want. 文字列比較メソッドは、次のとおりです。The string comparison methods include:

  • IndexOf、文字列インスタンスで最初に出現する文字または文字列の 0 から始まるインデックスが返されます。IndexOf, which returns the zero-based index of the first occurrence of a character or string in a string instance.

  • IndexOfAny、0 から始まるインデックスを最初に出現する文字配列の任意の文字の現在の文字列インスタンスで返されます。IndexOfAny, which returns the zero-based index in the current string instance of the first occurrence of any character in a character array.

  • LastIndexOf、文字列インスタンスで最後に出現する文字または文字列の 0 から始まるインデックスが返されます。LastIndexOf, which returns the zero-based index of the last occurrence of a character or string in a string instance.

  • LastIndexOfAny、0 から始まるインデックスを最後に出現する文字配列の任意の文字の現在の文字列インスタンスで返されます。LastIndexOfAny, which returns a zero-based index in the current string instance of the last occurrence of any character in a character array.

次の例では、IndexOfメソッドを文字列内の期間を検索します。The following example uses the IndexOf method to find the periods in a string. 次を使用して、Substring完全な文を返します。It then uses the Substring method to return full sentences.

String value = "This is the first sentence in a string. " +
               "More sentences will follow. For example, " +
               "this is the third sentence. This is the " +
               "fourth. And this is the fifth and final " +
               "sentence.";
var sentences = new List<String>();
int position = 0;
int start = 0;
// Extract sentences from the string.
do {
   position = value.IndexOf('.', start);
   if (position >= 0) {
      sentences.Add(value.Substring(start, position - start + 1).Trim());
      start = position + 1;
   }
} while (position > 0);

// Display the sentences.
foreach (var sentence in sentences)
   Console.WriteLine(sentence);
// The example displays the following output:
//       This is the first sentence in a string.
//       More sentences will follow.
//       For example, this is the third sentence.
//       This is the fourth.
//       And this is the fifth and final sentence.
Imports System.Collections.Generic

Module Example
   Public Sub Main()
      Dim value As String = "This is the first sentence in a string. " +
                            "More sentences will follow. For example, " +
                            "this is the third sentence. This is the " +
                            "fourth. And this is the fifth and final " +
                            "sentence."
      Dim sentences As New List(Of String)
      Dim position As Integer = 0
      Dim start As Integer = 0
      ' Extract sentences from the string.
      Do
         position = value.IndexOf("."c, start)
         If position >= 0 Then
            sentences.Add(value.Substring(start, position - start + 1).Trim())
            start = position + 1
         End If
      Loop While position > 0
      
      ' Display the sentences.
      For Each sentence In sentences
         Console.WriteLine(sentence)
      Next
   End Sub
End Module
' The example displays the following output:
'       This is the first sentence in a string.
'       More sentences will follow.
'       For example, this is the third sentence.
'       This is the fourth.
'       And this is the fifth and final sentence.

Split(Char[], Int32, StringSplitOptions) Split(Char[], Int32, StringSplitOptions) Split(Char[], Int32, StringSplitOptions) Split(Char[], Int32, StringSplitOptions)

配列内の文字に基づいて文字列を最大数の部分文字列に分割します。Splits a string into a maximum number of substrings based on the characters in an array.

public:
 cli::array <System::String ^> ^ Split(cli::array <char> ^ separator, int count, StringSplitOptions options);
[System.Runtime.InteropServices.ComVisible(false)]
public string[] Split (char[] separator, int count, StringSplitOptions options);
member this.Split : char[] * int * StringSplitOptions -> string[]
Public Function Split (separator As Char(), count As Integer, options As StringSplitOptions) As String()

パラメーター

separator
Char[]

この文字列から部分文字列を取り出すために区切り文字として使用する文字配列、区切り文字が含まれていない空の配列、または nullA character array that delimits the substrings in this string, an empty array that contains no delimiters, or null.

count
Int32 Int32 Int32 Int32

返される最大の部分文字列数。The maximum number of substrings to return.

options
StringSplitOptions StringSplitOptions StringSplitOptions StringSplitOptions

返される配列から空の配列要素を省略する場合は RemoveEmptyEntries。返される配列に空の配列要素も含める場合は NoneRemoveEmptyEntries to omit empty array elements from the array returned; or None to include empty array elements in the array returned.

戻り値

String[]

この文字列を、separator 配列のいずれかまたは複数の要素 (文字) で区切ることによって取り出された部分文字列を格納する配列。An array whose elements contain the substrings in this string that are delimited by one or more characters in separator. 詳細については、「解説」を参照してください。For more information, see the Remarks section.

例外

optionsStringSplitOptions 値のいずれでもありません。options is not one of the StringSplitOptions values.

次の例では、StringSplitOptions列挙体によって生成された部分文字列を含めたり除外したり、Splitメソッド。The following example uses the StringSplitOptions enumeration to include or exclude substrings generated by the Split method.

// This example demonstrates the String.Split(Char[], Boolean) and 
//                               String.Split(Char[], Int32, Boolean) methods
using namespace System;
void Show( array<String^>^entries )
{
   Console::WriteLine( "The return value contains these {0} elements:", entries->Length );
   System::Collections::IEnumerator^ myEnum = entries->GetEnumerator();
   while ( myEnum->MoveNext() )
   {
      String^ entry = safe_cast<String^>(myEnum->Current);
      Console::Write( "<{0}>", entry );
   }

   Console::Write( "{0}{0}", Environment::NewLine );
}

int main()
{
   String^ s = ",one,,,two,,,,,three,,";
   array<Char>^sep = gcnew array<Char>{
      ','
   };
   array<String^>^result;
   
   //
   Console::WriteLine( "The original string is \"{0}\".", s );
   Console::WriteLine( "The separation character is '{0}'.", sep[ 0 ] );
   Console::WriteLine();
   
   //
   Console::WriteLine( "Split the string and return all elements:" );
   result = s->Split( sep, StringSplitOptions::None );
   Show( result );
   
   //
   Console::WriteLine( "Split the string and return all non-empty elements:" );
   result = s->Split( sep, StringSplitOptions::RemoveEmptyEntries );
   Show( result );
   
   //
   Console::WriteLine( "Split the string and return 2 elements:" );
   result = s->Split( sep, 2, StringSplitOptions::None );
   Show( result );
   
   //
   Console::WriteLine( "Split the string and return 2 non-empty elements:" );
   result = s->Split( sep, 2, StringSplitOptions::RemoveEmptyEntries );
   Show( result );
}

/*
This example produces the following results:

The original string is ",one,,,two,,,,,three,,".
The separation character is ','.

Split the string and return all elements:
The return value contains these 12 elements:
<><one><><><two><><><><><three><><>

Split the string and return all non-empty elements:
The return value contains these 3 elements:
<one><two><three>

Split the string and return 2 elements:
The return value contains these 2 elements:
<><one,,,two,,,,,three,,>

Split the string and return 2 non-empty elements:
The return value contains these 2 elements:
<one><,,two,,,,,three,,>

*/
// This example demonstrates the String() methods that use
// the StringSplitOptions enumeration.
string s1 = ",ONE,,TWO,,,THREE,,";
string s2 = "[stop]" +
            "ONE[stop][stop]" +
            "TWO[stop][stop][stop]" +
            "THREE[stop][stop]";
char[] charSeparators = new char[] {','};
string[] stringSeparators = new string[] {"[stop]"};
string[] result;
// ------------------------------------------------------------------------------
// Split a string delimited by characters.
// ------------------------------------------------------------------------------
Console.WriteLine("1) Split a string delimited by characters:\n");

// Display the original string and delimiter characters.
Console.WriteLine("1a )The original string is \"{0}\".", s1);
Console.WriteLine("The delimiter character is '{0}'.\n", 
                   charSeparators[0]);

// Split a string delimited by characters and return all elements.
Console.WriteLine("1b) Split a string delimited by characters and " +
                  "return all elements:");
result = s1.Split(charSeparators, StringSplitOptions.None);
Show(result);

// Split a string delimited by characters and return all non-empty elements.
Console.WriteLine("1c) Split a string delimited by characters and " +
                  "return all non-empty elements:");
result = s1.Split(charSeparators, StringSplitOptions.RemoveEmptyEntries);
Show(result);

// Split the original string into the string and empty string before the 
// delimiter and the remainder of the original string after the delimiter.
Console.WriteLine("1d) Split a string delimited by characters and " +
                  "return 2 elements:");
result = s1.Split(charSeparators, 2, StringSplitOptions.None);
Show(result);

// Split the original string into the string after the delimiter and the 
// remainder of the original string after the delimiter.
Console.WriteLine("1e) Split a string delimited by characters and " +
                  "return 2 non-empty elements:");
result = s1.Split(charSeparators, 2, StringSplitOptions.RemoveEmptyEntries);
Show(result);

// ------------------------------------------------------------------------------
// Split a string delimited by another string.
// ------------------------------------------------------------------------------
Console.WriteLine("2) Split a string delimited by another string:\n");

// Display the original string and delimiter string.
Console.WriteLine("2a) The original string is \"{0}\".", s2);
Console.WriteLine("The delimiter string is \"{0}\".\n", stringSeparators[0]);

// Split a string delimited by another string and return all elements.
Console.WriteLine("2b) Split a string delimited by another string and " +
                  "return all elements:");
result = s2.Split(stringSeparators, StringSplitOptions.None);
Show(result);

// Split the original string at the delimiter and return all non-empty elements.
Console.WriteLine("2c) Split a string delimited by another string and " +
                  "return all non-empty elements:");
result = s2.Split(stringSeparators, StringSplitOptions.RemoveEmptyEntries);
Show(result);

// Split the original string into the empty string before the 
// delimiter and the remainder of the original string after the delimiter.
Console.WriteLine("2d) Split a string delimited by another string and " +
                  "return 2 elements:");
result = s2.Split(stringSeparators, 2, StringSplitOptions.None);
Show(result);

// Split the original string into the string after the delimiter and the 
// remainder of the original string after the delimiter.
Console.WriteLine("2e) Split a string delimited by another string and " + 
                  "return 2 non-empty elements:");
result = s2.Split(stringSeparators, 2, StringSplitOptions.RemoveEmptyEntries);
Show(result);

// Display the array of separated strings using a local function
void Show(string[] entries)
{
    Console.WriteLine("The return value contains these {0} elements:", entries.Length);
    foreach (string entry in entries)
    {
        Console.Write("<{0}>", entry);
    }
    Console.Write("\n\n");
}

/*
This example produces the following results:

1) Split a string delimited by characters:

1a )The original string is ",ONE,,TWO,,,THREE,,".
The delimiter character is ','.

1b) Split a string delimited by characters and return all elements:
The return value contains these 9 elements:
<><ONE><><TWO><><><THREE><><>

1c) Split a string delimited by characters and return all non-empty elements:
The return value contains these 3 elements:
<ONE><TWO><THREE>

1d) Split a string delimited by characters and return 2 elements:
The return value contains these 2 elements:
<><ONE,,TWO,,,THREE,,>

1e) Split a string delimited by characters and return 2 non-empty elements:
The return value contains these 2 elements:
<ONE><TWO,,,THREE,,>

2) Split a string delimited by another string:

2a) The original string is "[stop]ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]".
The delimiter string is "[stop]".

2b) Split a string delimited by another string and return all elements:
The return value contains these 9 elements:
<><ONE><><TWO><><><THREE><><>

2c) Split a string delimited by another string and return all non-empty elements:
The return value contains these 3 elements:
<ONE><TWO><THREE>

2d) Split a string delimited by another string and return 2 elements:
The return value contains these 2 elements:
<><ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]>

2e) Split a string delimited by another string and return 2 non-empty elements:
The return value contains these 2 elements:
<ONE><TWO[stop][stop][stop]THREE[stop][stop]>

*/

' This example demonstrates the String() methods that use
' the StringSplitOptions enumeration.
Imports System

Class Sample
    Public Shared Sub Main() 
        Dim s1 As String = ",ONE,,TWO,,,THREE,,"
        Dim s2 As String = "[stop]" & _
                           "ONE[stop][stop]" & _
                           "TWO[stop][stop][stop]" & _
                           "THREE[stop][stop]"
        Dim charSeparators() As Char = {","c}
        Dim stringSeparators() As String = {"[stop]"}
        Dim result() As String
        ' ------------------------------------------------------------------------------
        ' Split a string delimited by characters.
        ' ------------------------------------------------------------------------------
        Console.WriteLine("1) Split a string delimited by characters:" & vbCrLf)
        
        ' Display the original string and delimiter characters.
        Console.WriteLine("1a )The original string is ""{0}"".", s1)
        Console.WriteLine("The delimiter character is '{0}'." & vbCrLf, charSeparators(0))
        
        ' Split a string delimited by characters and return all elements.
        Console.WriteLine("1b) Split a string delimited by characters and " & _
                          "return all elements:")
        result = s1.Split(charSeparators, StringSplitOptions.None)
        Show(result)
        
        ' Split a string delimited by characters and return all non-empty elements.
        Console.WriteLine("1c) Split a string delimited by characters and " & _
                          "return all non-empty elements:")
        result = s1.Split(charSeparators, StringSplitOptions.RemoveEmptyEntries)
        Show(result)
        
        ' Split the original string into the string and empty string before the 
        ' delimiter and the remainder of the original string after the delimiter.
        Console.WriteLine("1d) Split a string delimited by characters and " & _
                          "return 2 elements:")
        result = s1.Split(charSeparators, 2, StringSplitOptions.None)
        Show(result)
        
        ' Split the original string into the string after the delimiter and the 
        ' remainder of the original string after the delimiter.
        Console.WriteLine("1e) Split a string delimited by characters and " & _
                          "return 2 non-empty elements:")
        result = s1.Split(charSeparators, 2, StringSplitOptions.RemoveEmptyEntries)
        Show(result)
        
        ' ------------------------------------------------------------------------------
        ' Split a string delimited by another string.
        ' ------------------------------------------------------------------------------
        Console.WriteLine("2) Split a string delimited by another string:" & vbCrLf)
        
        ' Display the original string and delimiter string.
        Console.WriteLine("2a) The original string is ""{0}"".", s2)
        Console.WriteLine("The delimiter string is ""{0}""." & vbCrLf, stringSeparators(0))
        
        ' Split a string delimited by another string and return all elements.
        Console.WriteLine("2b) Split a string delimited by another string and " & _
                          "return all elements:")
        result = s2.Split(stringSeparators, StringSplitOptions.None)
        Show(result)
        
        ' Split the original string at the delimiter and return all non-empty elements.
        Console.WriteLine("2c) Split a string delimited by another string and " & _
                          "return all non-empty elements:")
        result = s2.Split(stringSeparators, StringSplitOptions.RemoveEmptyEntries)
        Show(result)
        
        ' Split the original string into the empty string before the 
        ' delimiter and the remainder of the original string after the delimiter.
        Console.WriteLine("2d) Split a string delimited by another string and " & _
                          "return 2 elements:")
        result = s2.Split(stringSeparators, 2, StringSplitOptions.None)
        Show(result)
        
        ' Split the original string into the string after the delimiter and the 
        ' remainder of the original string after the delimiter.
        Console.WriteLine("2e) Split a string delimited by another string and " & _
                          "return 2 non-empty elements:")
        result = s2.Split(stringSeparators, 2, StringSplitOptions.RemoveEmptyEntries)
        Show(result)
    
    End Sub 'Main
    
    
    ' Display the array of separated strings.
    Public Shared Sub Show(ByVal entries() As String) 
        Console.WriteLine("The return value contains these {0} elements:", entries.Length)
        Dim entry As String
        For Each entry In  entries
            Console.Write("<{0}>", entry)
        Next entry
        Console.Write(vbCrLf & vbCrLf)
    
    End Sub 'Show
End Class 'Sample
'
'This example produces the following results:
'
'1) Split a string delimited by characters:
'
'1a )The original string is ",ONE,,TWO,,,THREE,,".
'The delimiter character is ','.
'
'1b) Split a string delimited by characters and return all elements:
'The return value contains these 9 elements:
'<><ONE><><TWO><><><THREE><><>
'
'1c) Split a string delimited by characters and return all non-empty elements:
'The return value contains these 3 elements:
'<ONE><TWO><THREE>
'
'1d) Split a string delimited by characters and return 2 elements:
'The return value contains these 2 elements:
'<><ONE,,TWO,,,THREE,,>
'
'1e) Split a string delimited by characters and return 2 non-empty elements:
'The return value contains these 2 elements:
'<ONE><TWO,,,THREE,,>
'
'2) Split a string delimited by another string:
'
'2a) The original string is "[stop]ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]".
'The delimiter string is "[stop]".
'
'2b) Split a string delimited by another string and return all elements:
'The return value contains these 9 elements:
'<><ONE><><TWO><><><THREE><><>
'
'2c) Split a string delimited by another string and return all non-empty elements:
'The return value contains these 3 elements:
'<ONE><TWO><THREE>
'
'2d) Split a string delimited by another string and return 2 elements:
'The return value contains these 2 elements:
'<><ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]>
'
'2e) Split a string delimited by another string and return 2 non-empty elements:
'The return value contains these 2 elements:
'<ONE><TWO[stop][stop][stop]THREE[stop][stop]>
'

注釈

返される配列の要素では、区切り記号の文字は含まれません。Delimiter characters are not included in the elements of the returned array.

このインスタンスに文字が含まれていないかどうかはseparator、またはcountパラメーターが 1 の場合、返される配列は、このインスタンスを含む 1 つの要素で構成されています。If this instance does not contain any of the characters in separator, or the count parameter is 1, the returned array consists of a single element that contains this instance. 場合、separatorパラメーターがnull文字が含まれていない、または空白文字が区切り記号と見なされます。If the separator parameter is null or contains no characters, white-space characters are assumed to be the delimiters. 空白文字が Unicode 標準および戻り値によって定義されますtrueに渡された場合、Char.IsWhiteSpaceメソッド。White-space characters are defined by the Unicode standard and return true if they are passed to the Char.IsWhiteSpace method. ただし場合、separatorこのメソッドのオーバー ロードの呼び出しでパラメーターがnullコンパイラのオーバー ロードの解決は失敗します。However, if the separator parameter in the call to this method overload is null, compiler overload resolution fails. 呼び出されたメソッドを明確に識別するには、コードは、null の種類を指定する必要があります。To unambiguously identify the called method, your code must indicate the type of the null. 次の例では、このオーバー ロードを明確に識別するためにいくつかの方法を示します。The following example shows several ways to unambiguously identify this overload.

string phrase = "The quick  brown fox";
string[] words;

words = phrase.Split(default(Char[]), 3, StringSplitOptions.RemoveEmptyEntries);

words = phrase.Split((char[]) null, 3, StringSplitOptions.RemoveEmptyEntries);

words = phrase.Split(null as char[], 3, StringSplitOptions.RemoveEmptyEntries);
Dim phrase As String = "The quick brown fox"
Dim words() As String

words = phrase.Split(TryCast(Nothing, Char()), 3, 
                       StringSplitOptions.RemoveEmptyEntries)

words = phrase.Split(New Char() {}, 3,
                     StringSplitOptions.RemoveEmptyEntries)

場合、countパラメーターが 0、またはoptionsパラメーターがRemoveEmptyEntriesし、このインスタンスの長さが 0、空の配列が返されます。If the count parameter is zero, or the options parameter is RemoveEmptyEntries and the length of this instance is zero, an empty array is returned.

各要素separator別の区切り記号を定義します。Each element of separator defines a separate delimiter character. 場合、optionsパラメーターがNone、2 つの区切り記号は隣接して、または配列の対応する要素を含む、先頭または、このインスタンスの末尾に、区切り記号が見つかったEmptyします。If the options parameter is None, and two delimiters are adjacent or a delimiter is found at the beginning or end of this instance, the corresponding array element contains Empty.

ある場合は、複数のcount、このインスタンス内の部分文字列最初countマイナス 1 の部分文字列が最初に返されますcount-1、戻り値のこのインスタンスの残りの文字が最後に返されます戻り値の要素。If there are more than count substrings in this instance, the first count minus 1 substrings are returned in the first count minus 1 elements of the return value, and the remaining characters in this instance are returned in the last element of the return value.

場合count数より大きい、部分文字列の使用可能な部分文字列が返され、例外はスローされません。If count is greater than the number of substrings, the available substrings are returned and no exception is thrown.

パフォーマンスに関する考慮事項Performance Considerations

Splitメソッドが返される配列オブジェクトのメモリを割り当てると、String配列の各要素のオブジェクト。The Split methods allocate memory for the returned array object and a String object for each array element. アプリケーションに最適なパフォーマンスを必要な場合、またはメモリの割り当てを管理するは、アプリケーションで重要な場合は、使用を検討して、IndexOfまたはIndexOfAnyメソッド、および必要に応じて、Compareメソッドは、文字列内の部分文字列を検索します。If your application requires optimal performance or if managing memory allocation is critical in your application, consider using the IndexOf or IndexOfAny method, and optionally the Compare method, to locate a substring within a string.

区切り記号文字の文字列を分割する場合は、使用、IndexOfまたはIndexOfAny文字列の区切り記号の文字を検索するメソッド。If you are splitting a string at a separator character, use the IndexOf or IndexOfAny method to locate a separator character in the string. 文字列に区切り記号文字列を分割する場合は、使用、IndexOfまたはIndexOfAny区切り記号の文字列の最初の文字を検索するメソッド。If you are splitting a string at a separator string, use the IndexOf or IndexOfAny method to locate the first character of the separator string. 使用して、Compareその最初の文字の後に文字が区切り記号の文字列の残りの文字に等しいかどうかを判断するメソッド。Then use the Compare method to determine whether the characters after that first character are equal to the remaining characters of the separator string.

さらに、同じ設定する場合の文字が使用で複数の文字列を分割するSplitメソッドの呼び出しが 1 つの配列を作成して、各メソッド呼び出しで参照することを検討してください。In addition, if the same set of characters is used to split strings in multiple Split method calls, consider creating a single array and referencing it in each method call. これには、各メソッド呼び出しのオーバーヘッドが大幅に削減されます。This significantly reduces the additional overhead of each method call.

注意 (呼び出し元)

.NET Framework 3.5.NET Framework 3.5以前のバージョンでは場合、Split(Char[])メソッドに渡されます、separatornull文字が含まれていない、またはメソッドは若干異なる一連の文字を使用してよりも文字列を分割する、Trim(Char[])メソッドには文字列を切り捨てます。In the .NET Framework 3.5.NET Framework 3.5 and earlier versions, if the Split(Char[]) method is passed a separator that is null or contains no characters, the method uses a slightly different set of characters to split the string than the Trim(Char[]) method does to trim the string. 以降、.NET Framework 4 では、どちらの方法は、同一 Unicode の空白文字のセットを使用します。Starting with the .NET Framework 4, both methods use an identical set of Unicode white-space characters.

Split(Char, Int32, StringSplitOptions) Split(Char, Int32, StringSplitOptions) Split(Char, Int32, StringSplitOptions)

public string[] Split (char separator, int count, StringSplitOptions options = System.StringSplitOptions.None);
member this.Split : char * int * StringSplitOptions -> string[]
Public Function Split (separator As Char, count As Integer, Optional options As StringSplitOptions = System.StringSplitOptions.None) As String()

パラメーター

separator
Char Char Char Char

戻り値

String[]

Split(String, Int32, StringSplitOptions) Split(String, Int32, StringSplitOptions) Split(String, Int32, StringSplitOptions)

public string[] Split (string separator, int count, StringSplitOptions options = System.StringSplitOptions.None);
member this.Split : string * int * StringSplitOptions -> string[]
Public Function Split (separator As String, count As Integer, Optional options As StringSplitOptions = System.StringSplitOptions.None) As String()

パラメーター

戻り値

String[]

Split(String[], StringSplitOptions) Split(String[], StringSplitOptions) Split(String[], StringSplitOptions) Split(String[], StringSplitOptions)

配列内の文字列に基づいて文字列を部分文字列に分割します。Splits a string into substrings based on the strings in an array. 部分文字列が空の配列の要素を含めるかどうかを指定することができます。You can specify whether the substrings include empty array elements.

public:
 cli::array <System::String ^> ^ Split(cli::array <System::String ^> ^ separator, StringSplitOptions options);
[System.Runtime.InteropServices.ComVisible(false)]
public string[] Split (string[] separator, StringSplitOptions options);
member this.Split : string[] * StringSplitOptions -> string[]
Public Function Split (separator As String(), options As StringSplitOptions) As String()

パラメーター

separator
String[]

この文字列から部分文字列を取り出すために区切り文字として使用する文字列配列。区切り文字が含まれていない空の配列。または nullA string array that delimits the substrings in this string, an empty array that contains no delimiters, or null.

options
StringSplitOptions StringSplitOptions StringSplitOptions StringSplitOptions

返される配列から空の配列要素を省略する場合は RemoveEmptyEntries。返される配列に空の配列要素も含める場合は NoneRemoveEmptyEntries to omit empty array elements from the array returned; or None to include empty array elements in the array returned.

戻り値

String[]

この文字列を、separator 配列のいずれかまたは複数の要素 (文字列) で区切ることによって取り出された部分文字列を格納する配列。An array whose elements contain the substrings in this string that are delimited by one or more strings in separator. 詳細については、「解説」を参照してください。For more information, see the Remarks section.

例外

optionsStringSplitOptions 値のいずれでもありません。options is not one of the StringSplitOptions values.

次の例は、文字列を呼び出すことによって返された配列の違いを示しています。String.Split(String[], StringSplitOptions)メソッドをそのoptionsパラメーターと等しいStringSplitOptions.NoneStringSplitOptions.RemoveEmptyEntriesします。The following example illustrates the difference in the arrays returned by calling a string's String.Split(String[], StringSplitOptions) method with its options parameter equal to StringSplitOptions.None and StringSplitOptions.RemoveEmptyEntries.

   string source = "[stop]ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]";
   string[] stringSeparators = new string[] {"[stop]"};
   string[] result;
   
   // Display the original string and delimiter string.
   Console.WriteLine("Splitting the string:\n   \"{0}\".", source);
   Console.WriteLine();
   Console.WriteLine("Using the delimiter string:\n   \"{0}\"", 
                     stringSeparators[0]);
   Console.WriteLine();                           
      
   // Split a string delimited by another string and return all elements.
   result = source.Split(stringSeparators, StringSplitOptions.None);
   Console.WriteLine("Result including all elements ({0} elements):", 
                     result.Length);
   Console.Write("   ");
   foreach (string s in result)
   {
      Console.Write("'{0}' ", String.IsNullOrEmpty(s) ? "<>" : s);                   
   }
   Console.WriteLine();
   Console.WriteLine();

   // Split delimited by another string and return all non-empty elements.
   result = source.Split(stringSeparators, 
                         StringSplitOptions.RemoveEmptyEntries);
   Console.WriteLine("Result including non-empty elements ({0} elements):", 
                     result.Length);
   Console.Write("   ");
   foreach (string s in result)
   {
      Console.Write("'{0}' ", String.IsNullOrEmpty(s) ? "<>" : s);                   
   }
   Console.WriteLine();
// The example displays the following output:
//    Splitting the string:
//       "[stop]ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]".
//    
//    Using the delimiter string:
//       "[stop]"
//    
//    Result including all elements (9 elements):
//       '<>' 'ONE' '<>' 'TWO' '<>' '<>' 'THREE' '<>' '<>'
//    
//    Result including non-empty elements (3 elements):
//       'ONE' 'TWO' 'THREE'
Module Example
   Public Sub Main()
      Dim source As String = "[stop]ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]"
      Dim stringSeparators() As String = {"[stop]"}
      Dim result() As String
      
      ' Display the original string and delimiter string.
      Console.WriteLine("Splitting the string:{0}   '{1}'.", vbCrLf, source)
      Console.WriteLine()
      Console.WriteLine("Using the delimiter string:{0}   '{1}'.", _
                        vbCrLf, stringSeparators(0))
      Console.WriteLine()                          
         
      ' Split a string delimited by another string and return all elements.
      result = source.Split(stringSeparators, StringSplitOptions.None)
      Console.WriteLine("Result including all elements ({0} elements):", _ 
                        result.Length)
      Console.Write("   ")
      For Each s As String In result
         Console.Write("'{0}' ", IIf(String.IsNullOrEmpty(s), "<>", s))                   
      Next
      Console.WriteLine()
      Console.WriteLine()

      ' Split delimited by another string and return all non-empty elements.
      result = source.Split(stringSeparators, _ 
                            StringSplitOptions.RemoveEmptyEntries)
      Console.WriteLine("Result including non-empty elements ({0} elements):", _ 
                        result.Length)
      Console.Write("   ")
      For Each s As String In result
         Console.Write("'{0}' ", IIf(String.IsNullOrEmpty(s), "<>", s))                   
      Next
      Console.WriteLine()
   End Sub
End Module
' The example displays the following output:
'    Splitting the string:
'       "[stop]ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]".
'    
'    Using the delimiter string:
'       "[stop]"
'    
'    Result including all elements (9 elements):
'       '<>' 'ONE' '<>' 'TWO' '<>' '<>' 'THREE' '<>' '<>'
'    
'    Result including non-empty elements (3 elements):
'       'ONE' 'TWO' 'THREE'

次の例では、区切り記号および空白文字を含む区切り記号の配列を定義します。The following example defines an array of separators that include punctuation and white-space characters. この配列の値と共に渡すStringSplitOptions.RemoveEmptyEntriesSplit(String[], StringSplitOptions)メソッドは、文字列から個々 の単語で構成される配列を返します。Passing this array along with a value of StringSplitOptions.RemoveEmptyEntries to the Split(String[], StringSplitOptions) method returns an array that consists of the individual words from the string.

string[] separators = {",", ".", "!", "?", ";", ":", " "};
string value = "The handsome, energetic, young dog was playing with his smaller, more lethargic litter mate.";
string[] words = value.Split(separators, StringSplitOptions.RemoveEmptyEntries);
foreach (var word in words)
   Console.WriteLine(word);
// The example displays the following output:
//       The
//       handsome
//       energetic
//       young
//       dog
//       was
//       playing
//       with
//       his
//       smaller
//       more
//       lethargic
//       litter
//       mate
Module Example
   Public Sub Main()
      Dim separators() As String = {",", ".", "!", "?", ";", ":", " "}
      Dim value As String = "The handsome, energetic, young dog was playing with his smaller, more lethargic litter mate."
      Dim words() As String = value.Split(separators, StringSplitOptions.RemoveEmptyEntries)
      For Each word In words
         Console.WriteLine(word)
      Next   
   End Sub
End Module
' The example displays the following output:
'       The
'       handsome
'       energetic
'       young
'       dog
'       was
'       playing
'       with
'       his
'       smaller
'       more
'       lethargic
'       litter
'       mate

メソッドが呼び出されたメモ、options引数に設定StringSplitOptions.RemoveEmptyEntriesします。Note that the method is called with the options argument set to StringSplitOptions.RemoveEmptyEntries. これにより、返される配列を含むString.Empty区切り記号と空白文字の間の空の部分文字列の一致を表す値。This prevents the returned array from including String.Empty values that represent empty substring matches between punctuation marks and white-space characters.

注釈

文字列は、既知の一連の文字列で区切られた、ときに使用できます、Splitメソッドを部分文字列に分割します。When a string is delimited by a known set of strings, you can use the Split method to separate it into substrings.

戻り値の詳細Return value details

区切り記号の文字列は、返される配列の要素には含まれません。Delimiter strings are not included in the elements of the returned array. たとえば場合、separator配列には、文字列が含まれています。"-"と現在の文字列インスタンスの値は"aa--bb cc"、3 つの要素を含む配列を返します:"aa"、"bb"、"cc"。For example, if the separator array includes the string "--" and the value of the current string instance is "aa--bb-cc", the method returns an array that contains three elements: "aa", "bb", and "cc".

このインスタンスに内の文字列が含まれていないかどうかはseparator、返される配列は、このインスタンスを含む 1 つの要素で構成されています。If this instance does not contain any of the strings in separator, the returned array consists of a single element that contains this instance.

場合、optionsパラメーターがRemoveEmptyEntriesとこのインスタンスの長さがゼロ、空の配列を返します。If the options parameter is RemoveEmptyEntries and the length of this instance is zero, the method returns an empty array.

各要素separator1 つまたは複数の文字で構成されている別の区切り記号を定義します。Each element of separator defines a separate delimiter that consists of one or more characters. 場合、options引数がNone、2 つの区切り記号は隣接して、または配列の対応する要素を含む、先頭または、このインスタンスの末尾に、区切り記号が見つかったString.Emptyします。If the options argument is None, and two delimiters are adjacent or a delimiter is found at the beginning or end of this instance, the corresponding array element contains String.Empty. たとえば場合、 separator 2 つの要素が含まれています"-"と"_"、文字列インスタンスの値が"-_aa -_"の値、options引数がNoneメソッドの文字列配列を返します次の 5 つの要素。For example, if separator includes two elements, "-" and "_", the value of the string instance is "-_aa-_", and the value of the options argument is None, the method returns a sting array with the following five elements:

  1. String.Emptyを前にある空の文字列を表す、"-"インデックス 0 位置にある部分文字列。String.Empty, which represents the empty string that precedes the "-" substring at index 0.

  2. String.Empty、間の空の文字列を表す、"-"インデックスが 0 と 1 のインデックス位置にある「」の部分文字列に部分文字列。String.Empty, which represents the empty string between the "-" substring at index 0 and the "" substring at index 1.

  3. "aa"など"aa",

  4. String.Emptyを表すインデックス 4「」の部分文字列を次の空の文字列。String.Empty, which represents the empty string that follows the "" substring at index 4.

  5. String.Empty、次の空の文字列を表す、"-"のインデックスを 5 にある部分文字列。String.Empty, which represents the empty string that follows the "-" substring at index 5.

区切り記号の配列The separator array

内の要素のいずれかseparatorは、複数の文字の部分文字列全体は、区切り記号と見なされます。If any of the elements in separator consists of multiple characters, the entire substring is considered a delimiter. たとえば、1 つの要素のseparatorは「10」、"This10is10a10string。"という文字列を分割しようとしています。For example, if one of the elements in separator is "10", attempting to split the string "This10is10a10string." 次の 4 つの要素の配列を返します: {"This"、"is"、"a"、「文字列」。returns the following four-element array: { "This", "is", "a", "string." }.}.

場合、separatorパラメーターがnull文字が含まれていない、または空白文字が区切り記号と見なされます。If the separator parameter is null or contains no characters, white-space characters are assumed to be the delimiters. 空白文字が Unicode 標準および戻り値によって定義されますtrueに渡された場合、Char.IsWhiteSpaceメソッド。White-space characters are defined by the Unicode standard and return true if they are passed to the Char.IsWhiteSpace method.

場合、separatorこのメソッドのオーバー ロードの呼び出しでパラメーターがnullコンパイラのオーバー ロードの解決は失敗します。If the separator parameter in the call to this method overload is null, compiler overload resolution fails. 呼び出されたメソッドを明確に識別するコードがの型を示す必要があります、nullします。To unambiguously identify the called method, your code must indicate the type of the null. 次の例では、このオーバー ロードを明確に識別するためにいくつかの方法を示します。The following example shows several ways to unambiguously identify this overload.

string phrase = "The quick  brown fox";
string[] words;

words = phrase.Split(default(string[]), StringSplitOptions.RemoveEmptyEntries);

words = phrase.Split((string[]) null, StringSplitOptions.RemoveEmptyEntries);

words = phrase.Split(null as string[], StringSplitOptions.RemoveEmptyEntries);
Dim phrase As String = "The quick brown fox"
Dim words() As String

words = phrase.Split(TryCast(Nothing, String()),  
                       StringSplitOptions.RemoveEmptyEntries)

words = phrase.Split(New String() {},
                     StringSplitOptions.RemoveEmptyEntries)

比較の詳細Comparison details

Splitメソッドが 1 つ以上の内の文字列で区切られた、この文字列の部分文字列を抽出し、separatorパラメーター、配列の要素としてそれらの部分文字列を返します。The Split method extracts the substrings in this string that are delimited by one or more of the strings in the separator parameter, and returns those substrings as elements of an array.

Splitメソッドが大文字の序数の並べ替え規則を使用する比較を実行することでは区切り記号を検索します。The Split method looks for delimiters by performing comparisons using case-sensitive ordinal sort rules. 単語、文字列、および序数の並べ替えの詳細については、次を参照してください。、System.Globalization.CompareOptions列挙体。For more information about word, string, and ordinal sorts, see the System.Globalization.CompareOptions enumeration.

Splitメソッドは任意の要素を無視separator値がnullまたは空の文字列 ("")。The Split method ignores any element of separator whose value is null or the empty string ("").

あいまいな結果を回避するときにで文字列separator共通の文字がある、Split操作は、インスタンスの値の末尾に、先頭から開始されの最初の要素と一致するseparator内の区切り記号と等しい、インスタンス。To avoid ambiguous results when strings in separator have characters in common, the Split operation proceeds from the beginning to the end of the value of the instance, and matches the first element in separator that is equal to a delimiter in the instance. 部分文字列が、インスタンスで発生した順序で要素の順序よりも優先separatorします。The order in which substrings are encountered in the instance takes precedence over the order of elements in separator.

たとえば、値を持つ"abcdef"のインスタンスがあるとします。For example, consider an instance whose value is "abcdef". 場合の最初の要素separator"ef"と 2 番目の要素が"bcde"に、split 操作の結果は 2 つの要素を格納する文字列配列になりますが、"a"および"f"です。If the first element in separator was "ef" and the second element was "bcde", the result of the split operation would be a string array that contains two elements, "a" and "f". これは、"bcde"、インスタンス内の部分文字列が検出され、内の要素と一致するためseparator前に、"f"の部分文字列が発生しました。This is because the substring in the instance, "bcde", is encountered and matches an element in separator before the substring "f" is encountered.

ただし場合の最初の要素separator"bcd"と 2 番目の要素が"bc"に、split 操作の結果は 2 つの要素を格納する文字列配列になりますが、"a"と"ef"。However, if the first element of separator was "bcd" and the second element was "bc", the result of the split operation would be a string array that contains two elements, "a" and "ef". これは最初の区切り記号が"bcd"separatorインスタンス内の区切り記号に一致します。This is because "bcd" is the first delimiter in separator that matches a delimiter in the instance. "Bcd"に、2 番目の要素が、結果は 2 つの要素を格納する文字列配列になりますので、最初の要素は"bc"区切り記号の順序が取り消された場合、"a"と"def"。If the order of the separators was reversed so the first element was "bc" and the second element was "bcd", the result would be a string array that contains two elements, "a" and "def".

パフォーマンスに関する考慮事項Performance considerations

Splitメソッドが返される配列オブジェクトのメモリを割り当てると、String配列の各要素のオブジェクト。The Split methods allocate memory for the returned array object and a String object for each array element. アプリケーションに最適なパフォーマンスを必要な場合、またはメモリの割り当てを管理するは、アプリケーションで重要な場合は、使用を検討して、IndexOfまたはIndexOfAnyメソッド、および必要に応じて、Compareメソッドは、文字列内の部分文字列を検索します。If your application requires optimal performance or if managing memory allocation is critical in your application, consider using the IndexOf or IndexOfAny method, and optionally the Compare method, to locate a substring within a string.

区切り記号文字の文字列を分割する場合は、使用、IndexOfまたはIndexOfAny文字列の区切り記号の文字を検索するメソッド。If you are splitting a string at a separator character, use the IndexOf or IndexOfAny method to locate a separator character in the string. 文字列に区切り記号文字列を分割する場合は、使用、IndexOfまたはIndexOfAny区切り記号の文字列の最初の文字を検索するメソッド。If you are splitting a string at a separator string, use the IndexOf or IndexOfAny method to locate the first character of the separator string. 使用して、Compareその最初の文字の後に文字が区切り記号の文字列の残りの文字に等しいかどうかを判断するメソッド。Then use the Compare method to determine whether the characters after that first character are equal to the remaining characters of the separator string.

さらに、同じ設定する場合の文字が使用で複数の文字列を分割するSplitメソッドの呼び出しが 1 つの配列を作成して、各メソッド呼び出しで参照することを検討してください。In addition, if the same set of characters is used to split strings in multiple Split method calls, consider creating a single array and referencing it in each method call. これには、各メソッド呼び出しのオーバーヘッドが大幅に削減されます。This significantly reduces the additional overhead of each method call.

注意 (呼び出し元)

.NET Framework 3.5.NET Framework 3.5以前のバージョンでは場合、Split(Char[])メソッドに渡されます、separatornull文字が含まれていない、またはメソッドは若干異なる一連の文字を使用してよりも文字列を分割する、Trim(Char[])メソッドには文字列を切り捨てます。In the .NET Framework 3.5.NET Framework 3.5 and earlier versions, if the Split(Char[]) method is passed a separator that is null or contains no characters, the method uses a slightly different set of characters to split the string than the Trim(Char[]) method does to trim the string. 以降、.NET Framework 4 では、どちらの方法は、同一 Unicode の空白文字のセットを使用します。Starting with the .NET Framework 4, both methods use an identical set of Unicode white-space characters.

Split(String[], Int32, StringSplitOptions) Split(String[], Int32, StringSplitOptions) Split(String[], Int32, StringSplitOptions) Split(String[], Int32, StringSplitOptions)

配列内の文字列に基づいて文字列を最大数の部分文字列に分割します。Splits a string into a maximum number of substrings based on the strings in an array. 部分文字列が空の配列の要素を含めるかどうかを指定することができます。You can specify whether the substrings include empty array elements.

public:
 cli::array <System::String ^> ^ Split(cli::array <System::String ^> ^ separator, int count, StringSplitOptions options);
[System.Runtime.InteropServices.ComVisible(false)]
public string[] Split (string[] separator, int count, StringSplitOptions options);
member this.Split : string[] * int * StringSplitOptions -> string[]
Public Function Split (separator As String(), count As Integer, options As StringSplitOptions) As String()

パラメーター

separator
String[]

この文字列から部分文字列を取り出すために区切り文字として使用する文字列配列。区切り文字が含まれていない空の配列。または nullA string array that delimits the substrings in this string, an empty array that contains no delimiters, or null.

count
Int32 Int32 Int32 Int32

返される最大の部分文字列数。The maximum number of substrings to return.

options
StringSplitOptions StringSplitOptions StringSplitOptions StringSplitOptions

返される配列から空の配列要素を省略する場合は RemoveEmptyEntries。返される配列に空の配列要素も含める場合は NoneRemoveEmptyEntries to omit empty array elements from the array returned; or None to include empty array elements in the array returned.

戻り値

String[]

この文字列を、separator 配列のいずれかまたは複数の要素 (文字列) で区切ることによって取り出された部分文字列を格納する配列。An array whose elements contain the substrings in this string that are delimited by one or more strings in separator. 詳細については、「解説」を参照してください。For more information, see the Remarks section.

例外

optionsStringSplitOptions 値のいずれでもありません。options is not one of the StringSplitOptions values.

次の例では、StringSplitOptions列挙体によって生成された部分文字列を含めたり除外したり、Splitメソッド。The following example uses the StringSplitOptions enumeration to include or exclude substrings generated by the Split method.

// This example demonstrates the String.Split(Char[], Boolean) and 
//                               String.Split(Char[], Int32, Boolean) methods
using namespace System;
void Show( array<String^>^entries )
{
   Console::WriteLine( "The return value contains these {0} elements:", entries->Length );
   System::Collections::IEnumerator^ myEnum = entries->GetEnumerator();
   while ( myEnum->MoveNext() )
   {
      String^ entry = safe_cast<String^>(myEnum->Current);
      Console::Write( "<{0}>", entry );
   }

   Console::Write( "{0}{0}", Environment::NewLine );
}

int main()
{
   String^ s = ",one,,,two,,,,,three,,";
   array<Char>^sep = gcnew array<Char>{
      ','
   };
   array<String^>^result;
   
   //
   Console::WriteLine( "The original string is \"{0}\".", s );
   Console::WriteLine( "The separation character is '{0}'.", sep[ 0 ] );
   Console::WriteLine();
   
   //
   Console::WriteLine( "Split the string and return all elements:" );
   result = s->Split( sep, StringSplitOptions::None );
   Show( result );
   
   //
   Console::WriteLine( "Split the string and return all non-empty elements:" );
   result = s->Split( sep, StringSplitOptions::RemoveEmptyEntries );
   Show( result );
   
   //
   Console::WriteLine( "Split the string and return 2 elements:" );
   result = s->Split( sep, 2, StringSplitOptions::None );
   Show( result );
   
   //
   Console::WriteLine( "Split the string and return 2 non-empty elements:" );
   result = s->Split( sep, 2, StringSplitOptions::RemoveEmptyEntries );
   Show( result );
}

/*
This example produces the following results:

The original string is ",one,,,two,,,,,three,,".
The separation character is ','.

Split the string and return all elements:
The return value contains these 12 elements:
<><one><><><two><><><><><three><><>

Split the string and return all non-empty elements:
The return value contains these 3 elements:
<one><two><three>

Split the string and return 2 elements:
The return value contains these 2 elements:
<><one,,,two,,,,,three,,>

Split the string and return 2 non-empty elements:
The return value contains these 2 elements:
<one><,,two,,,,,three,,>

*/
// This example demonstrates the String() methods that use
// the StringSplitOptions enumeration.
string s1 = ",ONE,,TWO,,,THREE,,";
string s2 = "[stop]" +
            "ONE[stop][stop]" +
            "TWO[stop][stop][stop]" +
            "THREE[stop][stop]";
char[] charSeparators = new char[] {','};
string[] stringSeparators = new string[] {"[stop]"};
string[] result;
// ------------------------------------------------------------------------------
// Split a string delimited by characters.
// ------------------------------------------------------------------------------
Console.WriteLine("1) Split a string delimited by characters:\n");

// Display the original string and delimiter characters.
Console.WriteLine("1a )The original string is \"{0}\".", s1);
Console.WriteLine("The delimiter character is '{0}'.\n", 
                   charSeparators[0]);

// Split a string delimited by characters and return all elements.
Console.WriteLine("1b) Split a string delimited by characters and " +
                  "return all elements:");
result = s1.Split(charSeparators, StringSplitOptions.None);
Show(result);

// Split a string delimited by characters and return all non-empty elements.
Console.WriteLine("1c) Split a string delimited by characters and " +
                  "return all non-empty elements:");
result = s1.Split(charSeparators, StringSplitOptions.RemoveEmptyEntries);
Show(result);

// Split the original string into the string and empty string before the 
// delimiter and the remainder of the original string after the delimiter.
Console.WriteLine("1d) Split a string delimited by characters and " +
                  "return 2 elements:");
result = s1.Split(charSeparators, 2, StringSplitOptions.None);
Show(result);

// Split the original string into the string after the delimiter and the 
// remainder of the original string after the delimiter.
Console.WriteLine("1e) Split a string delimited by characters and " +
                  "return 2 non-empty elements:");
result = s1.Split(charSeparators, 2, StringSplitOptions.RemoveEmptyEntries);
Show(result);

// ------------------------------------------------------------------------------
// Split a string delimited by another string.
// ------------------------------------------------------------------------------
Console.WriteLine("2) Split a string delimited by another string:\n");

// Display the original string and delimiter string.
Console.WriteLine("2a) The original string is \"{0}\".", s2);
Console.WriteLine("The delimiter string is \"{0}\".\n", stringSeparators[0]);

// Split a string delimited by another string and return all elements.
Console.WriteLine("2b) Split a string delimited by another string and " +
                  "return all elements:");
result = s2.Split(stringSeparators, StringSplitOptions.None);
Show(result);

// Split the original string at the delimiter and return all non-empty elements.
Console.WriteLine("2c) Split a string delimited by another string and " +
                  "return all non-empty elements:");
result = s2.Split(stringSeparators, StringSplitOptions.RemoveEmptyEntries);
Show(result);

// Split the original string into the empty string before the 
// delimiter and the remainder of the original string after the delimiter.
Console.WriteLine("2d) Split a string delimited by another string and " +
                  "return 2 elements:");
result = s2.Split(stringSeparators, 2, StringSplitOptions.None);
Show(result);

// Split the original string into the string after the delimiter and the 
// remainder of the original string after the delimiter.
Console.WriteLine("2e) Split a string delimited by another string and " + 
                  "return 2 non-empty elements:");
result = s2.Split(stringSeparators, 2, StringSplitOptions.RemoveEmptyEntries);
Show(result);

// Display the array of separated strings using a local function
void Show(string[] entries)
{
    Console.WriteLine("The return value contains these {0} elements:", entries.Length);
    foreach (string entry in entries)
    {
        Console.Write("<{0}>", entry);
    }
    Console.Write("\n\n");
}

/*
This example produces the following results:

1) Split a string delimited by characters:

1a )The original string is ",ONE,,TWO,,,THREE,,".
The delimiter character is ','.

1b) Split a string delimited by characters and return all elements:
The return value contains these 9 elements:
<><ONE><><TWO><><><THREE><><>

1c) Split a string delimited by characters and return all non-empty elements:
The return value contains these 3 elements:
<ONE><TWO><THREE>

1d) Split a string delimited by characters and return 2 elements:
The return value contains these 2 elements:
<><ONE,,TWO,,,THREE,,>

1e) Split a string delimited by characters and return 2 non-empty elements:
The return value contains these 2 elements:
<ONE><TWO,,,THREE,,>

2) Split a string delimited by another string:

2a) The original string is "[stop]ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]".
The delimiter string is "[stop]".

2b) Split a string delimited by another string and return all elements:
The return value contains these 9 elements:
<><ONE><><TWO><><><THREE><><>

2c) Split a string delimited by another string and return all non-empty elements:
The return value contains these 3 elements:
<ONE><TWO><THREE>

2d) Split a string delimited by another string and return 2 elements:
The return value contains these 2 elements:
<><ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]>

2e) Split a string delimited by another string and return 2 non-empty elements:
The return value contains these 2 elements:
<ONE><TWO[stop][stop][stop]THREE[stop][stop]>

*/

' This example demonstrates the String() methods that use
' the StringSplitOptions enumeration.
Imports System

Class Sample
    Public Shared Sub Main() 
        Dim s1 As String = ",ONE,,TWO,,,THREE,,"
        Dim s2 As String = "[stop]" & _
                           "ONE[stop][stop]" & _
                           "TWO[stop][stop][stop]" & _
                           "THREE[stop][stop]"
        Dim charSeparators() As Char = {","c}
        Dim stringSeparators() As String = {"[stop]"}
        Dim result() As String
        ' ------------------------------------------------------------------------------
        ' Split a string delimited by characters.
        ' ------------------------------------------------------------------------------
        Console.WriteLine("1) Split a string delimited by characters:" & vbCrLf)
        
        ' Display the original string and delimiter characters.
        Console.WriteLine("1a )The original string is ""{0}"".", s1)
        Console.WriteLine("The delimiter character is '{0}'." & vbCrLf, charSeparators(0))
        
        ' Split a string delimited by characters and return all elements.
        Console.WriteLine("1b) Split a string delimited by characters and " & _
                          "return all elements:")
        result = s1.Split(charSeparators, StringSplitOptions.None)
        Show(result)
        
        ' Split a string delimited by characters and return all non-empty elements.
        Console.WriteLine("1c) Split a string delimited by characters and " & _
                          "return all non-empty elements:")
        result = s1.Split(charSeparators, StringSplitOptions.RemoveEmptyEntries)
        Show(result)
        
        ' Split the original string into the string and empty string before the 
        ' delimiter and the remainder of the original string after the delimiter.
        Console.WriteLine("1d) Split a string delimited by characters and " & _
                          "return 2 elements:")
        result = s1.Split(charSeparators, 2, StringSplitOptions.None)
        Show(result)
        
        ' Split the original string into the string after the delimiter and the 
        ' remainder of the original string after the delimiter.
        Console.WriteLine("1e) Split a string delimited by characters and " & _
                          "return 2 non-empty elements:")
        result = s1.Split(charSeparators, 2, StringSplitOptions.RemoveEmptyEntries)
        Show(result)
        
        ' ------------------------------------------------------------------------------
        ' Split a string delimited by another string.
        ' ------------------------------------------------------------------------------
        Console.WriteLine("2) Split a string delimited by another string:" & vbCrLf)
        
        ' Display the original string and delimiter string.
        Console.WriteLine("2a) The original string is ""{0}"".", s2)
        Console.WriteLine("The delimiter string is ""{0}""." & vbCrLf, stringSeparators(0))
        
        ' Split a string delimited by another string and return all elements.
        Console.WriteLine("2b) Split a string delimited by another string and " & _
                          "return all elements:")
        result = s2.Split(stringSeparators, StringSplitOptions.None)
        Show(result)
        
        ' Split the original string at the delimiter and return all non-empty elements.
        Console.WriteLine("2c) Split a string delimited by another string and " & _
                          "return all non-empty elements:")
        result = s2.Split(stringSeparators, StringSplitOptions.RemoveEmptyEntries)
        Show(result)
        
        ' Split the original string into the empty string before the 
        ' delimiter and the remainder of the original string after the delimiter.
        Console.WriteLine("2d) Split a string delimited by another string and " & _
                          "return 2 elements:")
        result = s2.Split(stringSeparators, 2, StringSplitOptions.None)
        Show(result)
        
        ' Split the original string into the string after the delimiter and the 
        ' remainder of the original string after the delimiter.
        Console.WriteLine("2e) Split a string delimited by another string and " & _
                          "return 2 non-empty elements:")
        result = s2.Split(stringSeparators, 2, StringSplitOptions.RemoveEmptyEntries)
        Show(result)
    
    End Sub 'Main
    
    
    ' Display the array of separated strings.
    Public Shared Sub Show(ByVal entries() As String) 
        Console.WriteLine("The return value contains these {0} elements:", entries.Length)
        Dim entry As String
        For Each entry In  entries
            Console.Write("<{0}>", entry)
        Next entry
        Console.Write(vbCrLf & vbCrLf)
    
    End Sub 'Show
End Class 'Sample
'
'This example produces the following results:
'
'1) Split a string delimited by characters:
'
'1a )The original string is ",ONE,,TWO,,,THREE,,".
'The delimiter character is ','.
'
'1b) Split a string delimited by characters and return all elements:
'The return value contains these 9 elements:
'<><ONE><><TWO><><><THREE><><>
'
'1c) Split a string delimited by characters and return all non-empty elements:
'The return value contains these 3 elements:
'<ONE><TWO><THREE>
'
'1d) Split a string delimited by characters and return 2 elements:
'The return value contains these 2 elements:
'<><ONE,,TWO,,,THREE,,>
'
'1e) Split a string delimited by characters and return 2 non-empty elements:
'The return value contains these 2 elements:
'<ONE><TWO,,,THREE,,>
'
'2) Split a string delimited by another string:
'
'2a) The original string is "[stop]ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]".
'The delimiter string is "[stop]".
'
'2b) Split a string delimited by another string and return all elements:
'The return value contains these 9 elements:
'<><ONE><><TWO><><><THREE><><>
'
'2c) Split a string delimited by another string and return all non-empty elements:
'The return value contains these 3 elements:
'<ONE><TWO><THREE>
'
'2d) Split a string delimited by another string and return 2 elements:
'The return value contains these 2 elements:
'<><ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]>
'
'2e) Split a string delimited by another string and return 2 non-empty elements:
'The return value contains these 2 elements:
'<ONE><TWO[stop][stop][stop]THREE[stop][stop]>
'

注釈

戻り値の詳細Return value details

区切り記号の文字列は、返される配列の要素には含まれません。Delimiter strings are not included in the elements of the returned array.

このインスタンスに内の文字列が含まれていないかどうかはseparator、またはcountパラメーターが 1 の場合、返される配列は、このインスタンスを含む 1 つの要素で構成されています。If this instance does not contain any of the strings in separator, or the count parameter is 1, the returned array consists of a single element that contains this instance. 場合、separatorパラメーターがnull文字が含まれていない、または空白文字が区切り記号と見なされます。If the separator parameter is null or contains no characters, white-space characters are assumed to be the delimiters. 空白文字が Unicode 標準および戻り値によって定義されますtrueに渡された場合、Char.IsWhiteSpaceメソッド。White-space characters are defined by the Unicode standard and return true if they are passed to the Char.IsWhiteSpace method. ただし場合、separatorこのメソッドのオーバー ロードの呼び出しでパラメーターがnullコンパイラのオーバー ロードの解決は失敗します。However, if the separator parameter in the call to this method overload is null, compiler overload resolution fails. 呼び出されたメソッドを明確に識別するコードがの型を示す必要があります、nullします。To unambiguously identify the called method, your code must indicate the type of the null. 次の例では、このオーバー ロードを明確に識別するためにいくつかの方法を示します。The following example shows several ways to unambiguously identify this overload.

string phrase = "The quick  brown fox";
string[] words;

words = phrase.Split(default(string[]), 3, StringSplitOptions.RemoveEmptyEntries);

words = phrase.Split((string[]) null, 3, StringSplitOptions.RemoveEmptyEntries);

words = phrase.Split(null as string[], 3, StringSplitOptions.RemoveEmptyEntries);
Dim phrase As String = "The quick brown fox"
Dim words() As String

words = phrase.Split(TryCast(Nothing, String()), 3, 
                       StringSplitOptions.RemoveEmptyEntries)

words = phrase.Split(New String() {}, 3,
                     StringSplitOptions.RemoveEmptyEntries)

場合、countパラメーターが 0、またはoptionsパラメーターがRemoveEmptyEntriesし、このインスタンスの長さが 0、空の配列が返されます。If the count parameter is zero, or the options parameter is RemoveEmptyEntries and the length of this instance is zero, an empty array is returned.

各要素separator1 つまたは複数の文字で構成されている別の区切り記号を定義します。Each element of separator defines a separate delimiter that consists of one or more characters. 場合、optionsパラメーターがNone、2 つの区切り記号は隣接して、または配列の対応する要素を含む、先頭または、このインスタンスの末尾に、区切り記号が見つかったEmptyします。If the options parameter is None, and two delimiters are adjacent or a delimiter is found at the beginning or end of this instance, the corresponding array element contains Empty.

ある場合は、複数のcount、このインスタンス内の部分文字列最初countマイナス 1 の部分文字列が最初に返されますcount-1、戻り値のこのインスタンスの残りの文字が最後に返されます戻り値の要素。If there are more than count substrings in this instance, the first count minus 1 substrings are returned in the first count minus 1 elements of the return value, and the remaining characters in this instance are returned in the last element of the return value.

場合count数より大きい、部分文字列の使用可能な部分文字列が返され、例外はスローされません。If count is greater than the number of substrings, the available substrings are returned and no exception is thrown.

区切り記号の配列The separator array

内の要素のいずれかseparatorは、複数の文字の部分文字列全体は、区切り記号と見なされます。If any of the elements in separator consists of multiple characters, the entire substring is considered a delimiter. たとえば、1 つの要素のseparatorは「10」、"This10is10a10string。"という文字列を分割しようとしています。For example, if one of the elements in separator is "10", attempting to split the string "This10is10a10string." この 4 つの要素の配列を返します: {"This"、"is"、"a"、「文字列」。returns this four-element array: { "This", "is", "a", "string." }.}.

比較の詳細Comparison details

Splitメソッドが 1 つ以上の内の文字列で区切られた、この文字列の部分文字列を抽出し、separatorパラメーター、配列の要素としてそれらの部分文字列を返します。The Split method extracts the substrings in this string that are delimited by one or more of the strings in the separator parameter, and returns those substrings as elements of an array.

Splitメソッドが大文字の序数の並べ替え規則を使用する比較を実行することでは区切り記号を検索します。The Split method looks for delimiters by performing comparisons using case-sensitive ordinal sort rules. 単語、文字列、および序数の並べ替えの詳細については、次を参照してください。、System.Globalization.CompareOptions列挙体。For more information about word, string, and ordinal sorts, see the System.Globalization.CompareOptions enumeration.

Splitメソッドは任意の要素を無視separator値がnullまたは空の文字列 ("")。The Split method ignores any element of separator whose value is null or the empty string ("").

あいまいな結果を回避するときにで文字列separator共通の文字がある、Splitメソッドは、インスタンスの値の末尾に、先頭から開始されの最初の要素と一致するseparator内の区切り記号と等しい、インスタンス。To avoid ambiguous results when strings in separator have characters in common, the Split method proceeds from the beginning to the end of the value of the instance, and matches the first element in separator that is equal to a delimiter in the instance. 部分文字列が、インスタンスで発生した順序で要素の順序よりも優先separatorします。The order in which substrings are encountered in the instance takes precedence over the order of elements in separator.

たとえば、値を持つ"abcdef"のインスタンスがあるとします。For example, consider an instance whose value is "abcdef". 場合の最初の要素separator"bcde"を"ef"と 2 番目の要素が、split 操作の結果になりますが、"a"および"f"です。If the first element in separator was "ef" and the second element was "bcde", the result of the split operation would be "a" and "f". これは、"bcde"、インスタンス内の部分文字列が検出され、内の要素と一致するためseparator前に、"f"の部分文字列が発生しました。This is because the substring in the instance, "bcde", is encountered and matches an element in separator before the substring "f" is encountered.

ただし場合の最初の要素separator"bc"を"bcd"と 2 番目の要素が、split 操作の結果になりますが、"a"と"ef"。However, if the first element of separator was "bcd" and the second element was "bc", the result of the split operation would be "a" and "ef". これは最初の区切り記号が"bcd"separatorインスタンス内の区切り記号に一致します。This is because "bcd" is the first delimiter in separator that matches a delimiter in the instance. "Bcd"に、2 番目の要素が、結果になりますので、最初の要素は"bc"区切り記号の順序が取り消された場合、"a"と"def"。If the order of the separators was reversed so the first element was "bc" and the second element was "bcd", the result would be "a" and "def".

パフォーマンスに関する考慮事項Performance considerations

Splitメソッドが返される配列オブジェクトのメモリを割り当てると、String配列の各要素のオブジェクト。The Split methods allocate memory for the returned array object and a String object for each array element. アプリケーションに最適なパフォーマンスを必要な場合、またはメモリの割り当てを管理するは、アプリケーションで重要な場合は、使用を検討して、IndexOfまたはIndexOfAnyメソッド、および必要に応じて、Compareメソッドは、文字列内の部分文字列を検索します。If your application requires optimal performance or if managing memory allocation is critical in your application, consider using the IndexOf or IndexOfAny method, and optionally the Compare method, to locate a substring within a string.

区切り記号文字の文字列を分割する場合は、使用、IndexOfまたはIndexOfAny文字列の区切り記号の文字を検索するメソッド。If you are splitting a string at a separator character, use the IndexOf or IndexOfAny method to locate a separator character in the string. 文字列に区切り記号文字列を分割する場合は、使用、IndexOfまたはIndexOfAny区切り記号の文字列の最初の文字を検索するメソッド。If you are splitting a string at a separator string, use the IndexOf or IndexOfAny method to locate the first character of the separator string. 使用して、Compareその最初の文字の後に文字が区切り記号の文字列の残りの文字に等しいかどうかを判断するメソッド。Then use the Compare method to determine whether the characters after that first character are equal to the remaining characters of the separator string.

さらに、同じ設定する場合の文字が使用で複数の文字列を分割するSplitメソッドの呼び出しが 1 つの配列を作成して、各メソッド呼び出しで参照することを検討してください。In addition, if the same set of characters is used to split strings in multiple Split method calls, consider creating a single array and referencing it in each method call. これには、各メソッド呼び出しのオーバーヘッドが大幅に削減されます。This significantly reduces the additional overhead of each method call.

注意 (呼び出し元)

.NET Framework 3.5.NET Framework 3.5以前のバージョンでは場合、Split(Char[])メソッドに渡されます、separatornull文字が含まれていない、またはメソッドは若干異なる一連の文字を使用してよりも文字列を分割する、Trim(Char[])メソッドには文字列を切り捨てます。In the .NET Framework 3.5.NET Framework 3.5 and earlier versions, if the Split(Char[]) method is passed a separator that is null or contains no characters, the method uses a slightly different set of characters to split the string than the Trim(Char[]) method does to trim the string. 以降、.NET Framework 4 では、どちらの方法は、同一 Unicode の空白文字のセットを使用します。Starting with the .NET Framework 4, both methods use an identical set of Unicode white-space characters.

Split(Char[], StringSplitOptions) Split(Char[], StringSplitOptions) Split(Char[], StringSplitOptions) Split(Char[], StringSplitOptions)

配列内の文字に基づいて文字列を部分文字列に分割します。Splits a string into substrings based on the characters in an array. 部分文字列が空の配列の要素を含めるかどうかを指定することができます。You can specify whether the substrings include empty array elements.

public:
 cli::array <System::String ^> ^ Split(cli::array <char> ^ separator, StringSplitOptions options);
[System.Runtime.InteropServices.ComVisible(false)]
public string[] Split (char[] separator, StringSplitOptions options);
member this.Split : char[] * StringSplitOptions -> string[]
Public Function Split (separator As Char(), options As StringSplitOptions) As String()

パラメーター

separator
Char[]

この文字列から部分文字列を取り出すために区切り文字として使用する文字配列、区切り文字が含まれていない空の配列、または nullA character array that delimits the substrings in this string, an empty array that contains no delimiters, or null.

options
StringSplitOptions StringSplitOptions StringSplitOptions StringSplitOptions

返される配列から空の配列要素を省略する場合は RemoveEmptyEntries。返される配列に空の配列要素も含める場合は NoneRemoveEmptyEntries to omit empty array elements from the array returned; or None to include empty array elements in the array returned.

戻り値

String[]

この文字列を、separator 配列のいずれかまたは複数の要素 (文字) で区切ることによって取り出された部分文字列を格納する配列。An array whose elements contain the substrings in this string that are delimited by one or more characters in separator. 詳細については、「解説」を参照してください。For more information, see the Remarks section.

例外

optionsStringSplitOptions 値のいずれでもありません。options is not one of the StringSplitOptions values.

次の例では、StringSplitOptions列挙体によって生成された部分文字列を含めたり除外したり、Splitメソッド。The following example uses the StringSplitOptions enumeration to include or exclude substrings generated by the Split method.

// This example demonstrates the String.Split(Char[], Boolean) and 
//                               String.Split(Char[], Int32, Boolean) methods
using namespace System;
void Show( array<String^>^entries )
{
   Console::WriteLine( "The return value contains these {0} elements:", entries->Length );
   System::Collections::IEnumerator^ myEnum = entries->GetEnumerator();
   while ( myEnum->MoveNext() )
   {
      String^ entry = safe_cast<String^>(myEnum->Current);
      Console::Write( "<{0}>", entry );
   }

   Console::Write( "{0}{0}", Environment::NewLine );
}

int main()
{
   String^ s = ",one,,,two,,,,,three,,";
   array<Char>^sep = gcnew array<Char>{
      ','
   };
   array<String^>^result;
   
   //
   Console::WriteLine( "The original string is \"{0}\".", s );
   Console::WriteLine( "The separation character is '{0}'.", sep[ 0 ] );
   Console::WriteLine();
   
   //
   Console::WriteLine( "Split the string and return all elements:" );
   result = s->Split( sep, StringSplitOptions::None );
   Show( result );
   
   //
   Console::WriteLine( "Split the string and return all non-empty elements:" );
   result = s->Split( sep, StringSplitOptions::RemoveEmptyEntries );
   Show( result );
   
   //
   Console::WriteLine( "Split the string and return 2 elements:" );
   result = s->Split( sep, 2, StringSplitOptions::None );
   Show( result );
   
   //
   Console::WriteLine( "Split the string and return 2 non-empty elements:" );
   result = s->Split( sep, 2, StringSplitOptions::RemoveEmptyEntries );
   Show( result );
}

/*
This example produces the following results:

The original string is ",one,,,two,,,,,three,,".
The separation character is ','.

Split the string and return all elements:
The return value contains these 12 elements:
<><one><><><two><><><><><three><><>

Split the string and return all non-empty elements:
The return value contains these 3 elements:
<one><two><three>

Split the string and return 2 elements:
The return value contains these 2 elements:
<><one,,,two,,,,,three,,>

Split the string and return 2 non-empty elements:
The return value contains these 2 elements:
<one><,,two,,,,,three,,>

*/
// This example demonstrates the String() methods that use
// the StringSplitOptions enumeration.
string s1 = ",ONE,,TWO,,,THREE,,";
string s2 = "[stop]" +
            "ONE[stop][stop]" +
            "TWO[stop][stop][stop]" +
            "THREE[stop][stop]";
char[] charSeparators = new char[] {','};
string[] stringSeparators = new string[] {"[stop]"};
string[] result;
// ------------------------------------------------------------------------------
// Split a string delimited by characters.
// ------------------------------------------------------------------------------
Console.WriteLine("1) Split a string delimited by characters:\n");

// Display the original string and delimiter characters.
Console.WriteLine("1a )The original string is \"{0}\".", s1);
Console.WriteLine("The delimiter character is '{0}'.\n", 
                   charSeparators[0]);

// Split a string delimited by characters and return all elements.
Console.WriteLine("1b) Split a string delimited by characters and " +
                  "return all elements:");
result = s1.Split(charSeparators, StringSplitOptions.None);
Show(result);

// Split a string delimited by characters and return all non-empty elements.
Console.WriteLine("1c) Split a string delimited by characters and " +
                  "return all non-empty elements:");
result = s1.Split(charSeparators, StringSplitOptions.RemoveEmptyEntries);
Show(result);

// Split the original string into the string and empty string before the 
// delimiter and the remainder of the original string after the delimiter.
Console.WriteLine("1d) Split a string delimited by characters and " +
                  "return 2 elements:");
result = s1.Split(charSeparators, 2, StringSplitOptions.None);
Show(result);

// Split the original string into the string after the delimiter and the 
// remainder of the original string after the delimiter.
Console.WriteLine("1e) Split a string delimited by characters and " +
                  "return 2 non-empty elements:");
result = s1.Split(charSeparators, 2, StringSplitOptions.RemoveEmptyEntries);
Show(result);

// ------------------------------------------------------------------------------
// Split a string delimited by another string.
// ------------------------------------------------------------------------------
Console.WriteLine("2) Split a string delimited by another string:\n");

// Display the original string and delimiter string.
Console.WriteLine("2a) The original string is \"{0}\".", s2);
Console.WriteLine("The delimiter string is \"{0}\".\n", stringSeparators[0]);

// Split a string delimited by another string and return all elements.
Console.WriteLine("2b) Split a string delimited by another string and " +
                  "return all elements:");
result = s2.Split(stringSeparators, StringSplitOptions.None);
Show(result);

// Split the original string at the delimiter and return all non-empty elements.
Console.WriteLine("2c) Split a string delimited by another string and " +
                  "return all non-empty elements:");
result = s2.Split(stringSeparators, StringSplitOptions.RemoveEmptyEntries);
Show(result);

// Split the original string into the empty string before the 
// delimiter and the remainder of the original string after the delimiter.
Console.WriteLine("2d) Split a string delimited by another string and " +
                  "return 2 elements:");
result = s2.Split(stringSeparators, 2, StringSplitOptions.None);
Show(result);

// Split the original string into the string after the delimiter and the 
// remainder of the original string after the delimiter.
Console.WriteLine("2e) Split a string delimited by another string and " + 
                  "return 2 non-empty elements:");
result = s2.Split(stringSeparators, 2, StringSplitOptions.RemoveEmptyEntries);
Show(result);

// Display the array of separated strings using a local function
void Show(string[] entries)
{
    Console.WriteLine("The return value contains these {0} elements:", entries.Length);
    foreach (string entry in entries)
    {
        Console.Write("<{0}>", entry);
    }
    Console.Write("\n\n");
}

/*
This example produces the following results:

1) Split a string delimited by characters:

1a )The original string is ",ONE,,TWO,,,THREE,,".
The delimiter character is ','.

1b) Split a string delimited by characters and return all elements:
The return value contains these 9 elements:
<><ONE><><TWO><><><THREE><><>

1c) Split a string delimited by characters and return all non-empty elements:
The return value contains these 3 elements:
<ONE><TWO><THREE>

1d) Split a string delimited by characters and return 2 elements:
The return value contains these 2 elements:
<><ONE,,TWO,,,THREE,,>

1e) Split a string delimited by characters and return 2 non-empty elements:
The return value contains these 2 elements:
<ONE><TWO,,,THREE,,>

2) Split a string delimited by another string:

2a) The original string is "[stop]ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]".
The delimiter string is "[stop]".

2b) Split a string delimited by another string and return all elements:
The return value contains these 9 elements:
<><ONE><><TWO><><><THREE><><>

2c) Split a string delimited by another string and return all non-empty elements:
The return value contains these 3 elements:
<ONE><TWO><THREE>

2d) Split a string delimited by another string and return 2 elements:
The return value contains these 2 elements:
<><ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]>

2e) Split a string delimited by another string and return 2 non-empty elements:
The return value contains these 2 elements:
<ONE><TWO[stop][stop][stop]THREE[stop][stop]>

*/

' This example demonstrates the String() methods that use
' the StringSplitOptions enumeration.
Imports System

Class Sample
    Public Shared Sub Main() 
        Dim s1 As String = ",ONE,,TWO,,,THREE,,"
        Dim s2 As String = "[stop]" & _
                           "ONE[stop][stop]" & _
                           "TWO[stop][stop][stop]" & _
                           "THREE[stop][stop]"
        Dim charSeparators() As Char = {","c}
        Dim stringSeparators() As String = {"[stop]"}
        Dim result() As String
        ' ------------------------------------------------------------------------------
        ' Split a string delimited by characters.
        ' ------------------------------------------------------------------------------
        Console.WriteLine("1) Split a string delimited by characters:" & vbCrLf)
        
        ' Display the original string and delimiter characters.
        Console.WriteLine("1a )The original string is ""{0}"".", s1)
        Console.WriteLine("The delimiter character is '{0}'." & vbCrLf, charSeparators(0))
        
        ' Split a string delimited by characters and return all elements.
        Console.WriteLine("1b) Split a string delimited by characters and " & _
                          "return all elements:")
        result = s1.Split(charSeparators, StringSplitOptions.None)
        Show(result)
        
        ' Split a string delimited by characters and return all non-empty elements.
        Console.WriteLine("1c) Split a string delimited by characters and " & _
                          "return all non-empty elements:")
        result = s1.Split(charSeparators, StringSplitOptions.RemoveEmptyEntries)
        Show(result)
        
        ' Split the original string into the string and empty string before the 
        ' delimiter and the remainder of the original string after the delimiter.
        Console.WriteLine("1d) Split a string delimited by characters and " & _
                          "return 2 elements:")
        result = s1.Split(charSeparators, 2, StringSplitOptions.None)
        Show(result)
        
        ' Split the original string into the string after the delimiter and the 
        ' remainder of the original string after the delimiter.
        Console.WriteLine("1e) Split a string delimited by characters and " & _
                          "return 2 non-empty elements:")
        result = s1.Split(charSeparators, 2, StringSplitOptions.RemoveEmptyEntries)
        Show(result)
        
        ' ------------------------------------------------------------------------------
        ' Split a string delimited by another string.
        ' ------------------------------------------------------------------------------
        Console.WriteLine("2) Split a string delimited by another string:" & vbCrLf)
        
        ' Display the original string and delimiter string.
        Console.WriteLine("2a) The original string is ""{0}"".", s2)
        Console.WriteLine("The delimiter string is ""{0}""." & vbCrLf, stringSeparators(0))
        
        ' Split a string delimited by another string and return all elements.
        Console.WriteLine("2b) Split a string delimited by another string and " & _
                          "return all elements:")
        result = s2.Split(stringSeparators, StringSplitOptions.None)
        Show(result)
        
        ' Split the original string at the delimiter and return all non-empty elements.
        Console.WriteLine("2c) Split a string delimited by another string and " & _
                          "return all non-empty elements:")
        result = s2.Split(stringSeparators, StringSplitOptions.RemoveEmptyEntries)
        Show(result)
        
        ' Split the original string into the empty string before the 
        ' delimiter and the remainder of the original string after the delimiter.
        Console.WriteLine("2d) Split a string delimited by another string and " & _
                          "return 2 elements:")
        result = s2.Split(stringSeparators, 2, StringSplitOptions.None)
        Show(result)
        
        ' Split the original string into the string after the delimiter and the 
        ' remainder of the original string after the delimiter.
        Console.WriteLine("2e) Split a string delimited by another string and " & _
                          "return 2 non-empty elements:")
        result = s2.Split(stringSeparators, 2, StringSplitOptions.RemoveEmptyEntries)
        Show(result)
    
    End Sub 'Main
    
    
    ' Display the array of separated strings.
    Public Shared Sub Show(ByVal entries() As String) 
        Console.WriteLine("The return value contains these {0} elements:", entries.Length)
        Dim entry As String
        For Each entry In  entries
            Console.Write("<{0}>", entry)
        Next entry
        Console.Write(vbCrLf & vbCrLf)
    
    End Sub 'Show
End Class 'Sample
'
'This example produces the following results:
'
'1) Split a string delimited by characters:
'
'1a )The original string is ",ONE,,TWO,,,THREE,,".
'The delimiter character is ','.
'
'1b) Split a string delimited by characters and return all elements:
'The return value contains these 9 elements:
'<><ONE><><TWO><><><THREE><><>
'
'1c) Split a string delimited by characters and return all non-empty elements:
'The return value contains these 3 elements:
'<ONE><TWO><THREE>
'
'1d) Split a string delimited by characters and return 2 elements:
'The return value contains these 2 elements:
'<><ONE,,TWO,,,THREE,,>
'
'1e) Split a string delimited by characters and return 2 non-empty elements:
'The return value contains these 2 elements:
'<ONE><TWO,,,THREE,,>
'
'2) Split a string delimited by another string:
'
'2a) The original string is "[stop]ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]".
'The delimiter string is "[stop]".
'
'2b) Split a string delimited by another string and return all elements:
'The return value contains these 9 elements:
'<><ONE><><TWO><><><THREE><><>
'
'2c) Split a string delimited by another string and return all non-empty elements:
'The return value contains these 3 elements:
'<ONE><TWO><THREE>
'
'2d) Split a string delimited by another string and return 2 elements:
'The return value contains these 2 elements:
'<><ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]>
'
'2e) Split a string delimited by another string and return 2 non-empty elements:
'The return value contains these 2 elements:
'<ONE><TWO[stop][stop][stop]THREE[stop][stop]>
'

注釈

戻り値の詳細Return value details

区切り記号文字 (文字、separator配列) は、返される配列の要素に含まれません。Delimiter characters (the characters in the separator array) are not included in the elements of the returned array. たとえば場合、separator配列には、文字が含まれています。"-"と現在の文字列インスタンスの値は"aa、bb、cc"、3 つの要素を含む配列を返します:"aa"、"bb"、"cc"。For example, if the separator array includes the character "-" and the value of the current string instance is "aa-bb-cc", the method returns an array that contains three elements: "aa", "bb", and "cc".

このインスタンスに文字が含まれていないかどうかはseparator、返される配列は、このインスタンスを含む 1 つの要素で構成されています。If this instance does not contain any of the characters in separator, the returned array consists of a single element that contains this instance.

場合、optionsパラメーターがRemoveEmptyEntriesとこのインスタンスの長さがゼロ、空の配列を返します。If the options parameter is RemoveEmptyEntries and the length of this instance is zero, the method returns an empty array.

各要素separator単一の文字で構成されている別の区切り記号を定義します。Each element of separator defines a separate delimiter that consists of a single character. 場合、options引数がNone、2 つの区切り記号は隣接して、または配列の対応する要素を含む、先頭または、このインスタンスの末尾に、区切り記号が見つかったString.Emptyします。If the options argument is None, and two delimiters are adjacent or a delimiter is found at the beginning or end of this instance, the corresponding array element contains String.Empty. たとえば場合、 separator 2 つの要素が含まれています"-"と"_"、文字列インスタンスの値が"-_aa -_"の値、options引数がNoneメソッドの文字列配列を返します次の 5 つの要素。For example, if separator includes two elements, "-" and "_", the value of the string instance is "-_aa-_", and the value of the options argument is None, the method returns a string array with the following five elements:

  1. String.Emptyを前にある空の文字列を表す、"-"インデックス 0 位置にある文字。String.Empty, which represents the empty string that precedes the "-" character at index 0.

  2. String.Empty、間の空の文字列を表す、"-"インデックス 0 と 1 のインデックス位置にある文字「」にある文字。String.Empty, which represents the empty string between the "-" character at index 0 and the "" character at index 1.

  3. "aa"など"aa",

  4. String.Emptyを表すインデックス 4 文字「」に続く空の文字列。String.Empty, which represents the empty string that follows the "" character at index 4.

  5. String.Empty、次の空の文字列を表す、"-"文字のインデックスを 5 にします。String.Empty, which represents the empty string that follows the "-" character at index 5.

区切り記号の配列The separator array

場合、separatorパラメーターがnull文字が含まれていない、または空白文字が区切り記号と見なされます。If the separator parameter is null or contains no characters, white-space characters are assumed to be the delimiters. 空白文字が Unicode 標準および戻り値によって定義されますtrueに渡された場合、Char.IsWhiteSpaceメソッド。White-space characters are defined by the Unicode standard and return true if they are passed to the Char.IsWhiteSpace method.

場合、separatorこのメソッドのオーバー ロードの呼び出しでパラメーターがnullコンパイラのオーバー ロードの解決は失敗します。If the separator parameter in the call to this method overload is null, compiler overload resolution fails. 呼び出されたメソッドを明確に識別するコードがの型を示す必要があります、nullします。To unambiguously identify the called method, your code must indicate the type of the null. 次の例では、このオーバー ロードを明確に識別するためにいくつかの方法を示します。The following example shows several ways to unambiguously identify this overload.

string phrase = "The quick  brown fox";
string[] words;

words = phrase.Split(default(Char[]), StringSplitOptions.RemoveEmptyEntries);

words = phrase.Split((char[]) null, StringSplitOptions.RemoveEmptyEntries);

words = phrase.Split(null as char[], StringSplitOptions.RemoveEmptyEntries);
Dim phrase As String = "The quick brown fox"
Dim words() As String

words = phrase.Split(TryCast(Nothing, Char()),  
                       StringSplitOptions.RemoveEmptyEntries)

words = phrase.Split(New Char() {}, 
                     StringSplitOptions.RemoveEmptyEntries)

比較の詳細Comparison details

Splitメソッドが 1 つ以上の文字で区切られた、この文字列の部分文字列を抽出し、separatorパラメーター、配列の要素としてそれらの部分文字列を返します。The Split method extracts the substrings in this string that are delimited by one or more of the characters in the separator parameter, and returns those substrings as elements of an array.

Splitメソッドが大文字の序数の並べ替え規則を使用する比較を実行することでは区切り記号を検索します。The Split method looks for delimiters by performing comparisons using case-sensitive ordinal sort rules. 単語、文字列、および序数の並べ替えの詳細については、次を参照してください。、System.Globalization.CompareOptions列挙体。For more information about word, string, and ordinal sorts, see the System.Globalization.CompareOptions enumeration.

パフォーマンスに関する考慮事項Performance Considerations

Splitメソッドが返される配列オブジェクトのメモリを割り当てると、String配列の各要素のオブジェクト。The Split methods allocate memory for the returned array object and a String object for each array element. アプリケーションに最適なパフォーマンスを必要な場合、またはメモリの割り当てを管理するは、アプリケーションで重要な場合は、使用を検討して、IndexOfまたはIndexOfAnyメソッド、および必要に応じて、Compareメソッドは、文字列内の部分文字列を検索します。If your application requires optimal performance or if managing memory allocation is critical in your application, consider using the IndexOf or IndexOfAny method, and optionally the Compare method, to locate a substring within a string.

区切り記号文字の文字列を分割する場合は、使用、IndexOfまたはIndexOfAny文字列の区切り記号の文字を検索するメソッド。If you are splitting a string at a separator character, use the IndexOf or IndexOfAny method to locate a separator character in the string. 文字列に区切り記号文字列を分割する場合は、使用、IndexOfまたはIndexOfAny区切り記号の文字列の最初の文字を検索するメソッド。If you are splitting a string at a separator string, use the IndexOf or IndexOfAny method to locate the first character of the separator string. 使用して、Compareその最初の文字の後に文字が区切り記号の文字列の残りの文字に等しいかどうかを判断するメソッド。Then use the Compare method to determine whether the characters after that first character are equal to the remaining characters of the separator string.

さらに、同じ設定する場合の文字が使用で複数の文字列を分割するSplitメソッドの呼び出しが 1 つの配列を作成して、各メソッド呼び出しで参照することを検討してください。In addition, if the same set of characters is used to split strings in multiple Split method calls, consider creating a single array and referencing it in each method call. これには、各メソッド呼び出しのオーバーヘッドが大幅に削減されます。This significantly reduces the additional overhead of each method call.

注意 (呼び出し元)

.NET Framework 3.5.NET Framework 3.5以前のバージョンでは場合、Split(Char[])メソッドに渡されます、separatornull文字が含まれていない、またはメソッドは若干異なる一連の文字を使用してよりも文字列を分割する、Trim(Char[])メソッドには文字列を切り捨てます。In the .NET Framework 3.5.NET Framework 3.5 and earlier versions, if the Split(Char[]) method is passed a separator that is null or contains no characters, the method uses a slightly different set of characters to split the string than the Trim(Char[]) method does to trim the string. 以降、.NET Framework 4 では、どちらの方法は、同一 Unicode の空白文字のセットを使用します。Starting with the .NET Framework 4, both methods use an identical set of Unicode white-space characters.

Split(Char[], Int32) Split(Char[], Int32) Split(Char[], Int32) Split(Char[], Int32)

配列内の文字に基づいて文字列を最大数の部分文字列に分割します。Splits a string into a maximum number of substrings based on the characters in an array. 返される部分文字列の最大数を指定します。You also specify the maximum number of substrings to return.

public:
 cli::array <System::String ^> ^ Split(cli::array <char> ^ separator, int count);
public string[] Split (char[] separator, int count);
member this.Split : char[] * int -> string[]
Public Function Split (separator As Char(), count As Integer) As String()

パラメーター

separator
Char[]

この文字列から部分文字列を取り出すために区切り文字として使用する文字配列、区切り文字が含まれていない空の配列、または nullA character array that delimits the substrings in this string, an empty array that contains no delimiters, or null.

count
Int32 Int32 Int32 Int32

返される最大の部分文字列数。The maximum number of substrings to return.

戻り値

String[]

このインスタンスを、separator 配列のいずれかまたは複数の要素 (文字) で区切ることによって取り出された部分文字列を格納する配列。An array whose elements contain the substrings in this instance that are delimited by one or more characters in separator. 詳細については、「解説」を参照してください。For more information, see the Remarks section.

例外

次の例でどのようにcountによって返される文字列の数に影響を与えますSplitします。The following example demonstrates how count affects the number of strings returned by Split.

string delimStr = " ,.:";
char [] delimiter = delimStr.ToCharArray();
string words = "one two,three:four.";
string [] split = null;

Console.WriteLine("The delimiters are -{0}-", delimStr);
for (int x = 1; x <= 5; x++) {
   split = words.Split(delimiter, x);
   Console.WriteLine("\ncount = {0,2} ..............", x);
   foreach (var s in split) {
       Console.WriteLine("-{0}-", s);
   }
}
// The example displays the following output:
//       The delimiters are - ,.:-
//       count =  1 ..............
//       -one two,three:four.-
//       count =  2 ..............
//       -one-
//       -two,three:four.-
//       count =  3 ..............
//       -one-
//       -two-
//       -three:four.-
//       count =  4 ..............
//       -one-
//       -two-
//       -three-
//       -four.-
//       count =  5 ..............
//       -one-
//       -two-
//       -three-
//       -four-
//       --
Public Class StringSplit2
   Public Shared Sub Main()
      
      Dim delimStr As String = " ,.:"
      Dim delimiter As Char() = delimStr.ToCharArray()
      Dim words As String = "one two,three:four."
      Dim split As String() = Nothing
      
      Console.WriteLine("The delimiters are -{0}-", delimStr)
      Dim x As Integer
      For x = 1 To 5
         split = words.Split(delimiter, x)
         Console.WriteLine(ControlChars.Cr + "count = {0,2} ..............", x)
         Dim s As String
         For Each s In  split
            Console.WriteLine("-{0}-", s)
         Next s
      Next x
   End Sub 
End Class 
' The example displays the following output:
'       The delimiters are - ,.:-
'       count =  1 ..............
'       -one two,three:four.-
'       count =  2 ..............
'       -one-
'       -two,three:four.-
'       count =  3 ..............
'       -one-
'       -two-
'       -three:four.-
'       count =  4 ..............
'       -one-
'       -two-
'       -three-
'       -four.-
'       count =  5 ..............
'       -one-
'       -two-
'       -three-
'       -four-
'       --

注釈

返される配列の要素では、区切り記号の文字は含まれません。Delimiter characters are not included in the elements of the returned array.

このインスタンスに文字が含まれていないかどうかはseparator、返される配列は、このインスタンスを含む 1 つの要素で構成されています。If this instance does not contain any of the characters in separator, the returned array consists of a single element that contains this instance. 場合count0 の場合は、空の配列が返されます。If count is zero, an empty array is returned.

場合、separatorパラメーターがnull文字が含まれていない、または空白文字が区切り記号と見なされます。If the separator parameter is null or contains no characters, white-space characters are assumed to be the delimiters. 空白文字が Unicode 標準および戻り値によって定義されますtrueに渡された場合、Char.IsWhiteSpaceメソッド。White-space characters are defined by the Unicode standard and return true if they are passed to the Char.IsWhiteSpace method.

各要素separator別の区切り記号を定義します。Each element of separator defines a separate delimiter character. 配列の対応する要素を含む 2 つの区切り記号は、隣接するセル、または区切り記号が先頭またはこのインスタンスの末尾に見つかった、Emptyします。If two delimiters are adjacent, or a delimiter is found at the beginning or end of this instance, the corresponding array element contains Empty.

ある場合は、複数のcount、このインスタンス内の部分文字列最初countマイナス 1 の部分文字列が最初に返されますcount-1、戻り値のこのインスタンスの残りの文字が最後に返されます戻り値の要素。If there are more than count substrings in this instance, the first count minus 1 substrings are returned in the first count minus 1 elements of the return value, and the remaining characters in this instance are returned in the last element of the return value.

場合count数より大きい、部分文字列の使用可能な部分文字列が返され、例外はスローされません。If count is greater than the number of substrings, the available substrings are returned and no exception is thrown.

次の表では、例を示します。The following table provides examples.

文字列値String value 区切り記号Separator カウントCount 返される配列Returned array
"42, 12, 19""42, 12, 19" new Char[] {',', ' '} (C#)new Char[] {',', ' '} (C#)

Char() = {「,」c""c} (Visual Basic)Char() = {","c, " "c} (Visual Basic)
22 {"42", " 12, 19"}{"42", " 12, 19"}
"42..12..19""42..12..19" new Char[] {'.'}new Char[] {'.'} (C#)(C#)

Char() = {0}"."c} (Visual Basic)Char() = {"."c} (Visual Basic)
44 {"42", "", "12", ".19"}{"42", "", "12", ".19"}
"Banana""Banana" new Char[] {'.'}new Char[] {'.'} (C#)(C#)

Char() = {0}"."c} (Visual Basic)Char() = {"."c} (Visual Basic)
22 {"Banana"}{"Banana"}
"Darb\nSmarba"(c#)"Darb\nSmarba" (C#)

"Darb"& vbLf"Smarba"(Visual Basic)"Darb" & vbLf & "Smarba" (Visual Basic)
新しいを Char {} (C#)new Char[] {} (C#)

Char() = {} (Visual Basic)Char() = {} (Visual Basic)
11 {"Darb\nSmarba"}(C#){"Darb\nSmarba"} (C#)

"Darb"& vbLf"Smarba"(Visual Basic)"Darb" & vbLf & "Smarba" (Visual Basic)
"Darb\nSmarba"(c#)"Darb\nSmarba" (C#)

"Darb"& vbLf"Smarba"(Visual Basic)"Darb" & vbLf & "Smarba" (Visual Basic)
null の新しい charnew Char[] null (C#)

Char() = NothingChar() = Nothing
22 {"Darb"、"Smarba"}{"Darb", "Smarba"}
"Darb\nSmarba"(c#)"Darb\nSmarba" (C#)

"Darb"& vbLf"Smarba"(Visual Basic)"Darb" & vbLf & "Smarba" (Visual Basic)
null の新しい charnew Char[] null (C#)

Char() = NothingChar() = Nothing
100100 {"Darb"、"Smarba"}{"Darb", "Smarba"}

パフォーマンスに関する考慮事項Performance Considerations

Splitメソッドが返される配列オブジェクトのメモリを割り当てると、String配列の各要素のオブジェクト。The Split methods allocate memory for the returned array object and a String object for each array element. アプリケーションに最適なパフォーマンスを必要な場合、またはメモリの割り当てを管理するは、アプリケーションで重要な場合は、使用を検討して、IndexOfまたはIndexOfAnyメソッド、および必要に応じて、Compareメソッドは、文字列内の部分文字列を検索します。If your application requires optimal performance or if managing memory allocation is critical in your application, consider using the IndexOf or IndexOfAny method, and optionally the Compare method, to locate a substring within a string.

区切り記号文字の文字列を分割する場合は、使用、IndexOfまたはIndexOfAny文字列の区切り記号の文字を検索するメソッド。If you are splitting a string at a separator character, use the IndexOf or IndexOfAny method to locate a separator character in the string. 文字列に区切り記号文字列を分割する場合は、使用、IndexOfまたはIndexOfAny区切り記号の文字列の最初の文字を検索するメソッド。If you are splitting a string at a separator string, use the IndexOf or IndexOfAny method to locate the first character of the separator string. 使用して、Compareその最初の文字の後に文字が区切り記号の文字列の残りの文字に等しいかどうかを判断するメソッド。Then use the Compare method to determine whether the characters after that first character are equal to the remaining characters of the separator string.

さらに、同じ設定する場合の文字が使用で複数の文字列を分割するSplitメソッドの呼び出しが 1 つの配列を作成して、各メソッド呼び出しで参照することを検討してください。In addition, if the same set of characters is used to split strings in multiple Split method calls, consider creating a single array and referencing it in each method call. これには、各メソッド呼び出しのオーバーヘッドが大幅に削減されます。This significantly reduces the additional overhead of each method call.

注意 (呼び出し元)

.NET Framework 3.5.NET Framework 3.5以前のバージョンでは場合、Split(Char[])メソッドに渡されます、separatornull文字が含まれていない、またはメソッドは若干異なる一連の文字を使用してよりも文字列を分割する、Trim(Char[])メソッドには文字列を切り捨てます。In the .NET Framework 3.5.NET Framework 3.5 and earlier versions, if the Split(Char[]) method is passed a separator that is null or contains no characters, the method uses a slightly different set of characters to split the string than the Trim(Char[]) method does to trim the string. 以降、.NET Framework 4 では、どちらの方法は、同一 Unicode の空白文字のセットを使用します。Starting with the .NET Framework 4, both methods use an identical set of Unicode white-space characters.

こちらもご覧ください

Split(Char, StringSplitOptions) Split(Char, StringSplitOptions) Split(Char, StringSplitOptions)

public string[] Split (char separator, StringSplitOptions options = System.StringSplitOptions.None);
member this.Split : char * StringSplitOptions -> string[]
Public Function Split (separator As Char, Optional options As StringSplitOptions = System.StringSplitOptions.None) As String()

パラメーター

separator
Char Char Char Char

戻り値

String[]

Split(Char[]) Split(Char[]) Split(Char[]) Split(Char[])

配列内の文字に基づいて文字列を部分文字列に分割します。Splits a string into substrings that are based on the characters in an array.

public:
 cli::array <System::String ^> ^ Split(... cli::array <char> ^ separator);
public string[] Split (params char[] separator);
member this.Split : char[] -> string[]
Public Function Split (ParamArray separator As Char()) As String()

パラメーター

separator
Char[]

この文字列から部分文字列を取り出すために区切り文字として使用する文字配列、区切り文字が含まれていない空の配列、または nullA character array that delimits the substrings in this string, an empty array that contains no delimiters, or null.

戻り値

String[]

このインスタンスを separator の 1 つ以上の文字で区切った部分文字列を要素に格納する配列。An array whose elements contain the substrings from this instance that are delimited by one or more characters in separator. 詳細については、「解説」を参照してください。For more information, see the Remarks section.

次の例では、空白や句読点を区切り記号として扱うことにより、テキストのブロックから個々 の単語を抽出する方法を示します。The following example demonstrates how to extract individual words from a block of text by treating white space and punctuation marks as delimiters. 渡された文字の配列、separatorのパラメーター、String.Split(Char[])メソッドは、空白文字とと共に一部の一般的な区切り記号のタブ文字で構成されます。The character array passed to the separator parameter of the String.Split(Char[]) method consists of a space character and a tab character, together with some common punctuation symbols.

string words = "This is a list of words, with: a bit of punctuation" +
               "\tand a tab character.";

string [] split = words.Split(new Char [] {' ', ',', '.', ':', '\t' });

foreach (string s in split) {

    if (s.Trim() != "")
        Console.WriteLine(s);
}
// The example displays the following output to the console:
//       This
//       is
//       a
//       list
//       of
//       words
//       with
//       a
//       bit
//       of
//       punctuation
//       and
//       a
//       tab
//       character
Public Class SplitTest
    Public Shared Sub Main()
        Dim words As String = "This is a list of words, with: a bit of punctuation" + _
                              vbTab + "and a tab character."
        Dim split As String() = words.Split(New [Char]() {" "c, ","c, "."c, ":"c, CChar(vbTab) })
                
        For Each s As String In  split
            If s.Trim() <> "" Then
                Console.WriteLine(s)
            End If
        Next s
    End Sub 'Main
End Class 'SplitTest
' The example displays the following output to the console:
'       This
'       is
'       a
'       list
'       of
'       words
'       with
'       a
'       bit
'       of
'       punctuation
'       and
'       a
'       tab
'       character

注釈

文字列は、既知の一連の文字で区切られた、ときに使用できます、Split(Char[])メソッドを部分文字列に分割します。When a string is delimited by a known set of characters, you can use the Split(Char[]) method to separate it into substrings.

戻り値の詳細Return value details

返される配列の要素では、区切り記号の文字は含まれません。Delimiter characters are not included in the elements of the returned array. たとえば、区切り記号の配列に文字が含まれています"-"と、現在の文字列インスタンスの値は"aa、bb、cc"、3 つの要素を含む配列を返します:"aa"、"bb"、"cc"。For example, if the separator array includes the character "-" and the value of the current string instance is "aa-bb-cc", the method returns an array that contains three elements: "aa", "bb", and "cc".

このインスタンスに文字が含まれていないかどうかはseparator、返される配列は、このインスタンスを含む 1 つの要素で構成されています。If this instance does not contain any of the characters in separator, the returned array consists of a single element that contains this instance.

各要素separator別の区切り記号を定義します。Each element of separator defines a separate delimiter character. 返される配列に対応する要素に含まれる 2 つの区切り記号は、隣接するセル、または区切り記号が先頭またはこのインスタンスの末尾に見つかった、Emptyします。If two delimiters are adjacent, or a delimiter is found at the beginning or end of this instance, the corresponding element in the returned array contains Empty. 次にいくつかの例を示します。Here are some examples:

文字列値String value 区切り記号Separator 返される配列Returned array
"42, 12, 19""42, 12, 19" new Char[] {',', ' '} (C#)new Char[] {',', ' '} (C#)

Char() = {「,」c""c}) (Visual Basic)Char() = {","c, " "c}) (Visual Basic)
{"42", "", "12", "", "19"}{"42", "", "12", "", "19"}
"42..12..19""42..12..19" new Char[] {'.'}new Char[] {'.'} (C#)(C#)

Char() = {0}"."c} (Visual Basic)Char() = {"."c} (Visual Basic)
{"42", "", "12", "", "19"}{"42", "", "12", "", "19"}
"Banana""Banana" new Char[] {'.'}new Char[] {'.'} (C#)(C#)

Char() = {0}"."c} (Visual Basic)Char() = {"."c} (Visual Basic)
{"Banana"}{"Banana"}
"Darb\nSmarba"(c#)"Darb\nSmarba" (C#)

"Darb"& vbLf"Smarba"(Visual Basic)"Darb" & vbLf & "Smarba" (Visual Basic)
新しいを Char {} (C#)new Char[] {} (C#)

Char() = {} (Visual Basic)Char() = {} (Visual Basic)
{"Darb"、"Smarba"}{"Darb", "Smarba"}
"Darb\nSmarba"(c#)"Darb\nSmarba" (C#)

"Darb"& vbLf"Smarba"(Visual Basic)"Darb" & vbLf & "Smarba" (Visual Basic)
null (C#)null (C#)

Nothing (Visual Basic)Nothing (Visual Basic)
{"Darb"、"Smarba"}{"Darb", "Smarba"}

区切り記号の配列The separator array

区切り記号の各要素は、単一の文字で構成されている別の区切り記号を定義します。Each element of separator defines a separate delimiter that consists of a single character. 場合、separator引数がnull文字が含まれていない、またはメソッドの空白文字を区切り記号として扱われます。If the separator argument is null or contains no characters, the method treats white-space characters as the delimiters. 空白文字が Unicode 標準; で定義されています。返されるtrueに渡された場合、Char.IsWhiteSpaceメソッド。White-space characters are defined by the Unicode standard; they return true if they are passed to the Char.IsWhiteSpace method.

String.Split(Char[]) コンパイラ オーバー ロードの解決String.Split(Char[]) and compiler overload resolution

このオーバー ロードの 1 つのパラメーターString.Split文字配列では、次の例として、単一の文字を呼び出すことができます。Although the single parameter for this overload of String.Split is a character array, you can call it with a single character, as the following example shows.

String value = "This is a short string.";
Char delimiter = 's';
String[] substrings = value.Split(delimiter);
foreach (var substring in substrings)
   Console.WriteLine(substring);
// The example displays the following output:
//     Thi
//      i
//      a
//     hort
//     tring.
Module Example
   Public Sub Main()
      Dim value As String = "This is a short string."
      Dim delimiter As Char = "s"c
      Dim substrings() As String = value.Split(delimiter)
      For Each substring In substrings
         Console.WriteLine(substring)
      Next
   End Sub
End Module
' The example displays the following output:
'     Thi
'      i
'      a
'     hort
'     tring.

separatorでパラメーターが修飾されて、ParamArrayAttribute属性に、コンパイラでは、1 つの要素の文字配列として単一の文字が解釈されます。Because the separator parameter is decorated with the ParamArrayAttribute attribute, compilers will interpret a single character as a single-element character array. これは他のケースではありませんString.Split含むオーバー ロードをseparator; パラメーターを渡す必要があります明示的にこれらのオーバー ロードとして文字配列、separator引数。This is not the case for other String.Split overloads that include a separator parameter; you must explicitly pass these overloads a character array as the separator argument.

比較の詳細Comparison details

Split(Char[])メソッドが 1 つ以上の文字で区切られた、この文字列の部分文字列を抽出し、separator配列、および配列の要素としてそれらの部分文字列を返します。The Split(Char[]) method extracts the substrings in this string that are delimited by one or more of the characters in the separator array, and returns those substrings as elements of an array.

Split(Char[])メソッドが大文字の序数の並べ替え規則を使用する比較を実行することでは区切り記号を検索します。The Split(Char[]) method looks for delimiters by performing comparisons using case-sensitive ordinal sort rules. 単語、文字列、および序数の並べ替えの詳細については、次を参照してください。、System.Globalization.CompareOptions列挙体。For more information about word, string, and ordinal sorts, see the System.Globalization.CompareOptions enumeration.

パフォーマンスに関する考慮事項Performance Considerations

Splitメソッドが返される配列オブジェクトのメモリを割り当てると、String配列の各要素のオブジェクト。The Split methods allocate memory for the returned array object and a String object for each array element. アプリケーションに最適なパフォーマンスを必要な場合、またはメモリの割り当てを管理するは、アプリケーションで重要な場合は、使用を検討して、IndexOfまたはIndexOfAnyメソッド。If your application requires optimal performance or if managing memory allocation is critical in your application, consider using the IndexOf or IndexOfAny method. 使用するオプションもある、Compare文字列内の部分文字列を検索するメソッド。You also have the option of using the Compare method to locate a substring within a string.

区切り記号文字の文字列を分割するには、使用、IndexOfまたはIndexOfAny文字列の区切り記号の文字を検索するメソッド。To split a string at a separator character, use the IndexOf or IndexOfAny method to locate a separator character in the string. 文字列に区切り記号文字列を分割するには、使用、IndexOfまたはIndexOfAny区切り記号の文字列の最初の文字を検索するメソッド。To split a string at a separator string, use the IndexOf or IndexOfAny method to locate the first character of the separator string. 使用して、Compareその最初の文字の後に文字が区切り記号の文字列の残りの文字に等しいかどうかを判断するメソッド。Then use the Compare method to determine whether the characters after that first character are equal to the remaining characters of the separator string.

さらに、同じ設定する場合の文字が使用で複数の文字列を分割するSplitメソッドの呼び出しが 1 つの配列を作成して、各メソッド呼び出しで参照することを検討してください。In addition, if the same set of characters is used to split strings in multiple Split method calls, consider creating a single array and referencing it in each method call. これには、各メソッド呼び出しのオーバーヘッドが大幅に削減されます。This significantly reduces the additional overhead of each method call.

注意 (呼び出し元)

.NET Framework 3.5.NET Framework 3.5以前のバージョンでは場合、Split(Char[])メソッドに渡されます、separatornull文字が含まれていない、またはメソッドは若干異なる一連の文字を使用してよりも文字列を分割する、Trim(Char[])メソッドには文字列を切り捨てます。In the .NET Framework 3.5.NET Framework 3.5 and earlier versions, if the Split(Char[]) method is passed a separator that is null or contains no characters, the method uses a slightly different set of characters to split the string than the Trim(Char[]) method does to trim the string. 以降、.NET Framework 4 では、どちらの方法は、同一 Unicode の空白文字のセットを使用します。Starting with the .NET Framework 4, both methods use an identical set of Unicode white-space characters.

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Split(String, StringSplitOptions) Split(String, StringSplitOptions) Split(String, StringSplitOptions)

public string[] Split (string separator, StringSplitOptions options = System.StringSplitOptions.None);
member this.Split : string * StringSplitOptions -> string[]
Public Function Split (separator As String, Optional options As StringSplitOptions = System.StringSplitOptions.None) As String()

パラメーター

戻り値

String[]

適用対象