# Double.MaxValue 필드

## 정의

Double의 가능한 최대값을 나타냅니다.Represents the largest possible value of a Double. 이 필드는 상수입니다.This field is constant.

``public: double MaxValue = 1.7976931348623157E+308;``
``public const double MaxValue = 1.7976931348623157E+308;``
``val mutable MaxValue : double``
``Public Const MaxValue As Double  = 1.7976931348623157E+308``

Double

## 예제

다음 코드 예제에서는를 사용 하는 방법을 보여 줍니다 Double.MaxValue .The following code example illustrates the use of Double.MaxValue:

``````public ref class Temperature
{
public:
static property double MinValue
{
double get()
{
return Double::MinValue;
}
}

static property double MaxValue
{
double get()
{
return Double::MaxValue;
}
}

protected:
// The value holder
double m_value;

public:
property double Value
{
double get()
{
return m_value;
}
void set( double value )
{
m_value = value;
}
}

property double Celsius
{
double get()
{
return (m_value - 32.0) / 1.8;
}
void set( double value )
{
m_value = 1.8 * value + 32.0;
}
}
};
``````
``````public class Temperature {
public static double MinValue {
get {
return Double.MinValue;
}
}

public static double MaxValue {
get {
return Double.MaxValue;
}
}

// The value holder
protected double m_value;

public double Value {
get {
return m_value;
}
set {
m_value = value;
}
}

public double Celsius {
get {
return (m_value-32.0)/1.8;
}
set {
m_value = 1.8*value+32.0;
}
}
}
``````
``````Public Class Temperature

Public Shared ReadOnly Property MinValue() As Double
Get
Return Double.MinValue
End Get
End Property

Public Shared ReadOnly Property MaxValue() As Double
Get
Return Double.MaxValue
End Get
End Property

' The value holder
Protected m_value As Double

Public Property Value() As Double
Get
Return m_value
End Get
Set(ByVal Value As Double)
m_value = Value
End Set
End Property

Public Property Celsius() As Double
Get
Return (m_value - 32) / 1.8
End Get
Set(ByVal Value As Double)
m_value = Value * 1.8 + 32
End Set
End Property
End Class
``````

## 설명

이 상수의 값은 긍정 1.7976931348623157 E + 308입니다.The value of this constant is positive 1.7976931348623157E+308.

를 초과 하는 작업의 결과가 Double.MaxValueDouble.PositiveInfinity 경우The result of an operation that exceeds Double.MaxValue is Double.PositiveInfinity. 다음 예제에서 결과 Double.PositiveInfinity 는 결과가를 초과할 때 더하기, 곱하기 및 시간 연산이 수행 Double.MaxValue 됩니다.In the following example, Double.PositiveInfinity results from addition, multiplication, and exponentiation operations when the result exceeds Double.MaxValue.

``````using System;

public class Example
{
public static void Main()
{
double result1 = 7.997e307 + 9.985e307;
Console.WriteLine("{0} (Positive Infinity: {1})",
result1, Double.IsPositiveInfinity(result1));

double result2 = 1.5935e250 * 7.948e110;
Console.WriteLine("{0} (Positive Infinity: {1})",
result2, Double.IsPositiveInfinity(result2));

double result3 = Math.Pow(1.256e100, 1.34e20);
Console.WriteLine("{0} (Positive Infinity: {1})",
result3, Double.IsPositiveInfinity(result3));
}
}
// The example displays the following output:
//    Infinity (Positive Infinity: True)
//    Infinity (Positive Infinity: True)
//    Infinity (Positive Infinity: True)
``````
``````Module Example
Public Sub Main()
Dim result1 As Double = 7.997e307 + 9.985e307
Console.WriteLine("{0} (Positive Infinity: {1})",
result1, Double.IsPositiveInfinity(result1))

Dim result2 As Double = 1.5935e250 * 7.948e110
Console.WriteLine("{0} (Positive Infinity: {1})",
result2, Double.IsPositiveInfinity(result2))

Dim result3 As Double = Math.Pow(1.256e100, 1.34e20)
Console.WriteLine("{0} (Positive Infinity: {1})",
result3, Double.IsPositiveInfinity(result3))
End Sub
End Module
' The example displays the following output:
'    Infinity (Positive Infinity: True)
'    Infinity (Positive Infinity: True)
'    Infinity (Positive Infinity: True)
``````