Color.Inequality(Color, Color) Operator

public:
 static bool operator !=(System::Drawing::Color left, System::Drawing::Color right);

public static bool operator != (System.Drawing.Color left, System.Drawing.Color right);

static member op_Inequality : System.Drawing.Color * System.Drawing.Color -> bool

Public Shared Operator != (left As Color, right As Color) As Boolean

Parameters

Returns

Boolean

true if the two Color structures are different; otherwise, false.

Examples

The following code example demonstrates the Inequality operator and the SystemColors class. This example is designed to be used with a Windows Form that contains a button named Button2. Paste the following code into your form and associate the Button2_Click method with the button's Click event.

void Button2_Click( System::Object^ /*sender*/, System::EventArgs^ /*e*/ )
{
   if ( this->BackColor != SystemColors::ControlDark )
   {
      this->BackColor = SystemColors::ControlDark;
   }

   if (  !(this->Font->Bold) )
   {
      this->Font = gcnew System::Drawing::Font( this->Font,FontStyle::Bold );
   }
}

private void Button2_Click(System.Object sender, System.EventArgs e)
{

    if (this.BackColor != SystemColors.ControlDark)
    {
        this.BackColor = SystemColors.ControlDark;
    }
    if (!(this.Font.Bold))
    {
        this.Font = new Font(this.Font, FontStyle.Bold);
    }
}

Private Sub Button2_Click(ByVal sender As System.Object, _
    ByVal e As System.EventArgs) Handles Button2.Click

    If (Color.op_Inequality(Me.BackColor, SystemColors.ControlDark)) Then
        Me.BackColor = SystemColors.ControlDark
    End If
    If Not (Me.Font.Bold) Then
        Me.Font = New Font(Me.Font, FontStyle.Bold)
    End If
End Sub

Remarks

This method compares more than the ARGB values of the Color structures. It also does a comparison of some state flags. If you want to compare just the ARGB values of two Color structures, use the ToArgb method.

Applies to