Color.Inequality(Color, Color) Operator


Tests whether two specified Color structures are different.

 static bool operator !=(System::Drawing::Color left, System::Drawing::Color right);
public static bool operator != (System.Drawing.Color left, System.Drawing.Color right);
static member op_Inequality : System.Drawing.Color * System.Drawing.Color -> bool
Public Shared Operator != (left As Color, right As Color) As Boolean



The Color that is to the left of the inequality operator.


The Color that is to the right of the inequality operator.



true if the two Color structures are different; otherwise, false.


The following code example demonstrates the Inequality operator and the SystemColors class. This example is designed to be used with a Windows Form that contains a button named Button2. Paste the following code into your form and associate the Button2_Click method with the button's Click event.

void Button2_Click( System::Object^ /*sender*/, System::EventArgs^ /*e*/ )
   if ( this->BackColor != SystemColors::ControlDark )
      this->BackColor = SystemColors::ControlDark;

   if (  !(this->Font->Bold) )
      this->Font = gcnew System::Drawing::Font( this->Font,FontStyle::Bold );
private void Button2_Click(System.Object sender, System.EventArgs e)

    if (this.BackColor != SystemColors.ControlDark)
        this.BackColor = SystemColors.ControlDark;
    if (!(this.Font.Bold))
        this.Font = new Font(this.Font, FontStyle.Bold);
Private Sub Button2_Click(ByVal sender As System.Object, _
    ByVal e As System.EventArgs) Handles Button2.Click

    If (Color.op_Inequality(Me.BackColor, SystemColors.ControlDark)) Then
        Me.BackColor = SystemColors.ControlDark
    End If
    If Not (Me.Font.Bold) Then
        Me.Font = New Font(Me.Font, FontStyle.Bold)
    End If
End Sub


This method compares more than the ARGB values of the Color structures. It also does a comparison of some state flags. If you want to compare just the ARGB values of two Color structures, use the ToArgb method.

Applies to