# Single.IsNegativeInfinity(Single)Single.IsNegativeInfinity(Single)Single.IsNegativeInfinity(Single)Single.IsNegativeInfinity(Single) Method

## 정의

지정된 숫자가 음의 무한대로 계산되는지를 나타내는 값을 반환합니다.Returns a value indicating whether the specified number evaluates to negative infinity.

``````public:
static bool IsNegativeInfinity(float f);``````
``public static bool IsNegativeInfinity (float f);``
``static member IsNegativeInfinity : single -> bool``
``Public Shared Function IsNegativeInfinity (f As Single) As Boolean``

#### 매개 변수

f
Single Single Single Single

단정밀도 부동 소수점 숫자입니다.A single-precision floating-point number.

#### 반환

`f`NegativeInfinity으로 계산되면 `true`이고, 그렇지 않으면 `false`입니다.`true` if `f` evaluates to NegativeInfinity; otherwise, `false`.

## 예제

다음 코드 예제는 IsNegativeInfinity 메서드.The following code example demonstrates the IsNegativeInfinity method.

``````// This will return true.
Console::WriteLine( "IsNegativeInfinity(-5.0F / 0) == {0}.", Single::IsNegativeInfinity(  -5.0F / zero ) ? (String^)"true" : "false" );
``````
``````// This will return true.
Console.WriteLine("IsNegativeInfinity(-5.0F / 0) == {0}.", Single.IsNegativeInfinity(-5.0F / 0) ? "true" : "false");
``````
``````' This will return True.
Console.Write("IsNegativeInfinity(-5.0 / 0) = ")
If Single.IsNegativeInfinity(-5 / 0) Then
Console.WriteLine("True.")
Else
Console.WriteLine("False.")
End If
``````

## 설명

부동 소수점 NegativeInfinity 오버플로 조건을 알립니다.Floating-point operations return NegativeInfinity to signal an overflow condition.