# Vector3D.Divide(Vector3D, Double) 메서드

## 정의

지정된 Vector3D 구조체를 지정된 스칼라로 나누고 그 결과를 Vector3D로 반환합니다.Divides the specified Vector3D structure by the specified scalar and returns the result as a Vector3D.

``````public:
static System::Windows::Media::Media3D::Vector3D Divide(System::Windows::Media::Media3D::Vector3D vector, double scalar);``````
``public static System.Windows.Media.Media3D.Vector3D Divide (System.Windows.Media.Media3D.Vector3D vector, double scalar);``
``static member Divide : System.Windows.Media.Media3D.Vector3D * double -> System.Windows.Media.Media3D.Vector3D``
``Public Shared Function Divide (vector As Vector3D, scalar As Double) As Vector3D``

#### 매개 변수

vector
Vector3D

나눌 Vector3D 구조체입니다.The Vector3D structure to be divided.

scalar
Double

`vector`를 나눌 스칼라입니다.The scalar to divide `vector` by.

#### 반환

`vector``scalar`로 나눈 결과입니다.The result of dividing `vector` by `scalar`.

## 예제

다음 예제에서는 분할 방법을 Vector3D 스칼라 구조체입니다.The following example shows how to divide a Vector3D structure by a scalar.

``````// Divides a Vector3D by a Scalar using the overloaded / operator.
// Returns a Vector3D.

Vector3D vector1 = new Vector3D(20, 30, 40);
Vector3D vectorResult = new Vector3D();
Double scalar1 = 75;

vectorResult = vector1 / scalar1;
// vectorResult is approximately equal to (0.26667, 0.4, 0.53333)
``````
``````' Divides a Vector3D by a Scalar using the overloaded / operator.
' Returns a Vector3D.

Dim vector1 As New Vector3D(20, 30, 40)
Dim vectorResult As New Vector3D()
Dim scalar1 As Double = 75

vectorResult = vector1 / scalar1
' vectorResult is approximately equal to (0.26667, 0.4, 0.53333)
``````