# Vector3D.Division(Vector3D, Double) 연산자

## 정의

지정된 Vector3D 구조체를 지정된 스칼라로 나누고 그 결과를 Vector3D로 반환합니다.Divides the specified Vector3D structure by the specified scalar and returns the result as a Vector3D.

``````public:
static System::Windows::Media::Media3D::Vector3D operator /(System::Windows::Media::Media3D::Vector3D vector, double scalar);``````
``public static System.Windows.Media.Media3D.Vector3D operator / (System.Windows.Media.Media3D.Vector3D vector, double scalar);``
``static member ( / ) : System.Windows.Media.Media3D.Vector3D * double -> System.Windows.Media.Media3D.Vector3D``
``Public Shared Operator / (vector As Vector3D, scalar As Double) As Vector3D``

#### 매개 변수

vector
Vector3D

나눌 Vector3D 구조체입니다.The Vector3D structure to be divided.

scalar
Double

`vector`를 나눌 스칼라입니다.The scalar to divide `vector` by.

#### 반환

`vector``scalar`로 나눈 결과입니다.The result of dividing `vector` by `scalar`.

## 예제

다음 예제에서는 오버 로드 된 더하기 연산자를 사용 하는 방법을 보여 줍니다는 Vector3D 스칼라 구조체입니다.The following example shows how to use the overloaded addition operator to divide a Vector3D structure by a scalar.

``````private Vector overloadedDivisionOperatorExample()
{
Vector vector1 = new Vector(20, 30);
Vector vectorResult = new Vector();
Double scalar1 = 75;

// Divide vector by scalar.
// vectorResult is approximately equal to (0.26667,0.4)
vectorResult = vector1 / scalar1;

return vectorResult;

}
``````
``````Private Function overloadedDivisionOperatorExample() As Vector
Dim vector1 As New Vector(20, 30)
Dim vectorResult As New Vector()
Dim scalar1 As Double = 75

' Divide vector by scalar.
' vectorResult is approximately equal to (0.26667,0.4)
vectorResult = vector1 / scalar1

Return vectorResult

End Function
``````