IVsProject4 Interface

  • 아티클

Namespace:  Microsoft.VisualStudio.Shell.Interop
Assembly:  Microsoft.VisualStudio.Shell.Interop.10.0 (in Microsoft.VisualStudio.Shell.Interop.10.0.dll)

Syntax

‘선언
<GuidAttribute("12A0D88D-D8FE-4637-8350-214B5C29DE31")> _
<InterfaceTypeAttribute(ComInterfaceType.InterfaceIsIUnknown)> _
Public Interface IVsProject4 _
    Inherits IVsProject3
‘사용 방법
Dim instance As IVsProject4

[GuidAttribute("12A0D88D-D8FE-4637-8350-214B5C29DE31")]
[InterfaceTypeAttribute(ComInterfaceType.InterfaceIsIUnknown)]
public interface IVsProject4 : IVsProject3

[GuidAttribute(L"12A0D88D-D8FE-4637-8350-214B5C29DE31")]
[InterfaceTypeAttribute(ComInterfaceType::InterfaceIsIUnknown)]
public interface class IVsProject4 : IVsProject3

[<GuidAttribute("12A0D88D-D8FE-4637-8350-214B5C29DE31")>]
[<InterfaceTypeAttribute(ComInterfaceType.InterfaceIsIUnknown)>]
type IVsProject4 =  
    interface
        interface IVsProject3
    end

public interface IVsProject4 extends IVsProject3

See Also

Reference

IVsProject4 Members

Microsoft.VisualStudio.Shell.Interop Namespace