Object.GetType Object.GetType Object.GetType Object.GetType Method

Definição

Obtém o Type da instância atual.Gets the Type of the current instance.

public:
 Type ^ GetType();
public Type GetType ();
member this.GetType : unit -> Type
Public Function GetType () As Type

Retornos

O tipo de tempo de execução exato da instância atual.The exact runtime type of the current instance.

Exemplos

O exemplo de código a seguir demonstra que GetType retorna o tipo de tempo de execução da instância atual.The following code example demonstrates that GetType returns the runtime type of the current instance.

using namespace System;

public ref class MyBaseClass {};

public ref class MyDerivedClass: MyBaseClass{};

int main()
{
   MyBaseClass^ myBase = gcnew MyBaseClass;
   MyDerivedClass^ myDerived = gcnew MyDerivedClass;
   Object^ o = myDerived;
   MyBaseClass^ b = myDerived;
   Console::WriteLine( "mybase: Type is {0}", myBase->GetType() );
   Console::WriteLine( "myDerived: Type is {0}", myDerived->GetType() );
   Console::WriteLine( "object o = myDerived: Type is {0}", o->GetType() );
   Console::WriteLine( "MyBaseClass b = myDerived: Type is {0}", b->GetType() );
}

/*

This code produces the following output.

mybase: Type is MyBaseClass
myDerived: Type is MyDerivedClass
object o = myDerived: Type is MyDerivedClass
MyBaseClass b = myDerived: Type is MyDerivedClass 

*/
using System;

public class MyBaseClass {
}

public class MyDerivedClass: MyBaseClass {
}

public class Test 
{
   public static void Main() 
   {
      MyBaseClass myBase = new MyBaseClass();
      MyDerivedClass myDerived = new MyDerivedClass();
      object o = myDerived;
      MyBaseClass b = myDerived;

      Console.WriteLine("mybase: Type is {0}", myBase.GetType());
      Console.WriteLine("myDerived: Type is {0}", myDerived.GetType());
      Console.WriteLine("object o = myDerived: Type is {0}", o.GetType());
      Console.WriteLine("MyBaseClass b = myDerived: Type is {0}", b.GetType());
   }
}
// The example displays the following output:
//    mybase: Type is MyBaseClass
//    myDerived: Type is MyDerivedClass
//    object o = myDerived: Type is MyDerivedClass
//    MyBaseClass b = myDerived: Type is MyDerivedClass 
' Define a base and a derived class.
Public Class MyBaseClass
End Class 

Public Class MyDerivedClass : Inherits MyBaseClass
End Class 

Public Class Test
    Public Shared Sub Main() 
        Dim base As New MyBaseClass()
        Dim derived As New MyDerivedClass()
        Dim o As Object = derived
        Dim b As MyBaseClass = derived
        
        Console.WriteLine("base.GetType returns {0}", base.GetType())
        Console.WriteLine("derived.GetType returns {0}", derived.GetType())
        Console.WriteLine("Dim o As Object = derived; o.GetType returns {0}", o.GetType())
        Console.WriteLine("Dim b As MyBaseClass = derived; b.Type returns {0}", b.GetType())
    End Sub 
End Class 
' The example displays the following output:
'    base.GetType returns MyBaseClass
'    derived.GetType returns MyDerivedClass
'    Dim o As Object = derived; o.GetType returns MyDerivedClass
'    Dim b As MyBaseClass = derived; b.Type returns MyDerivedClass

Comentários

Porque System.Object é a classe base para todos os tipos no .NET, sistema, digite o GetType método pode ser usado para retornar Type objetos que representam todos os tipos de .NET.Because System.Object is the base class for all types in the .NET type system, the GetType method can be used to return Type objects that represent all .NET types. .NET reconhece os cinco categorias de tipos a seguir:.NET recognizes the following five categories of types:

Para dois objetos x e y que têm tipos de tempo de execução idênticos Object.ReferenceEquals(x.GetType(),y.GetType()) retorna true.For two objects x and y that have identical runtime types, Object.ReferenceEquals(x.GetType(),y.GetType()) returns true. O exemplo a seguir usa o GetType método com o ReferenceEquals método para determinar se um valor numérico é o mesmo tipo que dois outros valores numéricos.The following example uses the GetType method with the ReferenceEquals method to determine whether one numeric value is the same type as two other numeric values.

using System;

public class Example
{
   public static void Main()
   {
      int n1 = 12;
      int n2 = 82;
      long n3 = 12;
      
      Console.WriteLine("n1 and n2 are the same type: {0}",
                        Object.ReferenceEquals(n1.GetType(), n2.GetType()));
      Console.WriteLine("n1 and n3 are the same type: {0}",
                        Object.ReferenceEquals(n1.GetType(), n3.GetType()));
   }
}
// The example displays the following output:
//       n1 and n2 are the same type: True
//       n1 and n3 are the same type: False      
Module Example
   Public Sub Main()
      Dim n1 As Integer = 12
      Dim n2 As Integer = 82
      Dim n3 As Long = 12
      
      Console.WriteLine("n1 and n2 are the same type: {0}",
                        Object.ReferenceEquals(n1.GetType(), n2.GetType()))
      Console.WriteLine("n1 and n3 are the same type: {0}",
                        Object.ReferenceEquals(n1.GetType(), n3.GetType()))
   End Sub
End Module
' The example displays the following output:
'       n1 and n2 are the same type: True
'       n1 and n3 are the same type: False      

Observação

Para determinar se um objeto é um tipo específico, você pode usar a palavra-chave de comparação de tipo da sua linguagem ou construir.To determine whether an object is a specific type, you can use your language's type comparison keyword or construct. Por exemplo, você pode usar o TypeOf…Is construir no Visual Basic ou o is palavra-chave em c#.For example, you can use the TypeOf…Is construct in Visual Basic or the is keyword in C#.

O GetType método é herdado por todos os tipos que derivam de Object.The GetType method is inherited by all types that derive from Object. Isso significa que, além de usar a palavra-chave de comparação da sua própria linguagem, você pode usar o GetType método para determinar o tipo de um objeto específico, como mostra o exemplo a seguir.This means that, in addition to using your own language's comparison keyword, you can use the GetType method to determine the type of a particular object, as the following example shows.

using System;

public class Example
{
   public static void Main()
   {
      object[] values = { (int) 12, (long) 10653, (byte) 12, (sbyte) -5,
                         16.3, "string" }; 
      foreach (var value in values) {
         Type t = value.GetType();
         if (t.Equals(typeof(byte)))
            Console.WriteLine("{0} is an unsigned byte.", value);
         else if (t.Equals(typeof(sbyte)))
            Console.WriteLine("{0} is a signed byte.", value);
         else if (t.Equals(typeof(int)))   
            Console.WriteLine("{0} is a 32-bit integer.", value);
         else if (t.Equals(typeof(long)))   
            Console.WriteLine("{0} is a 32-bit integer.", value);
         else if (t.Equals(typeof(double)))
            Console.WriteLine("{0} is a double-precision floating point.", 
                              value);
         else
            Console.WriteLine("'{0}' is another data type.", value);
      }
   }
}
// The example displays the following output:
//    12 is a 32-bit integer.
//    10653 is a 32-bit integer.
//    12 is an unsigned byte.
//    -5 is a signed byte.
//    16.3 is a double-precision floating point.
//    'string' is another data type.
Module Example
   Public Sub Main()
      Dim values() As Object = { 12, CLng(10653), CByte(12), 
                                 CSbyte(-5), 16.3, "string" } 
      For Each value In values
         Dim t AS Type = value.GetType()
         If t.Equals(GetType(Byte))
            Console.WriteLine("{0} is an unsigned byte.", value)
         ElseIf t.Equals(GetType(SByte))
            Console.WriteLine("{0} is a signed byte.", value)
         ElseIf t.Equals(GetType(Integer))   
            Console.WriteLine("{0} is a 32-bit integer.", value)
         ElseIf t.Equals(GetType(Long))   
            Console.WriteLine("{0} is a 32-bit integer.", value)
         ElseIf t.Equals(GetType(Double))
            Console.WriteLine("{0} is a double-precision floating point.", 
                              value)
         Else
            Console.WriteLine("'{0}' is another data type.", value)
         End If   
      Next      
   End Sub
End Module
' The example displays the following output:
'       12 is a 32-bit integer.
'       10653 is a 32-bit integer.
'       12 is an unsigned byte.
'       -5 is a signed byte.
'       16.3 is a double-precision floating point.
'       'string' is another data type.

O Type objeto expõe os metadados associados com a classe do atual Object.The Type object exposes the metadata associated with the class of the current Object.

Aplica-se a

Veja também