InOutArgument<T>.FromExpression(Activity<Location<T>>) InOutArgument<T>.FromExpression(Activity<Location<T>>) InOutArgument<T>.FromExpression(Activity<Location<T>>) InOutArgument<T>.FromExpression(Activity<Location<T>>) Method

Определение

Инициализирует и возвращает новый аргумент InOutArgument<T>, построенный с помощью указанной переменной Activity<TResult>.Initializes and returns a new InOutArgument<T> constructed using the specified Activity<TResult>.

public:
 static System::Activities::InOutArgument<T> ^ FromExpression(System::Activities::Activity<System::Activities::Location<T> ^> ^ expression);
public static System.Activities.InOutArgument<T> FromExpression (System.Activities.Activity<System.Activities.Location<T>> expression);
static member FromExpression : System.Activities.Activity<System.Activities.Location<'T>> -> System.Activities.InOutArgument<'T>
Public Shared Function FromExpression (expression As Activity(Of Location(Of T))) As InOutArgument(Of T)

Параметры

expression
Activity<Location<T>>

Значение аргумента.The value of the argument.

Возвраты

Новый аргумент.The new argument.

Применяется к