Package.Open Метод

Определение

Открывает пакет.Opens a package.

Перегрузки

Open(Stream)

Открывает пакет в заданном потоке ввода-вывода.Opens a package on a given IO stream.

Open(String)

Открывает пакет с указанным путем и именем файла.Opens a package at a given path and file name.

Open(Stream, FileMode)

Открывает пакет в заданном потоке ввода-вывода в указанном файловом режиме.Opens a package with a given IO stream and file mode.

Open(String, FileMode)

Открывает пакет на заданном пути в указанном файловом режиме.Opens a package at a given path using a given file mode.

Open(Stream, FileMode, FileAccess)

Открывает пакет в заданном потоке ввода-вывода с указанными значениями файлового режима и режима доступа к файлу.Opens a package with a given IO stream, file mode, and file access setting.

Open(String, FileMode, FileAccess)

Открывает пакет на заданном пути с указанными значениями файлового режима и режима доступа к файлу.Opens a package at a given path using a given file mode and file access setting.

Open(String, FileMode, FileAccess, FileShare)

Открывает пакет на заданном пути с указанными значениями файлового режима, режима доступа к файлу и режима общего доступа.Opens a package at a given path using a given file mode, file access, and file share setting.

Примеры

В следующем примере показано, как создать новый элемент Package , включающий PackageRelationship элементы и, PackagePart вместе с хранимыми данными.The following example shows how to create a new Package that incorporates PackageRelationship and PackagePart elements together with stored data. Полный пример см. в разделе запись примера пакета.For the complete sample, see Writing a Package Sample.

//  -------------------------- CreatePackage --------------------------
/// <summary>
///   Creates a package zip file containing specified
///   content and resource files.</summary>
private static void CreatePackage()
{
    // Convert system path and file names to Part URIs. In this example
    // Uri partUriDocument /* /Content/Document.xml */ =
    //     PackUriHelper.CreatePartUri(
    //         new Uri("Content\Document.xml", UriKind.Relative));
    // Uri partUriResource /* /Resources/Image1.jpg */ =
    //     PackUriHelper.CreatePartUri(
    //         new Uri("Resources\Image1.jpg", UriKind.Relative));
    Uri partUriDocument = PackUriHelper.CreatePartUri(
                              new Uri(documentPath, UriKind.Relative));
    Uri partUriResource = PackUriHelper.CreatePartUri(
                              new Uri(resourcePath, UriKind.Relative));

    // Create the Package
    // (If the package file already exists, FileMode.Create will
    //  automatically delete it first before creating a new one.
    //  The 'using' statement insures that 'package' is
    //  closed and disposed when it goes out of scope.)
    using (Package package =
        Package.Open(packagePath, FileMode.Create))
    {
        // Add the Document part to the Package
        PackagePart packagePartDocument =
            package.CreatePart(partUriDocument,
                           System.Net.Mime.MediaTypeNames.Text.Xml);

        // Copy the data to the Document Part
        using (FileStream fileStream = new FileStream(
               documentPath, FileMode.Open, FileAccess.Read))
        {
            CopyStream(fileStream, packagePartDocument.GetStream());
        }// end:using(fileStream) - Close and dispose fileStream.

        // Add a Package Relationship to the Document Part
        package.CreateRelationship(packagePartDocument.Uri,
                                   TargetMode.Internal,
                                   PackageRelationshipType);

        // Add a Resource Part to the Package
        PackagePart packagePartResource =
            package.CreatePart(partUriResource,
                           System.Net.Mime.MediaTypeNames.Image.Jpeg);

        // Copy the data to the Resource Part
        using (FileStream fileStream = new FileStream(
               resourcePath, FileMode.Open, FileAccess.Read))
        {
            CopyStream(fileStream, packagePartResource.GetStream());
        }// end:using(fileStream) - Close and dispose fileStream.

        // Add Relationship from the Document part to the Resource part
        packagePartDocument.CreateRelationship(
                                new Uri(@"../resources/image1.jpg",
                                UriKind.Relative),
                                TargetMode.Internal,
                                ResourceRelationshipType);
    }// end:using (Package package) - Close and dispose package.
}// end:CreatePackage()

//  --------------------------- CopyStream ---------------------------
/// <summary>
///   Copies data from a source stream to a target stream.</summary>
/// <param name="source">
///   The source stream to copy from.</param>
/// <param name="target">
///   The destination stream to copy to.</param>
private static void CopyStream(Stream source, Stream target)
{
    const int bufSize = 0x1000;
    byte[] buf = new byte[bufSize];
    int bytesRead = 0;
    while ((bytesRead = source.Read(buf, 0, bufSize)) > 0)
        target.Write(buf, 0, bytesRead);
}// end:CopyStream()
'  -------------------------- CreatePackage --------------------------
''' <summary>
'''   Creates a package zip file containing specified
'''   content and resource files.</summary>
Private Shared Sub CreatePackage()
    ' Convert system path and file names to Part URIs. In this example
    ' Dim partUriDocument as Uri /* /Content/Document.xml */ =
    '     PackUriHelper.CreatePartUri(
    '         New Uri("Content\Document.xml", UriKind.Relative))
    ' Dim partUriResource as Uri /* /Resources/Image1.jpg */ =
    '     PackUriHelper.CreatePartUri(
    '         New Uri("Resources\Image1.jpg", UriKind.Relative))
    Dim partUriDocument As Uri = PackUriHelper.CreatePartUri(New Uri(documentPath, UriKind.Relative))
    Dim partUriResource As Uri = PackUriHelper.CreatePartUri(New Uri(resourcePath, UriKind.Relative))

    ' Create the Package
    ' (If the package file already exists, FileMode.Create will
    '  automatically delete it first before creating a new one.
    '  The 'using' statement insures that 'package' is
    '  closed and disposed when it goes out of scope.)
    Using package As Package = Package.Open(packagePath, FileMode.Create)
        ' Add the Document part to the Package
        Dim packagePartDocument As PackagePart = package.CreatePart(partUriDocument, System.Net.Mime.MediaTypeNames.Text.Xml)

        ' Copy the data to the Document Part
        Using fileStream As New FileStream(documentPath, FileMode.Open, FileAccess.Read)
            CopyStream(fileStream, packagePartDocument.GetStream())
        End Using ' end:using(fileStream) - Close and dispose fileStream.

        ' Add a Package Relationship to the Document Part
        package.CreateRelationship(packagePartDocument.Uri, TargetMode.Internal, PackageRelationshipType)

        ' Add a Resource Part to the Package
        Dim packagePartResource As PackagePart = package.CreatePart(partUriResource, System.Net.Mime.MediaTypeNames.Image.Jpeg)

        ' Copy the data to the Resource Part
        Using fileStream As New FileStream(resourcePath, FileMode.Open, FileAccess.Read)
            CopyStream(fileStream, packagePartResource.GetStream())
        End Using ' end:using(fileStream) - Close and dispose fileStream.

        ' Add Relationship from the Document part to the Resource part
        packagePartDocument.CreateRelationship(New Uri("../resources/image1.jpg", UriKind.Relative), TargetMode.Internal, ResourceRelationshipType)

    End Using ' end:using (Package package) - Close and dispose package.

End Sub


'  --------------------------- CopyStream ---------------------------
''' <summary>
'''   Copies data from a source stream to a target stream.</summary>
''' <param name="source">
'''   The source stream to copy from.</param>
''' <param name="target">
'''   The destination stream to copy to.</param>
Private Shared Sub CopyStream(ByVal source As Stream, ByVal target As Stream)
    Const bufSize As Integer = &H1000
    Dim buf(bufSize - 1) As Byte
    Dim bytesRead As Integer = 0
    bytesRead = source.Read(buf, 0, bufSize)
    Do While bytesRead > 0
        target.Write(buf, 0, bytesRead)
        bytesRead = source.Read(buf, 0, bufSize)
    Loop
End Sub

Комментарии

ZipPackage тип пакета по умолчанию, используемый Open методом.ZipPackage is the default package type that is used by the Open method.

Дополнительные сведения см. в спецификации Open Packaging Conventions (OPC), доступной для загрузки по адресу https://go.microsoft.com/fwlink/?LinkID=71255 .For additional information, see the Open Packaging Conventions (OPC) specification available for download at https://go.microsoft.com/fwlink/?LinkID=71255.

Open(Stream)

Открывает пакет в заданном потоке ввода-вывода.Opens a package on a given IO stream.

public:
 static System::IO::Packaging::Package ^ Open(System::IO::Stream ^ stream);
public static System.IO.Packaging.Package Open (System.IO.Stream stream);
static member Open : System.IO.Stream -> System.IO.Packaging.Package
Public Shared Function Open (stream As Stream) As Package

Параметры

stream
Stream

Поток ввода-вывода, в котором требуется открыть пакет.The IO stream on which to open the package.

Возвращаемое значение

Package

Открытый пакет.The opened package.

Исключения

stream имеет значение null.stream is null.

Для открываемого пакета требуются разрешения на чтение или чтение/запись, а указанный поток stream доступен только для записи, или для открываемого пакета требуются разрешения на запись или чтение/запись, а указанный поток stream доступен только для чтения.The package to open requires read or read/write permission and the specified stream is write-only; or, the package to open requires write or read/write permission and the specified stream is read-only.

Комментарии

ZipPackage тип пакета по умолчанию, используемый Open методом.ZipPackage is the default package type that is used by the Open method.

Дополнительные сведения см. в спецификации Open Packaging Conventions (OPC), доступной для загрузки по адресу https://go.microsoft.com/fwlink/?LinkID=71255 .For additional information, see the Open Packaging Conventions (OPC) specification available for download at https://go.microsoft.com/fwlink/?LinkID=71255.

Применяется к

Open(String)

Открывает пакет с указанным путем и именем файла.Opens a package at a given path and file name.

public:
 static System::IO::Packaging::Package ^ Open(System::String ^ path);
public static System.IO.Packaging.Package Open (string path);
static member Open : string -> System.IO.Packaging.Package
Public Shared Function Open (path As String) As Package

Параметры

path
String

Путь и имя файла пакета.The path and file name of the package.

Возвращаемое значение

Package

Открытый пакет.The opened package.

Исключения

path имеет значение null.path is null.

Примеры

В следующем примере показано, как создать новый элемент Package , включающий PackageRelationship элементы и, PackagePart вместе с хранимыми данными.The following example shows how to create a new Package that incorporates PackageRelationship and PackagePart elements together with stored data. Полный пример см. в разделе запись примера пакета.For the complete sample, see Writing a Package Sample.

//  -------------------------- CreatePackage --------------------------
/// <summary>
///   Creates a package zip file containing specified
///   content and resource files.</summary>
private static void CreatePackage()
{
    // Convert system path and file names to Part URIs. In this example
    // Uri partUriDocument /* /Content/Document.xml */ =
    //     PackUriHelper.CreatePartUri(
    //         new Uri("Content\Document.xml", UriKind.Relative));
    // Uri partUriResource /* /Resources/Image1.jpg */ =
    //     PackUriHelper.CreatePartUri(
    //         new Uri("Resources\Image1.jpg", UriKind.Relative));
    Uri partUriDocument = PackUriHelper.CreatePartUri(
                              new Uri(documentPath, UriKind.Relative));
    Uri partUriResource = PackUriHelper.CreatePartUri(
                              new Uri(resourcePath, UriKind.Relative));

    // Create the Package
    // (If the package file already exists, FileMode.Create will
    //  automatically delete it first before creating a new one.
    //  The 'using' statement insures that 'package' is
    //  closed and disposed when it goes out of scope.)
    using (Package package =
        Package.Open(packagePath, FileMode.Create))
    {
        // Add the Document part to the Package
        PackagePart packagePartDocument =
            package.CreatePart(partUriDocument,
                           System.Net.Mime.MediaTypeNames.Text.Xml);

        // Copy the data to the Document Part
        using (FileStream fileStream = new FileStream(
               documentPath, FileMode.Open, FileAccess.Read))
        {
            CopyStream(fileStream, packagePartDocument.GetStream());
        }// end:using(fileStream) - Close and dispose fileStream.

        // Add a Package Relationship to the Document Part
        package.CreateRelationship(packagePartDocument.Uri,
                                   TargetMode.Internal,
                                   PackageRelationshipType);

        // Add a Resource Part to the Package
        PackagePart packagePartResource =
            package.CreatePart(partUriResource,
                           System.Net.Mime.MediaTypeNames.Image.Jpeg);

        // Copy the data to the Resource Part
        using (FileStream fileStream = new FileStream(
               resourcePath, FileMode.Open, FileAccess.Read))
        {
            CopyStream(fileStream, packagePartResource.GetStream());
        }// end:using(fileStream) - Close and dispose fileStream.

        // Add Relationship from the Document part to the Resource part
        packagePartDocument.CreateRelationship(
                                new Uri(@"../resources/image1.jpg",
                                UriKind.Relative),
                                TargetMode.Internal,
                                ResourceRelationshipType);
    }// end:using (Package package) - Close and dispose package.
}// end:CreatePackage()

//  --------------------------- CopyStream ---------------------------
/// <summary>
///   Copies data from a source stream to a target stream.</summary>
/// <param name="source">
///   The source stream to copy from.</param>
/// <param name="target">
///   The destination stream to copy to.</param>
private static void CopyStream(Stream source, Stream target)
{
    const int bufSize = 0x1000;
    byte[] buf = new byte[bufSize];
    int bytesRead = 0;
    while ((bytesRead = source.Read(buf, 0, bufSize)) > 0)
        target.Write(buf, 0, bytesRead);
}// end:CopyStream()
'  -------------------------- CreatePackage --------------------------
''' <summary>
'''   Creates a package zip file containing specified
'''   content and resource files.</summary>
Private Shared Sub CreatePackage()
    ' Convert system path and file names to Part URIs. In this example
    ' Dim partUriDocument as Uri /* /Content/Document.xml */ =
    '     PackUriHelper.CreatePartUri(
    '         New Uri("Content\Document.xml", UriKind.Relative))
    ' Dim partUriResource as Uri /* /Resources/Image1.jpg */ =
    '     PackUriHelper.CreatePartUri(
    '         New Uri("Resources\Image1.jpg", UriKind.Relative))
    Dim partUriDocument As Uri = PackUriHelper.CreatePartUri(New Uri(documentPath, UriKind.Relative))
    Dim partUriResource As Uri = PackUriHelper.CreatePartUri(New Uri(resourcePath, UriKind.Relative))

    ' Create the Package
    ' (If the package file already exists, FileMode.Create will
    '  automatically delete it first before creating a new one.
    '  The 'using' statement insures that 'package' is
    '  closed and disposed when it goes out of scope.)
    Using package As Package = Package.Open(packagePath, FileMode.Create)
        ' Add the Document part to the Package
        Dim packagePartDocument As PackagePart = package.CreatePart(partUriDocument, System.Net.Mime.MediaTypeNames.Text.Xml)

        ' Copy the data to the Document Part
        Using fileStream As New FileStream(documentPath, FileMode.Open, FileAccess.Read)
            CopyStream(fileStream, packagePartDocument.GetStream())
        End Using ' end:using(fileStream) - Close and dispose fileStream.

        ' Add a Package Relationship to the Document Part
        package.CreateRelationship(packagePartDocument.Uri, TargetMode.Internal, PackageRelationshipType)

        ' Add a Resource Part to the Package
        Dim packagePartResource As PackagePart = package.CreatePart(partUriResource, System.Net.Mime.MediaTypeNames.Image.Jpeg)

        ' Copy the data to the Resource Part
        Using fileStream As New FileStream(resourcePath, FileMode.Open, FileAccess.Read)
            CopyStream(fileStream, packagePartResource.GetStream())
        End Using ' end:using(fileStream) - Close and dispose fileStream.

        ' Add Relationship from the Document part to the Resource part
        packagePartDocument.CreateRelationship(New Uri("../resources/image1.jpg", UriKind.Relative), TargetMode.Internal, ResourceRelationshipType)

    End Using ' end:using (Package package) - Close and dispose package.

End Sub


'  --------------------------- CopyStream ---------------------------
''' <summary>
'''   Copies data from a source stream to a target stream.</summary>
''' <param name="source">
'''   The source stream to copy from.</param>
''' <param name="target">
'''   The destination stream to copy to.</param>
Private Shared Sub CopyStream(ByVal source As Stream, ByVal target As Stream)
    Const bufSize As Integer = &H1000
    Dim buf(bufSize - 1) As Byte
    Dim bytesRead As Integer = 0
    bytesRead = source.Read(buf, 0, bufSize)
    Do While bytesRead > 0
        target.Write(buf, 0, bytesRead)
        bytesRead = source.Read(buf, 0, bufSize)
    Loop
End Sub

Комментарии

ZipPackage тип пакета по умолчанию, используемый Open методом.ZipPackage is the default package type that is used by the Open method.

Этот Open метод открывает пакет с атрибутами по умолчанию OpenOrCreate , ReadWrite и None (чтобы указать другие атрибуты, используйте одну из других перегрузок открытого метода).This Open method opens the package with default attributes OpenOrCreate, ReadWrite, and None (to specify different attributes use one of the other Open method overloads).

Дополнительные сведения см. в спецификации Open Packaging Conventions (OPC), доступной для загрузки по адресу https://go.microsoft.com/fwlink/?LinkID=71255 .For additional information, see the Open Packaging Conventions (OPC) specification available for download at https://go.microsoft.com/fwlink/?LinkID=71255.

Применяется к

Open(Stream, FileMode)

Открывает пакет в заданном потоке ввода-вывода в указанном файловом режиме.Opens a package with a given IO stream and file mode.

public:
 static System::IO::Packaging::Package ^ Open(System::IO::Stream ^ stream, System::IO::FileMode packageMode);
public static System.IO.Packaging.Package Open (System.IO.Stream stream, System.IO.FileMode packageMode);
static member Open : System.IO.Stream * System.IO.FileMode -> System.IO.Packaging.Package
Public Shared Function Open (stream As Stream, packageMode As FileMode) As Package

Параметры

stream
Stream

Поток ввода-вывода, в котором требуется открыть пакет.The IO stream on which to open the package.

packageMode
FileMode

Файловый режим, в котором следует открыть пакет.The file mode in which to open the package.

Возвращаемое значение

Package

Открытый пакет.The opened package.

Исключения

stream имеет значение null.stream is null.

Недопустимое значение параметра packageMode.packageMode value is not valid.

Для открываемого пакета требуются разрешения на чтение или чтение/запись, а указанный поток stream доступен только для записи, или для открываемого пакета требуются разрешения на запись или чтение/запись, а указанный поток stream доступен только для чтения.The package to open requires read or read/write permission and the specified stream is write-only; or, the package to open requires write or read/write permission and the specified stream is read-only.

Комментарии

ZipPackage тип пакета по умолчанию, используемый Open методом.ZipPackage is the default package type that is used by the Open method.

Дополнительные сведения см. в спецификации Open Packaging Conventions (OPC), доступной для загрузки по адресу https://go.microsoft.com/fwlink/?LinkID=71255 .For additional information, see the Open Packaging Conventions (OPC) specification available for download at https://go.microsoft.com/fwlink/?LinkID=71255.

Применяется к

Open(String, FileMode)

Открывает пакет на заданном пути в указанном файловом режиме.Opens a package at a given path using a given file mode.

public:
 static System::IO::Packaging::Package ^ Open(System::String ^ path, System::IO::FileMode packageMode);
public static System.IO.Packaging.Package Open (string path, System.IO.FileMode packageMode);
static member Open : string * System.IO.FileMode -> System.IO.Packaging.Package
Public Shared Function Open (path As String, packageMode As FileMode) As Package

Параметры

path
String

Путь и имя файла пакета.The path and file name of the package.

packageMode
FileMode

Файловый режим, в котором следует открыть пакет.The file mode in which to open the package.

Возвращаемое значение

Package

Открытый пакет.The opened package.

Исключения

path имеет значение null.path is null.

Значение packageMode является недопустимым.Value for packageMode is not valid.

Примеры

В следующем примере показано, как создать новый элемент Package , включающий PackageRelationship элементы и, PackagePart вместе с хранимыми данными.The following example shows how to create a new Package that incorporates PackageRelationship and PackagePart elements together with stored data. Полный пример см. в разделе запись примера пакета.For the complete sample, see Writing a Package Sample.

//  -------------------------- CreatePackage --------------------------
/// <summary>
///   Creates a package zip file containing specified
///   content and resource files.</summary>
private static void CreatePackage()
{
    // Convert system path and file names to Part URIs. In this example
    // Uri partUriDocument /* /Content/Document.xml */ =
    //     PackUriHelper.CreatePartUri(
    //         new Uri("Content\Document.xml", UriKind.Relative));
    // Uri partUriResource /* /Resources/Image1.jpg */ =
    //     PackUriHelper.CreatePartUri(
    //         new Uri("Resources\Image1.jpg", UriKind.Relative));
    Uri partUriDocument = PackUriHelper.CreatePartUri(
                              new Uri(documentPath, UriKind.Relative));
    Uri partUriResource = PackUriHelper.CreatePartUri(
                              new Uri(resourcePath, UriKind.Relative));

    // Create the Package
    // (If the package file already exists, FileMode.Create will
    //  automatically delete it first before creating a new one.
    //  The 'using' statement insures that 'package' is
    //  closed and disposed when it goes out of scope.)
    using (Package package =
        Package.Open(packagePath, FileMode.Create))
    {
        // Add the Document part to the Package
        PackagePart packagePartDocument =
            package.CreatePart(partUriDocument,
                           System.Net.Mime.MediaTypeNames.Text.Xml);

        // Copy the data to the Document Part
        using (FileStream fileStream = new FileStream(
               documentPath, FileMode.Open, FileAccess.Read))
        {
            CopyStream(fileStream, packagePartDocument.GetStream());
        }// end:using(fileStream) - Close and dispose fileStream.

        // Add a Package Relationship to the Document Part
        package.CreateRelationship(packagePartDocument.Uri,
                                   TargetMode.Internal,
                                   PackageRelationshipType);

        // Add a Resource Part to the Package
        PackagePart packagePartResource =
            package.CreatePart(partUriResource,
                           System.Net.Mime.MediaTypeNames.Image.Jpeg);

        // Copy the data to the Resource Part
        using (FileStream fileStream = new FileStream(
               resourcePath, FileMode.Open, FileAccess.Read))
        {
            CopyStream(fileStream, packagePartResource.GetStream());
        }// end:using(fileStream) - Close and dispose fileStream.

        // Add Relationship from the Document part to the Resource part
        packagePartDocument.CreateRelationship(
                                new Uri(@"../resources/image1.jpg",
                                UriKind.Relative),
                                TargetMode.Internal,
                                ResourceRelationshipType);
    }// end:using (Package package) - Close and dispose package.
}// end:CreatePackage()

//  --------------------------- CopyStream ---------------------------
/// <summary>
///   Copies data from a source stream to a target stream.</summary>
/// <param name="source">
///   The source stream to copy from.</param>
/// <param name="target">
///   The destination stream to copy to.</param>
private static void CopyStream(Stream source, Stream target)
{
    const int bufSize = 0x1000;
    byte[] buf = new byte[bufSize];
    int bytesRead = 0;
    while ((bytesRead = source.Read(buf, 0, bufSize)) > 0)
        target.Write(buf, 0, bytesRead);
}// end:CopyStream()
'  -------------------------- CreatePackage --------------------------
''' <summary>
'''   Creates a package zip file containing specified
'''   content and resource files.</summary>
Private Shared Sub CreatePackage()
    ' Convert system path and file names to Part URIs. In this example
    ' Dim partUriDocument as Uri /* /Content/Document.xml */ =
    '     PackUriHelper.CreatePartUri(
    '         New Uri("Content\Document.xml", UriKind.Relative))
    ' Dim partUriResource as Uri /* /Resources/Image1.jpg */ =
    '     PackUriHelper.CreatePartUri(
    '         New Uri("Resources\Image1.jpg", UriKind.Relative))
    Dim partUriDocument As Uri = PackUriHelper.CreatePartUri(New Uri(documentPath, UriKind.Relative))
    Dim partUriResource As Uri = PackUriHelper.CreatePartUri(New Uri(resourcePath, UriKind.Relative))

    ' Create the Package
    ' (If the package file already exists, FileMode.Create will
    '  automatically delete it first before creating a new one.
    '  The 'using' statement insures that 'package' is
    '  closed and disposed when it goes out of scope.)
    Using package As Package = Package.Open(packagePath, FileMode.Create)
        ' Add the Document part to the Package
        Dim packagePartDocument As PackagePart = package.CreatePart(partUriDocument, System.Net.Mime.MediaTypeNames.Text.Xml)

        ' Copy the data to the Document Part
        Using fileStream As New FileStream(documentPath, FileMode.Open, FileAccess.Read)
            CopyStream(fileStream, packagePartDocument.GetStream())
        End Using ' end:using(fileStream) - Close and dispose fileStream.

        ' Add a Package Relationship to the Document Part
        package.CreateRelationship(packagePartDocument.Uri, TargetMode.Internal, PackageRelationshipType)

        ' Add a Resource Part to the Package
        Dim packagePartResource As PackagePart = package.CreatePart(partUriResource, System.Net.Mime.MediaTypeNames.Image.Jpeg)

        ' Copy the data to the Resource Part
        Using fileStream As New FileStream(resourcePath, FileMode.Open, FileAccess.Read)
            CopyStream(fileStream, packagePartResource.GetStream())
        End Using ' end:using(fileStream) - Close and dispose fileStream.

        ' Add Relationship from the Document part to the Resource part
        packagePartDocument.CreateRelationship(New Uri("../resources/image1.jpg", UriKind.Relative), TargetMode.Internal, ResourceRelationshipType)

    End Using ' end:using (Package package) - Close and dispose package.

End Sub


'  --------------------------- CopyStream ---------------------------
''' <summary>
'''   Copies data from a source stream to a target stream.</summary>
''' <param name="source">
'''   The source stream to copy from.</param>
''' <param name="target">
'''   The destination stream to copy to.</param>
Private Shared Sub CopyStream(ByVal source As Stream, ByVal target As Stream)
    Const bufSize As Integer = &H1000
    Dim buf(bufSize - 1) As Byte
    Dim bytesRead As Integer = 0
    bytesRead = source.Read(buf, 0, bufSize)
    Do While bytesRead > 0
        target.Write(buf, 0, bytesRead)
        bytesRead = source.Read(buf, 0, bufSize)
    Loop
End Sub

Комментарии

ZipPackage тип пакета по умолчанию, используемый Open методом.ZipPackage is the default package type that is used by the Open method.

Этот Open метод открывает пакет с атрибутами по умолчанию ReadWrite и None (для указания различных атрибутов используйте одну из других перегрузок открытого метода).This Open method opens the package with default attributes ReadWrite and None (to specify different attributes use one of the other Open method overloads).

Дополнительные сведения см. в спецификации Open Packaging Conventions (OPC), доступной для загрузки по адресу https://go.microsoft.com/fwlink/?LinkID=71255 .For additional information, see the Open Packaging Conventions (OPC) specification available for download at https://go.microsoft.com/fwlink/?LinkID=71255.

Применяется к

Open(Stream, FileMode, FileAccess)

Открывает пакет в заданном потоке ввода-вывода с указанными значениями файлового режима и режима доступа к файлу.Opens a package with a given IO stream, file mode, and file access setting.

public:
 static System::IO::Packaging::Package ^ Open(System::IO::Stream ^ stream, System::IO::FileMode packageMode, System::IO::FileAccess packageAccess);
public static System.IO.Packaging.Package Open (System.IO.Stream stream, System.IO.FileMode packageMode, System.IO.FileAccess packageAccess);
static member Open : System.IO.Stream * System.IO.FileMode * System.IO.FileAccess -> System.IO.Packaging.Package
Public Shared Function Open (stream As Stream, packageMode As FileMode, packageAccess As FileAccess) As Package

Параметры

stream
Stream

Поток ввода-вывода, в котором требуется открыть пакет.The IO stream on which to open the package.

packageMode
FileMode

Файловый режим, в котором следует открыть пакет.The file mode in which to open the package.

packageAccess
FileAccess

Режим доступа к файлу, в котором следует открыть пакет.The file access in which to open the package.

Возвращаемое значение

Package

Открытый пакет.The opened package.

Исключения

stream имеет значение null.stream is null.

Значение packageMode или packageAccess является недопустимым.The value for packageMode or packageAccess is not valid.

Для открываемого пакета требуются разрешения на чтение или чтение/запись, а указанный поток stream доступен только для записи, или для открываемого пакета требуются разрешения на запись или чтение/запись, а указанный поток stream доступен только для чтения.The package to open requires read or read/write permission and the specified stream is write-only; or the package to open requires write or read/write permission and the specified stream is read-only.

Комментарии

ZipPackage тип пакета по умолчанию, используемый Open методом.ZipPackage is the default package type that is used by the Open method.

Дополнительные сведения см. в спецификации Open Packaging Conventions (OPC), доступной для загрузки по адресу https://go.microsoft.com/fwlink/?LinkID=71255 .For additional information, see the Open Packaging Conventions (OPC) specification available for download at https://go.microsoft.com/fwlink/?LinkID=71255.

Применяется к

Open(String, FileMode, FileAccess)

Открывает пакет на заданном пути с указанными значениями файлового режима и режима доступа к файлу.Opens a package at a given path using a given file mode and file access setting.

public:
 static System::IO::Packaging::Package ^ Open(System::String ^ path, System::IO::FileMode packageMode, System::IO::FileAccess packageAccess);
public static System.IO.Packaging.Package Open (string path, System.IO.FileMode packageMode, System.IO.FileAccess packageAccess);
static member Open : string * System.IO.FileMode * System.IO.FileAccess -> System.IO.Packaging.Package
Public Shared Function Open (path As String, packageMode As FileMode, packageAccess As FileAccess) As Package

Параметры

path
String

Путь и имя файла пакета.The path and file name of the package.

packageMode
FileMode

Файловый режим, в котором следует открыть пакет.The file mode in which to open the package.

packageAccess
FileAccess

Режим доступа к файлу, в котором следует открыть пакет.The file access in which to open the package.

Возвращаемое значение

Package

Открытый пакет.The opened package.

Исключения

path имеет значение null.path is null.

Значение packageMode или packageAccess является недопустимым.Value for packageMode or packageAccess is not valid.

Примеры

В следующем примере показано, как открыть и прочитать объект Package , содержащий PackageRelationship PackagePart элементы и вместе с хранимыми данными.The following example shows how to open and read a Package that contains PackageRelationship and PackagePart elements together with stored data. Полный пример см. в разделе Чтение примера пакета.For the complete sample, see Reading a Package Sample.

// Open the Package.
// ('using' statement insures that 'package' is
//  closed and disposed when it goes out of scope.)
using (Package package =
    Package.Open(packagePath, FileMode.Open, FileAccess.Read))
{
    PackagePart documentPart = null;
    PackagePart resourcePart = null;

    // Get the Package Relationships and look for
    //   the Document part based on the RelationshipType
    Uri uriDocumentTarget = null;
    foreach (PackageRelationship relationship in
        package.GetRelationshipsByType(PackageRelationshipType))
    {
        // Resolve the Relationship Target Uri
        //   so the Document Part can be retrieved.
        uriDocumentTarget = PackUriHelper.ResolvePartUri(
            new Uri("/", UriKind.Relative), relationship.TargetUri);

        // Open the Document Part, write the contents to a file.
        documentPart = package.GetPart(uriDocumentTarget);
        ExtractPart(documentPart, targetDirectory);
    }

    // Get the Document part's Relationships,
    //   and look for required resources.
    Uri uriResourceTarget = null;
    foreach (PackageRelationship relationship in
        documentPart.GetRelationshipsByType(
                                ResourceRelationshipType))
    {
        // Resolve the Relationship Target Uri
        //   so the Resource Part can be retrieved.
        uriResourceTarget = PackUriHelper.ResolvePartUri(
            documentPart.Uri, relationship.TargetUri);

        // Open the Resource Part and write the contents to a file.
        resourcePart = package.GetPart(uriResourceTarget);
        ExtractPart(resourcePart, targetDirectory);
    }
}// end:using(Package package) - Close & dispose package.
' Open the Package.
' ('using' statement insures that 'package' is
'  closed and disposed when it goes out of scope.)
Using package As Package = Package.Open(packagePath, FileMode.Open, FileAccess.Read)
    Dim documentPart As PackagePart = Nothing
    Dim resourcePart As PackagePart = Nothing

    ' Get the Package Relationships and look for
    '   the Document part based on the RelationshipType
    Dim uriDocumentTarget As Uri = Nothing
    For Each relationship As PackageRelationship In package.GetRelationshipsByType(PackageRelationshipType)
        ' Resolve the Relationship Target Uri
        '   so the Document Part can be retrieved.
        uriDocumentTarget = PackUriHelper.ResolvePartUri(New Uri("/", UriKind.Relative), relationship.TargetUri)

        ' Open the Document Part, write the contents to a file.
        documentPart = package.GetPart(uriDocumentTarget)
        ExtractPart(documentPart, targetDirectory)
    Next relationship

    ' Get the Document part's Relationships,
    '   and look for required resources.
    Dim uriResourceTarget As Uri = Nothing
    For Each relationship As PackageRelationship In documentPart.GetRelationshipsByType(ResourceRelationshipType)
        ' Resolve the Relationship Target Uri
        '   so the Resource Part can be retrieved.
        uriResourceTarget = PackUriHelper.ResolvePartUri(documentPart.Uri, relationship.TargetUri)

        ' Open the Resource Part and write the contents to a file.
        resourcePart = package.GetPart(uriResourceTarget)
        ExtractPart(resourcePart, targetDirectory)
    Next relationship

End Using ' end:using(Package package) - Close & dispose package.

Комментарии

ZipPackage тип пакета по умолчанию, используемый Open методом.ZipPackage is the default package type that is used by the Open method.

Этот Open метод открывает пакет с атрибутом по умолчанию None (для указания другого атрибута используйте Open перегрузку метода).This Open method opens the package with a default None attribute (to specify a different attribute use the Open method overload).

Дополнительные сведения см. в спецификации Open Packaging Conventions (OPC), доступной для загрузки по адресу https://go.microsoft.com/fwlink/?LinkID=71255 .For additional information, see the Open Packaging Conventions (OPC) specification available for download at https://go.microsoft.com/fwlink/?LinkID=71255.

Применяется к

Open(String, FileMode, FileAccess, FileShare)

Открывает пакет на заданном пути с указанными значениями файлового режима, режима доступа к файлу и режима общего доступа.Opens a package at a given path using a given file mode, file access, and file share setting.

public:
 static System::IO::Packaging::Package ^ Open(System::String ^ path, System::IO::FileMode packageMode, System::IO::FileAccess packageAccess, System::IO::FileShare packageShare);
public static System.IO.Packaging.Package Open (string path, System.IO.FileMode packageMode, System.IO.FileAccess packageAccess, System.IO.FileShare packageShare);
static member Open : string * System.IO.FileMode * System.IO.FileAccess * System.IO.FileShare -> System.IO.Packaging.Package
Public Shared Function Open (path As String, packageMode As FileMode, packageAccess As FileAccess, packageShare As FileShare) As Package

Параметры

path
String

Путь и имя файла пакета.The path and file name of the package.

packageMode
FileMode

Файловый режим, в котором следует открыть пакет.The file mode in which to open the package.

packageAccess
FileAccess

Режим доступа к файлу, в котором следует открыть пакет.The file access in which to open the package.

packageShare
FileShare

Режим общего доступа, в котором следует открыть пакет.The file sharing mode in which to open the package.

Возвращаемое значение

Package

Открытый пакет.The opened package.

Исключения

path имеет значение null.path is null.

Значение packageMode, packageAccess или packageShare является недопустимым.The value for packageMode, packageAccess, or packageShare is not valid.

Примеры

В следующем примере показано, как создать новый элемент Package , включающий PackageRelationship элементы и, PackagePart вместе с хранимыми данными.The following example shows how to create a new Package that incorporates PackageRelationship and PackagePart elements together with stored data. Полный пример см. в разделе запись примера пакета.For the complete sample, see Writing a Package Sample.

//  -------------------------- CreatePackage --------------------------
/// <summary>
///   Creates a package zip file containing specified
///   content and resource files.</summary>
private static void CreatePackage()
{
    // Convert system path and file names to Part URIs. In this example
    // Uri partUriDocument /* /Content/Document.xml */ =
    //     PackUriHelper.CreatePartUri(
    //         new Uri("Content\Document.xml", UriKind.Relative));
    // Uri partUriResource /* /Resources/Image1.jpg */ =
    //     PackUriHelper.CreatePartUri(
    //         new Uri("Resources\Image1.jpg", UriKind.Relative));
    Uri partUriDocument = PackUriHelper.CreatePartUri(
                              new Uri(documentPath, UriKind.Relative));
    Uri partUriResource = PackUriHelper.CreatePartUri(
                              new Uri(resourcePath, UriKind.Relative));

    // Create the Package
    // (If the package file already exists, FileMode.Create will
    //  automatically delete it first before creating a new one.
    //  The 'using' statement insures that 'package' is
    //  closed and disposed when it goes out of scope.)
    using (Package package =
        Package.Open(packagePath, FileMode.Create))
    {
        // Add the Document part to the Package
        PackagePart packagePartDocument =
            package.CreatePart(partUriDocument,
                           System.Net.Mime.MediaTypeNames.Text.Xml);

        // Copy the data to the Document Part
        using (FileStream fileStream = new FileStream(
               documentPath, FileMode.Open, FileAccess.Read))
        {
            CopyStream(fileStream, packagePartDocument.GetStream());
        }// end:using(fileStream) - Close and dispose fileStream.

        // Add a Package Relationship to the Document Part
        package.CreateRelationship(packagePartDocument.Uri,
                                   TargetMode.Internal,
                                   PackageRelationshipType);

        // Add a Resource Part to the Package
        PackagePart packagePartResource =
            package.CreatePart(partUriResource,
                           System.Net.Mime.MediaTypeNames.Image.Jpeg);

        // Copy the data to the Resource Part
        using (FileStream fileStream = new FileStream(
               resourcePath, FileMode.Open, FileAccess.Read))
        {
            CopyStream(fileStream, packagePartResource.GetStream());
        }// end:using(fileStream) - Close and dispose fileStream.

        // Add Relationship from the Document part to the Resource part
        packagePartDocument.CreateRelationship(
                                new Uri(@"../resources/image1.jpg",
                                UriKind.Relative),
                                TargetMode.Internal,
                                ResourceRelationshipType);
    }// end:using (Package package) - Close and dispose package.
}// end:CreatePackage()

//  --------------------------- CopyStream ---------------------------
/// <summary>
///   Copies data from a source stream to a target stream.</summary>
/// <param name="source">
///   The source stream to copy from.</param>
/// <param name="target">
///   The destination stream to copy to.</param>
private static void CopyStream(Stream source, Stream target)
{
    const int bufSize = 0x1000;
    byte[] buf = new byte[bufSize];
    int bytesRead = 0;
    while ((bytesRead = source.Read(buf, 0, bufSize)) > 0)
        target.Write(buf, 0, bytesRead);
}// end:CopyStream()
'  -------------------------- CreatePackage --------------------------
''' <summary>
'''   Creates a package zip file containing specified
'''   content and resource files.</summary>
Private Shared Sub CreatePackage()
    ' Convert system path and file names to Part URIs. In this example
    ' Dim partUriDocument as Uri /* /Content/Document.xml */ =
    '     PackUriHelper.CreatePartUri(
    '         New Uri("Content\Document.xml", UriKind.Relative))
    ' Dim partUriResource as Uri /* /Resources/Image1.jpg */ =
    '     PackUriHelper.CreatePartUri(
    '         New Uri("Resources\Image1.jpg", UriKind.Relative))
    Dim partUriDocument As Uri = PackUriHelper.CreatePartUri(New Uri(documentPath, UriKind.Relative))
    Dim partUriResource As Uri = PackUriHelper.CreatePartUri(New Uri(resourcePath, UriKind.Relative))

    ' Create the Package
    ' (If the package file already exists, FileMode.Create will
    '  automatically delete it first before creating a new one.
    '  The 'using' statement insures that 'package' is
    '  closed and disposed when it goes out of scope.)
    Using package As Package = Package.Open(packagePath, FileMode.Create)
        ' Add the Document part to the Package
        Dim packagePartDocument As PackagePart = package.CreatePart(partUriDocument, System.Net.Mime.MediaTypeNames.Text.Xml)

        ' Copy the data to the Document Part
        Using fileStream As New FileStream(documentPath, FileMode.Open, FileAccess.Read)
            CopyStream(fileStream, packagePartDocument.GetStream())
        End Using ' end:using(fileStream) - Close and dispose fileStream.

        ' Add a Package Relationship to the Document Part
        package.CreateRelationship(packagePartDocument.Uri, TargetMode.Internal, PackageRelationshipType)

        ' Add a Resource Part to the Package
        Dim packagePartResource As PackagePart = package.CreatePart(partUriResource, System.Net.Mime.MediaTypeNames.Image.Jpeg)

        ' Copy the data to the Resource Part
        Using fileStream As New FileStream(resourcePath, FileMode.Open, FileAccess.Read)
            CopyStream(fileStream, packagePartResource.GetStream())
        End Using ' end:using(fileStream) - Close and dispose fileStream.

        ' Add Relationship from the Document part to the Resource part
        packagePartDocument.CreateRelationship(New Uri("../resources/image1.jpg", UriKind.Relative), TargetMode.Internal, ResourceRelationshipType)

    End Using ' end:using (Package package) - Close and dispose package.

End Sub


'  --------------------------- CopyStream ---------------------------
''' <summary>
'''   Copies data from a source stream to a target stream.</summary>
''' <param name="source">
'''   The source stream to copy from.</param>
''' <param name="target">
'''   The destination stream to copy to.</param>
Private Shared Sub CopyStream(ByVal source As Stream, ByVal target As Stream)
    Const bufSize As Integer = &H1000
    Dim buf(bufSize - 1) As Byte
    Dim bytesRead As Integer = 0
    bytesRead = source.Read(buf, 0, bufSize)
    Do While bytesRead > 0
        target.Write(buf, 0, bytesRead)
        bytesRead = source.Read(buf, 0, bufSize)
    Loop
End Sub

Комментарии

ZipPackage тип пакета по умолчанию, используемый Open методом.ZipPackage is the default package type that is used by the Open method.

Дополнительные сведения см. в спецификации Open Packaging Conventions (OPC), доступной для загрузки по адресу https://go.microsoft.com/fwlink/?LinkID=71255 .For additional information, see the Open Packaging Conventions (OPC) specification available for download at https://go.microsoft.com/fwlink/?LinkID=71255.

Применяется к