ParameterInfo.ParameterType ParameterInfo.ParameterType ParameterInfo.ParameterType ParameterInfo.ParameterType Property

Определение

Получает тип Type данного параметра.Gets the Type of this parameter.

public:
 virtual property Type ^ ParameterType { Type ^ get(); };
public virtual Type ParameterType { get; }
member this.ParameterType : Type
Public Overridable ReadOnly Property ParameterType As Type

Значение свойства

Объект Type, который представляет тип Type данного параметра.The Type object that represents the Type of this parameter.

Примеры

В следующем примере показано, как получить ParameterInfo объекты для параметров метода, а затем ParameterType использовать свойство для отображения типа каждого параметра.The following example shows how to get ParameterInfo objects for the parameters of a method, and then use the ParameterType property to display the type of each parameter.

using namespace System;
using namespace System::Reflection;
using namespace System::Runtime::InteropServices;
public ref class parminfo
{
public:
   static void mymethod( int int1m, [Out]interior_ptr<String^> str2m, interior_ptr<String^> str3m )
   {
       *str2m = "in mymethod";
   }

};

int main()
{
   Console::WriteLine( "\nReflection.Parameterinfo" );
   
   //Get the ParameterInfo parameter of a function.
   //Get the type.
   Type^ Mytype = Type::GetType( "parminfo" );
   
   //Get and display the method.
   MethodBase^ Mymethodbase = Mytype->GetMethod( "mymethod" );
   Console::Write( "\nMymethodbase = {0}", Mymethodbase );
   
   //Get the ParameterInfo array.
   array<ParameterInfo^>^Myarray = Mymethodbase->GetParameters();
   
   //Get and display the ParameterInfo of each parameter.
   System::Collections::IEnumerator^ enum0 = Myarray->GetEnumerator();
   while ( enum0->MoveNext() )
   {
      ParameterInfo^ Myparam = safe_cast<ParameterInfo^>(enum0->Current);
      Console::Write( "\nFor parameter # {0}, the ParameterType is - {1}", Myparam->Position, Myparam->ParameterType );
   }

   return 0;
}

/*
This code produces the following output:

Reflection.Parameterinfo

Mymethodbase = Void mymethod(Int32, System.String ByRef, System.String ByRef)
For parameter # 0, the ParameterType is - System.Int32
For parameter # 1, the ParameterType is - System.String&
For parameter # 2, the ParameterType is - System.String&
*/
 using System;
 using System.Reflection;

 class parminfo
 {
    public static void mymethod (
       int int1m, out string str2m, ref string str3m)
    {
       str2m = "in mymethod";
    }
  
    public static int Main(string[] args)
    {
       Console.WriteLine("\nReflection.Parameterinfo");
       
       //Get the ParameterInfo parameter of a function.
  
       //Get the type.
       Type Mytype = Type.GetType("parminfo");
  
       //Get and display the method.
       MethodBase Mymethodbase = Mytype.GetMethod("mymethod");
       Console.Write("\nMymethodbase = " + Mymethodbase);
  
       //Get the ParameterInfo array.
       ParameterInfo[]Myarray = Mymethodbase.GetParameters();
       
       //Get and display the ParameterInfo of each parameter.
       foreach (ParameterInfo Myparam in Myarray)
       {
          Console.Write ("\nFor parameter # " + Myparam.Position 
             + ", the ParameterType is - " + Myparam.ParameterType);
       }
       return 0;
    }
 }

 /*
 This code produces the following output:
 
Reflection.Parameterinfo

Mymethodbase = Void mymethod(Int32, System.String ByRef, System.String ByRef)
For parameter # 0, the ParameterType is - System.Int32
For parameter # 1, the ParameterType is - System.String&
For parameter # 2, the ParameterType is - System.String&
 */
Imports System.Reflection

Class parminfo
    
    Public Shared Sub mymethod(int1m As Integer, ByRef str2m As String, _
    ByRef str3m As String)
        str2m = "in mymethod"
    End Sub
       
    Public Shared Function Main() As Integer
        Console.WriteLine(ControlChars.CrLf + "Reflection.Parameterinfo")
        
        'Get the ParameterInfo parameter of a function.
        'Get the type.
        Dim Mytype As Type = GetType(parminfo)
        
        'Get and display the method.
        Dim Mymethodbase As MethodBase = Mytype.GetMethod("mymethod")
        Console.Write(ControlChars.CrLf _
           + "Mymethodbase = " + Mymethodbase.ToString())
        
        'Get the ParameterInfo array.
        Dim Myarray As ParameterInfo() = Mymethodbase.GetParameters()
        
        'Get and display the ParameterInfo of each parameter.
        Dim Myparam As ParameterInfo
        For Each Myparam In  Myarray
            Console.Write(ControlChars.CrLf _
               + "For parameter # " + Myparam.Position.ToString() _
               + ", the ParameterType is - " + Myparam.ParameterType.ToString())
        Next Myparam
        Return 0
    End Function
End Class

' This code produces the following output:
' 
' Reflection.Parameterinfo

' Mymethodbase = Void mymethod(Int32, System.String ByRef, System.String ByRef)
' For parameter # 0, the ParameterType is - System.Int32
' For parameter # 1, the ParameterType is - System.String&
' For parameter # 2, the ParameterType is - System.String& 

Комментарии

Этот метод зависит от необязательных метаданных и может быть недоступен во всех компиляторах.This method depends on an optional metadata and might not be available in all compilers.

Чтобы получить ParameterInfo массив, сначала нужно получить метод или конструктор, а затем вызвать MethodBase.GetParameters.To get the ParameterInfo array, first get the method or the constructor and then call MethodBase.GetParameters.

Применяется к