DataGrid Constructor
Definition
Important
Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.
Initializes a new instance of the DataGrid class.
public:
DataGrid();
public DataGrid ();
Public Sub New ()
Examples
The following code example creates a new System.Windows.Forms.DataGrid and uses the SetDataBinding method to set the DataSource and DataMember properties.
' This object variable must go in the Declarations section:
Private DataGrid1 As DataGrid
Private Sub CreateDataGrid()
' Initialize a new DataGrid control.
me.Datagrid1 = New DataGrid
Dim myDataSet As DataSet = New DataSet("myDataSet")
Dim myDataTable As DataTable = New DataTable("Customers")
myDataSet.Tables.Add(myDataTable)
' Insert code to populate the DataTable with rows.
' Set the DataSource and DataMember of the DataGrid control.
DataGrid1.SetDataBinding(myDataSet, "Customers")
End Sub
Remarks
To populate a newly created System.Windows.Forms.DataGrid control, set the DataSource property to a valid source, such as a DataView, DataSet, or DataViewManager.
Applies to
See also
意見反應
https://aka.ms/ContentUserFeedback。
即將登場:在 2024 年,我們將逐步淘汰 GitHub 問題作為內容的意見反應機制,並將它取代為新的意見反應系統。 如需詳細資訊,請參閱:提交並檢視相關的意見反應